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100 results found for "advanced factorization" in Class 10.

किस उत्तर में तत्व और सिद्धांत का उन्नत संबंध है?

Which answer shows advanced relation of elements and principles?

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Correct Answer

A. रेखा मान रंग और स्थान को संतुलन जोर और लय बनाने के लिए व्यवस्थित किया जाता हैLine value colour and space are arranged to create balance emphasis and rhythm

Step 1

Concept

Elements are visual materials and principles explain their arrangement. Exam tip: keep what and how separate.

Step 2

Why this answer is correct

The correct answer is A. रेखा मान रंग और स्थान को संतुलन जोर और लय बनाने के लिए व्यवस्थित किया जाता है / Line value colour and space are arranged to create balance emphasis and rhythm. Elements are visual materials and principles explain their arrangement. Exam tip: keep what and how separate.

Step 3

Exam Tip

तत्व दृश्य सामग्री हैं और सिद्धांत उनकी व्यवस्था बताते हैं। परीक्षा में what and how अलग रखें।

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उच्च स्तर पर कला तत्वों का अध्ययन विद्यार्थी को क्या सिखाता है?

At advanced level what does study of art elements teach a student?

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Correct Answer

A. देखना बनाना समझना और सुधारनाTo observe create understand and improve

Step 1

Concept

Art elements are basis of both creation and analysis. Exam tip: write practical and analytical use.

Step 2

Why this answer is correct

The correct answer is A. देखना बनाना समझना और सुधारना / To observe create understand and improve. Art elements are basis of both creation and analysis. Exam tip: write practical and analytical use.

Step 3

Exam Tip

कला तत्व रचना और विश्लेषण दोनों के आधार हैं। परीक्षा में practical और analytical use लिखें।

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उच्च स्तरीय चित्र विश्लेषण में अंतिम निष्कर्ष किस आधार पर होना चाहिए?

On what should final conclusion in advanced picture analysis be based?

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Correct Answer

A. दृश्य प्रमाण तत्व प्रभाव और संदर्भVisual evidence elements effects and context

Step 1

Concept

A good conclusion is based on evidence and context. Exam tip: write evidence-based conclusion.

Step 2

Why this answer is correct

The correct answer is A. दृश्य प्रमाण तत्व प्रभाव और संदर्भ / Visual evidence elements effects and context. A good conclusion is based on evidence and context. Exam tip: write evidence-based conclusion.

Step 3

Exam Tip

अच्छा निष्कर्ष प्रमाण और संदर्भ पर आधारित होता है। परीक्षा में evidence based conclusion लिखें।

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नकारात्मक आकार का उपयोग करके द्विअर्थी छवि बनाना किस उच्च कौशल को दिखाता है?

Creating an ambiguous image using negative shape shows which advanced skill?

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Correct Answer

A. आकृति पृष्ठभूमि नियंत्रणFigure ground control

Step 1

Concept

In ambiguous image both positive and negative are read. Exam tip: understand figure-ground reversal.

Step 2

Why this answer is correct

The correct answer is A. आकृति पृष्ठभूमि नियंत्रण / Figure ground control. In ambiguous image both positive and negative are read. Exam tip: understand figure-ground reversal.

Step 3

Exam Tip

द्विअर्थी छवि में सकारात्मक और ऋणात्मक दोनों पढ़े जाते हैं। परीक्षा में figure ground reversal समझें।

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रेखा को दृश्य कला में कठिन स्तर पर समझने का सबसे उचित सार क्या है?

What is the most suitable advanced summary of line in visual art?

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Correct Answer

A. रेखा सीमा के साथ दिशा भाव बनावट आयतन और रचना नियंत्रित करती हैLine controls boundary direction mood texture volume and composition

Step 1

Concept

Line is a multifunctional element of visual art. In exams understand it as both technical and expressive.

Step 2

Why this answer is correct

The correct answer is A. रेखा सीमा के साथ दिशा भाव बनावट आयतन और रचना नियंत्रित करती है / Line controls boundary direction mood texture volume and composition. Line is a multifunctional element of visual art. In exams understand it as both technical and expressive.

Step 3

Exam Tip

रेखा दृश्य कला का बहुकार्य तत्व है। परीक्षा में इसे तकनीकी और अभिव्यक्तिपूर्ण दोनों रूप में समझें।

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किस उत्तर में रूप विश्लेषण सबसे उन्नत है?

Which answer gives the most advanced form analysis?

