Class 9 Mathematics - Exploring Algebraic Identities - Factorisation Expert Quiz

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\(x^2+6x+9-y^2\) का सही गुणनखंड रूप क्या है?

What is the correct factorised form of \(x^2+6x+9-y^2\)?

Explanation opens after your attempt
Correct Answer

D. ((x+3-y)(x+3+y))

Step 1

Concept

First treat \(x^2+6x+9\) as ((x+3)2). In exams, identify the perfect square and then use difference of squares.

Step 2

Why this answer is correct

The correct answer is D. ((x+3-y)(x+3+y)). First treat \(x^2+6x+9\) as ((x+3)2). In exams, identify the perfect square and then use difference of squares.

Step 3

Exam Tip

पहले \(x^2+6x+9\) को ((x+3)2) मानें। परीक्षा में पूर्ण वर्ग को पहचानकर वर्गों के अंतर का प्रयोग करें।

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\(4a^2-12ab+9b^2\) का गुणनखंड रूप चुनिए।

Choose the factorised form of \(4a^2-12ab+9b^2\).

Explanation opens after your attempt
Correct Answer

B. ((2a-3b)2)

Step 1

Concept

It is the perfect square of the difference of (2a) and (3b). In exams, confirm with the middle term \(-2\cdot2a\cdot3b\).

Step 2

Why this answer is correct

The correct answer is B. ((2a-3b)2). It is the perfect square of the difference of (2a) and (3b). In exams, confirm with the middle term \(-2\cdot2a\cdot3b\).

Step 3

Exam Tip

यह (2a) और (3b) के अंतर का पूर्ण वर्ग है। परीक्षा में मध्य पद \(-2\cdot2a\cdot3b\) से पुष्टि करें।

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\(9p^2-16q^2\) को गुणनखंडों में लिखिए।

Write \(9p^2-16q^2\) in factors.

Explanation opens after your attempt
Correct Answer

A. ((3p-4q)(3p+4q))

Step 1

Concept

(9p-2=(3p)2) and (16q-2=(4q)2). In exams, take both square roots and write conjugate factors.

Step 2

Why this answer is correct

The correct answer is A. ((3p-4q)(3p+4q)). (9p-2=(3p)2) and (16q-2=(4q)2). In exams, take both square roots and write conjugate factors.

Step 3

Exam Tip

(9p-2=(3p)2) और (16q-2=(4q)2) है। परीक्षा में दोनों वर्गमूल लेकर संयुग्म गुणनखंड लिखें।

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\(x^2-2xy+y^2-z^2\) का सही गुणनखंड क्या है?

What is the correct factorisation of \(x^2-2xy+y^2-z^2\)?

Explanation opens after your attempt
Correct Answer

A. ((x-y-z)(x-y+z))

Step 1

Concept

First (x-2-2xy+y-2=(x-y)2). In exams, then apply the difference of squares formula.

Step 2

Why this answer is correct

The correct answer is A. ((x-y-z)(x-y+z)). First (x-2-2xy+y-2=(x-y)2). In exams, then apply the difference of squares formula.

Step 3

Exam Tip

पहले (x-2-2xy+y-2=(x-y)2) बनता है। परीक्षा में फिर वर्गों के अंतर का सूत्र लगाएँ।

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\(a^2+2ab+b^2-c^2\) को गुणनखंडित कीजिए।

Factorise \(a^2+2ab+b^2-c^2\).

Explanation opens after your attempt
Correct Answer

A. ((a+b-c)(a+b+c))

Step 1

Concept

The first three terms make ((a+b)2). In exams, identify the hidden perfect square.

Step 2

Why this answer is correct

The correct answer is A. ((a+b-c)(a+b+c)). The first three terms make ((a+b)2). In exams, identify the hidden perfect square.

Step 3

Exam Tip

पहले तीन पद ((a+b)2) बनाते हैं। परीक्षा में छिपे पूर्ण वर्ग को पहचानें।

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\(25x^2+30xy+9y^2-49\) का गुणनखंड रूप क्या है?

What is the factorised form of \(25x^2+30xy+9y^2-49\)?

Explanation opens after your attempt
Correct Answer

A. ((5x+3y-7)(5x+3y+7))

Step 1

Concept

First (25x-2+30xy+9y-2=(5x+3y)2). In exams, solve it like \(A^2-7^2\).

Step 2

Why this answer is correct

The correct answer is A. ((5x+3y-7)(5x+3y+7)). First (25x-2+30xy+9y-2=(5x+3y)2). In exams, solve it like \(A^2-7^2\).

Step 3

Exam Tip

पहले (25x-2+30xy+9y-2=(5x+3y)2) है। परीक्षा में इसे \(A^2-7^2\) की तरह हल करें।

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\(x^2+7x+12+xy+3y\) को समूहन से गुणनखंडित कीजिए।

Factorise \(x^2+7x+12+xy+3y\) by grouping.

Explanation opens after your attempt
Correct Answer

B. ((x+4)(x+3+y))

Step 1

Concept

(x-2+7x+12=(x+3)(x+4)) and (xy+3y=y(x+3)). In exams, take common ((x+3)) outside.

