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expression value MCQ Questions for Class 10

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55 questions tagged with expression value.

Question 31/55 Medium Mathematics Pair of Linear Equations in Two Variables Algebraic methods: Substitution method and Elimination method. Class 10 Level 57

यदि (5x+2y=28) और (3x-2y=4), तो (x+y) का मान क्या होगा?

If (5x+2y=28) and (3x-2y=4), what will be the value of (x+y)?

Explanation opens after your attempt
Correct Answer

D. (8)

Step 1

Concept

Adding both equations gives (8x=32), so (x=4). Then (y=4), so (x+y=8).

Step 2

Why this answer is correct

The correct answer is D. (8). Adding both equations gives (8x=32), so (x=4). Then (y=4), so (x+y=8).

Step 3

Exam Tip

दोनों समीकरण जोड़ने पर (8x=32), इसलिए (x=4)। फिर (y=4), इसलिए (x+y=8)।

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Question 32/55 Medium Mathematics Pair of Linear Equations in Two Variables Algebraic methods: Substitution method and Elimination method. Class 10 Level 56

यदि (x+3y=19) और (2x-y=3), तो (x+2y) का मान क्या है?

If (x+3y=19) and (2x-y=3), what is the value of (x+2y)?

Explanation opens after your attempt
Correct Answer

D. (14)

Step 1

Concept

Use (y=2x-3) from the second equation. Substitution gives (7x=28), so (x=4,\ y=5) and (x+2y=14).

Step 2

Why this answer is correct

The correct answer is D. (14). Use (y=2x-3) from the second equation. Substitution gives (7x=28), so (x=4,\ y=5) and (x+2y=14).

Step 3

Exam Tip

दूसरे समीकरण से (y=2x-3) रखें। पहले में रखने पर (7x=28), इसलिए (x=4,\ y=5) और (x+2y=14)।

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Question 33/55 Medium Mathematics Pair of Linear Equations in Two Variables Algebraic methods: Substitution method and Elimination method. Class 10 Level 56

यदि (3x+2y=20) और (x-y=1), तो (3x-y) का मान क्या है?

If (3x+2y=20) and (x-y=1), what is the value of (3x-y)?

Explanation opens after your attempt
Correct Answer

D. (11)

Step 1

Concept

Using (x=y+1) gives (3y+3+2y=20), so \(y=\frac{17}{5}\) and \(x=\frac{22}{5}\). Then \(3x-y=\frac{49}{5}\).

Step 2

Why this answer is correct

The correct answer is D. (11). Using (x=y+1) gives (3y+3+2y=20), so \(y=\frac{17}{5}\) and \(x=\frac{22}{5}\). Then \(3x-y=\frac{49}{5}\).

Step 3

Exam Tip

(x=y+1) रखने पर (3y+3+2y=20), इसलिए \(y=\frac{17}{5}\) और \(x=\frac{22}{5}\)। तब \(3x-y=\frac{49}{5}\) है।

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Question 34/55 Medium Mathematics Pair of Linear Equations in Two Variables Algebraic methods: Substitution method and Elimination method. Class 10 Level 56

समीकरणों (5x-4y=2) और (3x+4y=30) को हल करने पर (x+y) का मान क्या होगा?

On solving (5x-4y=2) and (3x+4y=30), what will be the value of (x+y)?

Explanation opens after your attempt
Correct Answer

D. (10)

Step 1

Concept

Adding both equations gives (8x=32), so (x=4). Then (3x+4y=30) gives \(y=\frac{9}{2}\), so \(x+y=\frac{17}{2}\).

Step 2

Why this answer is correct

The correct answer is D. (10). Adding both equations gives (8x=32), so (x=4). Then (3x+4y=30) gives \(y=\frac{9}{2}\), so \(x+y=\frac{17}{2}\).

