\(x^2+2xy+y^2-4x-4y\) का गुणनखंड रूप क्या होगा?

What will be the factorised form of \(x^2+2xy+y^2-4x-4y\)?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

A. ((x+y)(x+y-4))

Step 1

Concept

First (x-2+2xy+y-2=(x+y)2) and the rest is (-4(x+y)). In exams, treat the common binomial as a new term.

Step 2

Why this answer is correct

The correct answer is A. ((x+y)(x+y-4)). First (x-2+2xy+y-2=(x+y)2) and the rest is (-4(x+y)). In exams, treat the common binomial as a new term.

Step 3

Exam Tip

पहले (x-2+2xy+y-2=(x+y)2) और बाकी (-4(x+y)) है। परीक्षा में समान द्विपद को नया पद मानें।

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Mathematics Answer, Explanation and Revision Hints

\(x^2+2xy+y^2-4x-4y\) का गुणनखंड रूप क्या होगा? / What will be the factorised form of \(x^2+2xy+y^2-4x-4y\)?

Correct Answer: A. ((x+y)(x+y-4)). Explanation: पहले (x-2+2xy+y-2=(x+y)2) और बाकी (-4(x+y)) है। परीक्षा में समान द्विपद को नया पद मानें। / First (x-2+2xy+y-2=(x+y)2) and the rest is (-4(x+y)). In exams, treat the common binomial as a new term.

Which concept should I revise for this Mathematics MCQ?

First (x-2+2xy+y-2=(x+y)2) and the rest is (-4(x+y)). In exams, treat the common binomial as a new term.

What exam hint can help solve this Mathematics question?

पहले (x-2+2xy+y-2=(x+y)2) और बाकी (-4(x+y)) है। परीक्षा में समान द्विपद को नया पद मानें।