संख्या 524880 का अभाज्य गुणनखंडन कौन सा है?
Which is the prime factorisation of 524880?
#prime-factorisation
#large-number
#expert
A \(2^4\times3^8\times5\)
B \(2^5\times3^7\times5\)
C \(2^4\times3^7\times5^2\)
D \(104976\times5\)
Explanation opens after your attempt
Correct Answer
A. \(2^4\times3^8\times5\)
Step 1
Concept
\(524880=104976\times5\) लिखें। / Write \(524880=104976\times5\).
Step 2
Why this answer is correct
\(104976=16\times6561=2^4\times3^8\)। / \(104976=16\times6561=2^4\times3^8\).
Step 3
Exam Tip
इसलिए \(524880=2^4\times3^8\times5\) है। / Therefore, \(524880=2^4\times3^8\times5\).
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संख्या 1000188 का अभाज्य गुणनखंडन क्या है?
What is the prime factorisation of 1000188?
#prime-factorisation
#large-number
#expert
A \(2^2\times3^6\times7^3\)
B \(2\times3^6\times7^3\)
C \(2^2\times3^5\times7^4\)
D \(4\times729\times343\)
Explanation opens after your attempt
Correct Answer
A. \(2^2\times3^6\times7^3\)
Step 1
Concept
\(1000188=4\times250047\) लिखें। / Write \(1000188=4\times250047\).
Step 2
Why this answer is correct
\(4=2^2\) और \(250047=3^6\times7^3\), इसलिए अभाज्य रूप \(2^2\times3^6\times7^3\) है। / \(4=2^2\) and \(250047=3^6\times7^3\), so the prime form is \(2^2\times3^6\times7^3\).
Step 3
Exam Tip
729 और 343 संयुक्त घातों के रूप में समझें, अंतिम उत्तर में अभाज्य आधार रखें। / Treat 729 and 343 as powers of prime bases and keep prime bases in the final answer.
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संख्या 443520 का सही अभाज्य गुणनखंडन कौन सा है?
Which is the correct prime factorisation of 443520?
#prime-factorisation
#large-number
#expert
A \(2^7\times3^2\times5\times7\times11\)
B \(2^6\times3^3\times5\times7\times11\)
C \(2^7\times3^2\times5^2\times7\)
D \(40320\times11\)
Explanation opens after your attempt
Correct Answer
A. \(2^7\times3^2\times5\times7\times11\)
Step 1
Concept
\(443520=40320\times11\) लिखें। / Write \(443520=40320\times11\).
Step 2
Why this answer is correct
\(40320=2^7\times3^2\times5\times7\), इसलिए पूरा अभाज्य रूप \(2^7\times3^2\times5\times7\times11\) है। / Since \(40320=2^7\times3^2\times5\times7\), the complete prime form is \(2^7\times3^2\times5\times7\times11\).
Step 3
Exam Tip
40320 संयुक्त है, इसलिए अंतिम रूप में नहीं रहना चाहिए। / 40320 is composite, so it should not remain in the final form.
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संख्या 262440 का अभाज्य गुणनखंडन कौन सा है?
Which is the prime factorisation of 262440?
#prime-factorisation
#large-number
#expert
A \(2^3\times3^8\times5\)
B \(2^4\times3^7\times5\)
C \(2^3\times3^7\times5^2\)
D \(52488\times5\)
Explanation opens after your attempt
Correct Answer
A. \(2^3\times3^8\times5\)
Step 1
Concept
\(262440=52488\times5\) लिखें। / Write \(262440=52488\times5\).
Step 2
Why this answer is correct
\(52488=8\times6561=2^3\times3^8\)। / \(52488=8\times6561=2^3\times3^8\).
Step 3
Exam Tip
इसलिए \(262440=2^3\times3^8\times5\) है। / Therefore, \(262440=2^3\times3^8\times5\).
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संख्या 500094 का अभाज्य गुणनखंडन क्या है?