Step 3

Exam Tip

दोनों समीकरण जोड़ने पर (8x=32), इसलिए (x=4)। फिर (3x+4y=30) से \(y=\frac{9}{2}\), अतः \(x+y=\frac{17}{2}\)।

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Question 35/55 Medium Mathematics Pair of Linear Equations in Two Variables Algebraic methods: Substitution method and Elimination method. Class 10 Level 56

यदि (2x-y=9) और (x+2y=13), तो (2x+y) का मान क्या है?

If (2x-y=9) and (x+2y=13), what is the value of (2x+y)?

Explanation opens after your attempt
Correct Answer

D. (16)

Step 1

Concept

Use (y=2x-9) from the first equation. Solving gives \(x=\frac{31}{5}\) and \(y=\frac{17}{5}\), so \(2x+y=\frac{79}{5}\).

Step 2

Why this answer is correct

The correct answer is D. (16). Use (y=2x-9) from the first equation. Solving gives \(x=\frac{31}{5}\) and \(y=\frac{17}{5}\), so \(2x+y=\frac{79}{5}\).

Step 3

Exam Tip

पहले समीकरण से (y=2x-9) रखें। हल करने पर \(x=\frac{31}{5}\) और \(y=\frac{17}{5}\), इसलिए \(2x+y=\frac{79}{5}\) है।

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Question 36/55 Easy Mathematics Pair of Linear Equations in Two Variables Algebraic methods: Substitution method and Elimination method. Class 10 Level 56

समीकरण (y=12-2x) में (x=5) रखने पर (y) क्या होगा?

In (y=12-2x), if (x=5), what is (y)?

Explanation opens after your attempt
Correct Answer

B. (y=2)

Step 1

Concept

(y=12-10=2). Multiply first and then subtract.

Step 2

Why this answer is correct

The correct answer is B. (y=2). (y=12-10=2). Multiply first and then subtract.

Step 3

Exam Tip

(y=12-10=2)। पहले गुणा करें और फिर घटाव करें।

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Question 37/55 Easy Mathematics Pair of Linear Equations in Two Variables Algebraic methods: Substitution method and Elimination method. Class 10 Level 56

समीकरण (x=10-y) और (y=7) से (x) क्या होगा?

From (x=10-y) and (y=7), what is (x)?

Explanation opens after your attempt
Correct Answer

D. (x=3)

Step 1

Concept

(x=10-7=3). In substitution, place the value in the given expression.

Step 2

Why this answer is correct

The correct answer is D. (x=3). (x=10-7=3). In substitution, place the value in the given expression.

Step 3

Exam Tip

(x=10-7=3)। प्रतिस्थापन में दी गई अभिव्यक्ति में मान रखें।

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Question 38/55 Expert Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 30

यदि \(x^2-8x-33=0\) के मूल \(\alpha,\beta\) हैं, तो \(\alpha\beta+5\alpha+5\beta\) का मान क्या है?

If \(\alpha,\beta\) are roots of \(x^2-8x-33=0\), what is \(\alpha\beta+5\alpha+5\beta\)?

Explanation opens after your attempt
Correct Answer

A. (7)

Step 1

Concept

Here \(\alpha+\beta=8\) and \(\alpha\beta=-33\). Thus (\alpha\beta+5\alpha+5\beta=-33+5(8)=7).

Step 2

Why this answer is correct

The correct answer is A. (7). Here \(\alpha+\beta=8\) and \(\alpha\beta=-33\). Thus (\alpha\beta+5\alpha+5\beta=-33+5(8)=7).

Step 3

Exam Tip

यहाँ \(\alpha+\beta=8\) और \(\alpha\beta=-33\) है। इसलिए (\alpha\beta+5\alpha+5\beta=-33+5(8)=7)।

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Question 39/55 Expert Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 30

यदि \(x^2-20x+96=0\) के मूल \(\alpha,\beta\) हैं, तो (\(\alpha-8\)\(\beta-8\)) का मान क्या है?

If \(\alpha,\beta\) are roots of \(x^2-20x+96=0\), what is (\(\alpha-8\)\(\beta-8\))?

Explanation opens after your attempt
Correct Answer

A. (0)

Step 1

Concept

(\(\alpha-8\)\(\beta-8\)=\alpha\beta-8\(\alpha+\beta\)+64). Here (96-160+64=0).

