Question 1/16
Hard Mathematics
Pair of Linear Equations in Two Variables Graphical method of finding solutions. Class 10 Level 53
यदि किसी रेखा की मान-सारणी में (\left\(-2,9\right\)) और (\left\(3,-1\right\)) हैं, तो कौन-सा समीकरण सही है?
If a value table of a line has (\left\(-2,9\right\)) and (\left\(3,-1\right\)), which equation is correct?
#value table
#line equation
#graph
A (2x+y=5)
B (x+2y=16)
C (2x+y=9)
D (x-y=-11)
Explanation opens after your attempt
Correct Answer
A. (2x+y=5)
Step 1
Concept
Both points satisfy (2x+y=5). Two correct points are enough to identify a line.
Step 2
Why this answer is correct
The correct answer is A. (2x+y=5). Both points satisfy (2x+y=5). Two correct points are enough to identify a line.
Step 3
Exam Tip
दोनों बिंदु (2x+y=5) को संतुष्ट करते हैं। दो सही बिंदु रेखा पहचानने में पर्याप्त होते हैं।
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Question 2/16
Hard Mathematics
Pair of Linear Equations in Two Variables Graphical method of finding solutions. Class 10 Level 53
रेखा (5x+y=21) के लिए कौन-सी मान-सारणी सही है?
Which value table is correct for the line (5x+y=21)?
#value table
#graph construction
#substitution
A (x=2,\ y=11) और (x=4,\ y=1) / (x=2,\ y=11) and (x=4,\ y=1)
B (x=2,\ y=1) और (x=4,\ y=11) / (x=2,\ y=1) and (x=4,\ y=11)
C (x=0,\ y=5) और (x=5,\ y=21) / (x=0,\ y=5) and (x=5,\ y=21)
D (x=3,\ y=11) और (x=4,\ y=4) / (x=3,\ y=11) and (x=4,\ y=4)
Explanation opens after your attempt
Correct Answer
A. (x=2,\ y=11) और (x=4,\ y=1) / (x=2,\ y=11) and (x=4,\ y=1)
Step 1
Concept
At (x=2), (y=11), and at (x=4), (y=1). Every point in the value table must satisfy the equation.
Step 2
Why this answer is correct
The correct answer is A. (x=2,\ y=11) और (x=4,\ y=1) / (x=2,\ y=11) and (x=4,\ y=1). At (x=2), (y=11), and at (x=4), (y=1). Every point in the value table must satisfy the equation.
Step 3
Exam Tip
(x=2) पर (y=11) और (x=4) पर (y=1)। मान-सारणी का हर बिंदु समीकरण को संतुष्ट करना चाहिए।
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Question 3/16
Hard Mathematics
Pair of Linear Equations in Two Variables Graphical method of finding solutions. Class 10 Level 52
यदि किसी रेखा की मान-सारणी में (\left\(-1,7\right\)) और (\left\(2,1\right\)) हैं, तो कौन-सा समीकरण सही है?
If a value table of a line has (\left\(-1,7\right\)) and (\left\(2,1\right\)), which equation is correct?
#value table
#line equation
#graph
A (2x+y=5)
B (x+2y=13)
C (2x+y=9)
D (x-y=-8)
Explanation opens after your attempt
Correct Answer
A. (2x+y=5)
Step 1
Concept
Both points satisfy (2x+y=5). Two correct points are enough to identify a line.
Step 2
Why this answer is correct
The correct answer is A. (2x+y=5). Both points satisfy (2x+y=5). Two correct points are enough to identify a line.
Step 3
Exam Tip
दोनों बिंदु (2x+y=5) को संतुष्ट करते हैं। दो सही बिंदु रेखा पहचानने में पर्याप्त होते हैं।
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Question 4/16
Hard Mathematics
Pair of Linear Equations in Two Variables Graphical method of finding solutions. Class 10 Level 52
रेखा (4x+y=16) के लिए कौन-सी मान-सारणी सही है?
Which value table is correct for the line (4x+y=16)?
