Practice focused topic-wise MCQs with answers and explanations for quick revision and exam preparation.
Difficulty select karke sirf is topic ke focused MCQs practice karein. Score, timer aur explanations student-friendly flow me milenge.
Showing 81-90 of 650 questions.
In a square root spiral, \(\sqrt{10}\) lies between which whole numbers?
C. (3) और (4)(3) and (4)
क्योंकि \(3^2<10<4^2\) है। इसलिए \(3<\sqrt{10}<4\) होता है। / Because \(3^2<10<4^2\). Therefore \(3<\sqrt{10}<4\).
Login to save your score, XP, coins and progress.
In a square root spiral, \(\sqrt{24}\) lies between which whole numbers?
B. (4) और (5)(4) and (5)
क्योंकि \(4^2<24<5^2\) है। इसलिए \(4<\sqrt{24}<5\) होता है। / Because \(4^2<24<5^2\). Therefore \(4<\sqrt{24}<5\).
Login to save your score, XP, coins and progress.
A. क्योंकि (\(\sqrt{n}\)2+12=n+1)Because (\(\sqrt{n}\)2+12=n+1)
पाइथागोरस प्रमेय में भुजाओं के वर्ग जुड़ते हैं। इसलिए नया कर्ण \(\sqrt{n+1}\) होता है। / In Pythagoras theorem the squares of sides are added. Therefore the new hypotenuse is \(\sqrt{n+1}\).
Login to save your score, XP, coins and progress.
In making \(\sqrt{4}\) from \(\sqrt{3}\) in a square root spiral, which statement is not wrong?
A. (\(\sqrt{3}\)2+12=4)
सही गणना वर्गों के योग से होती है। \(\sqrt{3}+1\) को \(\sqrt{4}\) नहीं माना जाता। / The correct calculation uses the sum of squares. \(\sqrt{3}+1\) is not taken as \(\sqrt{4}\).
Login to save your score, XP, coins and progress.
To make \(\sqrt{32}\) in a square root spiral, which will be the previous hypotenuse?
B. \(\sqrt{31}\)
\(\sqrt{31}\) में (1) इकाई लंब जोड़ने पर \(\sqrt{32}\) मिलता है। पिछली संख्या (1) कम होती है। / Adding a (1) unit perpendicular to \(\sqrt{31}\) gives \(\sqrt{32}\). The previous number is (1) less.
Login to save your score, XP, coins and progress.
What is the length of \(\sqrt{36}\) in a square root spiral?
C. (6)
\(\sqrt{36}=6\) होता है। (36) एक पूर्ण वर्ग है। / \(\sqrt{36}=6\). The number (36) is a perfect square.
Login to save your score, XP, coins and progress.
In a square root spiral, \(\sqrt{40}\) lies between which two whole numbers?
B. (6) और (7)(6) and (7)
क्योंकि \(6^2<40<7^2\) है। इसलिए \(6<\sqrt{40}<7\) होता है। / Because \(6^2<40<7^2\). Therefore \(6<\sqrt{40}<7\).
Login to save your score, XP, coins and progress.
Which conclusion is correct by looking at \(\sqrt{49}\) in a square root spiral?
A. यह (7) के बराबर हैIt is equal to (7)
\(\sqrt{49}=7\) होता है। पूर्ण वर्गों के वर्गमूल पूर्ण संख्या होते हैं। / \(\sqrt{49}=7\). Square roots of perfect squares are whole numbers.
Login to save your score, XP, coins and progress.
Why does the figure in a square root spiral look like a spiral?
A. क्योंकि समकोण त्रिभुज क्रम से घूमते हुए बनते हैंBecause right triangles are formed successively while turning
हर नए त्रिभुज की दिशा बदलती है। लगातार दिशा बदलने से सर्पिल आकृति बनती है। / The direction of each new triangle changes. Continuous turning forms a spiral shape.
Login to save your score, XP, coins and progress.
Before making \(\sqrt{50}\) in a square root spiral, which hypotenuse will be formed?
B. \(\sqrt{49}\)
\(\sqrt{49}\) पर (1) इकाई लंब जोड़ने से \(\sqrt{50}\) बनेगा। क्रम में पिछले वर्गमूल को लें। / Adding a (1) unit perpendicular to \(\sqrt{49}\) gives \(\sqrt{50}\). Take the previous square root in order.
Login to save your score, XP, coins and progress.
Use Google login or mobile OTP. Admin can block users and control login providers.