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Correct Answer

A. प्रकाश दिशा हाइलाइट मध्य मान और पड़ी छाया मिलकर फल को आयतन और आधार देते हैंLight direction highlight middle values and cast shadow give fruit volume and grounding

Step 1

Concept

Form analysis should include light value and space relation. Exam tip: write form plus cast shadow.

Step 2

Why this answer is correct

The correct answer is A. प्रकाश दिशा हाइलाइट मध्य मान और पड़ी छाया मिलकर फल को आयतन और आधार देते हैं / Light direction highlight middle values and cast shadow give fruit volume and grounding. Form analysis should include light value and space relation. Exam tip: write form plus cast shadow.

Step 3

Exam Tip

रूप विश्लेषण में प्रकाश मान और स्थान संबंध शामिल करें। परीक्षा में form plus cast shadow लिखें।

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यदि रेखा अनुपस्थित है पर आकृति फिर भी स्पष्ट है तो कलाकार किस उच्च नियंत्रण का उपयोग कर रहा है?

If line is absent but figure is still clear what advanced control is the artist using?

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Correct Answer

A. मान रंग और किनारा विरोध का नियंत्रणControl of value colour and edge contrast

Step 1

Concept

Edge is not made only by drawn line. Exam tip: identify edge control.

Step 2

Why this answer is correct

The correct answer is A. मान रंग और किनारा विरोध का नियंत्रण / Control of value colour and edge contrast. Edge is not made only by drawn line. Exam tip: identify edge control.

Step 3

Exam Tip

किनारा केवल खींची रेखा से नहीं बनता। परीक्षा में edge control को पहचानें।

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यदि पृष्ठभूमि की तिरछी रेखाएं मुख्य पात्र के विरुद्ध जाती हैं तो क्या उन्नत प्रभाव बन सकता है?

If diagonal background lines go against the main character what advanced effect can form?

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Correct Answer

A. दृश्य संघर्ष और मानसिक तनावVisual conflict and mental tension

Step 1

Concept

Opposing directions can create tension. Exam tip: connect direction contrast with meaning.

Step 2

Why this answer is correct

The correct answer is A. दृश्य संघर्ष और मानसिक तनाव / Visual conflict and mental tension. Opposing directions can create tension. Exam tip: connect direction contrast with meaning.

Step 3

Exam Tip

विरोधी दिशाएं तनाव का भाव बना सकती हैं। परीक्षा में direction contrast को अर्थ से जोड़ें।

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असममित संतुलन में खाली स्थान का उन्नत महत्व क्या है?

What is the advanced importance of empty space in asymmetrical balance?

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Correct Answer

A. यह दृश्य आराम और भार संतुलन दोनों देता हैIt gives both visual rest and weight balance

Step 1

Concept

Empty space also plays a role in visual weight. Exam tip: treat negative space as a balance factor.

Step 2

Why this answer is correct

The correct answer is A. यह दृश्य आराम और भार संतुलन दोनों देता है / It gives both visual rest and weight balance. Empty space also plays a role in visual weight. Exam tip: treat negative space as a balance factor.

Step 3

Exam Tip

खाली स्थान भी दृश्य भार में भूमिका निभाता है। परीक्षा में negative space को balance factor मानें।

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यदि कई वस्तुएं मिलकर एक अदृश्य तीर जैसा मार्ग बनाती हैं तो यह किसका उन्नत उदाहरण है?

If many objects together form an invisible arrow-like path what advanced example is this?

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Correct Answer

A. संकेतित रेखा और दृष्टि मार्गImplied line and visual path

Step 1

Concept

Arrangement of objects can also create unseen direction. Exam tip: do not treat implied line as only drawn line.

Step 2

Why this answer is correct

The correct answer is A. संकेतित रेखा और दृष्टि मार्ग / Implied line and visual path. Arrangement of objects can also create unseen direction. Exam tip: do not treat implied line as only drawn line.

Step 3

Exam Tip

वस्तुओं की व्यवस्था भी अदृश्य दिशा बना सकती है। परीक्षा में implied line को केवल खींची रेखा न समझें।

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दूर वस्तुओं में बनावट कम करने का उच्च स्तरीय लाभ क्या है?

What is the advanced benefit of reducing texture in distant objects?

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Correct Answer

A. गहराई मजबूत होती है और अग्रभूमि पर ध्यान आता हैDepth strengthens and attention comes to foreground

Step 1

Concept

Reducing distant detail clarifies both distance and focus. Exam tip: treat detail control as a composition tool.

