असमानता \(0<\frac{x-2}{3}\leq 4\) का हल कौन सा है?
Which is the solution of \(0<\frac{x-2}{3}\leq 4\)?
Explanation opens after your attempt
A. \(2<x\leq 14\)
Concept
Multiplying by (3) gives \(0<x-2\leq 12\). Adding (2) gives \(2<x\leq 14\).
Why this answer is correct
The correct answer is A. \(2<x\leq 14\). Multiplying by (3) gives \(0<x-2\leq 12\). Adding (2) gives \(2<x\leq 14\).
Exam Tip
(3) से गुणा करने पर \(0<x-2\leq 12\) मिलता है। फिर (2) जोड़कर \(2<x\leq 14\) मिलता है।
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