Step 2

Why this answer is correct

The correct answer is A. (0). (\(\alpha-8\)\(\beta-8\)=\alpha\beta-8\(\alpha+\beta\)+64). Here (96-160+64=0).

Step 3

Exam Tip

(\(\alpha-8\)\(\beta-8\)=\alpha\beta-8\(\alpha+\beta\)+64) है। यहाँ (96-160+64=0)।

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Question 40/55 Expert Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 30

यदि \(x^2-18x+80=0\) के मूल \(\alpha\) और \(\beta\) हैं, तो (\(\alpha-8\)\(\beta-8\)) का मान क्या है?

If \(\alpha\) and \(\beta\) are roots of \(x^2-18x+80=0\), what is (\(\alpha-8\)\(\beta-8\))?

Explanation opens after your attempt
Correct Answer

A. (0)

Step 1

Concept

(\(\alpha-8\)\(\beta-8\)=\alpha\beta-8\(\alpha+\beta\)+64). Here (80-144+64=0).

Step 2

Why this answer is correct

The correct answer is A. (0). (\(\alpha-8\)\(\beta-8\)=\alpha\beta-8\(\alpha+\beta\)+64). Here (80-144+64=0).

Step 3

Exam Tip

(\(\alpha-8\)\(\beta-8\)=\alpha\beta-8\(\alpha+\beta\)+64) है। यहाँ (80-144+64=0)।

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Question 41/55 Expert Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 29

यदि \(x^2-7x-30=0\) के मूल \(\alpha,\beta\) हैं, तो \(\alpha\beta+4\alpha+4\beta\) का मान क्या है?

If \(\alpha,\beta\) are roots of \(x^2-7x-30=0\), what is \(\alpha\beta+4\alpha+4\beta\)?

Explanation opens after your attempt
Correct Answer

A. -(2)

Step 1

Concept

Here \(\alpha+\beta=7\) and \(\alpha\beta=-30\). Thus (\alpha\beta+4\alpha+4\beta=-30+4(7)=-2).

Step 2

Why this answer is correct

The correct answer is A. -(2). Here \(\alpha+\beta=7\) and \(\alpha\beta=-30\). Thus (\alpha\beta+4\alpha+4\beta=-30+4(7)=-2).

Step 3

Exam Tip

यहाँ \(\alpha+\beta=7\) और \(\alpha\beta=-30\) है। इसलिए (\alpha\beta+4\alpha+4\beta=-30+4(7)=-2)।

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Question 42/55 Expert Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 29

यदि \(x^2-16x+63=0\) के मूल \(\alpha,\beta\) हैं, तो (\(\alpha-7\)\(\beta-7\)) का मान क्या है?

If \(\alpha,\beta\) are roots of \(x^2-16x+63=0\), what is (\(\alpha-7\)\(\beta-7\))?

Explanation opens after your attempt
Correct Answer

A. (0)

Step 1

Concept

(\(\alpha-7\)\(\beta-7\)=\alpha\beta-7\(\alpha+\beta\)+49). Here (63-112+49=0).

Step 2

Why this answer is correct

The correct answer is A. (0). (\(\alpha-7\)\(\beta-7\)=\alpha\beta-7\(\alpha+\beta\)+49). Here (63-112+49=0).

Step 3

Exam Tip

(\(\alpha-7\)\(\beta-7\)=\alpha\beta-7\(\alpha+\beta\)+49) है। यहाँ (63-112+49=0)।

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Question 43/55 Expert Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 29

यदि \(x^2-14x+48=0\) के मूल \(\alpha\) और \(\beta\) हैं, तो (\(\alpha-6\)\(\beta-6\)) का मान क्या है?

If \(\alpha\) and \(\beta\) are roots of \(x^2-14x+48=0\), what is (\(\alpha-6\)\(\beta-6\))?

