A. बिंदु (\left\(\frac{21}{5},\frac{16}{5}\right\))/Point (\left\(\frac{21}{5},\frac{16}{5}\right\))
Step 1
Concept
Using (x=y+1) from (x-y=1) gives \(y=\frac{16}{5}\) and \(x=\frac{21}{5}\). On the graph this is the intersection point.
Step 2
Why this answer is correct
The correct answer is A. बिंदु (\left\(\frac{21}{5},\frac{16}{5}\right\)) / Point (\left\(\frac{21}{5},\frac{16}{5}\right\)). Using (x=y+1) from (x-y=1) gives \(y=\frac{16}{5}\) and \(x=\frac{21}{5}\). On the graph this is the intersection point.
Step 3
Exam Tip
(x-y=1) से (x=y+1) रखकर \(y=\frac{16}{5}\) और \(x=\frac{21}{5}\) मिलता है। ग्राफ पर यही प्रतिच्छेद बिंदु होगा।
A. बिंदु (\left\(\frac{25}{7},\frac{37}{7}\right\))/Point (\left\(\frac{25}{7},\frac{37}{7}\right\))
Step 1
Concept
Using (y=4x-9) from (4x-y=9) gives \(x=\frac{25}{7}\). Then \(y=\frac{37}{7}\).
Step 2
Why this answer is correct
The correct answer is A. बिंदु (\left\(\frac{25}{7},\frac{37}{7}\right\)) / Point (\left\(\frac{25}{7},\frac{37}{7}\right\)). Using (y=4x-9) from (4x-y=9) gives \(x=\frac{25}{7}\). Then \(y=\frac{37}{7}\).
Step 3
Exam Tip
(4x-y=9) से (y=4x-9) रखकर \(x=\frac{25}{7}\) मिलता है। फिर \(y=\frac{37}{7}\) है।
A. बिंदु (\left\(5,2\right\))/Point (\left\(5,2\right\))
Step 1
Concept
Substituting (\left\(5,2\right\)) gives (5\left\(5\right\)+3\left\(2\right\)=31) and (5+2=7). If both equations are true, that is the intersection.
Step 2
Why this answer is correct
The correct answer is A. बिंदु (\left\(5,2\right\)) / Point (\left\(5,2\right\)). Substituting (\left\(5,2\right\)) gives (5\left\(5\right\)+3\left\(2\right\)=31) and (5+2=7). If both equations are true, that is the intersection.
Step 3
Exam Tip
(\left\(5,2\right\)) रखने पर (5\left\(5\right\)+3\left\(2\right\)=31) और (5+2=7)। दोनों समीकरण सत्य हों तो वही प्रतिच्छेद है।
A. बिंदु (\left\(\frac{91}{17},\frac{50}{17}\right\))/Point (\left\(\frac{91}{17},\frac{50}{17}\right\))
Step 1
Concept
Elimination gives (17y=50) and \(x=\frac{91}{17}\). Fraction coordinates can also be graphical solutions.
Step 2
Why this answer is correct
The correct answer is A. बिंदु (\left\(\frac{91}{17},\frac{50}{17}\right\)) / Point (\left\(\frac{91}{17},\frac{50}{17}\right\)). Elimination gives (17y=50) and \(x=\frac{91}{17}\). Fraction coordinates can also be graphical solutions.
Step 3
Exam Tip
उन्मूलन से (17y=50) और \(x=\frac{91}{17}\) मिलता है। भिन्न निर्देशांक भी ग्राफीय हल हो सकते हैं।
B. समांतर और अलग रेखाएँ/Parallel and distinct lines
Step 1
Concept
\(\frac{a_1}{a_2}=\frac{b_1}{b_2}=3\), but \(\frac{c_1}{c_2}=\frac{12}{5}\). Hence the lines are parallel and inconsistent.
Step 2
Why this answer is correct
The correct answer is B. समांतर और अलग रेखाएँ / Parallel and distinct lines. \(\frac{a_1}{a_2}=\frac{b_1}{b_2}=3\), but \(\frac{c_1}{c_2}=\frac{12}{5}\). Hence the lines are parallel and inconsistent.
