Practice focused topic-wise MCQs with answers and explanations for quick revision and exam preparation.
Difficulty select karke sirf is topic ke focused MCQs practice karein. Score, timer aur explanations student-friendly flow me milenge.
Showing 31-40 of 550 questions.
Which equation is quadratic in (x) but not in (y)?
A. \(x^2+5x+6=0\)
विकल्प (A) में चर (x) की घात (2) है। इसलिए यह (x) में द्विघात है। / In option (A), the variable (x) has degree (2). So it is quadratic in (x).
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What is the standard form of (3x(x-2)=0)?
A. \(3x^2-6x=0\)
(3x) को दोनों पदों से गुणा करने पर \(3x^2-6x=0\) मिलता है। चिन्ह पर ध्यान दें। / Multiplying (3x) by both terms gives \(3x^2-6x=0\). Watch the sign.
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If (p(x)=x-2-1), what is (p(1))?
A. (0)
(p(1)=12-1=0) है। जब (p(a)=0) हो तो (a) शून्यक कहलाता है। / (p(1)=12-1=0). When (p(a)=0), (a) is called a zero.
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Which option is the constant term in \(2x^2+3x+1=0\)?
C. (1)
स्थिर पद में (x) नहीं होता। इसलिए (1) स्थिर पद है। / The constant term does not contain (x). Hence (1) is the constant term.
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Which term is absent in \(x^2+10x=0\)?
C. स्थिर पदConstant term
इसे \(x^2+10x+0=0\) माना जाता है। इसलिए स्थिर पद अनुपस्थित है। / It is treated as \(x^2+10x+0=0\). So the constant term is absent.
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Which equation is a pure quadratic like \(x^2+5=0\)?
A. \(x^2-9=0\)
शुद्ध द्विघात में (x) वाला रैखिक पद नहीं होता। \(x^2-9=0\) ऐसा ही है। / A pure quadratic has no linear (x) term. \(x^2-9=0\) is of that type.
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What happens when (x=-2) is put in \(x^2+4x+4=0\)?
A. समीकरण संतुष्ट होता हैThe equation is satisfied
((-2)2+4(-2)+4=0) है। अतः (x=-2) हल है। / ((-2)2+4(-2)+4=0). Hence (x=-2) is a solution.
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Which form represents (a=2), (b=-5), (c=3) in \(ax^2+bx+c=0\)?
A. \(2x^2-5x+3=0\)
दिए गए मान सीधे मानक रूप में रखने पर \(2x^2-5x+3=0\) मिलता है। (b) का चिन्ह ध्यान रखें। / Putting the given values in standard form gives \(2x^2-5x+3=0\). Keep the sign of (b) carefully.
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If (a=1), (b=0), (c=-25), what is the equation?
A. \(x^2-25=0\)
\(ax^2+bx+c=0\) में रखने पर \(x^2+0x-25=0\) मिलता है। इसे \(x^2-25=0\) लिखते हैं। / Substituting in \(ax^2+bx+c=0\) gives \(x^2+0x-25=0\). This is written as \(x^2-25=0\).
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Which equation becomes \(x^2-7x+10=0\) after writing in standard form?
A. \(x^2-7x=-10\)
\(x^2-7x=-10\) में (-10) को बाईं ओर लाने पर (+10) बनता है। इसलिए मानक रूप \(x^2-7x+10=0\) है। / In \(x^2-7x=-10\), moving (-10) to the left gives (+10). So the standard form is \(x^2-7x+10=0\).
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