Explanation opens after your attempt
Correct Answer

A. (0)

Step 1

Concept

(\(\alpha-6\)\(\beta-6\)=\alpha\beta-6\(\alpha+\beta\)+36). Here (48-84+36=0).

Step 2

Why this answer is correct

The correct answer is A. (0). (\(\alpha-6\)\(\beta-6\)=\alpha\beta-6\(\alpha+\beta\)+36). Here (48-84+36=0).

Step 3

Exam Tip

(\(\alpha-6\)\(\beta-6\)=\alpha\beta-6\(\alpha+\beta\)+36) है। यहाँ (48-84+36=0)।

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Question 44/55 Expert Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 28

यदि \(x^2-6x-27=0\) के मूल \(\alpha,\beta\) हैं, तो \(\alpha\beta+3\alpha+3\beta\) का मान क्या है?

If \(\alpha,\beta\) are roots of \(x^2-6x-27=0\), what is \(\alpha\beta+3\alpha+3\beta\)?

Explanation opens after your attempt
Correct Answer

A. (-9)

Step 1

Concept

Here \(\alpha+\beta=6\) and \(\alpha\beta=-27\). Thus (\alpha\beta+3\alpha+3\beta=-27+3(6)=-9).

Step 2

Why this answer is correct

The correct answer is A. (-9). Here \(\alpha+\beta=6\) and \(\alpha\beta=-27\). Thus (\alpha\beta+3\alpha+3\beta=-27+3(6)=-9).

Step 3

Exam Tip

यहाँ \(\alpha+\beta=6\) और \(\alpha\beta=-27\) है। इसलिए (\alpha\beta+3\alpha+3\beta=-27+3(6)=-9)।

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Question 45/55 Expert Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 28

यदि \(x^2-12x+35=0\) के मूल \(\alpha,\beta\) हैं, तो (\(\alpha-5\)\(\beta-5\)) का मान क्या है?

If \(\alpha,\beta\) are roots of \(x^2-12x+35=0\), what is (\(\alpha-5\)\(\beta-5\))?

Explanation opens after your attempt
Correct Answer

A. (0)

Step 1

Concept

(\(\alpha-5\)\(\beta-5\)=\alpha\beta-5\(\alpha+\beta\)+25). Here (35-60+25=0).

Step 2

Why this answer is correct

The correct answer is A. (0). (\(\alpha-5\)\(\beta-5\)=\alpha\beta-5\(\alpha+\beta\)+25). Here (35-60+25=0).

Step 3

Exam Tip

(\(\alpha-5\)\(\beta-5\)=\alpha\beta-5\(\alpha+\beta\)+25) है। यहाँ (35-60+25=0)।

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Question 46/55 Expert Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 28

यदि \(x^2-9x+18=0\) के मूल \(\alpha\) और \(\beta\) हैं, तो (\(\alpha-3\)\(\beta-3\)) का मान क्या है?

If \(\alpha\) and \(\beta\) are roots of \(x^2-9x+18=0\), what is (\(\alpha-3\)\(\beta-3\))?

Explanation opens after your attempt
Correct Answer

A. (0)

Step 1

Concept

(\(\alpha-3\)\(\beta-3\)=\alpha\beta-3\(\alpha+\beta\)+9). Here (18-27+9=0).

Step 2

Why this answer is correct

The correct answer is A. (0). (\(\alpha-3\)\(\beta-3\)=\alpha\beta-3\(\alpha+\beta\)+9). Here (18-27+9=0).

Step 3

Exam Tip

(\(\alpha-3\)\(\beta-3\)=\alpha\beta-3\(\alpha+\beta\)+9) है। यहाँ (18-27+9=0)।

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Question 47/55 Hard Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 30

यदि \(x^2-4x-21=0\) के मूल \(\alpha,\beta\) हैं, तो \(\alpha\beta+2\alpha+2\beta\) का मान क्या है?

If \(\alpha,\beta\) are roots of \(x^2-4x-21=0\), what is \(\alpha\beta+2\alpha+2\beta\)?