Step 3
Exam Tip
\(\frac{a_1}{a_2}=\frac{b_1}{b_2}=3\), लेकिन \(\frac{c_1}{c_2}=\frac{12}{5}\)। इसलिए रेखाएँ समांतर और असंगत हैं।
Dividing the first equation by (4) gives (2x-3y=5). Therefore both are the same line and have infinitely many solutions.
Step 2
Why this answer is correct
The correct answer is C. संपाती / Coincident. Dividing the first equation by (4) gives (2x-3y=5). Therefore both are the same line and have infinitely many solutions.
Step 3
Exam Tip
पहला समीकरण (4) से भाग देने पर (2x-3y=5) बनता है। इसलिए दोनों एक ही रेखा हैं और अनंत हल हैं।
A. (\left\(5,0\right\)) और (\left\(0,-9\right\))/(\left\(5,0\right\)) and (\left\(0,-9\right\))
Step 1
Concept
At (y=0), (x=5), and at (x=0), (y=-9). Plot the negative intercept in the correct direction.
Step 2
Why this answer is correct
The correct answer is A. (\left\(5,0\right\)) और (\left\(0,-9\right\)) / (\left\(5,0\right\)) and (\left\(0,-9\right\)). At (y=0), (x=5), and at (x=0), (y=-9). Plot the negative intercept in the correct direction.
Step 3
Exam Tip
(y=0) पर (x=5) और (x=0) पर (y=-9)। ऋण अवरोध को सही दिशा में अंकित करें।
A. बिंदु (\left\(-5,-9\right\))/Point (\left\(-5,-9\right\))
Step 1
Concept
Putting (x=-5) gives (4\left\(-5\right\)-3y=7), so (y=-9). In a vertical line, (x) is already fixed.
Step 2
Why this answer is correct
The correct answer is A. बिंदु (\left\(-5,-9\right\)) / Point (\left\(-5,-9\right\)). Putting (x=-5) gives (4\left\(-5\right\)-3y=7), so (y=-9). In a vertical line, (x) is already fixed.
Step 3
Exam Tip
(x=-5) रखने पर (4\left\(-5\right\)-3y=7), इसलिए (y=-9)। ऊर्ध्वाधर रेखा में (x) पहले से निश्चित होता है।
A. बिंदु (\left\(7,6\right\))/Point (\left\(7,6\right\))
Step 1
Concept
Putting (y=6) gives (5x-12=23), so (x=7). In a horizontal line, the value of (y) is fixed.
Step 2
Why this answer is correct
The correct answer is A. बिंदु (\left\(7,6\right\)) / Point (\left\(7,6\right\)). Putting (y=6) gives (5x-12=23), so (x=7). In a horizontal line, the value of (y) is fixed.
Step 3
Exam Tip
(y=6) रखने पर (5x-12=23), इसलिए (x=7)। क्षैतिज रेखा में (y) का मान तय रहता है।
A. बिंदु (\left\(5,3\right\))/Point (\left\(5,3\right\))
Step 1
Concept
Adding the equations gives (5x=25), so (x=5). Then (x+3y=14) gives (y=3).
Step 2
Why this answer is correct
The correct answer is A. बिंदु (\left\(5,3\right\)) / Point (\left\(5,3\right\)). Adding the equations gives (5x=25), so (x=5). Then (x+3y=14) gives (y=3).
Step 3
Exam Tip
दोनों समीकरण जोड़ने पर (5x=25), इसलिए (x=5)। फिर (x+3y=14) से (y=3)।
A. बिंदु (\left\(\frac{25}{7},\frac{23}{7}\right\))/Point (\left\(\frac{25}{7},\frac{23}{7}\right\))
Step 1
Concept
(\left\(\frac{25}{7},\frac{23}{7}\right\)) satisfies both equations. Read fraction coordinates carefully using the graph scale.
Step 2
Why this answer is correct
The correct answer is A. बिंदु (\left\(\frac{25}{7},\frac{23}{7}\right\)) / Point (\left\(\frac{25}{7},\frac{23}{7}\right\)). (\left\(\frac{25}{7},\frac{23}{7}\right\)) satisfies both equations. Read fraction coordinates carefully using the graph scale.
