रेखाएं (2x-5y=1) और (3x+2y=22) ग्राफ पर किस बिंदु पर मिलेंगी?

At which point will the lines (2x-5y=1) and (3x+2y=22) meet on the graph?

Explanation opens after your attempt
Correct Answer

A. (\left\(\frac{112}{19},\frac{41}{19}\right\))

Step 1

Concept

Elimination gives (19x=112), so \(x=\frac{112}{19}\) and \(y=\frac{41}{19}\). A graphical solution may also have fractional coordinates.

Step 2

Why this answer is correct

The correct answer is A. (\left\(\frac{112}{19},\frac{41}{19}\right\)). Elimination gives (19x=112), so \(x=\frac{112}{19}\) and \(y=\frac{41}{19}\). A graphical solution may also have fractional coordinates.

Step 3

Exam Tip

उन्मूलन करने पर (19x=112), इसलिए \(x=\frac{112}{19}\) और \(y=\frac{41}{19}\)। ग्राफीय हल भिन्न निर्देशांक में भी हो सकता है।

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रेखाएं (2x-5y=1) और (3x+2y=22) ग्राफ पर किस बिंदु पर मिलेंगी? / At which point will the lines (2x-5y=1) and (3x+2y=22) meet on the graph?

Correct Answer: A. (\left\(\frac{112}{19},\frac{41}{19}\right\)). Explanation: उन्मूलन करने पर (19x=112), इसलिए \(x=\frac{112}{19}\) और \(y=\frac{41}{19}\)। ग्राफीय हल भिन्न निर्देशांक में भी हो सकता है। / Elimination gives (19x=112), so \(x=\frac{112}{19}\) and \(y=\frac{41}{19}\). A graphical solution may also have fractional coordinates.

Which concept should I revise for this Mathematics MCQ?

Elimination gives (19x=112), so \(x=\frac{112}{19}\) and \(y=\frac{41}{19}\). A graphical solution may also have fractional coordinates.

What exam hint can help solve this Mathematics question?

उन्मूलन करने पर (19x=112), इसलिए \(x=\frac{112}{19}\) और \(y=\frac{41}{19}\)। ग्राफीय हल भिन्न निर्देशांक में भी हो सकता है।

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