समीकरण (2x-5y=-4) और (3x+y=19) का प्रतिच्छेद बिंदु क्या है?
What is the intersection point of (2x-5y=-4) and (3x+y=19)?
Explanation opens after your attempt
Correct Answer
A. बिंदु (\left\(\frac{91}{17},\frac{50}{17}\right\))Point (\left\(\frac{91}{17},\frac{50}{17}\right\))
Concept
Elimination gives (17y=50) and \(x=\frac{91}{17}\). Fraction coordinates can also be graphical solutions.
Why this answer is correct
The correct answer is A. बिंदु (\left\(\frac{91}{17},\frac{50}{17}\right\)) / Point (\left\(\frac{91}{17},\frac{50}{17}\right\)). Elimination gives (17y=50) and \(x=\frac{91}{17}\). Fraction coordinates can also be graphical solutions.
Exam Tip
उन्मूलन से (17y=50) और \(x=\frac{91}{17}\) मिलता है। भिन्न निर्देशांक भी ग्राफीय हल हो सकते हैं।
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