समीकरणों (13x+qy=52) और (26x+18y=104) के अनंत हल होने के लिए (q) का मान क्या है?
What is the value of (q) for the equations (13x+qy=52) and (26x+18y=104) to have infinitely many solutions?
Explanation opens after your attempt
Step 1
Concept
The second equation is (2) times the first, so (q/18=1/2) must hold. Hence, (q=9).
Step 2
Why this answer is correct
The correct answer is C. (9). The second equation is (2) times the first, so (q/18=1/2) must hold. Hence, (q=9).
Step 3
Exam Tip
दूसरा समीकरण पहले का (2) गुना है, इसलिए (q/18=1/2) होना चाहिए। अतः (q=9)।
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समीकरणों (kx+14y=42) और (18x+21y=63) के अनंत हल होने के लिए (k) क्या होगा?
What will (k) be for the equations (kx+14y=42) and (18x+21y=63) to have infinitely many solutions?
Explanation opens after your attempt
Step 1
Concept
For infinitely many solutions, (k/18=14/21=42/63) must hold. Therefore, (k=12) is correct.
Step 2
Why this answer is correct
The correct answer is C. (12). For infinitely many solutions, (k/18=14/21=42/63) must hold. Therefore, (k=12) is correct.
Step 3
Exam Tip
अनंत हल के लिए (k/18=14/21=42/63) होना चाहिए। इसलिए (k=12) सही है।
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समीकरणों (px+9y=45) और (20x+30y=103) का कोई हल न होने के लिए (p) का मान क्या होगा?
What is the value of (p) for the equations (px+9y=45) and (20x+30y=103) to have no solution?
Explanation opens after your attempt
Step 1
Concept
For no solution, (p/20=9/30) and (45/103) must be different. This gives (p=6).
Step 2
Why this answer is correct
The correct answer is B. (6). For no solution, (p/20=9/30) and (45/103) must be different. This gives (p=6).
Step 3
Exam Tip
कोई हल नहीं के लिए (p/20=9/30) और (45/103) अलग होना चाहिए। इससे (p=6) मिलता है।
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समीकरणों (4x+ay=32) और (12x+21y=96) के अनंत हल होने के लिए (a) का मान क्या होगा?
What is the value of (a) for the equations (4x+ay=32) and (12x+21y=96) to have infinitely many solutions?
Explanation opens after your attempt
Step 1
Concept
For infinitely many solutions, (4/12=a/21=32/96) must hold. Therefore, (a=7) is correct.
Step 2
Why this answer is correct
The correct answer is C. (7). For infinitely many solutions, (4/12=a/21=32/96) must hold. Therefore, (a=7) is correct.
Step 3
Exam Tip
अनंत हल के लिए (4/12=a/21=32/96) होना चाहिए। इसलिए (a=7) सही है।
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समीकरणों (13x+py=52) और (6x+5y=24) का अद्वितीय हल होने के लिए कौन-सी शर्त सही है?
Which condition is correct for the equations (13x+py=52) and (6x+5y=24) to have a unique solution?
Explanation opens after your attempt
Correct Answer
A. (p \ne 65/6)
Step 1
Concept
For a unique solution, \(13/6 \ne p/5\) must hold. Therefore, \(p \ne 65/6\) is the correct condition.
Step 2
Why this answer is correct
The correct answer is A. \(p \ne 65 / 6\). For a unique solution, \(13/6 \ne p/5\) must hold. Therefore, \(p \ne 65/6\) is the correct condition.
Step 3
Exam Tip
अद्वितीय हल के लिए \(13/6 \ne p/5\) होना चाहिए। इसलिए \(p \ne 65/6\) सही शर्त है।
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समीकरणों (bx+9y=36) और (16x+24y=97) का कोई हल न होने के लिए (b) का मान क्या होगा?
What is the value of (b) for the equations (bx+9y=36) and (16x+24y=97) to have no solution?
Explanation opens after your attempt
Step 1
Concept
For no solution, (b/16=9/24) and (36/97) must be different. Hence, (b=6).
Step 2
Why this answer is correct
The correct answer is D. (6). For no solution, (b/16=9/24) and (36/97) must be different. Hence, (b=6).
