Concept-wise Practice

no-real-roots MCQ Questions for Class 10

no-real-roots se related questions ko ek jagah revise karein. Har question me bilingual content, answer feedback aur explanation available hai.

All Tags Search Similar

Practice Questions

171 questions tagged with no-real-roots.

Question 151/171 Hard Mathematics Quadratic Equations Roots of a Quadratic Equation Class 10 Level 32

यदि समीकरण (x-2-4x+(m+4)=0) के वास्तविक मूल नहीं हैं तो (m) के लिए कौन सी शर्त सही है?

If (x-2-4x+(m+4)=0) has no real roots, which condition on (m) is correct?

Explanation opens after your attempt
Correct Answer

A. (m>0)

Step 1

Concept

For no real roots (D<0) is required. From (16-4(m+4)<0), we get (m>0).

Step 2

Why this answer is correct

The correct answer is A. (m>0). For no real roots (D<0) is required. From (16-4(m+4)<0), we get (m>0).

Step 3

Exam Tip

वास्तविक मूल नहीं होने के लिए (D<0) चाहिए। (16-4(m+4)<0) से (m>0) मिलता है।

Open Question Page
Ask Friends
Question 152/171 Hard Mathematics Quadratic Equations Roots of a Quadratic Equation Class 10 Level 32

समीकरण \(x^2+4x+13=0\) के वास्तविक मूलों की संख्या कितनी है?

How many real roots does \(x^2+4x+13=0\) have?

Explanation opens after your attempt
Correct Answer

A. (0)

Step 1

Concept

Here (D=16-52=-36<0). Therefore the number of real roots is (0).

Step 2

Why this answer is correct

The correct answer is A. (0). Here (D=16-52=-36<0). Therefore the number of real roots is (0).

Step 3

Exam Tip

यहां (D=16-52=-36<0) है। इसलिए वास्तविक मूलों की संख्या (0) है।

Open Question Page
Ask Friends
Question 153/171 Hard Mathematics Quadratic Equations Roots of a Quadratic Equation Class 10 Level 31

यदि समीकरण (x-2-2x+(m+1)=0) के वास्तविक मूल नहीं हैं तो (m) के लिए कौन सी शर्त सही है?

If (x-2-2x+(m+1)=0) has no real roots, which condition on (m) is correct?

Explanation opens after your attempt
Correct Answer

A. (m>0)

Step 1

Concept

For no real roots (D<0) is required. From (4-4(m+1)<0), we get (m>0).

Step 2

Why this answer is correct

The correct answer is A. (m>0). For no real roots (D<0) is required. From (4-4(m+1)<0), we get (m>0).

Step 3

Exam Tip

वास्तविक मूल नहीं होने के लिए (D<0) चाहिए। (4-4(m+1)<0) से (m>0) मिलता है।

Open Question Page
Ask Friends
Question 154/171 Hard Mathematics Quadratic Equations Roots of a Quadratic Equation Class 10 Level 31

समीकरण \(x^2+2x+5=0\) के वास्तविक मूलों की संख्या कितनी है?

How many real roots does \(x^2+2x+5=0\) have?

Explanation opens after your attempt
Correct Answer

A. (0)

Step 1

Concept

Here (D=4-20=-16<0). Therefore the number of real roots is (0).

Step 2

Why this answer is correct

The correct answer is A. (0). Here (D=4-20=-16<0). Therefore the number of real roots is (0).

Step 3

Exam Tip

यहां (D=4-20=-16<0) है। इसलिए वास्तविक मूलों की संख्या (0) है।

Open Question Page
Ask Friends
Question 155/171 Medium Mathematics Quadratic Equations Roots of a Quadratic Equation Class 10 Level 33

समीकरण \(x^2-6x+20=0\) के वास्तविक मूलों के बारे में सही कथन कौन सा है?

Which statement is correct about the real roots of \(x^2-6x+20=0\)?

Explanation opens after your attempt
Correct Answer

C. कोई वास्तविक मूल नहीं हैIt has no real roots

Step 1

Concept

Here (D=(-6)2-4(1)(20)=-44<0). Therefore there are no real roots.

Step 2

Why this answer is correct

The correct answer is C. कोई वास्तविक मूल नहीं है / It has no real roots. Here (D=(-6)2-4(1)(20)=-44<0). Therefore there are no real roots.

Step 3

Exam Tip

यहां (D=(-6)2-4(1)(20)=-44<0) है। इसलिए कोई वास्तविक मूल नहीं है।

Open Question Page
Ask Friends
Question 156/171 Medium Mathematics Quadratic Equations Roots of a Quadratic Equation Class 10 Level 32

समीकरण \(x^2-4x+13=0\) के वास्तविक मूलों के बारे में सही कथन कौन सा है?

