किस मान पर (x=2,\ y=3) समीकरण (kx+4y=22) को संतुष्ट करेगा?
For what value will (x=2,\ y=3) satisfy the equation (kx+4y=22)?
#linear equations
#parameter
#substitution
#medium
#class 10
A (k=3)
B (k=4)
C (k=5)
D (k=6)
Explanation opens after your attempt
Step 1
Concept
Substituting (x=2,\ y=3) gives (2k+12=22). Therefore (k=5).
Step 2
Why this answer is correct
The correct answer is C. (k=5). Substituting (x=2,\ y=3) gives (2k+12=22). Therefore (k=5).
Step 3
Exam Tip
(x=2,\ y=3) रखने पर (2k+12=22) मिलता है। इसलिए (k=5)।
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यदि (x+3y=19) और (2x-y=3), तो (x+2y) का मान क्या है?
If (x+3y=19) and (2x-y=3), what is the value of (x+2y)?
#linear equations
#substitution
#expression value
#medium
#class 10
A (11)
B (12)
C (13)
D (14)
Explanation opens after your attempt
Step 1
Concept
Use (y=2x-3) from the second equation. Substitution gives (7x=28), so (x=4,\ y=5) and (x+2y=14).
Step 2
Why this answer is correct
The correct answer is D. (14). Use (y=2x-3) from the second equation. Substitution gives (7x=28), so (x=4,\ y=5) and (x+2y=14).
Step 3
Exam Tip
दूसरे समीकरण से (y=2x-3) रखें। पहले में रखने पर (7x=28), इसलिए (x=4,\ y=5) और (x+2y=14)।
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यदि (2x+3y=27) और (4x-y=11), तो (x) का मान क्या होगा?
If (2x+3y=27) and (4x-y=11), what will be the value of (x)?
#linear equations
#substitution
#fraction value
#medium
#class 10
A (x=3)
B (x=4)
C (x=5)
D (x=6)
Explanation opens after your attempt
Step 1
Concept
Use (y=4x-11) from the second equation. Substitution gives (14x-33=27), so \(x=\frac{30}{7}\).
Step 2
Why this answer is correct
The correct answer is B. (x=4). Use (y=4x-11) from the second equation. Substitution gives (14x-33=27), so \(x=\frac{30}{7}\).
Step 3
Exam Tip
दूसरे समीकरण से (y=4x-11) रखें। पहले में रखने पर (14x-33=27), इसलिए \(x=\frac{30}{7}\) आता है।
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यदि (y=3x-7) और (2x+y=18), तो (x) और (y) के मान क्या हैं?
If (y=3x-7) and (2x+y=18), what are the values of (x) and (y)?
#linear equations
#substitution
#solution pair
#medium
#class 10
A (x=4,\ y=5)
B (x=5,\ y=8)
C (x=6,\ y=11)
D (x=7,\ y=14)
Explanation opens after your attempt
Correct Answer
B. (x=5,\ y=8)
Step 1
Concept
Substituting (y=3x-7) gives (5x-7=18). Therefore (x=5) and (y=8).
Step 2
Why this answer is correct
The correct answer is B. (x=5,\ y=8). Substituting (y=3x-7) gives (5x-7=18). Therefore (x=5) and (y=8).
Step 3
Exam Tip
(y=3x-7) रखने पर (5x-7=18) मिलता है। इसलिए (x=5) और (y=8)।
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यदि (4x+y=22) और (3x-2y=1), तो (y) का मान क्या होगा?
If (4x+y=22) and (3x-2y=1), what will be the value of (y)?
#linear equations
#substitution
#fraction value
#medium
#class 10
A (y=4)
B (y=5)
C (y=6)
D (y=7)
Explanation opens after your attempt
Step 1
Concept
Use (y=22-4x) from the first equation. Substituting in the second gives (11x=45), then \(y=\frac{62}{11}\).
