समीकरण \(7x^2-5x+2=0\) में \(b^2+ac\) का मान क्या है?
What is the value of \(b^2+ac\) in \(7x^2-5x+2=0\)?
Explanation opens after your attempt
A. (39)
Concept
Here (a=7), (b=-5), (c=2), so \(b^2+ac=25+14=39\). In \(b^2\), the negative sign becomes positive after squaring.
Why this answer is correct
The correct answer is A. (39). Here (a=7), (b=-5), (c=2), so \(b^2+ac=25+14=39\). In \(b^2\), the negative sign becomes positive after squaring.
Exam Tip
यहाँ (a=7), (b=-5), (c=2) हैं, इसलिए \(b^2+ac=25+14=39\) है। \(b^2\) में ऋण चिन्ह वर्ग के कारण धनात्मक हो जाता है।
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