What is the prime factorisation of 500094?
#prime-factorisation
#large-number
#expert
A \(2\times3^3\times7^3\times13\)
B \(2^2\times3^2\times7^3\times13\)
C \(2\times3^3\times7^2\times13^2\)
D \(42^3\times13\)
Explanation opens after your attempt
Correct Answer
A. \(2\times3^3\times7^3\times13\)
Step 1
Concept
\(500094=2\times250047\) लिखें। / Write \(500094=2\times250047\).
Step 2
Why this answer is correct
\(250047=3^3\times7^3\times13\), इसलिए पूरा रूप \(2\times3^3\times7^3\times13\) है। / \(250047=3^3\times7^3\times13\), so the full form is \(2\times3^3\times7^3\times13\).
Step 3
Exam Tip
अंतिम अभाज्य रूप में संयुक्त आधार नहीं रहने चाहिए। / Composite bases should not remain in final prime form.
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संख्या 221760 का सही अभाज्य गुणनखंडन कौन सा है?
Which is the correct prime factorisation of 221760?
#prime-factorisation
#large-number
#expert
A \(2^6\times3^2\times5\times7\times11\)
B \(2^5\times3^3\times5\times7\times11\)
C \(2^6\times3^2\times5^2\times7\)
D \(20160\times11\)
Explanation opens after your attempt
Correct Answer
A. \(2^6\times3^2\times5\times7\times11\)
Step 1
Concept
\(221760=20160\times11\) लिखें। / Write \(221760=20160\times11\).
Step 2
Why this answer is correct
\(20160=2^6\times3^2\times5\times7\), इसलिए पूरा अभाज्य रूप \(2^6\times3^2\times5\times7\times11\) है। / Since \(20160=2^6\times3^2\times5\times7\), the complete prime form is \(2^6\times3^2\times5\times7\times11\).
Step 3
Exam Tip
20160 संयुक्त है, इसलिए उसे अंतिम उत्तर में न रखें। / 20160 is composite, so do not keep it in the final answer.
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संख्या 131220 का अभाज्य गुणनखंडन कौन सा है?
Which is the prime factorisation of 131220?
#prime-factorisation
#large-number
#expert
A \(2^2\times3^8\times5\)
B \(2^3\times3^7\times5\)
C \(2^2\times3^7\times5^2\)
D \(26244\times5\)
Explanation opens after your attempt
Correct Answer
A. \(2^2\times3^8\times5\)
Step 1
Concept
\(131220=26244\times5\) लिखें। / Write \(131220=26244\times5\).
Step 2
Why this answer is correct
\(26244=4\times6561=2^2\times3^8\)। / \(26244=4\times6561=2^2\times3^8\).
Step 3
Exam Tip
इसलिए \(131220=2^2\times3^8\times5\) है। / Therefore, \(131220=2^2\times3^8\times5\).
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संख्या 110880 का अभाज्य गुणनखंडन कौन सा है?
Which is the prime factorisation of 110880?
#prime-factorisation
#large-number
#expert
A \(2^5\times3^2\times5\times7\times11\)
B \(2^4\times3^3\times5\times7\times11\)
C \(2^5\times3^2\times5^2\times7\)
D \(10080\times11\)
Explanation opens after your attempt
Correct Answer
A. \(2^5\times3^2\times5\times7\times11\)
Step 1
Concept
\(110880=10080\times11\) लिखें। / Write \(110880=10080\times11\).
Step 2
Why this answer is correct
\(10080=2^5\times3^2\times5\times7\), इसलिए पूरा रूप \(2^5\times3^2\times5\times7\times11\) है। / Since \(10080=2^5\times3^2\times5\times7\), the full form is \(2^5\times3^2\times5\times7\times11\).
Step 3
Exam Tip
अंतिम उत्तर में 10080 जैसे संयुक्त गुणनखंड न छोड़ें। / Do not leave a composite factor such as 10080 in the final answer.
