Concept-wise Practice

construction-step MCQ Questions for Class 9

construction-step se related questions ko ek jagah revise karein. Har question me bilingual content, answer feedback aur explanation available hai.

Practice Questions

3 questions tagged with construction-step.

वर्गमूल सर्पिल में \(\sqrt{2}\) बनाने के बाद कौन-सा निर्माण करना होता है?

After constructing \(\sqrt{2}\) in a square root spiral, what construction is done next?

Explanation opens after your attempt
Correct Answer

A. \(\sqrt{2}\) के सिरे पर (1) इकाई लंब बनानाDraw a (1) unit perpendicular at the end of \(\sqrt{2}\)

Step 1

Concept

A (1) unit perpendicular is drawn at the end of \(\sqrt{2}\) to make the next triangle. This gives \(\sqrt{3}\).

Step 2

Why this answer is correct

The correct answer is A. \(\sqrt{2}\) के सिरे पर (1) इकाई लंब बनाना / Draw a (1) unit perpendicular at the end of \(\sqrt{2}\). A (1) unit perpendicular is drawn at the end of \(\sqrt{2}\) to make the next triangle. This gives \(\sqrt{3}\).

Step 3

Exam Tip

\(\sqrt{2}\) के सिरे पर (1) इकाई लंब बनाकर अगला त्रिभुज बनाया जाता है। इससे \(\sqrt{3}\) मिलता है।

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वर्गमूल सर्पिल में \(\sqrt{10}\) बनाने के लिए किस पिछले कर्ण पर (1) इकाई लंब बनाई जाती है?

To make \(\sqrt{10}\) in a square root spiral, a (1) unit perpendicular is drawn on which previous hypotenuse?

Explanation opens after your attempt
Correct Answer

B. \(\sqrt{9}\)

Step 1

Concept

The previous hypotenuse \(\sqrt{9}\) with a (1) unit perpendicular gives \(\sqrt{10}\). Identifying the previous step is important.

Step 2

Why this answer is correct

The correct answer is B. \(\sqrt{9}\). The previous hypotenuse \(\sqrt{9}\) with a (1) unit perpendicular gives \(\sqrt{10}\). Identifying the previous step is important.

Step 3

Exam Tip

\(\sqrt{9}\) और (1) इकाई लंब से नया कर्ण \(\sqrt{10}\) बनता है। पिछले चरण को पहचानना जरूरी है।

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वर्गमूल सर्पिल में \(\sqrt{10}\) लंबाई बनाने के लिए किस पिछले कर्ण पर (1) इकाई लंब जोड़ी जाती है?

To construct length \(\sqrt{10}\) in a square root spiral, a (1) unit perpendicular is added to which previous hypotenuse?

Explanation opens after your attempt
Correct Answer

B. \(\sqrt{9}\)

Step 1

Concept

Adding (1) unit to \(\sqrt{9}\) gives the new hypotenuse \(\sqrt{10}\). Identify the previous square root.

Step 2

Why this answer is correct

The correct answer is B. \(\sqrt{9}\). Adding (1) unit to \(\sqrt{9}\) gives the new hypotenuse \(\sqrt{10}\). Identify the previous square root.

Step 3

Exam Tip

\(\sqrt{9}\) पर (1) इकाई जोड़ने से नया कर्ण \(\sqrt{10}\) बनता है। पिछले वर्गमूल को पहचानें।

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