यदि दो रेखाओं का एकमात्र प्रतिच्छेद ((r,s)) है और (4r+s=29), (r-s=1), तो (r+s) क्या है?
If the only intersection of two lines is ((r,s)) and (4r+s=29), (r-s=1), what is (r+s)?
Explanation opens after your attempt
Correct Answer
C. (11)
Concept
Putting (s=r-1) gives (4r+r-1=29), so (r=6) and (s=5). Therefore (r+s=11).
Why this answer is correct
The correct answer is C. (11). Putting (s=r-1) gives (4r+r-1=29), so (r=6) and (s=5). Therefore (r+s=11).
Exam Tip
(s=r-1) रखने पर (4r+r-1=29), इसलिए (r=6) और (s=5)। अतः (r+s=11)।
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