समीकरणों (2x-y=7) और (x+2y=14) का हल क्या है?

What is the solution of (2x-y=7) and (x+2y=14)?

Explanation opens after your attempt
Correct Answer

A. \(x=\frac{28}{5},\ y=\frac{21}{5}\)

Step 1

Concept

Use (y=2x-7) from the first equation. Substitution gives (5x=28), so \(x=\frac{28}{5}\) and \(y=\frac{21}{5}\).

Step 2

Why this answer is correct

The correct answer is A. \(x=\frac{28}{5},\ y=\frac{21}{5}\). Use (y=2x-7) from the first equation. Substitution gives (5x=28), so \(x=\frac{28}{5}\) and \(y=\frac{21}{5}\).

Step 3

Exam Tip

पहले समीकरण से (y=2x-7) रखें। दूसरे में रखने पर (5x=28), इसलिए \(x=\frac{28}{5}\) और \(y=\frac{21}{5}\)।

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Mathematics Answer, Explanation and Revision Hints

समीकरणों (2x-y=7) और (x+2y=14) का हल क्या है? / What is the solution of (2x-y=7) and (x+2y=14)?

Correct Answer: A. \(x=\frac{28}{5},\ y=\frac{21}{5}\). Explanation: पहले समीकरण से (y=2x-7) रखें। दूसरे में रखने पर (5x=28), इसलिए \(x=\frac{28}{5}\) और \(y=\frac{21}{5}\)। / Use (y=2x-7) from the first equation. Substitution gives (5x=28), so \(x=\frac{28}{5}\) and \(y=\frac{21}{5}\).

Which concept should I revise for this Mathematics MCQ?

Use (y=2x-7) from the first equation. Substitution gives (5x=28), so \(x=\frac{28}{5}\) and \(y=\frac{21}{5}\).

What exam hint can help solve this Mathematics question?

पहले समीकरण से (y=2x-7) रखें। दूसरे में रखने पर (5x=28), इसलिए \(x=\frac{28}{5}\) और \(y=\frac{21}{5}\)।