ap-recursive-difference-hard se related questions ko ek jagah revise karein. Har question me bilingual content, answer feedback aur explanation available hai.
3 questions tagged with ap-recursive-difference-hard.
If \(a_{n+4}-a_n=44\) and \(a_{12}=91\), what is \(a_{36}\)?
C. (355)
(4d=44), so (d=11). \(a_{36}=91+24\times11=355\).
The correct answer is C. (355). (4d=44), so (d=11). \(a_{36}=91+24\times11=355\).
(4d=44) इसलिए (d=11)। \(a_{36}=91+24\times11=355\)।
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If \(a_{n+3}-a_n=30\) and \(a_{10}=68\), what is \(a_{31}\)?
C. (278)
(3d=30), so (d=10). \(a_{31}=68+21\times10=278\).
The correct answer is C. (278). (3d=30), so (d=10). \(a_{31}=68+21\times10=278\).
(3d=30) इसलिए (d=10)। \(a_{31}=68+21\times10=278\)।
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If \(a_{n+2}-a_n=18\) and \(a_9=74\), what is \(a_{25}\)?
C. (218)
\(a_{n+2}-a_n=2d=18\), so (d=9). \(a_{25}=74+16\times9=218\).
The correct answer is C. (218). \(a_{n+2}-a_n=2d=18\), so (d=9). \(a_{25}=74+16\times9=218\).
\(a_{n+2}-a_n=2d=18\) इसलिए (d=9)। \(a_{25}=74+16\times9=218\)।
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