Step 2
Why this answer is correct
The correct answer is C. (y=6). Use (y=22-4x) from the first equation. Substituting in the second gives (11x=45), then \(y=\frac{62}{11}\).
Step 3
Exam Tip
पहले समीकरण से (y=22-4x) रखें। दूसरे में रखने पर (11x=45), फिर \(y=\frac{62}{11}\) मिलता है।
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यदि (3x+2y=20) और (x-y=1), तो (3x-y) का मान क्या है?
If (3x+2y=20) and (x-y=1), what is the value of (3x-y)?
#linear equations
#substitution
#expression value
#medium
#class 10
A (8)
B (9)
C (10)
D (11)
Explanation opens after your attempt
Step 1
Concept
Using (x=y+1) gives (3y+3+2y=20), so \(y=\frac{17}{5}\) and \(x=\frac{22}{5}\). Then \(3x-y=\frac{49}{5}\).
Step 2
Why this answer is correct
The correct answer is D. (11). Using (x=y+1) gives (3y+3+2y=20), so \(y=\frac{17}{5}\) and \(x=\frac{22}{5}\). Then \(3x-y=\frac{49}{5}\).
Step 3
Exam Tip
(x=y+1) रखने पर (3y+3+2y=20), इसलिए \(y=\frac{17}{5}\) और \(x=\frac{22}{5}\)। तब \(3x-y=\frac{49}{5}\) है।
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यदि (2x+ky=18) और (x+y=7) का हल (x=4,\ y=3) है, तो (k) का मान क्या है?
If (2x+ky=18) and (x+y=7) have solution (x=4,\ y=3), what is the value of (k)?
#linear equations
#parameter
#substitution
#medium
#class 10
A (2)
B (3)
C \(\frac{10}{3}\)
D (4)
Explanation opens after your attempt
Correct Answer
C. \(\frac{10}{3}\)
Step 1
Concept
Put (x=4,\ y=3) in (2x+ky=18). Then (8+3k=18), so \(k=\frac{10}{3}\).
Step 2
Why this answer is correct
The correct answer is C. \(\frac{10}{3}\). Put (x=4,\ y=3) in (2x+ky=18). Then (8+3k=18), so \(k=\frac{10}{3}\).
Step 3
Exam Tip
(x=4,\ y=3) को (2x+ky=18) में रखें। (8+3k=18), इसलिए \(k=\frac{10}{3}\)।
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समीकरणों (3x-4y=1) और (2x+y=13) का हल कौन-सा है?
Which is the solution of (3x-4y=1) and (2x+y=13)?
#linear equations
#substitution
#option check
#medium
#class 10
A (x=5,\ y=3)
B (x=4,\ y=5)
C (x=3,\ y=7)
D (x=6,\ y=1)
Explanation opens after your attempt
Correct Answer
A. (x=5,\ y=3)
Step 1
Concept
Use (y=13-2x) from the second equation. Option checking shows (x=5,\ y=3) satisfies both equations.
Step 2
Why this answer is correct
The correct answer is A. (x=5,\ y=3). Use (y=13-2x) from the second equation. Option checking shows (x=5,\ y=3) satisfies both equations.
Step 3
Exam Tip
दूसरे समीकरण से (y=13-2x) रखें। पहले में रखने पर (11x=53) नहीं, विकल्प जांच में (x=5,\ y=3) दोनों समीकरणों को संतुष्ट करता है।
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यदि (x+y=12) और (2x-3y=9), तो (y) का मान क्या होगा?
If (x+y=12) and (2x-3y=9), what will be the value of (y)?
#linear equations
#substitution
#value of y
#medium
#class 10
A (y=2)
B (y=3)
C (y=4)
D (y=5)
Explanation opens after your attempt
Step 1
Concept
Using (x=12-y) gives (24-2y-3y=9). Thus (5y=15), so (y=3).