#value table
#graph construction
#substitution
A (x=1,\ y=12) और (x=3,\ y=4) / (x=1,\ y=12) and (x=3,\ y=4)
B (x=1,\ y=4) और (x=3,\ y=12) / (x=1,\ y=4) and (x=3,\ y=12)
C (x=0,\ y=4) और (x=4,\ y=16) / (x=0,\ y=4) and (x=4,\ y=16)
D (x=2,\ y=12) और (x=4,\ y=4) / (x=2,\ y=12) and (x=4,\ y=4)
Explanation opens after your attempt
Correct Answer
A. (x=1,\ y=12) और (x=3,\ y=4) / (x=1,\ y=12) and (x=3,\ y=4)
Step 1
Concept
At (x=1), (y=12), and at (x=3), (y=4). Every point in the value table must satisfy the equation.
Step 2
Why this answer is correct
The correct answer is A. (x=1,\ y=12) और (x=3,\ y=4) / (x=1,\ y=12) and (x=3,\ y=4). At (x=1), (y=12), and at (x=3), (y=4). Every point in the value table must satisfy the equation.
Step 3
Exam Tip
(x=1) पर (y=12) और (x=3) पर (y=4)। मान-सारणी का हर बिंदु समीकरण को संतुष्ट करना चाहिए।
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Question 5/16
Medium Mathematics
Pair of Linear Equations in Two Variables Graphical method of finding solutions. Class 10 Level 54
यदि किसी रेखा की मान-सारणी में (\left\(2,4\right\)) और (\left\(5,1\right\)) हैं, तो कौन-सा समीकरण सही है?
If a value table of a line has (\left\(2,4\right\)) and (\left\(5,1\right\)), which equation is correct?
#value table
#line equation
#graph
A (x+y=6)
B (2x+y=8)
C (x+2y=10)
D (3x-y=2)
Explanation opens after your attempt
Correct Answer
A. (x+y=6)
Step 1
Concept
Both points satisfy (x+y=6). Two correct points help identify a line.
Step 2
Why this answer is correct
The correct answer is A. (x+y=6). Both points satisfy (x+y=6). Two correct points help identify a line.
Step 3
Exam Tip
दोनों बिंदु (x+y=6) को संतुष्ट करते हैं। दो सही बिंदु रेखा पहचानने में मदद करते हैं।
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Question 6/16
Medium Mathematics
Pair of Linear Equations in Two Variables Graphical method of finding solutions. Class 10 Level 54
रेखा (3x-y=5) के लिए कौन-सी मान-सारणी सही है?
Which value table is correct for the line (3x-y=5)?
#value table
#graph construction
#substitution
A (x=2,\ y=1) और (x=4,\ y=7) / (x=2,\ y=1) and (x=4,\ y=7)
B (x=2,\ y=7) और (x=4,\ y=1) / (x=2,\ y=7) and (x=4,\ y=1)
C (x=1,\ y=2) और (x=3,\ y=6) / (x=1,\ y=2) and (x=3,\ y=6)
D (x=0,\ y=5) और (x=5,\ y=0) / (x=0,\ y=5) and (x=5,\ y=0)
Explanation opens after your attempt
Correct Answer
A. (x=2,\ y=1) और (x=4,\ y=7) / (x=2,\ y=1) and (x=4,\ y=7)
Step 1
Concept
At (x=2), (6-y=5) gives (y=1), and at (x=4), (12-y=5) gives (y=7). Every table point must satisfy the equation.
Step 2
Why this answer is correct
The correct answer is A. (x=2,\ y=1) और (x=4,\ y=7) / (x=2,\ y=1) and (x=4,\ y=7). At (x=2), (6-y=5) gives (y=1), and at (x=4), (12-y=5) gives (y=7). Every table point must satisfy the equation.
Step 3
Exam Tip
(x=2) पर (6-y=5) से (y=1), और (x=4) पर (12-y=5) से (y=7)। मान-सारणी का हर बिंदु समीकरण को संतुष्ट करे।
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Question 7/16
Medium Mathematics
Pair of Linear Equations in Two Variables Graphical method of finding solutions. Class 10 Level 54
रेखा (2x-7y=14) के लिए (x=0) रखने पर कौन-सा बिंदु मिलेगा?