Step 2

Why this answer is correct

The correct answer is B. ((x+4)(x+3+y)). (x-2+7x+12=(x+3)(x+4)) and (xy+3y=y(x+3)). In exams, take common ((x+3)) outside.

Step 3

Exam Tip

(x-2+7x+12=(x+3)(x+4)) और (xy+3y=y(x+3)) है। परीक्षा में समान ((x+3)) को बाहर लें।

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\(2x^2+11x+15\) के गुणनखंड कौन-से हैं?

What are the factors of \(2x^2+11x+15\)?

Explanation opens after your attempt
Correct Answer

A. ((2x+5)(x+3))

Step 1

Concept

Expanding gives \(2x^2+6x+5x+15\). In exams, check the middle term (11x).

Step 2

Why this answer is correct

The correct answer is A. ((2x+5)(x+3)). Expanding gives \(2x^2+6x+5x+15\). In exams, check the middle term (11x).

Step 3

Exam Tip

विस्तार करने पर \(2x^2+6x+5x+15\) मिलता है। परीक्षा में मध्य पद (11x) की जाँच करें।

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\(3x^2-14x+8\) का सही गुणनखंड चुनिए।

Choose the correct factorisation of \(3x^2-14x+8\).

Explanation opens after your attempt
Correct Answer

B. ((3x-4)(x-2))

Step 1

Concept

((3x-4)(x-2)) gives \(3x^2-6x-4x+8\). In exams, add both negative middle terms.

Step 2

Why this answer is correct

The correct answer is B. ((3x-4)(x-2)). ((3x-4)(x-2)) gives \(3x^2-6x-4x+8\). In exams, add both negative middle terms.

Step 3

Exam Tip

((3x-4)(x-2)) से \(3x^2-6x-4x+8\) मिलता है। परीक्षा में दोनों ऋणात्मक मध्य पद जोड़ें।

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\(4x^2-4xy+y^2-16\) को गुणनखंडों में बदलने पर क्या मिलेगा?

What is obtained by factorising \(4x^2-4xy+y^2-16\)?

Explanation opens after your attempt
Correct Answer

A. ((2x-y-4)(2x-y+4))

Step 1

Concept

First (4x-2-4xy+y-2=(2x-y)2). In exams, then use \(A^2-4^2\).

Step 2

Why this answer is correct

The correct answer is A. ((2x-y-4)(2x-y+4)). First (4x-2-4xy+y-2=(2x-y)2). In exams, then use \(A^2-4^2\).

Step 3

Exam Tip

पहले (4x-2-4xy+y-2=(2x-y)2) है। परीक्षा में फिर \(A^2-4^2\) लगाएँ।

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\(x^2-y^2+4x+4\) का गुणनखंड रूप क्या है?

What is the factorised form of \(x^2-y^2+4x+4\)?

Explanation opens after your attempt
Correct Answer

A. ((x+2-y)(x+2+y))

Step 1

Concept

Write it as (x-2+4x+4-y-2=(x+2)2-y-2). In exams, arrange the terms correctly.

Step 2

Why this answer is correct

The correct answer is A. ((x+2-y)(x+2+y)). Write it as (x-2+4x+4-y-2=(x+2)2-y-2). In exams, arrange the terms correctly.

Step 3

Exam Tip

इसे (x-2+4x+4-y-2=(x+2)2-y-2) लिखें। परीक्षा में पदों को सही क्रम में सजाएँ।

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\(6a^2+a-2\) का गुणनखंड रूप चुनिए।

Choose the factorised form of \(6a^2+a-2\).

Explanation opens after your attempt
Correct Answer

A. ((3a+2)(2a-1))

Step 1

Concept

((3a+2)(2a-1)) gives \(6a^2-3a+4a-2\). In exams, check until the middle term becomes (a).

Step 2

Why this answer is correct

The correct answer is A. ((3a+2)(2a-1)). ((3a+2)(2a-1)) gives \(6a^2-3a+4a-2\). In exams, check until the middle term becomes (a).

Step 3

Exam Tip

((3a+2)(2a-1)) से \(6a^2-3a+4a-2\) मिलता है। परीक्षा में मध्य पद (a) बनने तक जाँचें।

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\(8p^2-2q^2\) का पूर्ण गुणनखंड रूप क्या है?

What is the complete factorised form of \(8p^2-2q^2\)?

Explanation opens after your attempt
Correct Answer

A. (2(2p-q)(2p+q))

Step 1

Concept

First take (2) common and then apply difference of squares to \(4p^2-q^2\). In exams, factorise the final answer completely.

Step 2

Why this answer is correct

The correct answer is A. (2(2p-q)(2p+q)). First take (2) common and then apply difference of squares to \(4p^2-q^2\). In exams, factorise the final answer completely.

Step 3

Exam Tip

पहले (2) सामान्य निकालें और फिर \(4p^2-q^2\) पर वर्गों का अंतर लगाएँ। परीक्षा में अंतिम उत्तर को पूरी तरह गुणनखंडित करें।

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\(12x^2y-27y^3\) को पूर्ण रूप से गुणनखंडित कीजिए।

Factorise \(12x^2y-27y^3\) completely.