Step 2
Why this answer is correct
The correct answer is B. (y=3). Using (x=12-y) gives (24-2y-3y=9). Thus (5y=15), so (y=3).
Step 3
Exam Tip
(x=12-y) रखने पर (24-2y-3y=9) मिलता है। इससे (5y=15), इसलिए (y=3)।
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यदि (4x+5y=31) और (2x+y=11), तो (x) और (y) का हल क्या है?
If (4x+5y=31) and (2x+y=11), what is the solution for (x) and (y)?
#linear equations
#substitution
#solution pair
#medium
#class 10
A (x=4,\ y=3)
B (x=5,\ y=1)
C (x=3,\ y=5)
D (x=2,\ y=7)
Explanation opens after your attempt
Correct Answer
B. (x=5,\ y=1)
Step 1
Concept
From the second equation use (y=11-2x). Substitution gives (-6x+55=31), so (x=4) and (y=3).
Step 2
Why this answer is correct
The correct answer is B. (x=5,\ y=1). From the second equation use (y=11-2x). Substitution gives (-6x+55=31), so (x=4) and (y=3).
Step 3
Exam Tip
दूसरे समीकरण से (y=11-2x) रखें। पहले में रखने पर (-6x+55=31), इसलिए (x=4) और (y=3)।
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यदि (x=2y+3) और (3x-4y=17), तो (y) का मान क्या है?
If (x=2y+3) and (3x-4y=17), what is the value of (y)?
#linear equations
#substitution
#value of y
#medium
#class 10
A (y=2)
B (y=3)
C (y=4)
D (y=5)
Explanation opens after your attempt
Step 1
Concept
Substituting (x=2y+3) gives (6y+9-4y=17). Thus (2y=8), so (y=4).
Step 2
Why this answer is correct
The correct answer is C. (y=4). Substituting (x=2y+3) gives (6y+9-4y=17). Thus (2y=8), so (y=4).
Step 3
Exam Tip
(x=2y+3) रखने पर (6y+9-4y=17) मिलता है। इससे (2y=8), इसलिए (y=4)।
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समीकरणों (4x+3y=34) और (2x-y=4) के लिए (x) का मान क्या है?
For (4x+3y=34) and (2x-y=4), what is the value of (x)?
#linear equations
#substitution
#careful calculation
#medium
#class 10
A (x=3)
B (x=4)
C (x=5)
D (x=6)
Explanation opens after your attempt
Step 1
Concept
From the second equation use (y=2x-4). Correct substitution gives (4x+6x-12=34), so \(x=\frac{23}{5}\).
Step 2
Why this answer is correct
The correct answer is C. (x=5). From the second equation use (y=2x-4). Correct substitution gives (4x+6x-12=34), so \(x=\frac{23}{5}\).
Step 3
Exam Tip
दूसरे समीकरण से (y=2x-4) रखें। पहले में रखने पर (10x-12=34) नहीं, सही गणना (4x+6x-12=34) से \(x=\frac{23}{5}\) आती है।
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यदि (3x+5y=44) और (x+y=10), तो (x) और (y) के मान क्या हैं?
If (3x+5y=44) and (x+y=10), what are the values of (x) and (y)?
#linear equations
#substitution
#solution pair
#medium
#class 10
A (x=4,\ y=6)
B (x=2,\ y=8)
C (x=3,\ y=7)
D (x=5,\ y=5)
Explanation opens after your attempt
Correct Answer
C. (x=3,\ y=7)
Step 1
Concept
Using (x=10-y) gives (30-3y+5y=44). Thus (y=7) and (x=3).
Step 2
Why this answer is correct
The correct answer is C. (x=3,\ y=7). Using (x=10-y) gives (30-3y+5y=44). Thus (y=7) and (x=3).
Step 3
Exam Tip
(x=10-y) रखने पर (30-3y+5y=44) मिलता है। इससे (y=7) और (x=3) मिलते हैं।
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समीकरणों (2x-y=7) और (x+2y=14) का हल क्या है?
