difference of squares se related questions ko ek jagah revise karein. Har question me bilingual content, answer feedback aur explanation available hai.
\(144=12^2\), so it is a difference of squares form. In exams, choosing the correct identity is the fastest method.
Step 2
Why this answer is correct
The correct answer is A. (a-2-b-2=(a-b)(a+b)). \(144=12^2\), so it is a difference of squares form. In exams, choosing the correct identity is the fastest method.
Step 3
Exam Tip
\(144=12^2\), इसलिए यह वर्गों के अंतर का रूप है। परीक्षा में सही पहचान चुनना सबसे तेज तरीका है।
((4x-5)(4x+5)=0), so \(x=\frac{5}{4}\) or \(x=-\frac{5}{4}\). In exams, solve linear factors carefully.
Step 2
Why this answer is correct
The correct answer is A. \(x=\frac{5}{4},-\frac{5}{4}\). ((4x-5)(4x+5)=0), so \(x=\frac{5}{4}\) or \(x=-\frac{5}{4}\). In exams, solve linear factors carefully.
Step 3
Exam Tip
((4x-5)(4x+5)=0), इसलिए \(x=\frac{5}{4}\) या \(x=-\frac{5}{4}\) है। परीक्षा में रैखिक गुणनखंड सावधानी से हल करें।
A. वर्गों के अंतर की विधि/Difference of squares method
Step 1
Concept
\(x^2-49=x^2-7^2\), so the difference of squares method is fastest. In exams, recognizing \(a^2-b^2\) is useful.
Step 2
Why this answer is correct
The correct answer is A. वर्गों के अंतर की विधि / Difference of squares method. \(x^2-49=x^2-7^2\), so the difference of squares method is fastest. In exams, recognizing \(a^2-b^2\) is useful.
Step 3
Exam Tip
\(x^2-49=x^2-7^2\), इसलिए वर्गों के अंतर की विधि सबसे तेज है। परीक्षा में \(a^2-b^2\) पहचानना उपयोगी है।
\(100=10^2\), so it is a difference of squares form. In exams, choosing the correct identity is the fastest method.
Step 2
Why this answer is correct
The correct answer is A. (a-2-b-2=(a-b)(a+b)). \(100=10^2\), so it is a difference of squares form. In exams, choosing the correct identity is the fastest method.
Step 3
Exam Tip
\(100=10^2\), इसलिए यह वर्गों के अंतर का रूप है। परीक्षा में सही पहचान चुनना सबसे तेज तरीका है।
((3x-4)(3x+4)=0), so \(x=\frac{4}{3}\) or \(x=-\frac{4}{3}\). In exams, solve linear factors carefully.
Step 2
Why this answer is correct
The correct answer is A. \(x=\frac{4}{3},-\frac{4}{3}\). ((3x-4)(3x+4)=0), so \(x=\frac{4}{3}\) or \(x=-\frac{4}{3}\). In exams, solve linear factors carefully.
Step 3
Exam Tip
((3x-4)(3x+4)=0), इसलिए \(x=\frac{4}{3}\) या \(x=-\frac{4}{3}\) है। परीक्षा में रैखिक गुणनखंड सावधानी से हल करें।
A. वर्गों के अंतर की विधि/Difference of squares method
Step 1
Concept
\(x^2-36=x^2-6^2\), so it is solved quickly by difference of squares. In exams, recognizing \(a^2-b^2\) saves time.
Step 2
Why this answer is correct
The correct answer is A. वर्गों के अंतर की विधि / Difference of squares method. \(x^2-36=x^2-6^2\), so it is solved quickly by difference of squares. In exams, recognizing \(a^2-b^2\) saves time.
Step 3
Exam Tip
\(x^2-36=x^2-6^2\), इसलिए वर्गों के अंतर से तुरंत हल होता है। परीक्षा में \(a^2-b^2\) पहचानना समय बचाता है।
\(x^2-1=x^2-1^2\), so the difference of squares rule applies. In exams, avoid wrong pattern recognition.
Step 2
Why this answer is correct
The correct answer is A. (a-2-b-2=(a-b)(a+b)). \(x^2-1=x^2-1^2\), so the difference of squares rule applies. In exams, avoid wrong pattern recognition.