For the line (2x-7y=14), which point is obtained when (x=0)?
#negative value
#value table
#graph plotting
A बिंदु (\left\(0,2\right\)) / Point (\left\(0,2\right\))
B बिंदु (\left\(0,-2\right\)) / Point (\left\(0,-2\right\))
C बिंदु (\left\(7,0\right\)) / Point (\left\(7,0\right\))
D बिंदु (\left\(-7,0\right\)) / Point (\left\(-7,0\right\))
Explanation opens after your attempt
Correct Answer
B. बिंदु (\left\(0,-2\right\)) / Point (\left\(0,-2\right\))
Step 1
Concept
From (2\left\(0\right\)-7y=14), (y=-2). A sign error can make the graph wrong.
Step 2
Why this answer is correct
The correct answer is B. बिंदु (\left\(0,-2\right\)) / Point (\left\(0,-2\right\)). From (2\left\(0\right\)-7y=14), (y=-2). A sign error can make the graph wrong.
Step 3
Exam Tip
(2\left\(0\right\)-7y=14) से (y=-2) मिलता है। चिह्नों की गलती से ग्राफ गलत बन सकता है।
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Question 8/16
Medium Mathematics
Pair of Linear Equations in Two Variables Graphical method of finding solutions. Class 10 Level 53
यदि किसी रेखा की मान-सारणी में ( (1,5) ) और ( (3,1) ) हैं, तो इनमें से कौन-सा समीकरण उस रेखा को दर्शाता है?
If a value table of a line has ( (1,5) ) and ( (3,1) ), which equation represents that line?
#value table
#line equation
#graph
A (2x+y=7)
B (x+2y=11)
C (x+y=6)
D (3x+y=8)
Explanation opens after your attempt
Correct Answer
A. (2x+y=7)
Step 1
Concept
Both points satisfy (2x+y=7). Two correct points are enough to identify a line.
Step 2
Why this answer is correct
The correct answer is A. (2x+y=7). Both points satisfy (2x+y=7). Two correct points are enough to identify a line.
Step 3
Exam Tip
दोनों बिंदु (2x+y=7) को संतुष्ट करते हैं। दो सही बिंदु रेखा पहचानने के लिए पर्याप्त होते हैं।
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Question 9/16
Medium Mathematics
Pair of Linear Equations in Two Variables Graphical method of finding solutions. Class 10 Level 53
रेखा (3x-y=4) के लिए कौन-सी मान-सारणी सही है?
Which value table is correct for the line (3x-y=4)?
#value table
#graph construction
#substitution
A (x=2,\ y=2) और (x=3,\ y=5) / (x=2,\ y=2) and (x=3,\ y=5)
B (x=2,\ y=5) और (x=3,\ y=2) / (x=2,\ y=5) and (x=3,\ y=2)
C (x=1,\ y=3) और (x=4,\ y=4) / (x=1,\ y=3) and (x=4,\ y=4)
D (x=0,\ y=4) और (x=4,\ y=0) / (x=0,\ y=4) and (x=4,\ y=0)
Explanation opens after your attempt
Correct Answer
A. (x=2,\ y=2) और (x=3,\ y=5) / (x=2,\ y=2) and (x=3,\ y=5)
Step 1
Concept
At (x=2), (6-y=4) gives (y=2), and at (x=3), (9-y=4) gives (y=5). Every table point must satisfy the equation.
Step 2
Why this answer is correct
The correct answer is A. (x=2,\ y=2) और (x=3,\ y=5) / (x=2,\ y=2) and (x=3,\ y=5). At (x=2), (6-y=4) gives (y=2), and at (x=3), (9-y=4) gives (y=5). Every table point must satisfy the equation.