Which statement is correct about the real roots of \(x^2-4x+13=0\)?

Explanation opens after your attempt
Correct Answer

C. कोई वास्तविक मूल नहीं हैIt has no real roots

Step 1

Concept

Here (D=(-4)2-4(1)(13)=-36<0). Therefore there are no real roots.

Step 2

Why this answer is correct

The correct answer is C. कोई वास्तविक मूल नहीं है / It has no real roots. Here (D=(-4)2-4(1)(13)=-36<0). Therefore there are no real roots.

Step 3

Exam Tip

यहां (D=(-4)2-4(1)(13)=-36<0) है। इसलिए कोई वास्तविक मूल नहीं है।

Open Question Page
Ask Friends
Question 157/171 Medium Mathematics Quadratic Equations Roots of a Quadratic Equation Class 10 Level 31

यदि (D<0) है तो किसी द्विघात समीकरण के वास्तविक मूलों की संख्या कितनी होगी?

If (D<0), how many real roots will a quadratic equation have?

Explanation opens after your attempt
Correct Answer

A. (0)

Step 1

Concept

When (D<0), there are no real roots. Therefore the number of real roots is (0).

Step 2

Why this answer is correct

The correct answer is A. (0). When (D<0), there are no real roots. Therefore the number of real roots is (0).

Step 3

Exam Tip

(D<0) होने पर वास्तविक मूल नहीं होते। इसलिए वास्तविक मूलों की संख्या (0) होगी।

Open Question Page
Ask Friends
Question 158/171 Medium Mathematics Quadratic Equations Roots of a Quadratic Equation Class 10 Level 31

समीकरण \(x^2-2x+10=0\) के वास्तविक मूलों के बारे में सही कथन कौन सा है?

Which statement is correct about the real roots of \(x^2-2x+10=0\)?

Explanation opens after your attempt
Correct Answer

C. कोई वास्तविक मूल नहीं हैIt has no real roots

Step 1

Concept

Here (D=(-2)2-4(1)(10)=-36<0). Therefore there are no real roots.

Step 2

Why this answer is correct

The correct answer is C. कोई वास्तविक मूल नहीं है / It has no real roots. Here (D=(-2)2-4(1)(10)=-36<0). Therefore there are no real roots.

Step 3

Exam Tip

यहां (D=(-2)2-4(1)(10)=-36<0) है। इसलिए कोई वास्तविक मूल नहीं है।

Open Question Page
Ask Friends
Question 159/171 Easy Mathematics Quadratic Equations Roots of a Quadratic Equation Class 10 Level 33

समीकरण \(x^2+36=0\) के वास्तविक मूलों की संख्या कितनी है?

How many real roots does \(x^2+36=0\) have?

Explanation opens after your attempt
Correct Answer

C. (0)

Step 1

Concept

For a real number, \(x^2\ge0\). Therefore \(x^2+36=0\) has no real root.

Step 2

Why this answer is correct

The correct answer is C. (0). For a real number, \(x^2\ge0\). Therefore \(x^2+36=0\) has no real root.

Step 3

Exam Tip

वास्तविक संख्या के लिए \(x^2\ge0\) होता है। इसलिए \(x^2+36=0\) का कोई वास्तविक मूल नहीं है।

Open Question Page
Ask Friends
Question 160/171 Easy Mathematics Quadratic Equations Roots of a Quadratic Equation Class 10 Level 33

समीकरण \(x^2+25=0\) के वास्तविक मूलों के बारे में सही कथन कौन सा है?

Which statement is correct about the real roots of \(x^2+25=0\)?

Explanation opens after your attempt
Correct Answer

C. कोई वास्तविक मूल नहीं हैIt has no real roots

Step 1

Concept

For real (x), \(x^2\ge0\). Therefore \(x^2+25=0\) has no real root.

Step 2

Why this answer is correct

The correct answer is C. कोई वास्तविक मूल नहीं है / It has no real roots. For real (x), \(x^2\ge0\). Therefore \(x^2+25=0\) has no real root.

Step 3

Exam Tip

वास्तविक (x) के लिए \(x^2\ge0\) होता है। इसलिए \(x^2+25=0\) का कोई वास्तविक मूल नहीं है।

Open Question Page
Ask Friends
Question 161/171 Easy Mathematics Quadratic Equations Roots of a Quadratic Equation Class 10 Level 32

समीकरण \(x^2+16=0\) के वास्तविक मूलों की संख्या कितनी है?

How many real roots does \(x^2+16=0\) have?