Step 3
Exam Tip
कोई हल नहीं के लिए (b/16=9/24) और (36/97) अलग होना चाहिए। इसलिए (b=6)।
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समीकरणों (5x+ay=45) और (20x+28y=180) के अनंत हल होने के लिए (a) का मान क्या होगा?
What is the value of (a) for the equations (5x+ay=45) and (20x+28y=180) to have infinitely many solutions?
Explanation opens after your attempt
Step 1
Concept
For infinitely many solutions, (5/20=a/28=45/180) must hold. Therefore, (a=7) is correct.
Step 2
Why this answer is correct
The correct answer is C. (7). For infinitely many solutions, (5/20=a/28=45/180) must hold. Therefore, (a=7) is correct.
Step 3
Exam Tip
अनंत हल के लिए (5/20=a/28=45/180) होना चाहिए। इसलिए (a=7) सही है।
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समीकरणों (4x+7y=31) और (12x+21y=t) के असंगत होने के लिए (t) के लिए सही शर्त क्या है?
What is the correct condition on (t) for the equations (4x+7y=31) and (12x+21y=t) to be inconsistent?
Explanation opens after your attempt
Correct Answer
B. \(t \ne 93\)
Step 1
Concept
The first two ratios are equal. For inconsistency, the constant ratio must be different so \(t \ne 93\).
Step 2
Why this answer is correct
The correct answer is B. \(t \ne 93\). The first two ratios are equal. For inconsistency, the constant ratio must be different so \(t \ne 93\).
Step 3
Exam Tip
पहले दो अनुपात बराबर हैं। असंगत होने के लिए स्थिर पद का अनुपात अलग होना चाहिए इसलिए \(t \ne 93\)।
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यदि (lx+15y=60) और (18x+45y=181) का कोई हल नहीं है, तो (l) का मान क्या होगा?
If (lx+15y=60) and (18x+45y=181) have no solution, what will be the value of (l)?
Explanation opens after your attempt
Step 1
Concept
For no solution, (l/18=15/45) and (60/181) must be different. Hence, (l=6).
Step 2
Why this answer is correct
The correct answer is C. (6). For no solution, (l/18=15/45) and (60/181) must be different. Hence, (l=6).
Step 3
Exam Tip
कोई हल नहीं के लिए (l/18=15/45) और (60/181) अलग होना चाहिए। इसलिए (l=6)।
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समीकरणों (10x+ky=110) और (2x+9y=22) के अनंत हल होने के लिए (k) क्या होगा?
What will (k) be for the equations (10x+ky=110) and (2x+9y=22) to have infinitely many solutions?
Explanation opens after your attempt
Step 1
Concept
The first equation must be (5) times the second. Therefore, (k=45).
Step 2
Why this answer is correct
The correct answer is C. (45). The first equation must be (5) times the second. Therefore, (k=45).
Step 3
Exam Tip
पहला समीकरण दूसरे का (5) गुना होना चाहिए। इसलिए (k=45) है।
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समीकरणों (8x+7y=34) और (16x+ay=79) का कोई हल न होने के लिए (a) क्या होगा?
What will (a) be for the equations (8x+7y=34) and (16x+ay=79) to have no solution?
Explanation opens after your attempt
Step 1
Concept
For no solution, (8/16=7/a) and (34/79) must be different. This gives (a=14).
Step 2
Why this answer is correct
The correct answer is C. (14). For no solution, (8/16=7/a) and (34/79) must be different. This gives (a=14).
Step 3
Exam Tip
कोई हल नहीं के लिए (8/16=7/a) और (34/79) अलग होना चाहिए। इससे (a=14) मिलता है।
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समीकरणों (11x+6y=37) और (22x+12y=r) के असंगत होने के लिए कौन-सी शर्त सही है?
Which condition is correct for the equations (11x+6y=37) and (22x+12y=r) to be inconsistent?
Explanation opens after your attempt
Correct Answer
B. \(r \ne 74\)
Step 1
Concept
The first two ratios are equal. For inconsistency, the constant ratio must be different so \(r \ne 74\).
Step 2
Why this answer is correct
The correct answer is B. \(r \ne 74\). The first two ratios are equal. For inconsistency, the constant ratio must be different so \(r \ne 74\).