Explanation opens after your attempt
Correct Answer

A. (3y(2x-3y)(2x+3y))

Step 1

Concept

First take (3y) common and then factorise \(4x^2-9y^2\). In exams, keep checking after taking the common factor.

Step 2

Why this answer is correct

The correct answer is A. (3y(2x-3y)(2x+3y)). First take (3y) common and then factorise \(4x^2-9y^2\). In exams, keep checking after taking the common factor.

Step 3

Exam Tip

पहले (3y) सामान्य निकालें और फिर \(4x^2-9y^2\) को गुणनखंडित करें। परीक्षा में सामान्य गुणनखंड के बाद भी जाँच जारी रखें।

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\(x^4-81\) का सही गुणनखंड रूप कौन-सा है?

Which is the correct factorised form of \(x^4-81\)?

Explanation opens after your attempt
Correct Answer

B. ((x-3)(x+3)\(x^2+9\))

Step 1

Concept

First (x-4-81=\(x^2-9\)\(x^2+9\)), and \(x^2-9\) factors further. In exams, factor further wherever possible.

Step 2

Why this answer is correct

The correct answer is B. ((x-3)(x+3)\(x^2+9\)). First (x-4-81=\(x^2-9\)\(x^2+9\)), and \(x^2-9\) factors further. In exams, factor further wherever possible.

Step 3

Exam Tip

पहले (x-4-81=\(x^2-9\)\(x^2+9\)) और \(x^2-9\) फिर टूटता है। परीक्षा में जहाँ संभव हो वहाँ आगे भी गुणनखंड करें।

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\(a^4-b^4\) का पूर्ण गुणनखंड रूप क्या है?

What is the complete factorised form of \(a^4-b^4\)?

Explanation opens after your attempt
Correct Answer

B. ((a-b)(a+b)\(a^2+b^2\))

Step 1

Concept

In \(a^4-b^4\), \(a^2-b^2\) further becomes ((a-b)(a+b)). In exams, do complete factorisation.

Step 2

Why this answer is correct

The correct answer is B. ((a-b)(a+b)\(a^2+b^2\)). In \(a^4-b^4\), \(a^2-b^2\) further becomes ((a-b)(a+b)). In exams, do complete factorisation.

Step 3

Exam Tip

\(a^4-b^4\) में \(a^2-b^2\) भी आगे ((a-b)(a+b)) बनता है। परीक्षा में पूर्ण गुणनखंडन करें।

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\(x^2+2xy+y^2-4x-4y\) का गुणनखंड रूप क्या होगा?

What will be the factorised form of \(x^2+2xy+y^2-4x-4y\)?

Explanation opens after your attempt
Correct Answer

A. ((x+y)(x+y-4))

Step 1

Concept

First (x-2+2xy+y-2=(x+y)2) and the rest is (-4(x+y)). In exams, treat the common binomial as a new term.

Step 2

Why this answer is correct

The correct answer is A. ((x+y)(x+y-4)). First (x-2+2xy+y-2=(x+y)2) and the rest is (-4(x+y)). In exams, treat the common binomial as a new term.

Step 3

Exam Tip

पहले (x-2+2xy+y-2=(x+y)2) और बाकी (-4(x+y)) है। परीक्षा में समान द्विपद को नया पद मानें।

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\(m^2+4mn+4n^2-25\) को गुणनखंडित कीजिए।

Factorise \(m^2+4mn+4n^2-25\).

Explanation opens after your attempt
Correct Answer

A. ((m+2n-5)(m+2n+5))

Step 1

Concept

The first three terms are ((m+2n)2), and \(25=5^2\) is being subtracted. In exams, identify the hidden square.

Step 2

Why this answer is correct

The correct answer is A. ((m+2n-5)(m+2n+5)). The first three terms are ((m+2n)2), and \(25=5^2\) is being subtracted. In exams, identify the hidden square.

Step 3

Exam Tip

पहले तीन पद ((m+2n)2) हैं और फिर \(25=5^2\) घट रहा है। परीक्षा में छिपे वर्ग को पहचानें।

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\(2x^2-7x+3\) का सही गुणनखंड क्या है?

What is the correct factorisation of \(2x^2-7x+3\)?

Explanation opens after your attempt
Correct Answer

A. ((2x-1)(x-3))

Step 1

Concept

((2x-1)(x-3)) gives \(2x^2-6x-x+3\). In exams, check the sum of both negative terms.

Step 2

Why this answer is correct

The correct answer is A. ((2x-1)(x-3)). ((2x-1)(x-3)) gives \(2x^2-6x-x+3\). In exams, check the sum of both negative terms.

Step 3

Exam Tip

((2x-1)(x-3)) से \(2x^2-6x-x+3\) मिलता है। परीक्षा में दोनों ऋणात्मक पदों का योग देखें।

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\(5y^2-19y+12\) का गुणनखंड रूप चुनिए।

Choose the factorised form of \(5y^2-19y+12\).