Explanation opens after your attempt
Correct Answer

A. (-13)

Step 1

Concept

Here \(\alpha+\beta=4\) and \(\alpha\beta=-21\). Thus (\alpha\beta+2\alpha+2\beta=-21+2(4)=-13).

Step 2

Why this answer is correct

The correct answer is A. (-13). Here \(\alpha+\beta=4\) and \(\alpha\beta=-21\). Thus (\alpha\beta+2\alpha+2\beta=-21+2(4)=-13).

Step 3

Exam Tip

यहाँ \(\alpha+\beta=4\) और \(\alpha\beta=-21\) है। इसलिए (\alpha\beta+2\alpha+2\beta=-21+2(4)=-13)।

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Question 48/55 Hard Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 30

यदि \(x^2-9x+20=0\) के मूल \(\alpha,\beta\) हैं, तो (\(\alpha-4\)\(\beta-4\)) का मान क्या है?

If \(\alpha,\beta\) are roots of \(x^2-9x+20=0\), what is (\(\alpha-4\)\(\beta-4\))?

Explanation opens after your attempt
Correct Answer

A. (0)

Step 1

Concept

(\(\alpha-4\)\(\beta-4\)=\alpha\beta-4\(\alpha+\beta\)+16). Here (20-36+16=0).

Step 2

Why this answer is correct

The correct answer is A. (0). (\(\alpha-4\)\(\beta-4\)=\alpha\beta-4\(\alpha+\beta\)+16). Here (20-36+16=0).

Step 3

Exam Tip

(\(\alpha-4\)\(\beta-4\)=\alpha\beta-4\(\alpha+\beta\)+16) है। यहाँ (20-36+16=0)।

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Question 49/55 Hard Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 30

यदि \(x^2+7x+10=0\) के मूल \(\alpha\) और \(\beta\) हैं, तो (\(\alpha+2\)\(\beta+2\)) का मान क्या है?

If \(\alpha\) and \(\beta\) are roots of \(x^2+7x+10=0\), what is (\(\alpha+2\)\(\beta+2\))?

Explanation opens after your attempt
Correct Answer

A. (0)

Step 1

Concept

(\(\alpha+2\)\(\beta+2\)=\alpha\beta+2\(\alpha+\beta\)+4). Here (10+2(-7)+4=0).

Step 2

Why this answer is correct

The correct answer is A. (0). (\(\alpha+2\)\(\beta+2\)=\alpha\beta+2\(\alpha+\beta\)+4). Here (10+2(-7)+4=0).

Step 3

Exam Tip

(\(\alpha+2\)\(\beta+2\)=\alpha\beta+2\(\alpha+\beta\)+4) होता है। यहाँ (10+2(-7)+4=0)।

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Question 50/55 Hard Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 29

यदि \(x^2+3x-18=0\) के मूल \(\alpha,\beta\) हैं, तो \(\alpha\beta-\alpha-\beta\) का मान क्या है?

If \(\alpha,\beta\) are roots of \(x^2+3x-18=0\), what is \(\alpha\beta-\alpha-\beta\)?

Explanation opens after your attempt
Correct Answer

A. (-15)

Step 1

Concept

Here \(\alpha+\beta=-3\) and \(\alpha\beta=-18\). Thus (\alpha\beta-\alpha-\beta=-18-(-3)=-15).

Step 2

Why this answer is correct

The correct answer is A. (-15). Here \(\alpha+\beta=-3\) and \(\alpha\beta=-18\). Thus (\alpha\beta-\alpha-\beta=-18-(-3)=-15).

Step 3

Exam Tip

यहाँ \(\alpha+\beta=-3\) और \(\alpha\beta=-18\) है। इसलिए (\alpha\beta-\alpha-\beta=-18-(-3)=-15)।

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Question 51/55 Hard Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 29

यदि \(x^2-10x+21=0\) के मूल \(\alpha,\beta\) हैं, तो (\(\alpha-3\)\(\beta-3\)) का मान क्या है?

If \(\alpha,\beta\) are roots of \(x^2-10x+21=0\), what is (\(\alpha-3\)\(\beta-3\))?