Step 3
Exam Tip
(\left\(\frac{25}{7},\frac{23}{7}\right\)) रखने पर दोनों समीकरण संतुष्ट होते हैं। भिन्न निर्देशांक को ग्राफ के पैमाने से सावधानीपूर्वक पढ़ें।
A. बिंदु (\left\(2,5\right\))/Point (\left\(2,5\right\))
Step 1
Concept
At (\left\(2,5\right\)), (3\left\(2\right\)+4\left\(5\right\)=26), but (2+5=7) also, so check fully. The correct non-common point is (\left\(4,\frac{7}{2}\right\)).
Step 2
Why this answer is correct
The correct answer is A. बिंदु (\left\(2,5\right\)) / Point (\left\(2,5\right\)). At (\left\(2,5\right\)), (3\left\(2\right\)+4\left\(5\right\)=26), but (2+5=7) also, so check fully. The correct non-common point is (\left\(4,\frac{7}{2}\right\)).
Step 3
Exam Tip
(\left\(2,5\right\)) पर (3\left\(2\right\)+4\left\(5\right\)=26), लेकिन (2+5=7) भी है, इसलिए जाँच पूरी करें। सही अलग बिंदु (\left\(4,\frac{7}{2}\right\)) है।
The first coordinate of a point is (x) and the second is (y). Do not change order while reading negative fraction coordinates.
Step 2
Why this answer is correct
The correct answer is B. \(x=-\frac{5}{2},\ y=3\). The first coordinate of a point is (x) and the second is (y). Do not change order while reading negative fraction coordinates.
Step 3
Exam Tip
बिंदु में पहला निर्देशांक (x) और दूसरा (y) होता है। ऋण भिन्न निर्देशांक पढ़ते समय क्रम न बदलें।
B. वे समांतर और अलग हैं/They are parallel and distinct
Step 1
Concept
Multiplying the first equation by (2) gives (10x-6y=20), while the second is (10x-6y=25). Hence the lines are parallel and distinct.
Step 2
Why this answer is correct
The correct answer is B. वे समांतर और अलग हैं / They are parallel and distinct. Multiplying the first equation by (2) gives (10x-6y=20), while the second is (10x-6y=25). Hence the lines are parallel and distinct.
Step 3
Exam Tip
पहले समीकरण को (2) से गुणा करने पर (10x-6y=20), जबकि दूसरा (10x-6y=25) है। इसलिए रेखाएँ समांतर और अलग हैं।
B. बिंदु (\left\(8,0\right\))/Point (\left\(8,0\right\))
Step 1
Concept
Putting (y=0) gives (3x=24), so (x=8). The line (y=0) is the (x)-axis.
Step 2
Why this answer is correct
The correct answer is B. बिंदु (\left\(8,0\right\)) / Point (\left\(8,0\right\)). Putting (y=0) gives (3x=24), so (x=8). The line (y=0) is the (x)-axis.
Step 3
Exam Tip
(y=0) रखने पर (3x=24), इसलिए (x=8)। रेखा (y=0) (x)-अक्ष होती है।
B. बिंदु (\left\(0,-6\right\))/Point (\left\(0,-6\right\))
Step 1
Concept
Putting (x=0) gives (-7y=42), so (y=-6). The line (x=0) is the (y)-axis.
Step 2
Why this answer is correct
The correct answer is B. बिंदु (\left\(0,-6\right\)) / Point (\left\(0,-6\right\)). Putting (x=0) gives (-7y=42), so (y=-6). The line (x=0) is the (y)-axis.
Step 3
Exam Tip
(x=0) रखने पर (-7y=42), इसलिए (y=-6)। रेखा (x=0) (y)-अक्ष होती है।
\(\frac{a_1}{a_2}=\frac{b_1}{b_2}=3\), but \(\frac{c_1}{c_2}=\frac{11}{4}\). Hence the lines are parallel and inconsistent.
Step 2
Why this answer is correct
The correct answer is C. रेखाएँ समांतर हैं / Lines are parallel. \(\frac{a_1}{a_2}=\frac{b_1}{b_2}=3\), but \(\frac{c_1}{c_2}=\frac{11}{4}\). Hence the lines are parallel and inconsistent.
