If one zero of (p(x)=x^2+kx+16) is twice the other and both are positive, what is (k)?

Question

0 reads0 ratings0 helpful

Answer and explanation

Correct answer: -(6\sqrt{2}) / (-6\sqrt{2})

Let the zeroes be (t) and (2t), then (2t^2=16) gives (t=2\sqrt{2}). The sum is (6\sqrt{2}), so (-k=6\sqrt{2}) and (k=-6\sqrt{2}).

What is the correct answer to this question?

-(6\sqrt{2}) / (-6\sqrt{2})

Why is this the correct answer?

Let the zeroes be (t) and (2t), then (2t^2=16) gives (t=2\sqrt{2}). The sum is (6\sqrt{2}), so (-k=6\sqrt{2}) and (k=-6\sqrt{2}).

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Polynomials. Topic: Polynomials in one variable.

Student feedback

No ratings yetWrite a review / Rate this question

Was this question useful?

👍 0 Helpful 👎 0 Not helpful

Difficulty

Easy0%

Medium0%

Hard0%

Was the explanation clear?

Yes 0% No 0%

0 responses

No published reviews yet.