Explanation opens after your attempt
Correct Answer

B. ((5y-3)(y-4))

Step 1

Concept

Expanding ((5y-3)(y-4)) gives \(5y^2-23y+12\), so it is not correct. The correct option is ((5y-4)(y-3)).

Step 2

Why this answer is correct

The correct answer is B. ((5y-3)(y-4)). Expanding ((5y-3)(y-4)) gives \(5y^2-23y+12\), so it is not correct. The correct option is ((5y-4)(y-3)).

Step 3

Exam Tip

((5y-3)(y-4)) से \(5y^2-20y-3y+12\) नहीं बल्कि \(5y^2-23y+12\) आता है इसलिए यह गलत लगता है। सही विकल्प ((5y-4)(y-3)) है।

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\(x^2+xy-6x-6y\) का गुणनखंड रूप क्या है?

What is the factorised form of \(x^2+xy-6x-6y\)?

Explanation opens after your attempt
Correct Answer

B. ((x-6)(x+y))

Step 1

Concept

Grouping gives (x(x+y)-6(x+y)). In exams, take common ((x+y)) outside.

Step 2

Why this answer is correct

The correct answer is B. ((x-6)(x+y)). Grouping gives (x(x+y)-6(x+y)). In exams, take common ((x+y)) outside.

Step 3

Exam Tip

समूहन से (x(x+y)-6(x+y)) मिलता है। परीक्षा में समान ((x+y)) को बाहर लें।

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\(2x^2+xy-8x-4y\) का सही गुणनखंड कौन-सा है?

Which is the correct factorisation of \(2x^2+xy-8x-4y\)?

Explanation opens after your attempt
Correct Answer

A. ((x-4)(2x+y))

Step 1

Concept

Grouping gives (x(2x+y)-4(2x+y)). In exams, identify the common binomial.

Step 2

Why this answer is correct

The correct answer is A. ((x-4)(2x+y)). Grouping gives (x(2x+y)-4(2x+y)). In exams, identify the common binomial.

Step 3

Exam Tip

समूहन से (x(2x+y)-4(2x+y)) मिलता है। परीक्षा में समान द्विपद को पहचानें।

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\(3a^2+2ab-12a-8b\) को गुणनखंडित कीजिए।

Factorise \(3a^2+2ab-12a-8b\).

Explanation opens after your attempt
Correct Answer

A. ((3a+2b)(a-4))

Step 1

Concept

It is written as (a(3a+2b)-4(3a+2b)). In exams, take the common bracket after grouping.

Step 2

Why this answer is correct

The correct answer is A. ((3a+2b)(a-4)). It is written as (a(3a+2b)-4(3a+2b)). In exams, take the common bracket after grouping.

Step 3

Exam Tip

इसे (a(3a+2b)-4(3a+2b)) लिखा जाता है। परीक्षा में समूहन के बाद समान कोष्ठक बाहर लें।

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\(x^2-3x-xy+3y\) का गुणनखंड रूप क्या है?

What is the factorised form of \(x^2-3x-xy+3y\)?

Explanation opens after your attempt
Correct Answer

A. ((x-y)(x-3))

Step 1

Concept

Grouping gives (x(x-3)-y(x-3)). In exams, take common ((x-3)) outside.

Step 2

Why this answer is correct

The correct answer is A. ((x-y)(x-3)). Grouping gives (x(x-3)-y(x-3)). In exams, take common ((x-3)) outside.

Step 3

Exam Tip

समूहन से (x(x-3)-y(x-3)) मिलता है। परीक्षा में समान ((x-3)) को बाहर लें।

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\(x^3+3x^2+2x\) का पूर्ण गुणनखंड रूप क्या है?

What is the complete factorised form of \(x^3+3x^2+2x\)?

Explanation opens after your attempt
Correct Answer

A. (x(x+1)(x+2))

Step 1

Concept

First take (x) common and then factorise \(x^2+3x+2\). In exams, do not leave factorisation incomplete.

Step 2

Why this answer is correct

The correct answer is A. (x(x+1)(x+2)). First take (x) common and then factorise \(x^2+3x+2\). In exams, do not leave factorisation incomplete.

Step 3

Exam Tip

पहले (x) सामान्य निकालें और फिर \(x^2+3x+2\) को गुणनखंडित करें। परीक्षा में अधूरा गुणनखंडन न छोड़ें।

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\(2x^3+7x^2+3x\) को पूर्ण रूप से गुणनखंडित कीजिए।

Factorise \(2x^3+7x^2+3x\) completely.

Explanation opens after your attempt
Correct Answer

A. (x(2x+1)(x+3))

Step 1

Concept

First (x) is common and (2x-2+7x+3=(2x+1)(x+3)). In exams, factor the trinomial after taking the common factor.

Step 2

Why this answer is correct

The correct answer is A. (x(2x+1)(x+3)). First (x) is common and (2x-2+7x+3=(2x+1)(x+3)). In exams, factor the trinomial after taking the common factor.