Step 3
Exam Tip
\(x^2-1=x^2-1^2\), इसलिए वर्गों के अंतर का नियम लागू होता है। परीक्षा में गलत पहचान से बचें।
((2x-1)(2x+1)=0), so \(x=\frac{1}{2}\) or \(x=-\frac{1}{2}\). In exams, solve each linear factor carefully.
Step 2
Why this answer is correct
The correct answer is A. \(x=\frac{1}{2},-\frac{1}{2}\). ((2x-1)(2x+1)=0), so \(x=\frac{1}{2}\) or \(x=-\frac{1}{2}\). In exams, solve each linear factor carefully.
Step 3
Exam Tip
((2x-1)(2x+1)=0), इसलिए \(x=\frac{1}{2}\) या \(x=-\frac{1}{2}\) है। परीक्षा में रैखिक गुणनखंड को सावधानी से हल करें।
A. वर्गों के अंतर की विधि/Difference of squares method
Step 1
Concept
(x-2-9=x-2-32=(x-3)(x+3)), so it is solved quickly by difference of squares. In exams, recognizing \(a^2-b^2\) is useful.
Step 2
Why this answer is correct
The correct answer is A. वर्गों के अंतर की विधि / Difference of squares method. (x-2-9=x-2-32=(x-3)(x+3)), so it is solved quickly by difference of squares. In exams, recognizing \(a^2-b^2\) is useful.
Step 3
Exam Tip
(x-2-9=x-2-32=(x-3)(x+3)), इसलिए यह वर्गों के अंतर से तुरंत हल होता है। परीक्षा में \(a^2-b^2\) पहचानना उपयोगी है।
(x-2-9=(x-3)(x+3)) so the roots are (3) and (-3). In exams quickly identify the difference of squares.
Step 2
Why this answer is correct
The correct answer is A. (3) और (-3) / (3) and (-3). (x-2-9=(x-3)(x+3)) so the roots are (3) and (-3). In exams quickly identify the difference of squares.
Step 3
Exam Tip
(x-2-9=(x-3)(x+3)) इसलिए मूल (3) और (-3) हैं। परीक्षा में वर्गों के अंतर को तुरंत पहचानें।
\(49x^2=64\), so \(x^2=\frac{64}{49}\) and \(x=\pm\frac{8}{7}\). Take both signs while taking square roots.
Step 2
Why this answer is correct
The correct answer is A. \(x=\pm \frac{8}{7}\). \(49x^2=64\), so \(x^2=\frac{64}{49}\) and \(x=\pm\frac{8}{7}\). Take both signs while taking square roots.
Step 3
Exam Tip
\(49x^2=64\), इसलिए \(x^2=\frac{64}{49}\) और \(x=\pm\frac{8}{7}\) है। वर्गमूल लेते समय दोनों चिन्ह लें।
\(16x^2=81\), so \(x^2=\frac{81}{16}\) and \(x=\pm\frac{9}{4}\). Take both signs while taking square roots.
Step 2
Why this answer is correct
The correct answer is A. \(x=\pm \frac{9}{4}\). \(16x^2=81\), so \(x^2=\frac{81}{16}\) and \(x=\pm\frac{9}{4}\). Take both signs while taking square roots.
Step 3
Exam Tip
\(16x^2=81\), इसलिए \(x^2=\frac{81}{16}\) और \(x=\pm\frac{9}{4}\) है। वर्गमूल लेते समय दोनों चिन्ह लें।
\(9x^2=25\), so \(x^2=\frac{25}{9}\) and \(x=\pm \frac{5}{3}\). Take both signs while taking square roots.
Step 2
Why this answer is correct
The correct answer is A. \(x=\pm \frac{5}{3}\). \(9x^2=25\), so \(x^2=\frac{25}{9}\) and \(x=\pm \frac{5}{3}\). Take both signs while taking square roots.
Step 3
Exam Tip
\(9x^2=25\), इसलिए \(x^2=\frac{25}{9}\) और \(x=\pm \frac{5}{3}\)। वर्गमूल लेते समय दोनों चिन्ह लें।