Step 2

Why this answer is correct

The correct answer is A. गहराई मजबूत होती है और अग्रभूमि पर ध्यान आता है / Depth strengthens and attention comes to foreground. Reducing distant detail clarifies both distance and focus. Exam tip: treat detail control as a composition tool.

Step 3

Exam Tip

दूर विवरण घटाने से दूरी और केंद्र दोनों स्पष्ट होते हैं। परीक्षा में विवरण नियंत्रण को रचना साधन मानें।

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किस वाक्य में शेड का उच्च स्तरीय उपयोग सही है?

Which sentence correctly shows advanced use of shade?

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Correct Answer

A. शेड रहस्य और गहराई बढ़ाने के लिए नियंत्रित अंधेरा देता हैShade gives controlled darkness for mystery and depth

Step 1

Concept

Shade can create atmosphere through dark value. Exam tip: treat shade as mood tool not only darkness.

Step 2

Why this answer is correct

The correct answer is A. शेड रहस्य और गहराई बढ़ाने के लिए नियंत्रित अंधेरा देता है / Shade gives controlled darkness for mystery and depth. Shade can create atmosphere through dark value. Exam tip: treat shade as mood tool not only darkness.

Step 3

Exam Tip

शेड गहरे मान से वातावरण बना सकता है। परीक्षा में शेड को केवल अंधेरा नहीं बल्कि भाव साधन मानें।

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पैटर्न और लय में उच्च स्तरीय अंतर किस वाक्य में सही है?

Which sentence gives the advanced difference between pattern and rhythm correctly?

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Correct Answer

A. पैटर्न दोहराव की व्यवस्था है और लय आंख की गति का अनुभव हैPattern is arrangement of repetition and rhythm is experience of eye movement

Step 1

Concept

Both are related but rhythm gives a feeling of movement. Exam tip: explain pattern and rhythm with different examples.

Step 2

Why this answer is correct

The correct answer is A. पैटर्न दोहराव की व्यवस्था है और लय आंख की गति का अनुभव है / Pattern is arrangement of repetition and rhythm is experience of eye movement. Both are related but rhythm gives a feeling of movement. Exam tip: explain pattern and rhythm with different examples.

Step 3

Exam Tip

दोनों जुड़े हैं पर लय गति महसूस कराती है। परीक्षा में pattern rhythm को अलग उदाहरण से समझाएं।

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ऋणात्मक स्थान को बहुत कम रखने से पोस्टर में कौन सी उच्च स्तरीय समस्या पैदा होती है?

What advanced problem is created in a poster by keeping too little negative space?

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Correct Answer

A. संदेश की दृश्य पदानुक्रम और पठनीयता कमजोर होती हैVisual hierarchy and readability of message weaken

Step 1

Concept

Too little empty space hides message in crowd. Exam tip: observe hierarchy and space in poster layout.

Step 2

Why this answer is correct

The correct answer is A. संदेश की दृश्य पदानुक्रम और पठनीयता कमजोर होती है / Visual hierarchy and readability of message weaken. Too little empty space hides message in crowd. Exam tip: observe hierarchy and space in poster layout.

Step 3

Exam Tip

कम खाली स्थान संदेश को भीड़ में दबा देता है। परीक्षा में poster layout में hierarchy और space देखें।

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चिचेन इत्ज़ा की कठिन पहचान में कौन सा सांस्कृतिक संपर्क प्रमुख माना जाता है?

In advanced identification of Chichen Itza which cultural contact is considered important?

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Correct Answer

A. माया और टोल्टेक प्रभावMaya and Toltec influence

Step 1

Concept

Chichen Itza has architectural signs of Maya and Toltec influences. For exams remember Mexico and Mesoamerica.

Step 2

Why this answer is correct

The correct answer is A. माया और टोल्टेक प्रभाव / Maya and Toltec influence. Chichen Itza has architectural signs of Maya and Toltec influences. For exams remember Mexico and Mesoamerica.

Step 3

Exam Tip

चिचेन इत्ज़ा में माया और टोल्टेक प्रभावों के स्थापत्य संकेत मिलते हैं। परीक्षा में मेक्सिको और मेसोअमेरिका याद रखें।

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किस घटना ने यूरोपीय संघ के निर्माण की प्रक्रिया को आगे बढ़ाया?

Which event advanced the process of forming the European Union?

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Correct Answer

C. मास्ट्रिख्ट संधिMaastricht Treaty

Step 1

Concept

The Maastricht Treaty gave a formal direction to the creation of the European Union. For exams, link it with European integration.

