\(4x^2-1=0\) के मूल क्या हैं?
What are the roots of \(4x^2-1=0\)?
Explanation opens after your attempt
Correct Answer
A. \(x=\frac{1}{2},-\frac{1}{2}\)
Concept
((2x-1)(2x+1)=0), so \(x=\frac{1}{2}\) or \(x=-\frac{1}{2}\). In exams, solve each linear factor carefully.
Why this answer is correct
The correct answer is A. \(x=\frac{1}{2},-\frac{1}{2}\). ((2x-1)(2x+1)=0), so \(x=\frac{1}{2}\) or \(x=-\frac{1}{2}\). In exams, solve each linear factor carefully.
Exam Tip
((2x-1)(2x+1)=0), इसलिए \(x=\frac{1}{2}\) या \(x=-\frac{1}{2}\) है। परीक्षा में रैखिक गुणनखंड को सावधानी से हल करें।
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