Explanation opens after your attempt
Correct Answer

C. (0)

Step 1

Concept

For a real number, \(x^2\ge0\). Therefore \(x^2+16=0\) has no real root.

Step 2

Why this answer is correct

The correct answer is C. (0). For a real number, \(x^2\ge0\). Therefore \(x^2+16=0\) has no real root.

Step 3

Exam Tip

वास्तविक संख्या के लिए \(x^2\ge0\) होता है। इसलिए \(x^2+16=0\) का कोई वास्तविक मूल नहीं है।

Open Question Page
Ask Friends
Question 162/171 Easy Mathematics Quadratic Equations Roots of a Quadratic Equation Class 10 Level 32

समीकरण \(x^2+9=0\) के वास्तविक मूलों के बारे में सही कथन कौन सा है?

Which statement is correct about the real roots of \(x^2+9=0\)?

Explanation opens after your attempt
Correct Answer

C. कोई वास्तविक मूल नहीं हैIt has no real roots

Step 1

Concept

For any real (x), \(x^2\ge0\). So \(x^2+9=0\) is not satisfied by any real number.

Step 2

Why this answer is correct

The correct answer is C. कोई वास्तविक मूल नहीं है / It has no real roots. For any real (x), \(x^2\ge0\). So \(x^2+9=0\) is not satisfied by any real number.

Step 3

Exam Tip

किसी वास्तविक (x) के लिए \(x^2\ge0\) होता है। इसलिए \(x^2+9=0\) वास्तविक संख्या से संतुष्ट नहीं होता।

Open Question Page
Ask Friends
Question 163/171 Easy Mathematics Quadratic Equations Roots of a Quadratic Equation Class 10 Level 32

समीकरण \(x^2-2x+5=0\) का डिस्क्रिमिनेंट (D) क्या है?

What is the discriminant (D) of \(x^2-2x+5=0\)?

Explanation opens after your attempt
Correct Answer

C. (-16)

Step 1

Concept

Here \(D=b^2-4ac=4-20=-16\). Therefore there will be no real roots.

Step 2

Why this answer is correct

The correct answer is C. (-16). Here \(D=b^2-4ac=4-20=-16\). Therefore there will be no real roots.

Step 3

Exam Tip

यहां \(D=b^2-4ac=4-20=-16\) है। इसलिए वास्तविक मूल नहीं होंगे।

Open Question Page
Ask Friends
Question 164/171 Easy Mathematics Quadratic Equations Roots of a Quadratic Equation Class 10 Level 31

समीकरण \(x^2+4=0\) के वास्तविक मूलों की संख्या कितनी है?

How many real roots does \(x^2+4=0\) have?

Explanation opens after your attempt
Correct Answer

C. (0)

Step 1

Concept

Because \(x^2\ge 0\) so \(x^2+4\) never becomes (0). Therefore it has no real root.

Step 2

Why this answer is correct

The correct answer is C. (0). Because \(x^2\ge 0\) so \(x^2+4\) never becomes (0). Therefore it has no real root.

Step 3

Exam Tip

क्योंकि \(x^2\ge 0\) होता है इसलिए \(x^2+4\) कभी (0) नहीं बनता। इसलिए कोई वास्तविक मूल नहीं है।

Open Question Page
Ask Friends
Question 165/171 Easy Mathematics Quadratic Equations Roots of a Quadratic Equation Class 10 Level 31

समीकरण \(x^2+1=0\) के वास्तविक मूलों के बारे में सही कथन कौन सा है?

Which statement is correct about the real roots of \(x^2+1=0\)?

Explanation opens after your attempt
Correct Answer

C. कोई वास्तविक मूल नहीं हैIt has no real roots

Step 1

Concept

\(x^2\) is never negative so \(x^2+1=0\) is not satisfied by any real number. Sign checking helps solve such questions quickly.

Step 2

Why this answer is correct

The correct answer is C. कोई वास्तविक मूल नहीं है / It has no real roots. \(x^2\) is never negative so \(x^2+1=0\) is not satisfied by any real number. Sign checking helps solve such questions quickly.

Step 3

Exam Tip

\(x^2\) कभी ऋणात्मक नहीं होता इसलिए \(x^2+1=0\) वास्तविक संख्या से संतुष्ट नहीं होता। संकेत से ऐसे प्रश्न जल्दी हल होते हैं।

Open Question Page
Ask Friends
Question 166/171 Expert Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 30

समीकरण \(x^2+14x+k=0\) के कोई वास्तविक मूल नहीं हैं। (k) पर सही शर्त क्या है?

The equation \(x^2+14x+k=0\) has no real roots. What is the correct condition on (k)?