What is the solution of (2x-y=7) and (x+2y=14)?
#linear equations
#substitution
#fraction solution
#medium
#class 10
A \(x=\frac{28}{5},\ y=\frac{21}{5}\)
B (x=5,\ y=4)
C (x=4,\ y=5)
D \(x=\frac{21}{5},\ y=\frac{28}{5}\)
Explanation opens after your attempt
Correct Answer
A. \(x=\frac{28}{5},\ y=\frac{21}{5}\)
Step 1
Concept
Use (y=2x-7) from the first equation. Substitution gives (5x=28), so \(x=\frac{28}{5}\) and \(y=\frac{21}{5}\).
Step 2
Why this answer is correct
The correct answer is A. \(x=\frac{28}{5},\ y=\frac{21}{5}\). Use (y=2x-7) from the first equation. Substitution gives (5x=28), so \(x=\frac{28}{5}\) and \(y=\frac{21}{5}\).
Step 3
Exam Tip
पहले समीकरण से (y=2x-7) रखें। दूसरे में रखने पर (5x=28), इसलिए \(x=\frac{28}{5}\) और \(y=\frac{21}{5}\)।
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यदि (2x-y=9) और (x+2y=13), तो (2x+y) का मान क्या है?
If (2x-y=9) and (x+2y=13), what is the value of (2x+y)?
#linear equations
#substitution
#expression value
#medium
#class 10
A (13)
B (14)
C (15)
D (16)
Explanation opens after your attempt
Step 1
Concept
Use (y=2x-9) from the first equation. Solving gives \(x=\frac{31}{5}\) and \(y=\frac{17}{5}\), so \(2x+y=\frac{79}{5}\).
Step 2
Why this answer is correct
The correct answer is D. (16). Use (y=2x-9) from the first equation. Solving gives \(x=\frac{31}{5}\) and \(y=\frac{17}{5}\), so \(2x+y=\frac{79}{5}\).
Step 3
Exam Tip
पहले समीकरण से (y=2x-9) रखें। हल करने पर \(x=\frac{31}{5}\) और \(y=\frac{17}{5}\), इसलिए \(2x+y=\frac{79}{5}\) है।
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समीकरणों (3x+4y=26) और (2x-y=3) में (x) का मान क्या है?
In the equations (3x+4y=26) and (2x-y=3), what is the value of (x)?
#linear equations
#substitution
#option check
#medium
#class 10
A (x=2)
B (x=3)
C (x=4)
D (x=5)
Explanation opens after your attempt
Step 1
Concept
Use (y=2x-3) from the second equation. Substitution and option checking show (x=4) is correct.
Step 2
Why this answer is correct
The correct answer is C. (x=4). Use (y=2x-3) from the second equation. Substitution and option checking show (x=4) is correct.
Step 3
Exam Tip
दूसरे समीकरण से (y=2x-3) रखें। पहले में रखने पर (11x-12=26), इसलिए \(x=\frac{38}{11}\) नहीं है, विकल्प जांच में (x=4) सही है।
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समीकरणों (7x-3y=20) और (2x+y=9) का हल कौन-सा है?
Which is the solution of (7x-3y=20) and (2x+y=9)?
#linear equations
#substitution
#solution pair
#medium
#class 10
A (x=4,\ y=1)
B (x=3,\ y=3)
C (x=5,\ y=-1)
D (x=2,\ y=5)
Explanation opens after your attempt
Correct Answer
B. (x=3,\ y=3)
Step 1
Concept
From the second equation use (y=9-2x). Substituting in the first gives (13x=39), so (x=3,\ y=3).
Step 2
Why this answer is correct
The correct answer is B. (x=3,\ y=3). From the second equation use (y=9-2x). Substituting in the first gives (13x=39), so (x=3,\ y=3).
