linear-equations se related questions ko ek jagah revise karein. Har question me bilingual content, answer feedback aur explanation available hai.
1254 questions tagged with linear-equations.
C. असंगतInconsistent
पहले दो अनुपात बराबर हैं लेकिन (380/775) अलग है। इसलिए प्रणाली असंगत है। / The first two ratios are equal but (380/775) is different. Therefore, the system is inconsistent.
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C. अनंत हलInfinitely many solutions
दूसरा समीकरण पहले का (3) गुना है। इसलिए दोनों शर्तें एक ही जानकारी देती हैं और अनंत हल होते हैं। / The second equation is (3) times the first. Therefore, both conditions give the same information and have infinitely many solutions.
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What type of pair is formed by the equations (18x+7y=61) and (9x+4y=32)?
C. संगत और स्वतंत्रConsistent and independent
यहां \(18/9 \ne 7/4\), इसलिए रेखाएं कटती हैं। अतः युग्म संगत और स्वतंत्र है। / Here \(18/9 \ne 7/4\), so the lines intersect. Hence, the pair is consistent and independent.
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What type of pair is formed by the equations (26x+39y=117) and (2x+3y=10)?
C. असंगतInconsistent
यहां (26/2=39/3) लेकिन (117/10) अलग है। इसलिए यह असंगत युग्म है। / Here (26/2=39/3) but (117/10) is different. Therefore, this is an inconsistent pair.
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What type of pair is formed by the equations (30x+45y=210) and (2x+3y=14)?
A. संगत और आश्रितConsistent and dependent
पहला समीकरण दूसरे का (15) गुना है। इसलिए दोनों एक ही रेखा हैं और युग्म आश्रित है। / The first equation is (15) times the second. Therefore, both are the same line and the pair is dependent.
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What is found by comparing the ratios of (a) and (b) in the equations (19x+12y=71) and (9x+6y=35)?
C. (199 \ne 12 / 6), इसलिए एक अद्वितीय हल / 6), so one unique solution
यहां पहले दो अनुपात अलग हैं। इसलिए रेखाएं एक बिंदु पर कटती हैं और एक हल देती हैं। / Here the first two ratios are different. Therefore, the lines intersect at one point and give one solution.
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Which conclusion is correct by observing the equations (24x+32y=96) and (3x+4y=13)?
B. पहले दो अनुपात बराबर हैं लेकिन स्थिर पद का अनुपात अलग हैFirst two ratios are equal but the constant ratio is different
यहां (24/3=32/4) लेकिन (96/13) अलग है। इसलिए कोई हल नहीं होगा। / Here (24/3=32/4) but (96/13) is different. Therefore, there will be no solution.
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What is the most suitable conclusion by observing the equations (8x+15y=73) and (24x+45y=219)?
C. अनंत हल हैंThere are infinitely many solutions
दूसरा समीकरण पहले का (3) गुना है। इसलिए दोनों रेखाएं संपाती हैं। / The second equation is (3) times the first. Therefore, both lines are coincident.
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If (16x-8y=64) and (2x-y=t) are inconsistent, what is the correct condition for (t)?
B. \(t\ne8\)
पहले दो अनुपात बराबर हैं। असंगत होने के लिए (64/t) अलग होना चाहिए इसलिए \(t\ne8\)। / The first two ratios are equal. For inconsistency, (64/t) must be different so \(t\ne8\).
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If (11x+7y=59) and (33x+21y=n) have infinitely many solutions, what is (n)?
C. (177)
दूसरा समीकरण पहले का (3) गुना होना चाहिए। इसलिए (n=177) होगा। / The second equation must be (3) times the first. Therefore, (n=177).
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Which condition is correct for the equations (17x+py=51) and (8x+3y=25) to have a unique solution?
B. (p\ne518)
अद्वितीय हल के लिए \(17/8 \ne p/3\) होना चाहिए। इसलिए \(p\ne51/8\) सही शर्त है। / For a unique solution, \(17/8 \ne p/3\) must hold. Therefore, \(p\ne51/8\) is the correct condition.
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C. (9)
अनंत हल के लिए (7/28=d/36=63/252) होना चाहिए। इसलिए (d=9)। / For infinitely many solutions, (7/28=d/36=63/252) must hold. Therefore, (d=9).
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If (cx+18y=72) and (24x+48y=145) have no solution, what will (c) be?
C. (9)
कोई हल नहीं के लिए (c/24=18/48) और (72/145) अलग होना चाहिए। इसलिए (c=9)। / For no solution, (c/24=18/48) and (72/145) must be different. Therefore, (c=9).
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What is the correct conclusion for the equations (15x+8y-47=0) and (30x+17y-94=0)?
C. एक अद्वितीय हलOne unique solution
यहां \(15/30 \ne 8/17\), इसलिए रेखाएं एक बिंदु पर कटती हैं। ऐसी स्थिति में एक अद्वितीय हल मिलता है। / Here \(15/30 \ne 8/17\), so the lines intersect at one point. In this case, one unique solution is obtained.
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What is the correct ratio relation for the equations (16x-9y+55=0) and (32x-18y+113=0)?
A. (1632=(-9) / (-18) \ne 55 / 113)
पहले दो अनुपात बराबर हैं और तीसरा अलग है। इसलिए कोई हल नहीं होगा। / The first two ratios are equal and the third is different. Therefore, there will be no solution.
