In which of the following expressions is \(3m\) a common factor of every term?
Answer and explanation
Correct answer: \(6m^2+9mn\)
In option A, \(6m^2=3m\times2m\) and \(9mn=3m\times3n\). Thus, \(3m\) is a common factor of both terms. In option B, \(6n\) does not contain \(m\), so it is not divisible by \(3m\). Exam tip: for a common factor, both the numerical factor and the variable must occur in every term.
Frequently asked questions
What is the correct answer to this question?
\(6m^2+9mn\)
Why is this the correct answer?
In option A, \(6m^2=3m\times2m\) and \(9mn=3m\times3n\). Thus, \(3m\) is a common factor of both terms. In option B, \(6n\) does not contain \(m\), so it is not divisible by \(3m\). Exam tip: for a common factor, both the numerical factor and the variable must occur in every term.
Which subject and chapter does this question cover?
This is a Class 9 Mathematics question. Chapter: Exploring Algebraic Identities. Topic: Factorisation.
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