\(m^2+4mn+4n^2-25\) को गुणनखंडित कीजिए।

Factorise \(m^2+4mn+4n^2-25\).

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

A. ((m+2n-5)(m+2n+5))

Step 1

Concept

The first three terms are ((m+2n)2), and \(25=5^2\) is being subtracted. In exams, identify the hidden square.

Step 2

Why this answer is correct

The correct answer is A. ((m+2n-5)(m+2n+5)). The first three terms are ((m+2n)2), and \(25=5^2\) is being subtracted. In exams, identify the hidden square.

Step 3

Exam Tip

पहले तीन पद ((m+2n)2) हैं और फिर \(25=5^2\) घट रहा है। परीक्षा में छिपे वर्ग को पहचानें।

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FAQs

Mathematics Answer, Explanation and Revision Hints

\(m^2+4mn+4n^2-25\) को गुणनखंडित कीजिए। / Factorise \(m^2+4mn+4n^2-25\).

Correct Answer: A. ((m+2n-5)(m+2n+5)). Explanation: पहले तीन पद ((m+2n)2) हैं और फिर \(25=5^2\) घट रहा है। परीक्षा में छिपे वर्ग को पहचानें। / The first three terms are ((m+2n)2), and \(25=5^2\) is being subtracted. In exams, identify the hidden square.

Which concept should I revise for this Mathematics MCQ?

The first three terms are ((m+2n)2), and \(25=5^2\) is being subtracted. In exams, identify the hidden square.

What exam hint can help solve this Mathematics question?

पहले तीन पद ((m+2n)2) हैं और फिर \(25=5^2\) घट रहा है। परीक्षा में छिपे वर्ग को पहचानें।