\(16x^2-25=0\) का सही गुणनखंड रूप कौनसा है?
What is the correct factorised form of \(16x^2-25=0\)?
Explanation opens after your attempt
A. ((4x-5)(4x+5)=0)
Concept
(16x-2-25=(4x)2-52), so ((4x-5)(4x+5)) is obtained. In exams, identify both squares first.
Why this answer is correct
The correct answer is A. ((4x-5)(4x+5)=0). (16x-2-25=(4x)2-52), so ((4x-5)(4x+5)) is obtained. In exams, identify both squares first.
Exam Tip
(16x-2-25=(4x)2-52), इसलिए ((4x-5)(4x+5)) मिलता है। परीक्षा में दोनों वर्गों को पहले पहचानें।
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