समीकरण \(7x^2-5x+2=0\) में \(b^2+ac\) का मान क्या है?

What is the value of \(b^2+ac\) in \(7x^2-5x+2=0\)?

Explanation opens after your attempt
Correct Answer

A. (39)

Step 1

Concept

Here (a=7), (b=-5), (c=2), so \(b^2+ac=25+14=39\). In \(b^2\), the negative sign becomes positive after squaring.

Step 2

Why this answer is correct

The correct answer is A. (39). Here (a=7), (b=-5), (c=2), so \(b^2+ac=25+14=39\). In \(b^2\), the negative sign becomes positive after squaring.

Step 3

Exam Tip

यहाँ (a=7), (b=-5), (c=2) हैं, इसलिए \(b^2+ac=25+14=39\) है। \(b^2\) में ऋण चिन्ह वर्ग के कारण धनात्मक हो जाता है।

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समीकरण \(7x^2-5x+2=0\) में \(b^2+ac\) का मान क्या है? / What is the value of \(b^2+ac\) in \(7x^2-5x+2=0\)?

Correct Answer: A. (39). Explanation: यहाँ (a=7), (b=-5), (c=2) हैं, इसलिए \(b^2+ac=25+14=39\) है। \(b^2\) में ऋण चिन्ह वर्ग के कारण धनात्मक हो जाता है। / Here (a=7), (b=-5), (c=2), so \(b^2+ac=25+14=39\). In \(b^2\), the negative sign becomes positive after squaring.

Which concept should I revise for this Mathematics MCQ?

Here (a=7), (b=-5), (c=2), so \(b^2+ac=25+14=39\). In \(b^2\), the negative sign becomes positive after squaring.

What exam hint can help solve this Mathematics question?

यहाँ (a=7), (b=-5), (c=2) हैं, इसलिए \(b^2+ac=25+14=39\) है। \(b^2\) में ऋण चिन्ह वर्ग के कारण धनात्मक हो जाता है।