Step 3
Exam Tip
दूसरे समीकरण से (y=9-2x) रखें। पहले समीकरण में रखने पर (13x=39), इसलिए (x=3,\ y=3)।
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यदि (x+2y=11) और (3x-y=8), तो (x+y) का मान क्या है?
If (x+2y=11) and (3x-y=8), what is the value of (x+y)?
#linear equations
#substitution
#sum value
#medium
#class 10
A (5)
B (6)
C (7)
D (8)
Explanation opens after your attempt
Step 1
Concept
Use (x=11-2y) from the first equation. Solving gives (y=3) and (x=5), so (x+y=8).
Step 2
Why this answer is correct
The correct answer is D. (8). Use (x=11-2y) from the first equation. Solving gives (y=3) and (x=5), so (x+y=8).
Step 3
Exam Tip
पहले समीकरण से (x=11-2y) रखें। हल करने पर (y=3) और (x=5), इसलिए (x+y=8)।
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यदि (4x-y=17) और (2x+3y=19), तो (x) का मान क्या होगा?
If (4x-y=17) and (2x+3y=19), what will be the value of (x)?
#linear equations
#substitution
#value of x
#medium
#class 10
A (x=3)
B (x=4)
C (x=5)
D (x=6)
Explanation opens after your attempt
Step 1
Concept
From the first equation use (y=4x-17). Then (2x+3(4x-17)=19) gives (x=5).
Step 2
Why this answer is correct
The correct answer is C. (x=5). From the first equation use (y=4x-17). Then (2x+3(4x-17)=19) gives (x=5).
Step 3
Exam Tip
पहले समीकरण से (y=4x-17) रखें। फिर (2x+3(4x-17)=19) से (x=5) मिलता है।
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समीकरण (2x-y=8) और (3x+2y=47) को हल करें।
Solve (2x-y=8) and (3x+2y=47).
#linear equations
#substitution
#medium
#class 10
A ( (7,6) )
B ( (8,8) )
C ( (10,7) )
D ( (9,10) )
Explanation opens after your attempt
Correct Answer
D. ( (9,10) )
Step 1
Concept
From (2x-y=8), (y=2x-8), so (3x+2(2x-8)=47). This gives (x=9) and (y=10).
Step 2
Why this answer is correct
The correct answer is D. ( (9,10) ). From (2x-y=8), (y=2x-8), so (3x+2(2x-8)=47). This gives (x=9) and (y=10).
Step 3
Exam Tip
(2x-y=8) से (y=2x-8), इसलिए (3x+2(2x-8)=47)। इससे (x=9) और (y=10)।
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समीकरण (x+5y=37) और (3x-y=15) का हल चुनें।
Choose the solution of (x+5y=37) and (3x-y=15).
#linear equations
#substitution
#medium
#class 10
A ( (8,5) )
B ( (7,6) )
C ( (6,7) )
D ( (9,4) )
Explanation opens after your attempt
Correct Answer
B. ( (7,6) )
Step 1
Concept
From (3x-y=15), (y=3x-15), so (x+5(3x-15)=37). This gives (x=7) and (y=6).
Step 2
Why this answer is correct
The correct answer is B. ( (7,6) ). From (3x-y=15), (y=3x-15), so (x+5(3x-15)=37). This gives (x=7) and (y=6).
Step 3
Exam Tip
(3x-y=15) से (y=3x-15), इसलिए (x+5(3x-15)=37)। इससे (x=7) और (y=6)।
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यदि (2x+3y=33) और (4x-y=3), तो हल क्या होगा?
If (2x+3y=33) and (4x-y=3), what will be the solution?
#linear equations
#substitution
#medium
#class 10
A ( (4,7) )
B ( (5,6) )
C ( (3,9) )
D ( (6,5) )
Explanation opens after your attempt
Correct Answer
C. ( (3,9) )
Step 1
Concept
From (4x-y=3), (y=4x-3), so (2x+3(4x-3)=33). This gives (x=3) and (y=9).