Step 3
Exam Tip
पहले दो अनुपात बराबर हैं। असंगत होने के लिए स्थिर पद का अनुपात अलग होना चाहिए इसलिए \(r \ne 74\)।
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समीकरणों (7x+13y=67) और (21x+39y=s) के संगत और आश्रित होने के लिए (s) क्या होगा?
What should (s) be for the equations (7x+13y=67) and (21x+39y=s) to be consistent and dependent?
Explanation opens after your attempt
Step 1
Concept
To be consistent and dependent, the second equation must be (3) times the first. Hence, (s=201).
Step 2
Why this answer is correct
The correct answer is C. (201). To be consistent and dependent, the second equation must be (3) times the first. Hence, (s=201).
Step 3
Exam Tip
संगत और आश्रित होने के लिए दूसरा समीकरण पहले का (3) गुना होना चाहिए। अतः (s=201)।
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यदि (14x-7y=56) और (2x-y=t) असंगत हैं, तो (t) के लिए सही शर्त क्या है?
If (14x-7y=56) and (2x-y=t) are inconsistent, what is the correct condition for (t)?
Explanation opens after your attempt
Correct Answer
B. \(t \ne 8\)
Step 1
Concept
The first two ratios are equal. For inconsistency, (56/t) must be different so \(t \ne 8\).
Step 2
Why this answer is correct
The correct answer is B. \(t \ne 8\). The first two ratios are equal. For inconsistency, (56/t) must be different so \(t \ne 8\).
Step 3
Exam Tip
पहले दो अनुपात बराबर हैं। असंगत होने के लिए (56/t) अलग होना चाहिए इसलिए \(t \ne 8\)।
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यदि (9x+5y=47) और (27x+15y=n) के अनंत हल हैं, तो (n) कितना होगा?
If (9x+5y=47) and (27x+15y=n) have infinitely many solutions, what is (n)?
Explanation opens after your attempt
Step 1
Concept
The second equation must be (3) times the first. Therefore, (n=141).
Step 2
Why this answer is correct
The correct answer is C. (141). The second equation must be (3) times the first. Therefore, (n=141).
Step 3
Exam Tip
दूसरा समीकरण पहले का (3) गुना होना चाहिए। इसलिए (n=141) होगा।
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समीकरणों (15x+py=45) और (7x+2y=24) का अद्वितीय हल होने के लिए कौन-सी शर्त सही है?
Which condition is correct for the equations (15x+py=45) and (7x+2y=24) to have a unique solution?
Explanation opens after your attempt
Correct Answer
B. (p \ne 30/7)
Step 1
Concept
For a unique solution, \(15/7 \ne p/2\) must hold. Therefore, \(p \ne 30/7\) is the correct condition.
Step 2
Why this answer is correct
The correct answer is B. \(p \ne 30 / 7\). For a unique solution, \(15/7 \ne p/2\) must hold. Therefore, \(p \ne 30/7\) is the correct condition.
Step 3
Exam Tip
अद्वितीय हल के लिए \(15/7 \ne p/2\) होना चाहिए। इसलिए \(p \ne 30/7\) सही शर्त है।
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समीकरणों (6x+dy=54) और (18x+30y=162) के अनंत हल होने के लिए (d) का मान क्या है?
What is the value of (d) for the equations (6x+dy=54) and (18x+30y=162) to have infinitely many solutions?
Explanation opens after your attempt
Step 1
Concept
For infinitely many solutions, (6/18=d/30=54/162) must hold. Therefore, (d=10).
Step 2
Why this answer is correct
The correct answer is C. (10). For infinitely many solutions, (6/18=d/30=54/162) must hold. Therefore, (d=10).
Step 3
Exam Tip
अनंत हल के लिए (6/18=d/30=54/162) होना चाहिए। इसलिए (d=10)।
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यदि (cx+16y=64) और (21x+42y=130) का कोई हल नहीं है, तो (c) क्या होगा?
If (cx+16y=64) and (21x+42y=130) have no solution, what will (c) be?
Explanation opens after your attempt
Step 1
Concept
For no solution, (c/21=16/42) and (64/130) must be different. Therefore, (c=8).
Step 2
Why this answer is correct
The correct answer is C. (8). For no solution, (c/21=16/42) and (64/130) must be different. Therefore, (c=8).