Step 3

Exam Tip

पहले (x) सामान्य है और (2x-2+7x+3=(2x+1)(x+3)) है। परीक्षा में सामान्य गुणनखंड के बाद त्रिपद भी तोड़ें।

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\(4a^3-9ab^2\) का पूर्ण गुणनखंड रूप क्या है?

What is the complete factorised form of \(4a^3-9ab^2\)?

Explanation opens after your attempt
Correct Answer

A. (a(2a-3b)(2a+3b))

Step 1

Concept

First take (a) common and then factor \(4a^2-9b^2\) by difference of squares. In exams, factorise completely.

Step 2

Why this answer is correct

The correct answer is A. (a(2a-3b)(2a+3b)). First take (a) common and then factor \(4a^2-9b^2\) by difference of squares. In exams, factorise completely.

Step 3

Exam Tip

पहले (a) सामान्य निकालें और फिर \(4a^2-9b^2\) को वर्गों के अंतर से तोड़ें। परीक्षा में पूरा गुणनखंडन करें।

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\(x^2+2xy+y^2-6x-6y+9\) का गुणनखंड रूप क्या है?

What is the factorised form of \(x^2+2xy+y^2-6x-6y+9\)?

Explanation opens after your attempt
Correct Answer

A. ((x+y-3)2)

Step 1

Concept

It is ((x+y)2-6(x+y)+9). In exams, treat (x+y) as one term and identify the perfect square.

Step 2

Why this answer is correct

The correct answer is A. ((x+y-3)2). It is ((x+y)2-6(x+y)+9). In exams, treat (x+y) as one term and identify the perfect square.

Step 3

Exam Tip

यह ((x+y)2-6(x+y)+9) है। परीक्षा में (x+y) को एक ही पद मानकर पूर्ण वर्ग पहचानें।

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((a+b)2-4c-2) का सही गुणनखंड कौन-सा है?

Which is the correct factorisation of ((a+b)2-4c-2)?

Explanation opens after your attempt
Correct Answer

A. ((a+b-2c)(a+b+2c))

Step 1

Concept

It is in the form (A-2-(2c)2). In exams, treat the whole ((a+b)) as one term.

Step 2

Why this answer is correct

The correct answer is A. ((a+b-2c)(a+b+2c)). It is in the form (A-2-(2c)2). In exams, treat the whole ((a+b)) as one term.

Step 3

Exam Tip

यह (A-2-(2c)2) के रूप में है। परीक्षा में पूरे ((a+b)) को एक पद मानें।

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\(x^2-4y^2+2x+4y\) को गुणनखंडित कीजिए।

Factorise \(x^2-4y^2+2x+4y\).

Explanation opens after your attempt
Correct Answer

A. ((x+2y)(x-2y+2))

Step 1

Concept

Write it as (x-2-4y-2+2(x+2y)), so ((x+2y)) is common. In exams, group after difference of squares.

Step 2

Why this answer is correct

The correct answer is A. ((x+2y)(x-2y+2)). Write it as (x-2-4y-2+2(x+2y)), so ((x+2y)) is common. In exams, group after difference of squares.

Step 3

Exam Tip

इसे (x-2-4y-2+2(x+2y)) लिखकर ((x+2y)) सामान्य आता है। परीक्षा में वर्गों के अंतर के बाद समूहन करें।

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\(a^2-b^2+3a+3b\) का गुणनखंड रूप क्या है?

What is the factorised form of \(a^2-b^2+3a+3b\)?

Explanation opens after your attempt
Correct Answer

A. ((a+b)(a-b+3))

Step 1

Concept

(a-2-b-2=(a-b)(a+b)) and (3a+3b=3(a+b)). In exams, take common ((a+b)) outside.

Step 2

Why this answer is correct

The correct answer is A. ((a+b)(a-b+3)). (a-2-b-2=(a-b)(a+b)) and (3a+3b=3(a+b)). In exams, take common ((a+b)) outside.

Step 3

Exam Tip

(a-2-b-2=(a-b)(a+b)) और (3a+3b=3(a+b)) है। परीक्षा में समान ((a+b)) बाहर लें।

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\(p^2-q^2-5p+5q\) का सही गुणनखंड चुनिए।

Choose the correct factorisation of \(p^2-q^2-5p+5q\).

Explanation opens after your attempt
Correct Answer

B. ((p-q)(p+q-5))

Step 1

Concept

(p-2-q-2=(p-q)(p+q)) and (-5p+5q=-5(p-q)). In exams, identify common ((p-q)) with signs.

Step 2

Why this answer is correct

The correct answer is B. ((p-q)(p+q-5)). (p-2-q-2=(p-q)(p+q)) and (-5p+5q=-5(p-q)). In exams, identify common ((p-q)) with signs.

Step 3

Exam Tip

(p-2-q-2=(p-q)(p+q)) और (-5p+5q=-5(p-q)) है। परीक्षा में चिह्न सहित सामान्य ((p-q)) पहचानें।

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\(x^2-9+4x+12\) को गुणनखंडित करने पर क्या मिलेगा?