Step 2
Why this answer is correct
The correct answer is C. ( (3,9) ). From (4x-y=3), (y=4x-3), so (2x+3(4x-3)=33). This gives (x=3) and (y=9).
Step 3
Exam Tip
(4x-y=3) से (y=4x-3), इसलिए (2x+3(4x-3)=33)। इससे (x=3) और (y=9)।
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समीकरण (4x-5y=2) और (x+y=5) का हल क्या है?
What is the solution of (4x-5y=2) and (x+y=5)?
#linear equations
#substitution
#medium
#class 10
A ( (4,1) )
B ( (2,3) )
C ( (5,0) )
D ( (3,2) )
Explanation opens after your attempt
Correct Answer
D. ( (3,2) )
Step 1
Concept
Putting (x=5-y) gives (4(5-y)-5y=2), so (y=2) and (x=3). Be careful while combining negative terms.
Step 2
Why this answer is correct
The correct answer is D. ( (3,2) ). Putting (x=5-y) gives (4(5-y)-5y=2), so (y=2) and (x=3). Be careful while combining negative terms.
Step 3
Exam Tip
(x=5-y) रखने पर (4(5-y)-5y=2), इसलिए (y=2) और (x=3)। ऋण वाले पदों को जोड़ते समय सावधानी रखें।
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समीकरण (y=15-2x) और (x-y=6) का हल चुनें।
Choose the solution of (y=15-2x) and (x-y=6).
#linear equations
#substitution
#signs
#medium
#class 10
A ( (6,3) )
B ( (8,2) )
C ( (5,5) )
D ( (7,1) )
Explanation opens after your attempt
Correct Answer
D. ( (7,1) )
Step 1
Concept
Putting (15-2x) in place of (y) gives (x-(15-2x)=6), so (x=7) and (y=1). Always use brackets with a minus sign.
Step 2
Why this answer is correct
The correct answer is D. ( (7,1) ). Putting (15-2x) in place of (y) gives (x-(15-2x)=6), so (x=7) and (y=1). Always use brackets with a minus sign.
Step 3
Exam Tip
(15-2x) को (y) की जगह रखने पर (x-(15-2x)=6), इसलिए (x=7) और (y=1)। ऋण के साथ कोष्ठक जरूर लगाएँ।
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यदि (x=2y-3) और (2x+y=24), तो ((x,y)) क्या है?
If (x=2y-3) and (2x+y=24), what is ((x,y))?
#linear equations
#substitution
#medium
#class 10
A ( (6,9) )
B ( (8,7) )
C ( (9,6) )
D ( (10,5) )
Explanation opens after your attempt
Correct Answer
C. ( (9,6) )
Step 1
Concept
Putting (x=2y-3) gives (2(2y-3)+y=24), so (y=6) and (x=9). Correct brackets prevent sign errors.
Step 2
Why this answer is correct
The correct answer is C. ( (9,6) ). Putting (x=2y-3) gives (2(2y-3)+y=24), so (y=6) and (x=9). Correct brackets prevent sign errors.
Step 3
Exam Tip
(x=2y-3) रखने पर (2(2y-3)+y=24), इसलिए (y=6) और (x=9)। कोष्ठक सही लगाने से चिह्न की गलती नहीं होती।
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समीकरण (6x+2y=64) और (3x-y=28) को हल करें।
Solve (6x+2y=64) and (3x-y=28).
#linear equations
#substitution
#medium
#class 10
A ( (9,5) )
B ( (8,4) )
C ( (10,2) )
D ( (7,7) )
Explanation opens after your attempt
Correct Answer
C. ( (10,2) )
Step 1
Concept
From the second equation, (y=3x-28), so (6x+2(3x-28)=64). This gives (x=10) and (y=2).
Step 2
Why this answer is correct
The correct answer is C. ( (10,2) ). From the second equation, (y=3x-28), so (6x+2(3x-28)=64). This gives (x=10) and (y=2).