Step 3
Exam Tip
कोई हल नहीं के लिए (c/21=16/42) और (64/130) अलग होना चाहिए। इसलिए (c=8)।
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समीकरणों (bx+14y=56) और (12x+28y=115) का कोई हल न होने के लिए (b) का मान क्या होगा?
What is the value of (b) for the equations (bx+14y=56) and (12x+28y=115) to have no solution?
Explanation opens after your attempt
Step 1
Concept
For no solution, (b/12=14/28) and (56/115) must be different. Hence, (b=6).
Step 2
Why this answer is correct
The correct answer is C. (6). For no solution, (b/12=14/28) and (56/115) must be different. Hence, (b=6).
Step 3
Exam Tip
कोई हल नहीं के लिए (b/12=14/28) और (56/115) अलग होना चाहिए। इसलिए (b=6)।
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समीकरणों (9x+ay=63) और (27x+24y=189) के अनंत हल होने के लिए (a) क्या होगा?
What will (a) be for the equations (9x+ay=63) and (27x+24y=189) to have infinitely many solutions?
Explanation opens after your attempt
Step 1
Concept
For infinitely many solutions, (9/27=a/24=63/189) must hold. This gives (a=8).
Step 2
Why this answer is correct
The correct answer is C. (8). For infinitely many solutions, (9/27=a/24=63/189) must hold. This gives (a=8).
Step 3
Exam Tip
अनंत हल के लिए (9/27=a/24=63/189) होना चाहिए। इससे (a=8) मिलता है।
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समीकरणों (10x+py=50) और (2x+7y=19) का अद्वितीय हल होने के लिए कौन-सी शर्त सही है?
Which condition is correct for the equations (10x+py=50) and (2x+7y=19) to have a unique solution?
Explanation opens after your attempt
Correct Answer
B. \(p \ne 35\)
Step 1
Concept
For a unique solution, \(10/2 \ne p/7\) must hold. Therefore, \(p \ne 35\) is the correct condition.
Step 2
Why this answer is correct
The correct answer is B. \(p \ne 35\). For a unique solution, \(10/2 \ne p/7\) must hold. Therefore, \(p \ne 35\) is the correct condition.
Step 3
Exam Tip
अद्वितीय हल के लिए \(10/2 \ne p/7\) होना चाहिए। इसलिए \(p \ne 35\) सही शर्त है।
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समीकरणों (11x+qy=44) और (22x+18y=88) के अनंत हल होने के लिए (q) का मान क्या है?
What is the value of (q) for the equations (11x+qy=44) and (22x+18y=88) to have infinitely many solutions?
Explanation opens after your attempt
Step 1
Concept
The second equation is (2) times the first so (q/18=1/2) must hold. Hence, (q=9).
Step 2
Why this answer is correct
The correct answer is C. (9). The second equation is (2) times the first so (q/18=1/2) must hold. Hence, (q=9).
Step 3
Exam Tip
दूसरा समीकरण पहले का (2) गुना है इसलिए (q/18=1/2) होना चाहिए। अतः (q=9)।
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समीकरणों (kx+12y=36) और (15x+20y=60) के अनंत हल होने के लिए (k) क्या होगा?
What will (k) be for the equations (kx+12y=36) and (15x+20y=60) to have infinitely many solutions?
Explanation opens after your attempt
Step 1
Concept
For infinitely many solutions, (k/15=12/20=36/60) must hold. Therefore, (k=9) is correct.
Step 2
Why this answer is correct
The correct answer is C. (9). For infinitely many solutions, (k/15=12/20=36/60) must hold. Therefore, (k=9) is correct.
Step 3
Exam Tip
अनंत हल के लिए (k/15=12/20=36/60) होना चाहिए। इसलिए (k=9) सही है।
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समीकरणों (px+8y=24) और (10x+20y=61) का कोई हल न होने के लिए (p) का मान क्या होगा?
What is the value of (p) for the equations (px+8y=24) and (10x+20y=61) to have no solution?
Explanation opens after your attempt
Step 1
Concept
For no solution, (p/10=8/20) and (24/61) must be different. This gives (p=4).
Step 2
Why this answer is correct
The correct answer is C. (4). For no solution, (p/10=8/20) and (24/61) must be different. This gives (p=4).
