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3 questions tagged with practice.
A. (3)
The original number is (6q+2).
Adding (1) gives (6q+3).
Since (3<6), the new remainder is (3). चरण 1: मूल संख्या (6q+2) होगी। चरण 2: (1) जोड़ने पर (6q+3) मिलेगा। चरण 3: (3<6), इसलिए नया शेषफल (3) है।
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Which option gives the correct quotient and remainder for (52=7q+r)?
A. (q=7,\ r=3)
\(7\times7=49\) and (52-49=3).
Since (3) is less than (7), (q=7,\ r=3) is correct.
Reject negative remainders or remainders equal to the divisor. चरण 1: \(7\times7=49\) और (52-49=3)। चरण 2: (3), (7) से छोटा है, इसलिए (q=7,\ r=3) सही है। चरण 3: ऋणात्मक या भाजक के बराबर शेषफल को तुरंत गलत मानें।
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What is the correct Euclidean form when (38) is divided by (7)?
A. \(38=7 \times 5+3\)
\(7 \times 5=35\) and \(7 \times 6=42\).
(35) is the correct smaller multiple, so (38-35=3) is the remainder.
Since (3<7), the form is valid. चरण 1: \(7 \times 5=35\) और \(7 \times 6=42\) है। चरण 2: (35) सही छोटा गुणज है, इसलिए (38-35=3) शेषफल है। चरण 3: (3<7), इसलिए रूप मान्य है।
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