Step 2

Why this answer is correct

The correct answer is C. मास्ट्रिख्ट संधि / Maastricht Treaty. The Maastricht Treaty gave a formal direction to the creation of the European Union. For exams, link it with European integration.

Step 3

Exam Tip

मास्ट्रिख्ट संधि ने यूरोपीय संघ के निर्माण को औपचारिक दिशा दी। परीक्षा में इसे यूरोपीय एकीकरण से जोड़ें।

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मुहम्मद अली जिन्ना किस राजनीतिक सिद्धांत से पाकिस्तान की मांग को आगे बढ़ाते थे?

Muhammad Ali Jinnah advanced the demand for Pakistan through which political theory?

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A. द्विराष्ट्र सिद्धांतTwo-Nation Theory

Step 1

Concept

Jinnah advanced the demand for Pakistan based on the Two-Nation Theory. For exams connect it with the Partition of India.

Step 2

Why this answer is correct

The correct answer is A. द्विराष्ट्र सिद्धांत / Two-Nation Theory. Jinnah advanced the demand for Pakistan based on the Two-Nation Theory. For exams connect it with the Partition of India.

Step 3

Exam Tip

जिन्ना ने द्विराष्ट्र सिद्धांत के आधार पर पाकिस्तान की मांग को आगे बढ़ाया। परीक्षा में इसे भारत विभाजन से जोड़ें।

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हड़प्पा नगरों में उन्नत जल निकासी व्यवस्था किस विशेषता को दर्शाती है?

The advanced drainage system in Harappan cities indicates which feature?

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Correct Answer

C. संगठित नगर योजनाOrganized urban planning

Step 1

Concept

Harappan streets and drains were planned. For exams treat drainage as evidence of urban planning.

Step 2

Why this answer is correct

The correct answer is C. संगठित नगर योजना / Organized urban planning. Harappan streets and drains were planned. For exams treat drainage as evidence of urban planning.

Step 3

Exam Tip

हड़प्पा में सड़कें और नालियां योजनाबद्ध थीं। परीक्षा में जल निकासी को शहरी नियोजन का प्रमाण मानें।

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माया सभ्यता की उन्नत जानकारी किस विषय में प्रसिद्ध थी?

Maya civilization was famous for advanced knowledge in which subject?

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Correct Answer

A. खगोल और कैलेंडरAstronomy and calendar

Step 1

Concept

Maya civilization was famous for astronomy and calendar knowledge. In exams, link it with Mesoamerica.

Step 2

Why this answer is correct

The correct answer is A. खगोल और कैलेंडर / Astronomy and calendar. Maya civilization was famous for astronomy and calendar knowledge. In exams, link it with Mesoamerica.

Step 3

Exam Tip

माया सभ्यता खगोल और कैलेंडर ज्ञान के लिए प्रसिद्ध थी। परीक्षा में इसे मेसोअमेरिका से जोड़ें।

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किस प्राचीन सभ्यता में शून्य की अवधारणा का उन्नत उपयोग माया कैलेंडर में दिखता है?

In which ancient civilization is an advanced use of zero seen in the Maya calendar?

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Correct Answer

A. मायाMaya

Step 1

Concept

Maya civilization had an advanced counting and calendar system. Link it with astronomical knowledge in exams.

Step 2

Why this answer is correct

The correct answer is A. माया / Maya. Maya civilization had an advanced counting and calendar system. Link it with astronomical knowledge in exams.

Step 3

Exam Tip

माया सभ्यता में गणना और कैलेंडर प्रणाली उन्नत थी। परीक्षा में इसे खगोल ज्ञान से जोड़ें।

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तामलुक राष्ट्रीय सरकार को उन्नत स्थानीय प्रतिरोध क्यों कहा जाता है?

Why is the Tamluk National Government called advanced local resistance?

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Correct Answer

A. क्योंकि उसने ब्रिटिश सत्ता के समानांतर स्थानीय व्यवस्था बनाईBecause it created a local arrangement parallel to British authority

Step 1

Concept

The Tamluk National Government was an attempt at local self-rule during Quit India. Remember it among parallel governments.

Step 2

Why this answer is correct

The correct answer is A. क्योंकि उसने ब्रिटिश सत्ता के समानांतर स्थानीय व्यवस्था बनाई / Because it created a local arrangement parallel to British authority. The Tamluk National Government was an attempt at local self-rule during Quit India. Remember it among parallel governments.