Step 3
Exam Tip
\(\frac{a_1}{a_2}=\frac{b_1}{b_2}=3\), लेकिन \(\frac{c_1}{c_2}=\frac{11}{4}\)। इसलिए रेखाएँ समांतर और असंगत हैं।
A. (\left\(0,-4\right\)) और (\left\(16,0\right\))/(\left\(0,-4\right\)) and (\left\(16,0\right\))
Step 1
Concept
At (x=0), (y=-4), and at (y=0), (x=16). While finding intercepts, note which variable is kept zero.
Step 2
Why this answer is correct
The correct answer is A. (\left\(0,-4\right\)) और (\left\(16,0\right\)) / (\left\(0,-4\right\)) and (\left\(16,0\right\)). At (x=0), (y=-4), and at (y=0), (x=16). While finding intercepts, note which variable is kept zero.
Step 3
Exam Tip
(x=0) पर (y=-4) और (y=0) पर (x=16)। अवरोध निकालते समय कौन-सा चर शून्य रखा है, यह ध्यान रखें।
\(3.75=\frac{15}{4}\) and \(-2.5=-\frac{5}{2}\). It is better to convert decimal coordinates into simplified fractions.
Step 2
Why this answer is correct
The correct answer is A. (\left\(\frac{15}{4},-\frac{5}{2}\right\)). \(3.75=\frac{15}{4}\) and \(-2.5=-\frac{5}{2}\). It is better to convert decimal coordinates into simplified fractions.
Step 3
Exam Tip
\(3.75=\frac{15}{4}\) और \(-2.5=-\frac{5}{2}\)। दशमलव निर्देशांक को सरल भिन्न में बदलना बेहतर रहता है।
A. बिंदु (\left\(4,5\right\))/Point (\left\(4,5\right\))
Step 1
Concept
Substituting (\left\(4,5\right\)) gives (3\left\(4\right\)+5=17) and (4+3\left\(5\right\)=19). This is the common point of both lines.
Step 2
Why this answer is correct
The correct answer is A. बिंदु (\left\(4,5\right\)) / Point (\left\(4,5\right\)). Substituting (\left\(4,5\right\)) gives (3\left\(4\right\)+5=17) and (4+3\left\(5\right\)=19). This is the common point of both lines.
Step 3
Exam Tip
(\left\(4,5\right\)) रखने पर (3\left\(4\right\)+5=17) और (4+3\left\(5\right\)=19)। यही दोनों रेखाओं का सामान्य बिंदु है।
A. बिंदु (\left\(\frac{79}{19},\frac{113}{19}\right\))/Point (\left\(\frac{79}{19},\frac{113}{19}\right\))
Step 1
Concept
Using (y=6x-19) from the first equation gives \(x=\frac{79}{19}\). Then \(y=\frac{113}{19}\).
Step 2
Why this answer is correct
The correct answer is A. बिंदु (\left\(\frac{79}{19},\frac{113}{19}\right\)) / Point (\left\(\frac{79}{19},\frac{113}{19}\right\)). Using (y=6x-19) from the first equation gives \(x=\frac{79}{19}\). Then \(y=\frac{113}{19}\).
Step 3
Exam Tip
पहले समीकरण से (y=6x-19) रखकर \(x=\frac{79}{19}\) मिलता है। फिर \(y=\frac{113}{19}\) है।
A. (x=2,\ y=11) और (x=4,\ y=1)/(x=2,\ y=11) and (x=4,\ y=1)
Step 1
Concept
At (x=2), (y=11), and at (x=4), (y=1). Every point in the value table must satisfy the equation.
Step 2
Why this answer is correct
The correct answer is A. (x=2,\ y=11) और (x=4,\ y=1) / (x=2,\ y=11) and (x=4,\ y=1). At (x=2), (y=11), and at (x=4), (y=1). Every point in the value table must satisfy the equation.
Step 3
Exam Tip
(x=2) पर (y=11) और (x=4) पर (y=1)। मान-सारणी का हर बिंदु समीकरण को संतुष्ट करना चाहिए।
C. वे समांतर और अलग हैं/They are parallel and distinct
Step 1
Concept
Dividing the second equation by (2) gives (2x+3y=15). Same left side with different constants gives parallel lines.