Explanation opens after your attempt
Correct Answer

A. (k>49)

Step 1

Concept

For no real roots, (D<0) is needed. Here (196-4k<0), so (k>49).

Step 2

Why this answer is correct

The correct answer is A. (k>49). For no real roots, (D<0) is needed. Here (196-4k<0), so (k>49).

Step 3

Exam Tip

कोई वास्तविक मूल न होने के लिए (D<0) चाहिए। यहाँ (196-4k<0), इसलिए (k>49)।

Open Question Page
Ask Friends
Question 167/171 Expert Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 29

समीकरण \(x^2+12x+k=0\) के कोई वास्तविक मूल नहीं हैं। (k) पर सही शर्त क्या है?

The equation \(x^2+12x+k=0\) has no real roots. What is the correct condition on (k)?

Explanation opens after your attempt
Correct Answer

A. (k>36)

Step 1

Concept

For no real roots, (D<0) is needed. Here (144-4k<0), so (k>36).

Step 2

Why this answer is correct

The correct answer is A. (k>36). For no real roots, (D<0) is needed. Here (144-4k<0), so (k>36).

Step 3

Exam Tip

कोई वास्तविक मूल न होने के लिए (D<0) चाहिए। यहाँ (144-4k<0), इसलिए (k>36)।

Open Question Page
Ask Friends
Question 168/171 Expert Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 28

समीकरण \(x^2+10x+k=0\) के कोई वास्तविक मूल नहीं हैं। (k) पर सही शर्त क्या है?

The equation \(x^2+10x+k=0\) has no real roots. What is the correct condition on (k)?

Explanation opens after your attempt
Correct Answer

A. (k>25)

Step 1

Concept

For no real roots, (D<0) is needed. Here (100-4k<0), so (k>25).

Step 2

Why this answer is correct

The correct answer is A. (k>25). For no real roots, (D<0) is needed. Here (100-4k<0), so (k>25).

Step 3

Exam Tip

कोई वास्तविक मूल न होने के लिए (D<0) चाहिए। यहाँ (100-4k<0), इसलिए (k>25)।

Open Question Page
Ask Friends
Question 169/171 Hard Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 30

समीकरण \(x^2+8x+k=0\) के कोई वास्तविक मूल नहीं हैं। (k) पर सही शर्त क्या है?

The equation \(x^2+8x+k=0\) has no real roots. What is the correct condition on (k)?

Explanation opens after your attempt
Correct Answer

A. (k>16)

Step 1

Concept

For no real roots, (D<0) is needed. Here (64-4k<0), so (k>16).

Step 2

Why this answer is correct

The correct answer is A. (k>16). For no real roots, (D<0) is needed. Here (64-4k<0), so (k>16).

Step 3

Exam Tip

कोई वास्तविक मूल न होने के लिए (D<0) चाहिए। यहाँ (64-4k<0), इसलिए (k>16)।

Open Question Page
Ask Friends
Question 170/171 Hard Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 29

समीकरण \(x^2+4x+k=0\) के कोई वास्तविक मूल नहीं हैं। (k) पर सही शर्त क्या है?

The equation \(x^2+4x+k=0\) has no real roots. What is the correct condition on (k)?

Explanation opens after your attempt
Correct Answer

A. (k>4)

Step 1

Concept

For no real roots, (D<0) is needed. Here (16-4k<0), so (k>4).

Step 2

Why this answer is correct

The correct answer is A. (k>4). For no real roots, (D<0) is needed. Here (16-4k<0), so (k>4).

Step 3

Exam Tip

कोई वास्तविक मूल न होने के लिए (D<0) चाहिए। यहाँ (16-4k<0), इसलिए (k>4)।

Open Question Page
Ask Friends
Question 171/171 Easy Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 30

यदि किसी द्विघात समीकरण का विवेचक (D<0) है तो वास्तविक मूलों के बारे में क्या सही है?

If the discriminant (D<0), what is true about real roots?

Explanation opens after your attempt
Correct Answer

C. कोई वास्तविक मूल नहीं होताIt has no real roots

Step 1

Concept

When (D<0), there are no real roots. A negative discriminant gives no roots on the real number line.

Step 2

Why this answer is correct

The correct answer is C. कोई वास्तविक मूल नहीं होता / It has no real roots. When (D<0), there are no real roots. A negative discriminant gives no roots on the real number line.

Step 3

Exam Tip

(D<0) होने पर वास्तविक मूल नहीं होते। विवेचक नकारात्मक हो तो वास्तविक संख्या रेखा पर मूल नहीं मिलते।

Open Question Page
Ask Friends

no-real-roots Revision Links

All MCQ Tags

Browse concept directory

All Subjects

Subject-wise practice

Search no-real-roots

More keyword results