How many real roots does the equation \(x^2+4x+13=0\) have?
Answer and explanation
Correct answer: 0
Here, \(a=1\), \(b=4\), and \(c=13\). The discriminant is \(D=b^2-4ac=4^2-4(1)(13)=16-52=-36<0\). Therefore, the quadratic equation has no real roots, so the answer is 0. Exam tip: \(D<0\) means zero real roots; one or two real roots occur only when \(D=0\) or \(D>0\), respectively.
Frequently asked questions
What is the correct answer to this question?
0
Why is this the correct answer?
Here, \(a=1\), \(b=4\), and \(c=13\). The discriminant is \(D=b^2-4ac=4^2-4(1)(13)=16-52=-36<0\). Therefore, the quadratic equation has no real roots, so the answer is 0. Exam tip: \(D<0\) means zero real roots; one or two real roots occur only when \(D=0\) or \(D>0\), respectively.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Quadratic Equations. Topic: Roots of a Quadratic Equation.
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