Practice focused topic-wise MCQs with answers and explanations for quick revision and exam preparation.
Difficulty select karke sirf is topic ke focused MCQs practice karein. Score, timer aur explanations student-friendly flow me milenge.
Showing 181-190 of 584 questions.
What is the solution of \(\frac{x}{2}-\frac{x}{3}>1\)?
A. (x>6)
\(\frac{x}{6}>1\) मिलता है इसलिए (x>6) है। भिन्नों में लघुत्तम समापवर्त्य लेना उपयोगी है। / We get \(\frac{x}{6}>1\), so (x>6). Using the least common multiple is useful with fractions.
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What is the solution for (x) in \(\frac{3x}{5}+2\leq \frac{x}{5}+6\)?
A. \(x\leq 10\)
(5) से गुणा करने पर \(3x+10\leq x+30\) मिलता है। इसलिए \(2x\leq 20\) और \(x\leq 10\) है। / Multiplying by (5) gives \(3x+10\leq x+30\). So \(2x\leq 20\) and \(x\leq 10\).
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Which is the solution of \(0<\frac{x-2}{3}\leq 4\)?
A. \(2<x\leq 14\)
(3) से गुणा करने पर \(0<x-2\leq 12\) मिलता है। फिर (2) जोड़कर \(2<x\leq 14\) मिलता है। / Multiplying by (3) gives \(0<x-2\leq 12\). Adding (2) gives \(2<x\leq 14\).
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What is the solution of \(-6\leq 3x<12\)?
A. \(-2\leq x<4\)
सभी भागों को (3) से भाग देने पर \(-2\leq x<4\) मिलता है। सकारात्मक भाग से चिन्ह नहीं बदलता। / Dividing all parts by (3) gives \(-2\leq x<4\). Division by a positive number does not change signs.
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For \(7x-4\geq 3x+20\) and integer (x), what is the least possible (x)?
A. (6)
\(4x\geq 24\) से \(x\geq 6\) मिलता है। इसलिए सबसे छोटा पूर्णांक हल (6) है। / From \(4x\geq 24\), we get \(x\geq 6\). Hence the least integer solution is (6).
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Choose the solution of \(\frac{4x-3}{5}<\frac{x+6}{2}\).
A. (x<12)
(10) से गुणा करने पर (8x-6<5x+30) मिलता है। इसलिए (3x<36) और (x<12) है। / Multiplying by (10) gives (8x-6<5x+30). Therefore (3x<36) and (x<12).
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If (x) is an integer and \(3<2x+1\leq 13\), how many values of (x) are possible?
A. (5)
\(2<2x\leq 12\) से \(1<x\leq 6\) मिलता है। पूर्णांक मान (2,3,4,5,6) हैं। / From \(2<2x\leq 12\), we get \(1<x\leq 6\). The integer values are (2,3,4,5,6).
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What is the correct solution of (9-4(x+2)>x-14)?
A. (x<3)
सरल करने पर (1-4x>x-14) मिलता है। इसलिए (15>5x) और (x<3) है। / Simplifying gives (1-4x>x-14). Thus (15>5x) and (x<3).
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A. \(x\geq 4\)
कथन \(2x-9\geq -1\) देता है। इससे \(2x\geq 8\) और \(x\geq 4\) मिलता है। / The statement gives \(2x-9\geq -1\). This gives \(2x\geq 8\) and \(x\geq 4\).
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What is the solution of \(-3\leq \frac{x+4}{2}<5\)?
A. \(-10\leq x<6\)
सभी भागों को (2) से गुणा करने पर \(-6\leq x+4<10\) मिलता है। फिर (4) घटाकर \(-10\leq x<6\) मिलता है। / Multiplying all parts by (2) gives \(-6\leq x+4<10\). Subtracting (4) gives \(-10\leq x<6\).
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