Step 3
Exam Tip
कोई हल नहीं के लिए (p/10=8/20) और (24/61) अलग होना चाहिए। इससे (p=4) मिलता है।
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समीकरणों (5x+2y=18) और (15x+ay=54) के अनंत हल होने के लिए (a) का मान क्या होगा?
What is the value of (a) for the equations (5x+2y=18) and (15x+ay=54) to have infinitely many solutions?
Explanation opens after your attempt
Step 1
Concept
For infinitely many solutions, (5/15=2/a=18/54) must hold. Therefore, (a=6) is correct.
Step 2
Why this answer is correct
The correct answer is C. (6). For infinitely many solutions, (5/15=2/a=18/54) must hold. Therefore, (a=6) is correct.
Step 3
Exam Tip
अनंत हल के लिए (5/15=2/a=18/54) होना चाहिए। इसलिए (a=6) सही है।
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समीकरणों (10x+3y=44) और (20x+ay=88) के अनंत हल होने के लिए (a) का मान क्या होगा?
What is the value of (a) for the equations (10x+3y=44) and (20x+ay=88) to have infinitely many solutions?
Explanation opens after your attempt
Step 1
Concept
For infinitely many solutions, (10/20=3/a=44/88) must hold. Therefore, (a=6) is correct.
Step 2
Why this answer is correct
The correct answer is D. (6). For infinitely many solutions, (10/20=3/a=44/88) must hold. Therefore, (a=6) is correct.
Step 3
Exam Tip
अनंत हल के लिए (10/20=3/a=44/88) होना चाहिए। इसलिए (a=6) सही है।
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यदि (lx+13y=52) और (14x+26y=109) का कोई हल नहीं है, तो (l) का मान क्या होगा?
If (lx+13y=52) and (14x+26y=109) have no solution, what will be the value of (l)?
Explanation opens after your attempt
Step 1
Concept
For no solution, (l/14=13/26) and (52/109) must be different. Hence, (l=7).
Step 2
Why this answer is correct
The correct answer is C. (7). For no solution, (l/14=13/26) and (52/109) must be different. Hence, (l=7).
Step 3
Exam Tip
कोई हल नहीं के लिए (l/14=13/26) और (52/109) अलग होना चाहिए। इसलिए (l=7)।
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समीकरणों (9x+ky=81) और (3x+8y=27) के अनंत हल होने के लिए (k) क्या होगा?
What will (k) be for the equations (9x+ky=81) and (3x+8y=27) to have infinitely many solutions?
Explanation opens after your attempt
Step 1
Concept
The first equation must be (3) times the second. Therefore, (k=24).
Step 2
Why this answer is correct
The correct answer is C. (24). The first equation must be (3) times the second. Therefore, (k=24).
Step 3
Exam Tip
पहला समीकरण दूसरे का (3) गुना होना चाहिए। इसलिए (k=24) है।
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समीकरणों (7x+5y=22) और (14x+ay=51) का कोई हल न होने के लिए (a) क्या होगा?
What will (a) be for the equations (7x+5y=22) and (14x+ay=51) to have no solution?
Explanation opens after your attempt
Step 1
Concept
For no solution, (7/14=5/a) and (22/51) must be different. This gives (a=10).
Step 2
Why this answer is correct
The correct answer is C. (10). For no solution, (7/14=5/a) and (22/51) must be different. This gives (a=10).
Step 3
Exam Tip
कोई हल नहीं के लिए (7/14=5/a) और (22/51) अलग होना चाहिए। इससे (a=10) मिलता है।
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समीकरणों (9x+4y=31) और (18x+8y=r) के असंगत होने के लिए कौन-सी शर्त सही है?
Which condition is correct for the equations (9x+4y=31) and (18x+8y=r) to be inconsistent?
Explanation opens after your attempt
Correct Answer
B. \(r \ne 62\)
Step 1
Concept
The first two ratios are equal, so the constant ratio must be different for inconsistency. Hence, \(r \ne 62\).
Step 2
Why this answer is correct
The correct answer is B. \(r \ne 62\). The first two ratios are equal, so the constant ratio must be different for inconsistency. Hence, \(r \ne 62\).
Step 3
Exam Tip
पहले दो अनुपात बराबर हैं, इसलिए असंगत होने के लिए स्थिर पद का अनुपात अलग होना चाहिए। अतः \(r \ne 62\)।
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