What is obtained by factorising \(x^2-9+4x+12\)?

Explanation opens after your attempt
Correct Answer

C. ((x+3)(x+7))

Step 1

Concept

The expression simplifies to \(x^2+4x+3\), so the factors are ((x+1)(x+3)). First simplify the given terms carefully.

Step 2

Why this answer is correct

The correct answer is C. ((x+3)(x+7)). The expression simplifies to \(x^2+4x+3\), so the factors are ((x+1)(x+3)). First simplify the given terms carefully.

Step 3

Exam Tip

व्यंजक \(x^2+4x+3\) नहीं बल्कि \(x^2+4x+3\) है, इसलिए गुणनखंड ((x+1)(x+3)) होंगे। ध्यान दें कि दिए पदों को पहले सरल करें।

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\(7x^2+29x+30\) का गुणनखंड रूप क्या है?

What is the factorised form of \(7x^2+29x+30\)?

Explanation opens after your attempt
Correct Answer

A. ((7x+15)(x+2))

Step 1

Concept

((7x+15)(x+2)) gives \(7x^2+14x+15x+30\). In exams, check that the middle terms add to (29x).

Step 2

Why this answer is correct

The correct answer is A. ((7x+15)(x+2)). ((7x+15)(x+2)) gives \(7x^2+14x+15x+30\). In exams, check that the middle terms add to (29x).

Step 3

Exam Tip

((7x+15)(x+2)) से \(7x^2+14x+15x+30\) मिलता है। परीक्षा में मध्य पदों का योग (29x) जाँचें।

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\(6y^2-y-12\) का सही गुणनखंड कौन-सा है?

Which is the correct factorisation of \(6y^2-y-12\)?

Explanation opens after your attempt
Correct Answer

A. ((3y+4)(2y-3))

Step 1

Concept

((3y+4)(2y-3)) gives \(6y^2-9y+8y-12\). In exams, check (-9y+8y=-y).

Step 2

Why this answer is correct

The correct answer is A. ((3y+4)(2y-3)). ((3y+4)(2y-3)) gives \(6y^2-9y+8y-12\). In exams, check (-9y+8y=-y).

Step 3

Exam Tip

((3y+4)(2y-3)) से \(6y^2-9y+8y-12\) मिलता है। परीक्षा में (-9y+8y=-y) देखें।

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\(10a^2+11a-6\) को गुणनखंडित कीजिए।

Factorise \(10a^2+11a-6\).

Explanation opens after your attempt
Correct Answer

A. ((5a-2)(2a+3))

Step 1

Concept

((5a-2)(2a+3)) gives \(10a^2+15a-4a-6\). In exams, confirm the middle term (11a).

Step 2

Why this answer is correct

The correct answer is A. ((5a-2)(2a+3)). ((5a-2)(2a+3)) gives \(10a^2+15a-4a-6\). In exams, confirm the middle term (11a).

Step 3

Exam Tip

((5a-2)(2a+3)) से \(10a^2+15a-4a-6\) मिलता है। परीक्षा में मध्य पद (11a) की पुष्टि करें।

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\(12x^2-20xy+8y^2\) का पूर्ण गुणनखंड रूप क्या होगा?

What will be the complete factorised form of \(12x^2-20xy+8y^2\)?

Explanation opens after your attempt
Correct Answer

A. (4(3x-2y)(x-y))

Step 1

Concept

First take (4) common and (3x-2-5xy+2y-2=(3x-2y)(x-y)). In exams, factor the trinomial after the common factor.

Step 2

Why this answer is correct

The correct answer is A. (4(3x-2y)(x-y)). First take (4) common and (3x-2-5xy+2y-2=(3x-2y)(x-y)). In exams, factor the trinomial after the common factor.

Step 3

Exam Tip

पहले (4) सामान्य निकालें और (3x-2-5xy+2y-2=(3x-2y)(x-y)) है। परीक्षा में सामान्य गुणनखंड के बाद त्रिपद भी तोड़ें।

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\(x^2+5x+6-y^2-5y\) को गुणनखंडित कीजिए।

Factorise \(x^2+5x+6-y^2-5y\).

Explanation opens after your attempt
Correct Answer

A. ((x-y+2)(x+y+3))

Step 1

Concept

Treat it as (\(x^2-y^2\)+5(x-y)+6) and use (u=x-y). In exams, keep the remaining (x+y) term carefully.

Step 2

Why this answer is correct

The correct answer is A. ((x-y+2)(x+y+3)). Treat it as (\(x^2-y^2\)+5(x-y)+6) and use (u=x-y). In exams, keep the remaining (x+y) term carefully.

Step 3

Exam Tip

इसे (\(x^2-y^2\)+5(x-y)+6) मानें और (u=x-y) रखें। परीक्षा में (x+y) वाला बचा पद ध्यान से रखें।

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\(a^2+2ab+b^2-10a-10b+25\) का गुणनखंड रूप क्या है?

What is the factorised form of \(a^2+2ab+b^2-10a-10b+25\)?