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संख्या 20412 का अभाज्य गुणनखंडन कौन सा है?
Which is the prime factorisation of 20412?
#prime-factorisation
#large-number
#hard
A \(2^2\times3^6\times7\)
B \(2^3\times3^5\times7\)
C \(2^2\times3^5\times7^2\)
D \(2916\times7\)
Explanation opens after your attempt
Correct Answer
A. \(2^2\times3^6\times7\)
Step 1
Concept
\(20412=2916\times7\) लिखें। / Write \(20412=2916\times7\).
Step 2
Why this answer is correct
\(2916=4\times729=2^2\times3^6\)। / \(2916=4\times729=2^2\times3^6\).
Step 3
Exam Tip
इसलिए \(20412=2^2\times3^6\times7\)। / Therefore, \(20412=2^2\times3^6\times7\).
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संख्या 83160 का अभाज्य गुणनखंडन कौन सा है?
Which is the prime factorisation of 83160?
#prime-factorisation
#large-number
#hard
A \(2^3\times3^3\times5\times7\times11\)
B \(2^4\times3^2\times5\times7\times11\)
C \(2^3\times3^2\times5^2\times7\)
D \(7560\times11\)
Explanation opens after your attempt
Correct Answer
A. \(2^3\times3^3\times5\times7\times11\)
Step 1
Concept
\(83160=7560\times11\) लिखें। / Write \(83160=7560\times11\).
Step 2
Why this answer is correct
\(7560=2^3\times3^3\times5\times7\), इसलिए पूरा गुणनखंडन \(2^3\times3^3\times5\times7\times11\) है। / Since \(7560=2^3\times3^3\times5\times7\), the full factorisation is \(2^3\times3^3\times5\times7\times11\).
Step 3
Exam Tip
अंतिम उत्तर में 7560 जैसा संयुक्त गुणनखंड न छोड़ें। / Do not leave a composite factor like 7560 in the final answer.
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संख्या 14700 का अभाज्य गुणनखंडन कौन सा है?
Which is the prime factorisation of 14700?
#prime-factorisation
#large-number
#hard
A \(2^2\times3\times5^2\times7^2\)
B \(2^2\times3^2\times5\times7^2\)
C \(2^3\times3\times5^2\times7\)
D \(147\times100\)
Explanation opens after your attempt
Correct Answer
A. \(2^2\times3\times5^2\times7^2\)
Step 1
Concept
\(14700=147\times100\) लिखें। / Write \(14700=147\times100\).
Step 2
Why this answer is correct
\(147=3\times7^2\) और \(100=2^2\times5^2\), इसलिए \(14700=2^2\times3\times5^2\times7^2\)। / \(147=3\times7^2\) and \(100=2^2\times5^2\), so \(14700=2^2\times3\times5^2\times7^2\).
Step 3
Exam Tip
147 और 100 संयुक्त हैं, इसलिए उन्हें अंतिम रूप में न रखें। / 147 and 100 are composite, so do not keep them in the final form.
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संख्या 55440 का अभाज्य गुणनखंडन कौन सा है?
Which is the prime factorisation of 55440?
#prime-factorisation
#large-number
#hard
A \(2^4\times3^2\times5\times7\times11\)
B \(2^3\times3^3\times5\times7\times11\)
C \(2^4\times3^2\times5^2\times7\)
D \(5040\times11\)
Explanation opens after your attempt
Correct Answer
A. \(2^4\times3^2\times5\times7\times11\)
Step 1
Concept
\(55440=5040\times11\) लिखें। / Write \(55440=5040\times11\).
Step 2
Why this answer is correct
\(5040=2^4\times3^2\times5\times7\), इसलिए पूरा गुणनखंडन \(2^4\times3^2\times5\times7\times11\) है। / Since \(5040=2^4\times3^2\times5\times7\), the complete factorisation is \(2^4\times3^2\times5\times7\times11\).
