\(4x^2+4xy+y^2-6x-3y\) का गुणनखंड रूप चुनिए।

Choose the factorised form of \(4x^2+4xy+y^2-6x-3y\).

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

A. ((2x+y)(2x+y-3))

Step 1

Concept

First (4x-2+4xy+y-2=(2x+y)2), and the rest is (-3(2x+y)). In exams, take the common binomial outside.

Step 2

Why this answer is correct

The correct answer is A. ((2x+y)(2x+y-3)). First (4x-2+4xy+y-2=(2x+y)2), and the rest is (-3(2x+y)). In exams, take the common binomial outside.

Step 3

Exam Tip

पहले (4x-2+4xy+y-2=(2x+y)2) और बाकी (-3(2x+y)) है। परीक्षा में समान द्विपद को सामान्य लें।

Question me issue ya doubt hai?

Answer, explanation, typing mistake ya suggestion directly hamari team ko bhejein. 📱Helpline (Call / WhatsApp): +91 7272824365

Related Mathematics Questions

FAQs

Mathematics Answer, Explanation and Revision Hints

\(4x^2+4xy+y^2-6x-3y\) का गुणनखंड रूप चुनिए। / Choose the factorised form of \(4x^2+4xy+y^2-6x-3y\).

Correct Answer: A. ((2x+y)(2x+y-3)). Explanation: पहले (4x-2+4xy+y-2=(2x+y)2) और बाकी (-3(2x+y)) है। परीक्षा में समान द्विपद को सामान्य लें। / First (4x-2+4xy+y-2=(2x+y)2), and the rest is (-3(2x+y)). In exams, take the common binomial outside.

Which concept should I revise for this Mathematics MCQ?

First (4x-2+4xy+y-2=(2x+y)2), and the rest is (-3(2x+y)). In exams, take the common binomial outside.

What exam hint can help solve this Mathematics question?

पहले (4x-2+4xy+y-2=(2x+y)2) और बाकी (-3(2x+y)) है। परीक्षा में समान द्विपद को सामान्य लें।