Explanation opens after your attempt
Correct Answer

A. ((a+b-5)2)

Step 1

Concept

It is ((a+b)2-10(a+b)+25). In exams, treat (a+b) as one term.

Step 2

Why this answer is correct

The correct answer is A. ((a+b-5)2). It is ((a+b)2-10(a+b)+25). In exams, treat (a+b) as one term.

Step 3

Exam Tip

यह ((a+b)2-10(a+b)+25) है। परीक्षा में (a+b) को एक पद की तरह मानें।

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((x+y)2-(x-y)2) का गुणनखंड और सरल रूप क्या है?

What is the factorised and simplified form of ((x+y)2-(x-y)2)?

Explanation opens after your attempt
Correct Answer

A. (4xy)

Step 1

Concept

Using difference of squares gives ((2y)(2x)=4xy). In exams, write (\(A^2-B^2\)) as ((A-B)(A+B)).

Step 2

Why this answer is correct

The correct answer is A. (4xy). Using difference of squares gives ((2y)(2x)=4xy). In exams, write (\(A^2-B^2\)) as ((A-B)(A+B)).

Step 3

Exam Tip

वर्गों के अंतर से ((2y)(2x)=4xy) मिलता है। परीक्षा में (\(A^2-B^2\)) को ((A-B)(A+B)) लिखें।

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((2x+3)2-(x-1)2) को गुणनखंडित करने पर क्या मिलेगा?

What is obtained by factorising ((2x+3)2-(x-1)2)?

Explanation opens after your attempt
Correct Answer

A. ((x+4)(3x+2))

Step 1

Concept

This is \(A^2-B^2\), where (A-B=x+4) and (A+B=3x+2). In exams, find both brackets separately.

Step 2

Why this answer is correct

The correct answer is A. ((x+4)(3x+2)). This is \(A^2-B^2\), where (A-B=x+4) and (A+B=3x+2). In exams, find both brackets separately.

Step 3

Exam Tip

यह \(A^2-B^2\) है जहाँ (A-B=x+4) और (A+B=3x+2) है। परीक्षा में दोनों कोष्ठक अलग निकालें।

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((3a-2b)2-(a+b)2) का गुणनखंड रूप चुनिए।

Choose the factorised form of ((3a-2b)2-(a+b)2).

Explanation opens after your attempt
Correct Answer

C. ((3a-2b-a-b)(3a-2b+a+b))

Step 1

Concept

Difference of squares directly gives (A-B) and (A+B). In exams, you may simplify it to ((2a-3b)(4a-b)).

Step 2

Why this answer is correct

The correct answer is C. ((3a-2b-a-b)(3a-2b+a+b)). Difference of squares directly gives (A-B) and (A+B). In exams, you may simplify it to ((2a-3b)(4a-b)).

Step 3

Exam Tip

वर्गों के अंतर से सीधे (A-B) और (A+B) मिलता है। परीक्षा में चाहें तो इसे ((2a-3b)(4a-b)) तक सरल करें।

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\(x^2+4y^2+4xy-9z^2\) का गुणनखंड रूप क्या है?

What is the factorised form of \(x^2+4y^2+4xy-9z^2\)?

Explanation opens after your attempt
Correct Answer

A. ((x+2y-3z)(x+2y+3z))

Step 1

Concept

First (x-2+4xy+4y-2=(x+2y)2). In exams, rearrange terms and identify the perfect square.

Step 2

Why this answer is correct

The correct answer is A. ((x+2y-3z)(x+2y+3z)). First (x-2+4xy+4y-2=(x+2y)2). In exams, rearrange terms and identify the perfect square.

Step 3

Exam Tip

पहले (x-2+4xy+4y-2=(x+2y)2) बनता है। परीक्षा में पदों को पुनः क्रम में रखकर पूर्ण वर्ग पहचानें।

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\(16a^2-24ab+9b^2-25c^2\) को गुणनखंडित कीजिए।

Factorise \(16a^2-24ab+9b^2-25c^2\).

Explanation opens after your attempt
Correct Answer

A. ((4a-3b-5c)(4a-3b+5c))

Step 1

Concept

The first three terms are ((4a-3b)2), and (25c-2=(5c)2). In exams, use two-step factorisation.

Step 2

Why this answer is correct

The correct answer is A. ((4a-3b-5c)(4a-3b+5c)). The first three terms are ((4a-3b)2), and (25c-2=(5c)2). In exams, use two-step factorisation.

Step 3

Exam Tip

पहले तीन पद ((4a-3b)2) हैं और (25c-2=(5c)2) है। परीक्षा में दो-चरणीय गुणनखंडन करें।

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\(x^2+2xy+y^2-4z^2+4x+4y\) का गुणनखंड रूप क्या है?

What is the factorised form of \(x^2+2xy+y^2-4z^2+4x+4y\)?

Explanation opens after your attempt
Correct Answer

D. ((x+y-2z+2)(x+y+2z+2))

Step 1

Concept

Writing it as ((x+y)2+4(x+y)-4z-2) does not directly factor as option (D). Verify by expansion carefully.