Step 3
Exam Tip
अंतिम उत्तर में 5040 जैसे संयुक्त गुणनखंड को न छोड़ें। / Do not leave a composite factor like 5040 in the final answer.
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संख्या 27720 का अभाज्य गुणनखंडन कौन सा है?
Which is the prime factorisation of 27720?
#prime-factorisation
#large-number
#hard
A \(2^3\times3^2\times5\times7\times11\)
B \(2^2\times3^3\times5\times7\times11\)
C \(2^3\times3^2\times5^2\times7\)
D \(2520\times11\)
Explanation opens after your attempt
Correct Answer
A. \(2^3\times3^2\times5\times7\times11\)
Step 1
Concept
\(27720=2520\times11\) लिखें। / Write \(27720=2520\times11\).
Step 2
Why this answer is correct
\(2520=2^3\times3^2\times5\times7\), इसलिए पूरा गुणनखंडन \(2^3\times3^2\times5\times7\times11\) है। / Since \(2520=2^3\times3^2\times5\times7\), the full factorisation is \(2^3\times3^2\times5\times7\times11\).
Step 3
Exam Tip
अंतिम उत्तर में 2520 जैसा संयुक्त गुणनखंड नहीं छोड़ना चाहिए। / Do not leave a composite factor like 2520 in the final answer.
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संख्या 2772 का अभाज्य गुणनखंडन कौन सा है?
Which is the prime factorisation of 2772?
#prime-factorisation
#large-number
#medium
A \(2^2\times3^2\times7\times11\)
B \(2^3\times3\times7\times11\)
C \(2^2\times3\times7^2\times11\)
D \(252\times11\)
Explanation opens after your attempt
Correct Answer
A. \(2^2\times3^2\times7\times11\)
Step 1
Concept
\(2772=252\times11\) लिखें। / Write \(2772=252\times11\).
Step 2
Why this answer is correct
\(252=2^2\times3^2\times7\), इसलिए \(2772=2^2\times3^2\times7\times11\)। / \(252=2^2\times3^2\times7\), so \(2772=2^2\times3^2\times7\times11\).
Step 3
Exam Tip
252 संयुक्त है, इसलिए अंतिम रूप में नहीं रखना चाहिए। / 252 is composite, so it should not remain in the final form.
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संख्या 1890 का अभाज्य गुणनखंडन क्या है?
What is the prime factorisation of 1890?
#prime-factorisation
#large-number
#medium
A \(2\times3^3\times5\times7\)
B \(2^2\times3^2\times5\times7\)
C \(2\times3^2\times5\times7\)
D \(189\times10\)
Explanation opens after your attempt
Correct Answer
A. \(2\times3^3\times5\times7\)
Step 1
Concept
\(1890=189\times10\) लिखें। / Write \(1890=189\times10\).
Step 2
Why this answer is correct
\(189=3^3\times7\) और \(10=2\times5\)। / \(189=3^3\times7\) and \(10=2\times5\).
Step 3
Exam Tip
इसलिए \(1890=2\times3^3\times5\times7\)। / Therefore, \(1890=2\times3^3\times5\times7\).
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संख्या 924 का अभाज्य गुणनखंडन कौन सा है?
Which is the prime factorisation of 924?
#prime-factorisation
#large-number
#medium
A \(2^2\times3\times7\times11\)
B \(2\times3^2\times7\times11\)
C \(2^2\times3\times7^2\)
D \(84\times11\)
Explanation opens after your attempt
Correct Answer
A. \(2^2\times3\times7\times11\)
Step 1
Concept
\(924=84\times11\) लिखें। / Write \(924=84\times11\).
Step 2
Why this answer is correct
\(84=2^2\times3\times7\), इसलिए \(924=2^2\times3\times7\times11\)। / \(84=2^2\times3\times7\), so \(924=2^2\times3\times7\times11\).
Step 3
Exam Tip
84 संयुक्त है, इसलिए उसे अंतिम अभाज्य रूप में न छोड़ें। / 84 is composite, so do not leave it in the final prime form.
