(\left\(\frac{x^{-2}y^{4}}{z^{-3}}\right\)^{-1}\cdot\frac{y^{2}}{x^{3}z^{2}}) का सरल रूप क्या है?
What is the simplified form of (\left\(\frac{x^{-2}y^{4}}{z^{-3}}\right\)^{-1}\cdot\frac{y^{2}}{x^{3}z^{2}})?
Explanation opens after your attempt
A. \(\frac{z}{xy^{2}}\)
Concept
Inside, \(\frac{x^{-2}y^{4}}{z^{-3}}=x^{-2}y^{4}z^{3}\), so its reciprocal is \(x^{2}y^{-4}z^{-3}\). Multiplying by \(\frac{y^{2}}{x^{3}z^{2}}\) gives \(\frac{1}{xy^{2}z^{5}}\).
Why this answer is correct
The correct answer is A. \(\frac{z}{xy^{2}}\). Inside, \(\frac{x^{-2}y^{4}}{z^{-3}}=x^{-2}y^{4}z^{3}\), so its reciprocal is \(x^{2}y^{-4}z^{-3}\). Multiplying by \(\frac{y^{2}}{x^{3}z^{2}}\) gives \(\frac{1}{xy^{2}z^{5}}\).
Exam Tip
अंदर \(\frac{x^{-2}y^{4}}{z^{-3}}=x^{-2}y^{4}z^{3}\), इसलिए उल्टा \(x^{2}y^{-4}z^{-3}\) है। \(\frac{y^{2}}{x^{3}z^{2}}\) से गुणा करने पर \(\frac{1}{xy^{2}z^{5}}\) मिलता है।
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