Step 3
Exam Tip
(x=2) पर (6-y=4) से (y=2), और (x=3) पर (9-y=4) से (y=5)। तालिका के हर बिंदु को समीकरण संतुष्ट करना चाहिए।
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Question 10/16
Medium Mathematics
Pair of Linear Equations in Two Variables Graphical method of finding solutions. Class 10 Level 53
रेखा (x+3y=12) के लिए (x=3) और (x=6) पर कौन-से बिंदु मिलेंगे?
For the line (x+3y=12), which points are obtained at (x=3) and (x=6)?
#value table
#graph plotting
#linear equation
A ( (3,3) ) और ( (6,2) ) / ( (3,3) ) and ( (6,2) )
B ( (3,6) ) और ( (6,3) ) / ( (3,6) ) and ( (6,3) )
C ( (3,2) ) और ( (6,3) ) / ( (3,2) ) and ( (6,3) )
D ( (3,1) ) और ( (6,2) ) / ( (3,1) ) and ( (6,2) )
Explanation opens after your attempt
Correct Answer
A. ( (3,3) ) और ( (6,2) ) / ( (3,3) ) and ( (6,2) )
Step 1
Concept
At (x=3), (3y=9) gives (y=3), and at (x=6), (3y=6) gives (y=2). A correct value table gives a correct graph.
Step 2
Why this answer is correct
The correct answer is A. ( (3,3) ) और ( (6,2) ) / ( (3,3) ) and ( (6,2) ). At (x=3), (3y=9) gives (y=3), and at (x=6), (3y=6) gives (y=2). A correct value table gives a correct graph.
Step 3
Exam Tip
(x=3) पर (3y=9) से (y=3), और (x=6) पर (3y=6) से (y=2)। सही मान-सारणी से सही ग्राफ बनता है।
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Question 11/16
Medium Mathematics
Pair of Linear Equations in Two Variables Graphical method of finding solutions. Class 10 Level 52
रेखा (2x-y=3) के लिए कौन-सी मान-सारणी सही है?
Which value table is correct for the line (2x-y=3)?
#value table
#graph construction
#substitution
A (x=2,\ y=1) और (x=3,\ y=3) / (x=2,\ y=1) and (x=3,\ y=3)
B (x=2,\ y=3) और (x=3,\ y=1) / (x=2,\ y=3) and (x=3,\ y=1)
C (x=1,\ y=2) और (x=3,\ y=6) / (x=1,\ y=2) and (x=3,\ y=6)
D (x=0,\ y=3) और (x=3,\ y=0) / (x=0,\ y=3) and (x=3,\ y=0)
Explanation opens after your attempt
Correct Answer
A. (x=2,\ y=1) और (x=3,\ y=3) / (x=2,\ y=1) and (x=3,\ y=3)
Step 1
Concept
At (x=2), (4-y=3) gives (y=1), and at (x=3), (6-y=3) gives (y=3). Table points must satisfy the equation.
Step 2
Why this answer is correct
The correct answer is A. (x=2,\ y=1) और (x=3,\ y=3) / (x=2,\ y=1) and (x=3,\ y=3). At (x=2), (4-y=3) gives (y=1), and at (x=3), (6-y=3) gives (y=3). Table points must satisfy the equation.
Step 3
Exam Tip
(x=2) पर (4-y=3) से (y=1), और (x=3) पर (6-y=3) से (y=3)। मान-सारणी के बिंदु समीकरण को संतुष्ट करने चाहिए।
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Question 12/16
Easy Mathematics
Pair of Linear Equations in Two Variables Graphical method of finding solutions. Class 10 Level 53
रेखा (x+5y=15) पर (x=5) रखने पर कौन-सा बिंदु मिलेगा?
For the line (x+5y=15), which point is obtained when (x=5)?
#value table
#graph plotting
#linear equations
A ( (5,2) )
B ( (2,5) )
C ( (5,1) )
D ( (1,5) )
Explanation opens after your attempt
Correct Answer
A. ( (5,2) )
Step 1
Concept
From (5+5y=15), (5y=10) and (y=2). Therefore, the point is ( (5,2) ).
Step 2
Why this answer is correct
The correct answer is A. ( (5,2) ). From (5+5y=15), (5y=10) and (y=2). Therefore, the point is ( (5,2) ).