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संख्या 1848 का अभाज्य गुणनखंडन कौन सा है?
Which is the prime factorisation of 1848?
#prime-factorisation
#large-number
#medium
A \(2^3\times3\times7\times11\)
B \(2^2\times3^2\times7\times11\)
C \(2^3\times3^2\times7\)
D \(168\times11\)
Explanation opens after your attempt
Correct Answer
A. \(2^3\times3\times7\times11\)
Step 1
Concept
\(1848=168\times11\) लिखें। / Write \(1848=168\times11\).
Step 2
Why this answer is correct
\(168=2^3\times3\times7\), इसलिए \(1848=2^3\times3\times7\times11\)। / \(168=2^3\times3\times7\), so \(1848=2^3\times3\times7\times11\).
Step 3
Exam Tip
168 संयुक्त है, इसलिए उसे अंतिम रूप में न रखें। / 168 is composite, so do not keep it in the final form.
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संख्या 1260 का अभाज्य गुणनखंडन क्या है?
What is the prime factorisation of 1260?
#prime-factorisation
#large-number
#medium
A \(2^2\times3^2\times5\times7\)
B \(2\times3^3\times5\times7\)
C \(2^2\times3\times5^2\times7\)
D \(126\times10\)
Explanation opens after your attempt
Correct Answer
A. \(2^2\times3^2\times5\times7\)
Step 1
Concept
\(1260=126\times10\) लिखें। / Write \(1260=126\times10\).
Step 2
Why this answer is correct
\(126=2\times3^2\times7\) और \(10=2\times5\)। / \(126=2\times3^2\times7\) and \(10=2\times5\).
Step 3
Exam Tip
इसलिए \(1260=2^2\times3^2\times5\times7\)। / Therefore, \(1260=2^2\times3^2\times5\times7\).
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संख्या 208 का अभाज्य गुणनखंडन क्या है?
What is the prime factorisation of 208?
#prime-factorisation
#large-number
#easy
A \(2^4\times13\)
B \(2^3\times13\)
C \(2^4\times11\)
D \(16\times13\)
Explanation opens after your attempt
Correct Answer
A. \(2^4\times13\)
Step 1
Concept
\(208=16\times13\) लिखें। / Write \(208=16\times13\).
Step 2
Why this answer is correct
\(16=2^4\) और 13 अभाज्य है, इसलिए \(208=2^4\times13\)। / \(16=2^4\) and 13 is prime, so \(208=2^4\times13\).
Step 3
Exam Tip
16 संयुक्त है, इसलिए अंतिम रूप में \(2^4\) लिखें। / Since 16 is composite, write it as \(2^4\) in the final form.
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संख्या 182 का सही अभाज्य गुणनखंडन क्या है?
What is the correct prime factorisation of 182?
#prime-factorisation
#large-number
#easy
A \(2\times7\times13\)
B \(2^2\times7\times13\)
C \(7^2\times13\)
D \(14\times13\)
Explanation opens after your attempt
Correct Answer
A. \(2\times7\times13\)
Step 1
Concept
\(182=2\times91\) लिखें। / Write \(182=2\times91\).
Step 2
Why this answer is correct
\(91=7\times13\), इसलिए \(182=2\times7\times13\)। / \(91=7\times13\), so \(182=2\times7\times13\).
Step 3
Exam Tip
14 संयुक्त है, इसलिए \(14\times13\) अंतिम अभाज्य गुणनखंडन नहीं है। / 14 is composite, so \(14\times13\) is not the final prime factorisation.
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संख्या 176 का अभाज्य गुणनखंडन क्या है?
What is the prime factorisation of 176?
#prime-factorisation
#large-number
#easy
A \(2^4\times11\)
B \(2^3\times11\)
C \(2^4\times7\)
D \(16\times11\)
Explanation opens after your attempt
Correct Answer
A. \(2^4\times11\)
Step 1
Concept
\(176=16\times11\) लिखें। / Write \(176=16\times11\).