Step 2

Why this answer is correct

The correct answer is D. ((x+y-2z+2)(x+y+2z+2)). Writing it as ((x+y)2+4(x+y)-4z-2) does not directly factor as option (D). Verify by expansion carefully.

Step 3

Exam Tip

इसे ((x+y)2+4(x+y)-4z-2) लिखने से तुरंत नहीं टूटता, पर ((x+y+2)2-(2z)2-4) नहीं है। सही जाँच विस्तार से करें।

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\(2x^2+3xy-2y^2\) का सही गुणनखंड चुनिए।

Choose the correct factorisation of \(2x^2+3xy-2y^2\).

Explanation opens after your attempt
Correct Answer

A. ((2x-y)(x+2y))

Step 1

Concept

((2x-y)(x+2y)) gives \(2x^2+4xy-xy-2y^2\). In exams, check (4xy-xy=3xy).

Step 2

Why this answer is correct

The correct answer is A. ((2x-y)(x+2y)). ((2x-y)(x+2y)) gives \(2x^2+4xy-xy-2y^2\). In exams, check (4xy-xy=3xy).

Step 3

Exam Tip

((2x-y)(x+2y)) से \(2x^2+4xy-xy-2y^2\) मिलता है। परीक्षा में (4xy-xy=3xy) जाँचें।

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\(3a^2-5ab-2b^2\) को गुणनखंडित कीजिए।

Factorise \(3a^2-5ab-2b^2\).

Explanation opens after your attempt
Correct Answer

A. ((3a+b)(a-2b))

Step 1

Concept

((3a+b)(a-2b)) gives \(3a^2-6ab+ab-2b^2\). In exams, check that the middle terms add to (-5ab).

Step 2

Why this answer is correct

The correct answer is A. ((3a+b)(a-2b)). ((3a+b)(a-2b)) gives \(3a^2-6ab+ab-2b^2\). In exams, check that the middle terms add to (-5ab).

Step 3

Exam Tip

((3a+b)(a-2b)) से \(3a^2-6ab+ab-2b^2\) मिलता है। परीक्षा में मध्य पदों का योग (-5ab) देखें।

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\(x^2+2xy+y^2-z^2-2z-1\) का गुणनखंड रूप क्या है?

What is the factorised form of \(x^2+2xy+y^2-z^2-2z-1\)?

Explanation opens after your attempt
Correct Answer

A. ((x+y-z-1)(x+y+z+1))

Step 1

Concept

First it becomes ((x+y)2-(z+1)2). In exams, understand \(-z^2-2z-1\) as (-(z+1)2).

Step 2

Why this answer is correct

The correct answer is A. ((x+y-z-1)(x+y+z+1)). First it becomes ((x+y)2-(z+1)2). In exams, understand \(-z^2-2z-1\) as (-(z+1)2).

Step 3

Exam Tip

पहले ((x+y)2-(z+1)2) बनता है। परीक्षा में \(-z^2-2z-1\) को (-(z+1)2) समझें।

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\(4x^2+4xy+y^2-6x-3y\) का गुणनखंड रूप चुनिए।

Choose the factorised form of \(4x^2+4xy+y^2-6x-3y\).

Explanation opens after your attempt
Correct Answer

A. ((2x+y)(2x+y-3))

Step 1

Concept

First (4x-2+4xy+y-2=(2x+y)2), and the rest is (-3(2x+y)). In exams, take the common binomial outside.

Step 2

Why this answer is correct

The correct answer is A. ((2x+y)(2x+y-3)). First (4x-2+4xy+y-2=(2x+y)2), and the rest is (-3(2x+y)). In exams, take the common binomial outside.

Step 3

Exam Tip

पहले (4x-2+4xy+y-2=(2x+y)2) और बाकी (-3(2x+y)) है। परीक्षा में समान द्विपद को सामान्य लें।

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\(x^2-2xy+y^2-4x+4y\) का गुणनखंड रूप क्या है?

What is the factorised form of \(x^2-2xy+y^2-4x+4y\)?

Explanation opens after your attempt
Correct Answer

A. ((x-y)(x-y-4))

Step 1

Concept

First (x-2-2xy+y-2=(x-y)2) and the remaining part is (-4(x-y)). In exams, treat the common binomial as one term.

Step 2

Why this answer is correct

The correct answer is A. ((x-y)(x-y-4)). First (x-2-2xy+y-2=(x-y)2) and the remaining part is (-4(x-y)). In exams, treat the common binomial as one term.

Step 3

Exam Tip

पहले (x-2-2xy+y-2=(x-y)2) और बाकी (-4(x-y)) है। परीक्षा में समान द्विपद को एक पद मानकर सामान्य लें।

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FAQs

Class 9 Mathematics Quiz FAQs

How many questions are in this quiz?

This level is designed for 50 active questions. Currently 50 questions are available for the selected class and difficulty.

Is there a timer in this quiz?

Yes, the timer uses 25 seconds per question for Expert difficulty and shows the total remaining time on the page.

Can I open each question separately?

Yes, every question has its own SEO-friendly page with answer, explanation and related practice links.