Step 2
Why this answer is correct
The correct answer is C. वे समांतर और अलग हैं / They are parallel and distinct. Dividing the second equation by (2) gives (2x+3y=15). Same left side with different constants gives parallel lines.
Step 3
Exam Tip
दूसरे समीकरण को (2) से भाग देने पर (2x+3y=15) मिलता है। समान बाएँ पक्ष और अलग नियतांक समांतर रेखाएँ देते हैं।
A. बिंदु (\left\(5,4\right\))/Point (\left\(5,4\right\))
Step 1
Concept
Subtracting the second from the first gives (5y=20), so (y=4). Then (3x-4=11) gives (x=5).
Step 2
Why this answer is correct
The correct answer is A. बिंदु (\left\(5,4\right\)) / Point (\left\(5,4\right\)). Subtracting the second from the first gives (5y=20), so (y=4). Then (3x-4=11) gives (x=5).
Step 3
Exam Tip
पहले से दूसरे को घटाने पर (5y=20), इसलिए (y=4)। फिर (3x-4=11) से (x=5)।
A. बिंदु (\left\(4,6\right\))/Point (\left\(4,6\right\))
Step 1
Concept
Subtracting the equations gives (4y=24), so (y=6). Then (4x-6=10) gives (x=4).
Step 2
Why this answer is correct
The correct answer is A. बिंदु (\left\(4,6\right\)) / Point (\left\(4,6\right\)). Subtracting the equations gives (4y=24), so (y=6). Then (4x-6=10) gives (x=4).
Step 3
Exam Tip
दोनों समीकरण घटाने पर (4y=24), इसलिए (y=6)। फिर (4x-6=10) से (x=4)।
Dividing (6x-4y=20) by (2) gives (3x-2y=10). Same left side with different constants gives distinct parallel lines.
Step 2
Why this answer is correct
The correct answer is C. (6x-4y=20). Dividing (6x-4y=20) by (2) gives (3x-2y=10). Same left side with different constants gives distinct parallel lines.
Step 3
Exam Tip
(6x-4y=20) को (2) से भाग देने पर (3x-2y=10) मिलता है। समान बाएँ पक्ष और अलग नियतांक अलग समांतर रेखाएँ देते हैं।
A. बिंदु (\left\(5,3\right\))/Point (\left\(5,3\right\))
Step 1
Concept
Subtracting the equations gives (3x=15), so (x=5) and (y=3). In a real situation this is the meeting point.
Step 2
Why this answer is correct
The correct answer is A. बिंदु (\left\(5,3\right\)) / Point (\left\(5,3\right\)). Subtracting the equations gives (3x=15), so (x=5) and (y=3). In a real situation this is the meeting point.
Step 3
Exam Tip
दोनों समीकरण घटाने पर (3x=15), इसलिए (x=5) और (y=3)। वास्तविक स्थिति में यही मिलन बिंदु है।
A. बिंदु (\left\(7,\frac{18}{5}\right\))/Point (\left\(7,\frac{18}{5}\right\))
Step 1
Concept
Subtracting the equations gives (2x=14), then (x=7) and (7+5y=25) gives \(y=\frac{18}{5}\). This is the graphical intersection.
Step 2
Why this answer is correct
The correct answer is A. बिंदु (\left\(7,\frac{18}{5}\right\)) / Point (\left\(7,\frac{18}{5}\right\)). Subtracting the equations gives (2x=14), then (x=7) and (7+5y=25) gives \(y=\frac{18}{5}\). This is the graphical intersection.
Step 3
Exam Tip
दोनों समीकरण घटाने पर (2x=14), फिर (x=7) और (7+5y=25) से \(y=\frac{18}{5}\)। यही ग्राफीय प्रतिच्छेद है।
A. बिंदु (\left\(\frac{52}{10},\frac{22}{5}\right\))/Point (\left\(\frac{52}{10},\frac{22}{5}\right\))
Step 1
Concept
Solving both equations gives \(y=\frac{22}{5}\) and \(x=\frac{26}{5}\). \(\frac{52}{10}\) can also be written as \(\frac{26}{5}\).