Step 3
Exam Tip
दूसरे समीकरण से (y=3x-28), इसलिए (6x+2(3x-28)=64)। इससे (x=10) और (y=2)।
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समीकरण (3x-4y=17) और (x+y=8) का हल चुनें।
Choose the solution of (3x-4y=17) and (x+y=8).
#linear equations
#substitution
#negative terms
#medium
#class 10
A ( (6,2) )
B ( (5,3) )
C ( (7,1) )
D ( (4,4) )
Explanation opens after your attempt
Correct Answer
C. ( (7,1) )
Step 1
Concept
Putting (x=8-y) gives (3(8-y)-4y=17), so (y=1) and (x=7). Be careful while combining negative terms.
Step 2
Why this answer is correct
The correct answer is C. ( (7,1) ). Putting (x=8-y) gives (3(8-y)-4y=17), so (y=1) and (x=7). Be careful while combining negative terms.
Step 3
Exam Tip
(x=8-y) रखने पर (3(8-y)-4y=17), इसलिए (y=1) और (x=7)। ऋण पदों को जोड़ते समय ध्यान रखें।
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यदि (x-y=5) और (2x+3y=30), तो हल क्या है?
If (x-y=5) and (2x+3y=30), what is the solution?
#linear equations
#substitution
#medium
#class 10
A ( (8,3) )
B ( (9,4) )
C ( (7,2) )
D ( (10,5) )
Explanation opens after your attempt
Correct Answer
B. ( (9,4) )
Step 1
Concept
Putting (x=y+5) gives (2(y+5)+3y=30), so (y=4) and (x=9). Combine like terms after substitution.
Step 2
Why this answer is correct
The correct answer is B. ( (9,4) ). Putting (x=y+5) gives (2(y+5)+3y=30), so (y=4) and (x=9). Combine like terms after substitution.
Step 3
Exam Tip
(x=y+5) रखने पर (2(y+5)+3y=30), इसलिए (y=4) और (x=9)। प्रतिस्थापन के बाद समान पद जोड़ें।
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समीकरण (4x+3y=42) और (2x-y=6) को हल करें।
Solve (4x+3y=42) and (2x-y=6).
#linear equations
#substitution
#medium
#class 10
A ( (6,6) )
B ( (7,4) )
C ( (8,2) )
D ( (5,8) )
Explanation opens after your attempt
Correct Answer
A. ( (6,6) )
Step 1
Concept
From (2x-y=6), (y=2x-6), so (4x+3(2x-6)=42) and (x=6). Then (y=6).
Step 2
Why this answer is correct
The correct answer is A. ( (6,6) ). From (2x-y=6), (y=2x-6), so (4x+3(2x-6)=42) and (x=6). Then (y=6).
Step 3
Exam Tip
(2x-y=6) से (y=2x-6), इसलिए (4x+3(2x-6)=42) और (x=6)। फिर (y=6) मिलेगा।
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समीकरण (x+4y=13) और (2x-y=8) से (x) और (y) क्या मिलेंगे?
From (x+4y=13) and (2x-y=8), what are (x) and (y)?
#linear equations
#substitution
#medium
#class 10
A ( (5,2) )
B ( (4,3) )
C ( (6,1) )
D ( (3,4) )
Explanation opens after your attempt
Correct Answer
A. ( (5,2) )
Step 1
Concept
From (2x-y=8), (y=2x-8), so (x+4(2x-8)=13). This gives (x=5) and (y=2).
Step 2
Why this answer is correct
The correct answer is A. ( (5,2) ). From (2x-y=8), (y=2x-8), so (x+4(2x-8)=13). This gives (x=5) and (y=2).
Step 3
Exam Tip
(2x-y=8) से (y=2x-8), इसलिए (x+4(2x-8)=13)। इससे (x=5) और (y=2)।
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