Step 2
Why this answer is correct
\(16=2^4\) और 11 अभाज्य है, इसलिए \(176=2^4\times11\)। / \(16=2^4\) and 11 is prime, so \(176=2^4\times11\).
Step 3
Exam Tip
16 संयुक्त है, इसलिए अंतिम रूप में \(2^4\) लिखें। / Since 16 is composite, write it as \(2^4\) in the final form.
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संख्या 154 का सही अभाज्य गुणनखंडन क्या है?
What is the correct prime factorisation of 154?
#prime-factorisation
#large-number
#easy
A \(2\times7\times11\)
B \(2^2\times7\times11\)
C \(7^2\times11\)
D \(14\times11\)
Explanation opens after your attempt
Correct Answer
A. \(2\times7\times11\)
Step 1
Concept
\(154=2\times77\) लिखें। / Write \(154=2\times77\).
Step 2
Why this answer is correct
\(77=7\times11\), इसलिए \(154=2\times7\times11\)। / \(77=7\times11\), so \(154=2\times7\times11\).
Step 3
Exam Tip
14 संयुक्त है, इसलिए \(14\times11\) अंतिम अभाज्य गुणनखंडन नहीं है। / 14 is composite, so \(14\times11\) is not the final prime factorisation.
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संख्या 132 का अभाज्य गुणनखंडन क्या है?
What is the prime factorisation of 132?
#prime-factorisation
#large-number
#easy
A \(2^2\times3\times11\)
B \(2\times3^2\times11\)
C \(2^2\times3^2\)
D \(12\times11\)
Explanation opens after your attempt
Correct Answer
A. \(2^2\times3\times11\)
Step 1
Concept
\(132=12\times11\) लिखें। / Write \(132=12\times11\).
Step 2
Why this answer is correct
\(12=2^2\times3\) और 11 अभाज्य है, इसलिए \(132=2^2\times3\times11\)। / \(12=2^2\times3\) and 11 is prime, so \(132=2^2\times3\times11\).
Step 3
Exam Tip
12 को अंतिम रूप में न छोड़ें क्योंकि वह संयुक्त है। / Do not leave 12 in the final form because it is composite.
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किसी संख्या को 94 से भाग देने पर शेषफल 93 है। उस संख्या में 283 जोड़ने पर 94 से भाग देने पर शेषफल क्या होगा?
A number leaves remainder 93 when divided by 94. What is the remainder when 283 is added to the number and the result is divided by 94?
#euclids-division-lemma
#remainder-addition
#large-number
A 0
B 93
C 94
D 1
Explanation opens after your attempt
Step 1
Concept
मूल शेषफल 93 है। / The original remainder is 93.
Step 2
Why this answer is correct
283 को 94 से भाग देने पर शेषफल 1 है। / 283 leaves remainder 1 when divided by 94.
Step 3
Exam Tip
(93+1=94), इसलिए अंतिम शेषफल 0 होगा। / (93+1=94), so the final remainder is 0.
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यदि 9876 को 412 से भाग दिया जाए, तो शेषफल क्या होगा?
If 9876 is divided by 412, what is the remainder?
#euclids-division-lemma
#remainder
#large-number
A 0
B 12
C 24
D 36
Explanation opens after your attempt
Step 1
Concept
\(412\times23=9476\) और \(412\times24=9888\) है। / \(412\times23=9476\) and \(412\times24=9888\).
Step 2
Why this answer is correct
9876 से छोटा निकट गुणज 9476 है, इसलिए शेषफल (400) होना चाहिए। / The nearest lower multiple below 9876 is 9476, so the remainder is (400).
Step 3
Exam Tip
शेषफल 412 से छोटा है, इसलिए वैध है। / Since the remainder is less than 412, it is valid.
