Practice focused topic-wise MCQs with answers and explanations for quick revision and exam preparation.
Difficulty select karke sirf is topic ke focused MCQs practice karein. Score, timer aur explanations student-friendly flow me milenge.
Showing 131-140 of 650 questions.
In a square root spiral, what type of number is \(\sqrt{2}\)?
A. अपरिमेय संख्याIrrational number
\(\sqrt{2}\) किसी पूर्ण वर्ग का वर्गमूल नहीं है। इसलिए यह अपरिमेय संख्या है। / \(\sqrt{2}\) is not the square root of a perfect square. Therefore it is irrational.
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Just before constructing \(\sqrt{15}\) in a square root spiral, which hypotenuse will be present?
B. \(\sqrt{14}\)
\(\sqrt{14}\) के साथ (1) इकाई लंब से \(\sqrt{15}\) बनता है। पिछला कर्ण एक कम संख्या का है। / With \(\sqrt{14}\) and a (1) unit perpendicular, \(\sqrt{15}\) is formed. The previous hypotenuse has one less number.
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In a square root spiral, which hypotenuse will be formed after \(\sqrt{24}\)?
C. \(\sqrt{25}\)
अगले चरण में \(\sqrt{24+1}=\sqrt{25}\) बनता है। संख्या क्रम में (1) बढ़ती है। / In the next step \(\sqrt{24+1}=\sqrt{25}\) is formed. The number increases by (1).
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B. \(\sqrt{3}\) का कर्णHypotenuse of \(\sqrt{3}\)
जिस वर्गमूल को अंकित करना है, उसी कर्ण की लंबाई कंपास में लेते हैं। इसलिए \(\sqrt{3}\) का कर्ण चाहिए। / The hypotenuse length of the required square root is taken in the compass. So the hypotenuse of \(\sqrt{3}\) is needed.
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In a square root spiral, \(\sqrt{3}\) lies between which whole numbers?
B. (1) और (2)(1) and (2)
क्योंकि \(1^2<3<2^2\) है। इसलिए \(\sqrt{3}\) (1) और (2) के बीच है। / Because \(1^2<3<2^2\). Therefore \(\sqrt{3}\) lies between (1) and (2).
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For what can a set square be used in a square root spiral?
A. \(90^\circ\) का कोण बनाने के लिएTo make a \(90^\circ\) angle
सेट स्क्वायर से समकोण आसानी से बनता है। सही समकोण से सही कर्ण मिलता है। / A set square helps make a right angle easily. A correct right angle gives the correct hypotenuse.
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In a square root spiral, \(\sqrt{72}\) lies between which two whole numbers?
C. (8) और (9)(8) and (9)
क्योंकि \(8^2<72<9^2\) है। इसलिए \(8<\sqrt{72}<9\) होता है। / Because \(8^2<72<9^2\). Therefore \(8<\sqrt{72}<9\).
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To construct \(\sqrt{80}\) in a square root spiral, which previous hypotenuse will be used?
B. \(\sqrt{79}\)
\(\sqrt{79}\) पर (1) इकाई लंब जोड़ने से \(\sqrt{80}\) बनता है। पिछला कर्ण एक कम संख्या का होता है। / Adding a (1) unit perpendicular to \(\sqrt{79}\) gives \(\sqrt{80}\). The previous hypotenuse has one less number.
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What is the length of \(\sqrt{81}\) in a square root spiral?
C. (9)
\(\sqrt{81}=9\) होता है। (81) पूर्ण वर्ग है। / \(\sqrt{81}=9\). The number (81) is a perfect square.
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After constructing \(\sqrt{2}\) in a square root spiral, what construction is done next?
A. \(\sqrt{2}\) के सिरे पर (1) इकाई लंब बनानाDraw a (1) unit perpendicular at the end of \(\sqrt{2}\)
\(\sqrt{2}\) के सिरे पर (1) इकाई लंब बनाकर अगला त्रिभुज बनाया जाता है। इससे \(\sqrt{3}\) मिलता है। / A (1) unit perpendicular is drawn at the end of \(\sqrt{2}\) to make the next triangle. This gives \(\sqrt{3}\).
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