वर्गमूल सर्पिल में \(\sqrt{15}\) बनाने से ठीक पहले कौन-सा कर्ण होगा?

Just before constructing \(\sqrt{15}\) in a square root spiral, which hypotenuse will be present?

Author: Muft Shiksha Editorial Team Published:
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Correct Answer

B. \(\sqrt{14}\)

Explanation

Simple Explanation

\(\sqrt{14}\) के साथ (1) इकाई लंब से \(\sqrt{15}\) बनता है। पिछला कर्ण एक कम संख्या का है। / With \(\sqrt{14}\) and a (1) unit perpendicular, \(\sqrt{15}\) is formed. The previous hypotenuse has one less number.

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Mathematics Answer, Explanation and Revision Hints

वर्गमूल सर्पिल में \(\sqrt{15}\) बनाने से ठीक पहले कौन-सा कर्ण होगा? / Just before constructing \(\sqrt{15}\) in a square root spiral, which hypotenuse will be present?

Correct Answer: B. \(\sqrt{14}\). Explanation: \(\sqrt{14}\) के साथ (1) इकाई लंब से \(\sqrt{15}\) बनता है। पिछला कर्ण एक कम संख्या का है। / With \(\sqrt{14}\) and a (1) unit perpendicular, \(\sqrt{15}\) is formed. The previous hypotenuse has one less number.