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किसी संख्या को 74 से भाग देने पर शेषफल 73 है। उस संख्या में 223 जोड़ने पर 74 से भाग देने पर शेषफल क्या होगा?
A number leaves remainder 73 when divided by 74. What is the remainder when 223 is added to the number and the result is divided by 74?
#euclids-division-lemma
#remainder-addition
#large-number
A 0
B 73
C 74
D 1
Explanation opens after your attempt
Step 1
Concept
मूल शेषफल 73 है। / The original remainder is 73.
Step 2
Why this answer is correct
223 को 74 से भाग देने पर शेषफल 1 है। / 223 leaves remainder 1 when divided by 74.
Step 3
Exam Tip
(73+1=74), इसलिए अंतिम शेषफल 0 होगा। / (73+1=74), so the final remainder is 0.
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यदि 7341 को 307 से भाग दिया जाए, तो शेषफल क्या होगा?
If 7341 is divided by 307, what is the remainder?
#euclids-division-lemma
#remainder
#large-number
A 261
B 280
C 303
D 307
Explanation opens after your attempt
Step 1
Concept
\(307\times23=7061\) है। / \(307\times23=7061\).
Step 2
Why this answer is correct
(7341-7061=280), इसलिए शेषफल 280 है। / (7341-7061=280), so the remainder is 280.
Step 3
Exam Tip
ऐसा गुणज चुनें जो दी गई संख्या से बड़ा न हो और अंतर भाजक से छोटा हो। / Choose a multiple that does not exceed the number and leaves a difference smaller than the divisor.
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किसी संख्या को 58 से भाग देने पर शेषफल 57 है। उस संख्या में 175 जोड़ने पर 58 से भाग देने पर शेषफल क्या होगा?
A number leaves remainder 57 when divided by 58. What is the remainder when 175 is added to the number and the result is divided by 58?
#euclids-division-lemma
#remainder-addition
#large-number
A 0
B 57
C 58
D 1
Explanation opens after your attempt
Step 1
Concept
मूल शेषफल 57 है। / The original remainder is 57.
Step 2
Why this answer is correct
175 को 58 से भाग देने पर शेषफल 1 है। / 175 leaves remainder 1 when divided by 58.
Step 3
Exam Tip
(57+1=58), इसलिए अंतिम शेषफल 0 होगा। / (57+1=58), so the final remainder is 0.
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यदि 5289 को 211 से भाग दिया जाए, तो शेषफल क्या होगा?
If 5289 is divided by 211, what is the remainder?
#euclids-division-lemma
#remainder
#large-number
A 12
B 13
C 14
D 15
Explanation opens after your attempt
Step 1
Concept
\(211\times25=5275\) है। / \(211\times25=5275\).
Step 2
Why this answer is correct
(5289-5275=14), इसलिए शेषफल 14 है। / (5289-5275=14), so the remainder is 14.
Step 3
Exam Tip
भाग करते समय ऐसा गुणज चुनें जो दी गई संख्या से बड़ा न हो। / While dividing, choose a multiple that does not exceed the given number.
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किसी संख्या को 42 से भाग देने पर शेषफल 41 है। उस संख्या में 85 जोड़ने पर 42 से भाग देने पर शेषफल क्या होगा?
A number leaves remainder 41 when divided by 42. What is the remainder when 85 is added to the number and the result is divided by 42?
#euclids-division-lemma
#remainder-addition
#large-number
A 0
B 41
C 42
D 1
Explanation opens after your attempt
Step 1
Concept
मूल शेषफल 41 है। / The original remainder is 41.
Step 2
Why this answer is correct
85 को 42 से भाग देने पर शेषफल 1 है, इसलिए कुल शेषफल (41+1=42), जो 0 बनता है। / (85) leaves remainder 1 on division by 42, so total remainder (41+1=42), which becomes 0.
Step 3
Exam Tip
बड़ी संख्या जोड़ने पर पहले उसका छोटा शेषफल निकालें। / When adding a large number, first find its smaller remainder.
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