Step 2
Why this answer is correct
The correct answer is A. बिंदु (\left\(\frac{52}{10},\frac{22}{5}\right\)) / Point (\left\(\frac{52}{10},\frac{22}{5}\right\)). Solving both equations gives \(y=\frac{22}{5}\) and \(x=\frac{26}{5}\). \(\frac{52}{10}\) can also be written as \(\frac{26}{5}\).
Step 3
Exam Tip
दोनों समीकरण हल करने पर \(y=\frac{22}{5}\) और \(x=\frac{26}{5}\) मिलता है। \(\frac{52}{10}\) को \(\frac{26}{5}\) भी लिख सकते हैं।
A. चिह्न और निर्देशांक क्रम की गलती/Error of sign and coordinate order
Step 1
Concept
In (\left\(7,-3\right\)), (x=7) and (y=-3). Reversing coordinates and changing sign makes the answer wrong.
Step 2
Why this answer is correct
The correct answer is A. चिह्न और निर्देशांक क्रम की गलती / Error of sign and coordinate order. In (\left\(7,-3\right\)), (x=7) and (y=-3). Reversing coordinates and changing sign makes the answer wrong.
Step 3
Exam Tip
बिंदु (\left\(7,-3\right\)) में (x=7) और (y=-3) है। निर्देशांक उलटने और चिह्न बदलने से उत्तर गलत हो जाता है।
A. बिंदु (\left\(4,10\right\))/Point (\left\(4,10\right\))
Step 1
Concept
Subtracting the equations gives (3x=12), so (x=4) and (y=10). Whatever the context, the intersection point is the solution.
Step 2
Why this answer is correct
The correct answer is A. बिंदु (\left\(4,10\right\)) / Point (\left\(4,10\right\)). Subtracting the equations gives (3x=12), so (x=4) and (y=10). Whatever the context, the intersection point is the solution.
Step 3
Exam Tip
दोनों समीकरण घटाने पर (3x=12), इसलिए (x=4) और (y=10)। संदर्भ कोई भी हो, प्रतिच्छेद बिंदु ही हल है।
A. बिंदु (\left\(0,-5\right\))/Point (\left\(0,-5\right\))
Step 1
Concept
Substituting (\left\(0,-5\right\)) gives (5\left\(0\right\)-6\left\(-5\right\)=30). A negative (y)-intercept is plotted downward on the graph.
Step 2
Why this answer is correct
The correct answer is A. बिंदु (\left\(0,-5\right\)) / Point (\left\(0,-5\right\)). Substituting (\left\(0,-5\right\)) gives (5\left\(0\right\)-6\left\(-5\right\)=30). A negative (y)-intercept is plotted downward on the graph.
Step 3
Exam Tip
(\left\(0,-5\right\)) रखने पर (5\left\(0\right\)-6\left\(-5\right\)=30)। ऋण (y)-अवरोध ग्राफ में नीचे की ओर लगाया जाता है।
Here \(x+y=\frac{7}{2}+\frac{9}{2}=\frac{16}{2}=8\). Values of (x) and (y) are read directly from the intersection point.
Step 2
Why this answer is correct
The correct answer is A. (8). Here \(x+y=\frac{7}{2}+\frac{9}{2}=\frac{16}{2}=8\). Values of (x) and (y) are read directly from the intersection point.
Step 3
Exam Tip
यहाँ \(x+y=\frac{7}{2}+\frac{9}{2}=\frac{16}{2}=8\)। प्रतिच्छेद बिंदु से (x) और (y) के मान सीधे पढ़े जाते हैं।
For parallel lines, \(\frac{k}{3}=\frac{-2}{-6}\), so (k=1). The constants ratio is different, so the lines are distinct parallel lines.
Step 2
Why this answer is correct
The correct answer is A. (1). For parallel lines, \(\frac{k}{3}=\frac{-2}{-6}\), so (k=1). The constants ratio is different, so the lines are distinct parallel lines.
Step 3
Exam Tip
समांतर होने के लिए \(\frac{k}{3}=\frac{-2}{-6}\), इसलिए (k=1)। नियतांकों का अनुपात अलग है, इसलिए रेखाएँ अलग समांतर हैं।
A. बिंदु (\left\(\frac{38}{9},\frac{29}{9}\right\))/Point (\left\(\frac{38}{9},\frac{29}{9}\right\))
Step 1
Concept
From (x-y=1), (x=y+1), and substituting in the first equation gives (9y=29). Hence \(y=\frac{29}{9}\) and \(x=\frac{38}{9}\).
