Class/stream choose karne par subjects, quizzes aur daily practice relevant content ke saath open honge.
start-point se related questions ko ek jagah revise karein. Har question me bilingual content, answer feedback aur explanation available hai.
7 questions tagged with start-point.
What is the starting point of \(y=\sqrt{x+9}-4\)?
A. ((-9,-4))
From the inside (x+9=0), (x=-9). Then (y=-4).
The correct answer is A. ((-9,-4)). From the inside (x+9=0), (x=-9). Then (y=-4).
अंदर (x+9=0) से (x=-9) मिलता है। तब (y=-4) है।
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What is the starting point of the graph \(y=5-\sqrt{x+2}\)?
A. ((-2,5))
The expression inside the square root starts at (x+2=0). Then (y=5), so the point is ((-2,5)).
The correct answer is A. ((-2,5)). The expression inside the square root starts at (x+2=0). Then (y=5), so the point is ((-2,5)).
वर्गमूल का अंदरूनी भाग (x+2=0) पर शुरू होता है। तब (y=5) है इसलिए बिंदु ((-2,5)) है।
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What is the starting point of (f(x)=\sqrt{x+6}-2)?
A. ((-6,-2))
\(\sqrt{x+6}\) starts at (x=-6), and (-2) is added outside. So the starting point is ((-6,-2)).
The correct answer is A. ((-6,-2)). \(\sqrt{x+6}\) starts at (x=-6), and (-2) is added outside. So the starting point is ((-6,-2)).
\(\sqrt{x+6}\) (x=-6) से शुरू होता है और बाहर (-2) जुड़ता है। इसलिए प्रारंभिक बिंदु ((-6,-2)) है।
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What is the starting point of (f(x)=\sqrt{x+2}-3)?
A. ((-2,-3))
\(\sqrt{x+2}\) starts when (x+2=0), that is (x=-2). The outside (-3) makes the starting point ((-2,-3)).
The correct answer is A. ((-2,-3)). \(\sqrt{x+2}\) starts when (x+2=0), that is (x=-2). The outside (-3) makes the starting point ((-2,-3)).
\(\sqrt{x+2}\) तब शुरू होता है जब (x+2=0), अर्थात (x=-2)। बाहर (-3) होने से प्रारंभिक बिंदु ((-2,-3)) है।
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What is the starting point of (f(x)=\sqrt{x+1}-3)?
A. ((-1,-3))
\(\sqrt{x+1}\) starts at (x=-1), and (3) is subtracted outside. So the starting point is ((-1,-3)).
The correct answer is A. ((-1,-3)). \(\sqrt{x+1}\) starts at (x=-1), and (3) is subtracted outside. So the starting point is ((-1,-3)).
\(\sqrt{x+1}\) (x=-1) से शुरू होता है और बाहर (3) घटता है। इसलिए प्रारंभिक बिंदु ((-1,-3)) है।
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What is the starting point of (f(x)=\sqrt{x+4})?
A. ((-4,0))
In \(\sqrt{x+4}\), (x+4=0) gives (x=-4). So the starting point is ((-4,0)).
The correct answer is A. ((-4,0)). In \(\sqrt{x+4}\), (x+4=0) gives (x=-4). So the starting point is ((-4,0)).
\(\sqrt{x+4}\) में (x+4=0) से (x=-4) मिलता है। इसलिए प्रारंभिक बिंदु ((-4,0)) है।
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From which point does the graph of (f(x)=\sqrt{x-1}) start?
B. ((1,0))
In \(\sqrt{x-1}\), (x-1=0) gives (x=1). So the graph starts from ((1,0)).
The correct answer is B. ((1,0)). In \(\sqrt{x-1}\), (x-1=0) gives (x=1). So the graph starts from ((1,0)).
\(\sqrt{x-1}\) में (x-1=0) से (x=1) मिलता है। इसलिए ग्राफ ((1,0)) से शुरू होता है।
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