Step 3
Exam Tip
(5+5y=15) से (5y=10) और (y=2)। इसलिए बिंदु ( (5,2) ) है।
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Question 13/16
Easy Mathematics
Pair of Linear Equations in Two Variables Graphical method of finding solutions. Class 10 Level 54
रेखा (x+4y=8) पर (x=4) रखने पर कौन-सा बिंदु मिलेगा?
For the line (x+4y=8), which point is obtained when (x=4)?
#value table
#graph plotting
#linear equations
A ( (4,2) )
B ( (2,4) )
C ( (4,1) )
D ( (1,4) )
Explanation opens after your attempt
Correct Answer
C. ( (4,1) )
Step 1
Concept
From (4+4y=8), (4y=4) and (y=1). Therefore, the point is ( (4,1) ).
Step 2
Why this answer is correct
The correct answer is C. ( (4,1) ). From (4+4y=8), (4y=4) and (y=1). Therefore, the point is ( (4,1) ).
Step 3
Exam Tip
(4+4y=8) से (4y=4) और (y=1)। इसलिए बिंदु ( (4,1) ) है।
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Question 14/16
Easy Mathematics
Pair of Linear Equations in Two Variables Graphical method of finding solutions. Class 10 Level 54
समीकरण (y=3x-1) के लिए (x=2) होने पर कौन-सा बिंदु मिलेगा?
For (y=3x-1), which point is obtained when (x=2)?
#linear equations
#value table
#graph plotting
A ( (2,3) )
B ( (3,2) )
C ( (2,5) )
D ( (5,2) )
Explanation opens after your attempt
Correct Answer
C. ( (2,5) )
Step 1
Concept
(y=3(2)-1=5), so the point is ( (2,5) ). After calculation, write the point as ( (x,y) ).
Step 2
Why this answer is correct
The correct answer is C. ( (2,5) ). (y=3(2)-1=5), so the point is ( (2,5) ). After calculation, write the point as ( (x,y) ).
Step 3
Exam Tip
(y=3(2)-1=5), इसलिए बिंदु ( (2,5) ) है। गणना के बाद बिंदु को ( (x,y) ) रूप में लिखें।
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Question 15/16
Easy Mathematics
Pair of Linear Equations in Two Variables Graphical method of finding solutions. Class 10 Level 52
समीकरण (x+y=8) में (x=5) रखने पर कौन-सा बिंदु मिलेगा?
For (x+y=8), which point is obtained when (x=5)?
#linear equations
#ordered pair
#value table
#easy
A ( (5,3) )
B ( (3,5) )
C ( (5,8) )
D ( (8,5) )
Explanation opens after your attempt
Correct Answer
A. ( (5,3) )
Step 1
Concept
(5+y=8), so (y=3) and the point is ( (5,3) ). Always write a point in ( (x,y) ) order.
Step 2
Why this answer is correct
The correct answer is A. ( (5,3) ). (5+y=8), so (y=3) and the point is ( (5,3) ). Always write a point in ( (x,y) ) order.
Step 3
Exam Tip
(5+y=8), इसलिए (y=3) और बिंदु ( (5,3) ) है। बिंदु हमेशा ( (x,y) ) क्रम में लिखें।
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Question 16/16
Easy Mathematics
Pair of Linear Equations in Two Variables Graphical method of finding solutions. Class 10 Level 52
समीकरण (x+y=7) के लिए (x=2) होने पर (y) कितना होगा?
For (x+y=7), what is (y) when (x=2)?
#linear equations
#value table
#graphical method
#easy
A (5)
B (7)
C (2)
D (9)
Explanation opens after your attempt
Step 1
Concept
(2+y=7), so (y=5). For a graph, it is useful to find at least two points.
Step 2
Why this answer is correct
The correct answer is A. (5). (2+y=7), so (y=5). For a graph, it is useful to find at least two points.
Step 3
Exam Tip
(2+y=7), इसलिए (y=5)। ग्राफ के लिए कम से कम दो बिंदु निकालना उपयोगी होता है।
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