Practice focused topic-wise MCQs with answers and explanations for quick revision and exam preparation.
Difficulty select karke sirf is topic ke focused MCQs practice karein. Score, timer aur explanations student-friendly flow me milenge.
Showing 491-500 of 600 questions.
Which polynomial has zeroes (-1) and (4)?
A. \(x^2-3x-4\)
शून्यकों से बहुपद ((x+1)(x-4)=x-2-3x-4) बनता है। चिन्ह बदलते समय सावधानी रखें। / The polynomial is ((x+1)(x-4)=x-2-3x-4). Be careful with signs while forming factors.
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If the sum and product of zeroes of (p(x)=x-2-ax+a) are equal, and \(a\neq0\), what is (a)?
A. कोई भी अशून्य वास्तविक संख्याAny non-zero real number
योग (a) और गुणनफल (a) दोनों समान हैं। इसलिए \(a\neq0\) के लिए हर अशून्य (a) काम करता है। / The sum is (a) and the product is also (a). Therefore every non-zero (a) works.
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If both zeroes of (p(x)=2x-2+kx+8) are equal, what is \(k^2\)?
A. (64)
बराबर शून्यकों के लिए विविक्तकर (0) होता है, अतः \(k^2-4\cdot2\cdot8=0\)। इसलिए \(k^2=64\) है। / For equal zeroes, the discriminant is (0), so \(k^2-4\cdot2\cdot8=0\). Hence \(k^2=64\).
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If one zero of (p(x)=x-2+kx+16) is twice the other and both are positive, what is (k)?
A. -\(6\sqrt{2}\)
शून्यक (t) और (2t) मानें, तो \(2t^2=16\) से \(t=2\sqrt{2}\) है। योग \(6\sqrt{2}\) है, इसलिए \(-k=6\sqrt{2}\) और \(k=-6\sqrt{2}\)। / Let the zeroes be (t) and (2t), then \(2t^2=16\) gives \(t=2\sqrt{2}\). The sum is \(6\sqrt{2}\), so \(-k=6\sqrt{2}\) and \(k=-6\sqrt{2}\).
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If one zero of (p(x)=x-2-10x+r) is (4), what is the other zero?
A. (6)
शून्यकों का योग (10) है। एक शून्यक (4) है, इसलिए दूसरा (10-4=6) है। / The sum of zeroes is (10). Since one zero is (4), the other is (10-4=6).
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If one zero of (p(x)=x-2+3x-18) is (3), what is the other zero?
A. -(6)
शून्यकों का गुणनफल (-18) है। एक शून्यक (3) है, इसलिए दूसरा \(-18\div3=-6\) है। / The product of zeroes is (-18). Since one zero is (3), the other is \(-18\div3=-6\).
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If (p(x)=x-3-7x+6), which of the following is not a factor of (p(x))?
A. (x+3)
(p(-3)=-27+21+6=0), इसलिए (x+3) वास्तव में गुणनखंड है। सही जाँच में यह प्रश्न विकल्प-त्रुटि दिखाता है, इसलिए हर विकल्प को (p(a)) से जाँचें। / (p(-3)=-27+21+6=0), so (x+3) is actually a factor. This reveals an option error, so check each option using (p(a)).
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If (p(x)=x-4-1), how many real zeroes are there besides (x=1) and (x=-1)?
A. (0)
(x-4-1=\(x^2-1\)\(x^2+1\)) है। \(x^2+1\) के वास्तविक शून्यक नहीं हैं, इसलिए अतिरिक्त वास्तविक शून्यक (0) हैं। / (x-4-1=\(x^2-1\)\(x^2+1\)). Since \(x^2+1\) has no real zeroes, there are (0) extra real zeroes.
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For (p(x)=x-2-2x+2), what is the correct conclusion about real zeroes?
A. कोई वास्तविक शून्यक नहींNo real zeroes
(x-2-2x+2=(x-1)2+1), जो हर वास्तविक (x) के लिए धनात्मक है। इसलिए इसका कोई वास्तविक शून्यक नहीं है। / (x-2-2x+2=(x-1)2+1), which is positive for every real (x). Hence it has no real zeroes.
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If (p(x)=x-2-7x+10) and (q(x)=p(x+1)), what are the zeroes of (q(x))?
A. (1,4)
(p(x)) के शून्यक (2) और (5) हैं, इसलिए (p(x+1)=0) के लिए (x+1=2) या (x+1=5)। अतः (q(x)) के शून्यक (1) और (4) हैं। / The zeroes of (p(x)) are (2) and (5), so for (p(x+1)=0), (x+1=2) or (x+1=5). Hence the zeroes of (q(x)) are (1) and (4).
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