Step 2
Why this answer is correct
The correct answer is A. बिंदु (\left\(\frac{38}{9},\frac{29}{9}\right\)) / Point (\left\(\frac{38}{9},\frac{29}{9}\right\)). From (x-y=1), (x=y+1), and substituting in the first equation gives (9y=29). Hence \(y=\frac{29}{9}\) and \(x=\frac{38}{9}\).
Step 3
Exam Tip
(x-y=1) से (x=y+1), और पहले समीकरण में रखने पर (9y=29)। इसलिए \(y=\frac{29}{9}\) और \(x=\frac{38}{9}\) है।
A. (\left\(3,0\right\)) और (\left\(0,-8\right\))/(\left\(3,0\right\)) and (\left\(0,-8\right\))
Step 1
Concept
At (y=0), (x=3), and at (x=0), (y=-8). Plot the negative intercept in the correct direction on the graph.
Step 2
Why this answer is correct
The correct answer is A. (\left\(3,0\right\)) और (\left\(0,-8\right\)) / (\left\(3,0\right\)) and (\left\(0,-8\right\)). At (y=0), (x=3), and at (x=0), (y=-8). Plot the negative intercept in the correct direction on the graph.
Step 3
Exam Tip
(y=0) पर (x=3) और (x=0) पर (y=-8)। ऋण अवरोध को ग्राफ में सही दिशा में अंकित करें।
A. (5x+2y=9) और (10x+4y=25)/(5x+2y=9) and (10x+4y=25)
Step 1
Concept
Multiplying the first equation by (2) gives (10x+4y=18), while the second is (10x+4y=25). Hence the lines are parallel and have no solution.
Step 2
Why this answer is correct
The correct answer is A. (5x+2y=9) और (10x+4y=25) / (5x+2y=9) and (10x+4y=25). Multiplying the first equation by (2) gives (10x+4y=18), while the second is (10x+4y=25). Hence the lines are parallel and have no solution.
Step 3
Exam Tip
पहले समीकरण को (2) से गुणा करने पर (10x+4y=18), जबकि दूसरा (10x+4y=25) है। इसलिए रेखाएँ समांतर हैं और कोई हल नहीं है।
A. बिंदु (\left\(\frac{15}{4},\frac{73}{16}\right\))/Point (\left\(\frac{15}{4},\frac{73}{16}\right\))
Step 1
Concept
From (x+4y=22), (x=22-4y), and substituting in the first equation gives \(y=\frac{73}{16}\). Then \(x=\frac{15}{4}\).
Step 2
Why this answer is correct
The correct answer is A. बिंदु (\left\(\frac{15}{4},\frac{73}{16}\right\)) / Point (\left\(\frac{15}{4},\frac{73}{16}\right\)). From (x+4y=22), (x=22-4y), and substituting in the first equation gives \(y=\frac{73}{16}\). Then \(x=\frac{15}{4}\).
Step 3
Exam Tip
(x+4y=22) से (x=22-4y), और पहले समीकरण में रखने पर \(y=\frac{73}{16}\)। फिर \(x=\frac{15}{4}\) है।
A. बिंदु (\left\(8,\frac{18}{5}\right\))/Point (\left\(8,\frac{18}{5}\right\))
Step 1
Concept
Subtracting the equations gives (x=8), then (8+5y=26) gives \(y=\frac{18}{5}\). This is the meeting point of both paths.
Step 2
Why this answer is correct
The correct answer is A. बिंदु (\left\(8,\frac{18}{5}\right\)) / Point (\left\(8,\frac{18}{5}\right\)). Subtracting the equations gives (x=8), then (8+5y=26) gives \(y=\frac{18}{5}\). This is the meeting point of both paths.
Step 3
Exam Tip
दोनों समीकरण घटाने पर (x=8), फिर (8+5y=26) से \(y=\frac{18}{5}\)। यही दोनों रास्तों का मिलन बिंदु है।
