यदि \(a_{n+3}-a_n=30\) है और \(a_{10}=68\) है तो \(a_{31}\) क्या होगा?
If \(a_{n+3}-a_n=30\) and \(a_{10}=68\), what is \(a_{31}\)?
Explanation opens after your attempt
C. (278)
Concept
(3d=30), so (d=10). \(a_{31}=68+21\times10=278\).
Why this answer is correct
The correct answer is C. (278). (3d=30), so (d=10). \(a_{31}=68+21\times10=278\).
Exam Tip
(3d=30) इसलिए (d=10)। \(a_{31}=68+21\times10=278\)।
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