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Which ratio relation is correct for the equations (10x+13y-71=0) and (30x+39y-213=0)?
C. (1030=13 / 39=(-71) / (-213))
यहां तीनों अनुपात बराबर हैं। इसलिए दोनों रेखाएं संपाती हैं और अनंत हल हैं। / Here all three ratios are equal. Therefore, both lines are coincident and have infinitely many solutions.
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What is the correct description of the graph of the equations (5x+17y=69) and (12x+41y=166)?
C. एक बिंदु पर कटती रेखाएंLines intersecting at one point
यहां \(5/12 \ne 17/41\), इसलिए रेखाएं एक बिंदु पर कटेंगी। इससे एक अद्वितीय हल मिलेगा। / Here \(5/12 \ne 17/41\), so the lines will intersect at one point. This gives one unique solution.
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What will be shown in the graph of the equations (30x+18y=126) and (5x+3y=21)?
A. एक ही रेखाSame line
पहला समीकरण दूसरे का (6) गुना है। इसलिए दोनों समीकरण एक ही रेखा दिखाते हैं। / The first equation is (6) times the second. Therefore, both equations show the same line.
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Which statement is correct about the graph of the equations (22x+33y=99) and (2x+3y=12)?
C. रेखाएं अलग समानांतर हैंLines are distinct parallel
यहां (22/2=33/3) लेकिन (99/12) अलग है। इसलिए ग्राफ में अलग समानांतर रेखाएं बनेंगी। / Here (22/2=33/3) but (99/12) is different. Therefore, the graph will show distinct parallel lines.
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What is the value of (b) for the equations (bx+16y=64) and (14x+28y=131) to have no solution?
C. (8)
कोई हल नहीं के लिए (b/14=16/28) और (64/131) अलग होना चाहिए। इसलिए (b=8)। / For no solution, (b/14=16/28) and (64/131) must be different. Hence, (b=8).
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What will (a) be for the equations (8x+ay=72) and (24x+30y=216) to have infinitely many solutions?
C. (10)
अनंत हल के लिए (8/24=a/30=72/216) होना चाहिए। इससे (a=10) मिलता है। / For infinitely many solutions, (8/24=a/30=72/216) must hold. This gives (a=10).
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Which condition is correct for the equations (12x+py=60) and (3x+5y=16) to have a unique solution?
B. \(p\ne20\)
अद्वितीय हल के लिए \(12/3 \ne p/5\) होना चाहिए। इसलिए \(p\ne20\) सही शर्त है। / For a unique solution, \(12/3 \ne p/5\) must hold. Therefore, \(p\ne20\) is the correct condition.
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C. (9)
दूसरा समीकरण पहले का (2) गुना है, इसलिए (q/18=1/2) होना चाहिए। अतः (q=9)। / The second equation is (2) times the first, so (q/18=1/2) must hold. Hence, (q=9).
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What will (k) be for the equations (kx+14y=42) and (18x+21y=63) to have infinitely many solutions?
C. (12)
अनंत हल के लिए (k/18=14/21=42/63) होना चाहिए। इसलिए (k=12) सही है। / For infinitely many solutions, (k/18=14/21=42/63) must hold. Therefore, (k=12) is correct.
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What is the correct solution status for the equations (11x+14y=53) and (17x+22y=83)?
B. एक अद्वितीय हलOne unique solution
यहां \(11/17 \ne 14/22\), इसलिए रेखाएं एक बिंदु पर कटती हैं। पहले दो अनुपात अलग हों तो एक अद्वितीय हल मिलता है। / Here \(11/17 \ne 14/22\), so the lines intersect at one point. If the first two ratios are different, one unique solution is obtained.
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How many solutions will the equations (9x+5y=41) and (18x+10y=85) have?
C. कोई हल नहींNo solution
यहां (9/18=5/10) लेकिन (41/85) अलग है। इसलिए रेखाएं समानांतर और अलग हैं। / Here (9/18=5/10) but (41/85) is different. Therefore, the lines are parallel and distinct.
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Which conclusion is correct for the equations (7x-4y=29) and (21x-12y=87)?
C. अनंत हलInfinitely many solutions
दूसरा समीकरण पहले का (3) गुना है। इसलिए दोनों रेखाएं संपाती हैं और अनंत हल हैं। / The second equation is (3) times the first. Therefore, both lines are coincident and have infinitely many solutions.
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If (5x+8y=37) and (15x+24y=m) form an inconsistent pair, what is the correct condition for (m)?
B. \(m\ne111\)
पहले दो अनुपात बराबर हैं। असंगत होने के लिए स्थिर पद का अनुपात अलग होना चाहिए। / The first two ratios are equal. For inconsistency, the constant ratio must be different.
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What is the value of (p) for the equations (px+9y=45) and (20x+30y=103) to have no solution?
B. (6)
कोई हल नहीं के लिए (p/20=9/30) और (45/103) अलग होना चाहिए। इससे (p=6) मिलता है। / For no solution, (p/20=9/30) and (45/103) must be different. This gives (p=6).
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C. (7)
अनंत हल के लिए (4/12=a/21=32/96) होना चाहिए। इसलिए (a=7) सही है। / For infinitely many solutions, (4/12=a/21=32/96) must hold. Therefore, (a=7) is correct.
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