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What type of pair is formed by the equations (26x+39y=117) and (2x+3y=10)?

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Answer and explanation

Correct answer: Inconsistent; having no solution

Here, a₁/a₂ = 26/2 = 13 and b₁/b₂ = 39/3 = 13, but c₁/c₂ = 117/10, which is not equal to 13. Thus, a₁/a₂ = b₁/b₂ ≠ c₁/c₂, so the two lines are distinct and parallel. The pair has no solution and is therefore inconsistent. Option B would be correct only if all three ratios were equal. Exam tip: first compare a₁/a₂ and b₁/b₂; if they are equal but c₁/c₂ is different, the pair is inconsistent.

Related tags

Linear EquationsConditions For SolvabilityInconsistent PairParallel LinesUnique Solution

Frequently asked questions

What is the correct answer to this question?

Inconsistent; having no solution

Why is this the correct answer?

Here, a₁/a₂ = 26/2 = 13 and b₁/b₂ = 39/3 = 13, but c₁/c₂ = 117/10, which is not equal to 13. Thus, a₁/a₂ = b₁/b₂ ≠ c₁/c₂, so the two lines are distinct and parallel. The pair has no solution and is therefore inconsistent. Option B would be correct only if all three ratios were equal. Exam tip: first compare a₁/a₂ and b₁/b₂; if they are equal but c₁/c₂ is different, the pair is inconsistent.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Pair of Linear Equations in Two Variables. Topic: Conditions for solvability.

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