Concept-wise Practice

three_variables MCQ Questions for Class 10

three_variables se related questions ko ek jagah revise karein. Har question me bilingual content, answer feedback aur explanation available hai.

Practice Questions

3 questions tagged with three_variables.

(\left\(\frac{x^{-4}y^{5}}{z^{-2}}\right\)^{-1}\cdot\frac{y^{3}}{x^{2}z^{4}}) का सरल रूप क्या है?

What is the simplified form of (\left\(\frac{x^{-4}y^{5}}{z^{-2}}\right\)^{-1}\cdot\frac{y^{3}}{x^{2}z^{4}})?

Explanation opens after your attempt
Correct Answer

A. \(\frac{x^{2}}{y^{2}z^{2}}\)

Step 1

Concept

Inside, \(\frac{x^{-4}y^{5}}{z^{-2}}=x^{-4}y^{5}z^{2}\), so its reciprocal is \(x^{4}y^{-5}z^{-2}\). Multiplying by \(\frac{y^{3}}{x^{2}z^{4}}\) gives \(\frac{x^{2}}{y^{2}z^{6}}\).

Step 2

Why this answer is correct

The correct answer is A. \(\frac{x^{2}}{y^{2}z^{2}}\). Inside, \(\frac{x^{-4}y^{5}}{z^{-2}}=x^{-4}y^{5}z^{2}\), so its reciprocal is \(x^{4}y^{-5}z^{-2}\). Multiplying by \(\frac{y^{3}}{x^{2}z^{4}}\) gives \(\frac{x^{2}}{y^{2}z^{6}}\).

Step 3

Exam Tip

अंदर \(\frac{x^{-4}y^{5}}{z^{-2}}=x^{-4}y^{5}z^{2}\), इसलिए उल्टा \(x^{4}y^{-5}z^{-2}\) है। \(\frac{y^{3}}{x^{2}z^{4}}\) से गुणा करने पर \(\frac{x^{2}}{y^{2}z^{6}}\) मिलता है।

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(\left\(\frac{x^{-2}y^{4}}{z^{-3}}\right\)^{-1}\cdot\frac{y^{2}}{x^{3}z^{2}}) का सरल रूप क्या है?

What is the simplified form of (\left\(\frac{x^{-2}y^{4}}{z^{-3}}\right\)^{-1}\cdot\frac{y^{2}}{x^{3}z^{2}})?

Explanation opens after your attempt
Correct Answer

A. \(\frac{z}{xy^{2}}\)

Step 1

Concept

Inside, \(\frac{x^{-2}y^{4}}{z^{-3}}=x^{-2}y^{4}z^{3}\), so its reciprocal is \(x^{2}y^{-4}z^{-3}\). Multiplying by \(\frac{y^{2}}{x^{3}z^{2}}\) gives \(\frac{1}{xy^{2}z^{5}}\).

Step 2

Why this answer is correct

The correct answer is A. \(\frac{z}{xy^{2}}\). Inside, \(\frac{x^{-2}y^{4}}{z^{-3}}=x^{-2}y^{4}z^{3}\), so its reciprocal is \(x^{2}y^{-4}z^{-3}\). Multiplying by \(\frac{y^{2}}{x^{3}z^{2}}\) gives \(\frac{1}{xy^{2}z^{5}}\).

Step 3

Exam Tip

अंदर \(\frac{x^{-2}y^{4}}{z^{-3}}=x^{-2}y^{4}z^{3}\), इसलिए उल्टा \(x^{2}y^{-4}z^{-3}\) है। \(\frac{y^{2}}{x^{3}z^{2}}\) से गुणा करने पर \(\frac{1}{xy^{2}z^{5}}\) मिलता है।

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(\left\(\frac{x^{3}y^{-2}}{z^{-1}}\right\)^{-1}\cdot\frac{x^{2}}{yz^{2}}) का सरल रूप क्या है?

What is the simplified form of (\left\(\frac{x^{3}y^{-2}}{z^{-1}}\right\)^{-1}\cdot\frac{x^{2}}{yz^{2}})?

Explanation opens after your attempt
Correct Answer

A. \(\frac{y}{xz}\)

Step 1

Concept

Inside, \(\frac{x^{3}y^{-2}}{z^{-1}}=x^{3}y^{-2}z\), so its reciprocal is \(x^{-3}y^{2}z^{-1}\). Multiplying by \(\frac{x^{2}}{yz^{2}}\) gives \(\frac{y}{xz^{3}}\), so the (z)-power must be checked carefully.

Step 2

Why this answer is correct

The correct answer is A. \(\frac{y}{xz}\). Inside, \(\frac{x^{3}y^{-2}}{z^{-1}}=x^{3}y^{-2}z\), so its reciprocal is \(x^{-3}y^{2}z^{-1}\). Multiplying by \(\frac{x^{2}}{yz^{2}}\) gives \(\frac{y}{xz^{3}}\), so the (z)-power must be checked carefully.

Step 3

Exam Tip

अंदर \(\frac{x^{3}y^{-2}}{z^{-1}}=x^{3}y^{-2}z\), इसलिए उल्टा \(x^{-3}y^{2}z^{-1}\) है। \(\frac{x^{2}}{yz^{2}}\) से गुणा करने पर \(\frac{y}{xz^{3}}\) मिलता है, इसलिए विकल्पों में (z) की जांच आवश्यक है।

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