Explanation opens after your attempt
Correct Answer

A. (0)

Step 1

Concept

(\(\alpha-3\)\(\beta-3\)=\alpha\beta-3\(\alpha+\beta\)+9). Here (21-30+9=0).

Step 2

Why this answer is correct

The correct answer is A. (0). (\(\alpha-3\)\(\beta-3\)=\alpha\beta-3\(\alpha+\beta\)+9). Here (21-30+9=0).

Step 3

Exam Tip

(\(\alpha-3\)\(\beta-3\)=\alpha\beta-3\(\alpha+\beta\)+9) है। यहाँ (21-30+9=0)।

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Question 52/55 Hard Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 29

यदि \(x^2-8x+15=0\) के मूल \(\alpha\) और \(\beta\) हैं, तो (\(\alpha-1\)\(\beta-1\)) का मान क्या है?

If \(\alpha\) and \(\beta\) are roots of \(x^2-8x+15=0\), what is (\(\alpha-1\)\(\beta-1\))?

Explanation opens after your attempt
Correct Answer

A. (8)

Step 1

Concept

(\(\alpha-1\)\(\beta-1\)=\alpha\beta-\(\alpha+\beta\)+1). Here (15-8+1=8).

Step 2

Why this answer is correct

The correct answer is A. (8). (\(\alpha-1\)\(\beta-1\)=\alpha\beta-\(\alpha+\beta\)+1). Here (15-8+1=8).

Step 3

Exam Tip

(\(\alpha-1\)\(\beta-1\)=\alpha\beta-\(\alpha+\beta\)+1) होता है। यहाँ (15-8+1=8)।

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Question 53/55 Medium Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 30

समीकरण \(7x^2-5x+2=0\) में \(b^2+ac\) का मान क्या है?

What is the value of \(b^2+ac\) in \(7x^2-5x+2=0\)?

Explanation opens after your attempt
Correct Answer

A. (39)

Step 1

Concept

Here (a=7), (b=-5), (c=2), so \(b^2+ac=25+14=39\). In \(b^2\), the negative sign becomes positive after squaring.

Step 2

Why this answer is correct

The correct answer is A. (39). Here (a=7), (b=-5), (c=2), so \(b^2+ac=25+14=39\). In \(b^2\), the negative sign becomes positive after squaring.

Step 3

Exam Tip

यहाँ (a=7), (b=-5), (c=2) हैं, इसलिए \(b^2+ac=25+14=39\) है। \(b^2\) में ऋण चिन्ह वर्ग के कारण धनात्मक हो जाता है।

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Question 54/55 Easy Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 29

समीकरण \(4x^2-2x-6=0\) में (a-b+c) का मान क्या है?

What is the value of (a-b+c) for \(4x^2-2x-6=0\)?

Explanation opens after your attempt
Correct Answer

A. (0)

Step 1

Concept

Here (a=4), (b=-2), (c=-6). Thus (a-b+c=4-(-2)-6=0).

Step 2

Why this answer is correct

The correct answer is A. (0). Here (a=4), (b=-2), (c=-6). Thus (a-b+c=4-(-2)-6=0).

Step 3

Exam Tip

यहां (a=4), (b=-2), (c=-6) हैं। इसलिए (a-b+c=4-(-2)-6=0) है।

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Question 55/55 Easy Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 28

समीकरण \(2x^2-3x-5=0\) में (a-b+c) का मान क्या है?

What is the value of (a-b+c) for \(2x^2-3x-5=0\)?

Explanation opens after your attempt
Correct Answer

A. (0)

Step 1

Concept

Here (a=2), (b=-3), (c=-5). Thus (a-b+c=2-(-3)-5=0).

Step 2

Why this answer is correct

The correct answer is A. (0). Here (a=2), (b=-3), (c=-5). Thus (a-b+c=2-(-3)-5=0).

Step 3

Exam Tip

यहां (a=2), (b=-3), (c=-5) हैं। इसलिए (a-b+c=2-(-3)-5=0) है।

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