Practice focused topic-wise MCQs with answers and explanations for quick revision and exam preparation.
Difficulty select karke sirf is topic ke focused MCQs practice karein. Score, timer aur explanations student-friendly flow me milenge.
Showing 171-180 of 600 questions.
Which polynomial is written in standard form with descending powers?
B. \(5x^3+2x-1\)
मानक रूप में बड़ी घात से छोटी घात की ओर लिखते हैं। \(5x^3+2x-1\) इसी क्रम में है। / In standard form, terms are written from highest power to lowest power. \(5x^3+2x-1\) follows this order.
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What is the sum of (p(x)=3x-2-4x+1) and (q(x)=x-2+2x-5)?
A. \(4x^2-2x-4\)
समान घात वाले पद जोड़ने पर \(4x^2-2x-4\) मिलता है। केवल समान पदों को मिलाएं। / Adding like terms gives \(4x^2-2x-4\). Combine only like terms.
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What is obtained when (r(x)=2x-2-x+4) is subtracted from (p(x)=5x-2+3x-2)?
A. \(3x^2+4x-6\)
(p(x)-r(x)=5x-2+3x-2-\(2x^2-x+4\)=3x-2+4x-6)। घटाते समय सभी संकेत बदलें। / (p(x)-r(x)=5x-2+3x-2-\(2x^2-x+4\)=3x-2+4x-6). Change all signs while subtracting.
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What is the simplified form of (2x\(3x^2-5x+1\))?
A. \(6x^3-10x^2+2x\)
प्रत्येक पद को (2x) से गुणा करने पर \(6x^3-10x^2+2x\) मिलता है। वितरण नियम का प्रयोग करें। / Multiplying each term by (2x) gives \(6x^3-10x^2+2x\). Use the distributive property.
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What is the polynomial form of ((x+3)(x-4))?
A. \(x^2-x-12\)
((x+3)(x-4)=x-2-4x+3x-12=x-2-x-12)। मध्य पद जोड़ते समय संकेत देखें। / ((x+3)(x-4)=x-2-4x+3x-12=x-2-x-12). Watch signs while combining middle terms.
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What is obtained by simplifying ((2x-1)(x+5))?
A. \(2x^2+9x-5\)
((2x-1)(x+5)=2x-2+10x-x-5=2x-2+9x-5)। हर पद का हर पद से गुणा करें। / ((2x-1)(x+5)=2x-2+10x-x-5=2x-2+9x-5). Multiply each term by each term.
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What is the value of (p(1)) in (p(x)=x-3-6x-2+11x-6)?
A. (0)
(p(1)=1-6+11-6=0)। इसलिए (1) इस बहुपद का शून्य है। / (p(1)=1-6+11-6=0). Therefore (1) is a zero of this polynomial.
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If (p(x)=x-2+kx+6) and (p(2)=0), what is (k)?
A. (-5)
(p(2)=4+2k+6=0), इसलिए (2k=-10) और (k=-5)। शून्य की शर्त में मान रखकर समीकरण बनाएं। / (p(2)=4+2k+6=0), so (2k=-10) and (k=-5). Substitute the zero and form an equation.
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If (p(x)=x-2-ax+10) and (p(5)=0), what is the value of (a)?
B. (7)
(p(5)=25-5a+10=0), इसलिए (35=5a) और (a=7)। दिए गए शून्य का उपयोग करें। / (p(5)=25-5a+10=0), so (35=5a) and (a=7). Use the given zero.
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For what value of (m) will (x=1) be a zero of \(x^2-4x+m\)?
C. (3)
(1-4+m=0), इसलिए (m=3)। शून्य मिलने पर बहुपद का मान (0) रखें। / (1-4+m=0), so (m=3). When a zero is given, set the polynomial value equal to (0).
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