Step 3

Exam Tip

तामलुक राष्ट्रीय सरकार भारत छोड़ो आंदोलन के दौरान स्थानीय स्वशासन की कोशिश थी। इसे समानांतर सरकारों में याद रखें।

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तामलुक राष्ट्रीय सरकार किस आंदोलन की उन्नत स्थानीय अभिव्यक्ति थी?

The Tamluk National Government was an advanced local expression of which movement?

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Correct Answer

C. भारत छोड़ो आंदोलनQuit India Movement

Step 1

Concept

The Tamluk National Government arose in the background of the Quit India Movement. Remember it as an example of parallel government.

Step 2

Why this answer is correct

The correct answer is C. भारत छोड़ो आंदोलन / Quit India Movement. The Tamluk National Government arose in the background of the Quit India Movement. Remember it as an example of parallel government.

Step 3

Exam Tip

तामलुक राष्ट्रीय सरकार भारत छोड़ो आंदोलन की पृष्ठभूमि में बनी थी। इसे समानांतर सरकारों के उदाहरण में याद रखें।

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मुगल चित्रकला में प्रकृति और व्यक्तिचित्रण किस शासक के काल में विशेष रूप से उन्नत हुआ?

Mughal painting especially advanced in naturalism and portraiture under which ruler?

Explanation opens after your attempt
Correct Answer

C. जहांगीरJahangir

Step 1

Concept

Under Jahangir natural detail and portraiture in painting developed greatly. Exam tip: connect artistic features with reigns.

Step 2

Why this answer is correct

The correct answer is C. जहांगीर / Jahangir. Under Jahangir natural detail and portraiture in painting developed greatly. Exam tip: connect artistic features with reigns.

Step 3

Exam Tip

जहांगीर के समय चित्रकला में प्राकृतिक विवरण और व्यक्तिचित्रण निखरा। परीक्षा में कला की विशेषताओं को शासनकाल से जोड़ें।

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उत्तरमेरूर अभिलेख में कुडवोलै प्रणाली का उल्लेख किस विषय का उन्नत प्रमाण है?

The mention of Kudavolai system in the Uttaramerur inscription is advanced evidence of which subject?

Explanation opens after your attempt
Correct Answer

A. चोल ग्राम प्रशासन और चयन प्रक्रियाChola village administration and selection process

Step 1

Concept

Kudavolai system was linked with selection rules in Chola village assemblies. For exams, remember it as a source for local self-government.

Step 2

Why this answer is correct

The correct answer is A. चोल ग्राम प्रशासन और चयन प्रक्रिया / Chola village administration and selection process. Kudavolai system was linked with selection rules in Chola village assemblies. For exams, remember it as a source for local self-government.

Step 3

Exam Tip

कुडवोलै प्रणाली चोल ग्रामसभा में चयन नियमों से जुड़ी थी। परीक्षा में स्थानीय स्वशासन के स्रोत के रूप में इसे याद रखें।

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हड़प्पाई बाटों की प्रणाली किस विशेषता के कारण उन्नत मानी जाती है?

Why is the Harappan system of weights considered advanced?

Explanation opens after your attempt
Correct Answer

C. इसमें मानकीकरण और अनुपात थाIt had standardization and proportion

Step 1

Concept

Harappan weights were standardized and likely helped trade. For exams, treat them as evidence of economic organization.

Step 2

Why this answer is correct

The correct answer is C. इसमें मानकीकरण और अनुपात था / It had standardization and proportion. Harappan weights were standardized and likely helped trade. For exams, treat them as evidence of economic organization.

Step 3

Exam Tip

हड़प्पाई बाट मानकीकृत थे और व्यापार में सहायक रहे होंगे। परीक्षा में इन्हें आर्थिक संगठन का प्रमाण मानें।

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जिबरेलिन और साइटोकाइनिन की भूमिकाओं से पौध वृद्धि के बारे में कौन सा उन्नत निष्कर्ष निकलेगा?

What advanced conclusion about plant growth follows from the roles of gibberellin and cytokinin?

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Correct Answer

A. वृद्धि में कोशिका विभाजन और कोशिका लंबाई दोनों अलग अलग नियंत्रण से प्रभावित होते हैंGrowth is affected by different controls of cell division and cell elongation

Step 1

Concept

Gibberellin is linked with stem growth.

Step 2

Why this answer is correct

Cytokinin promotes cell division.

Step 3

Exam Tip

This shows plant growth is controlled by balance of several hormones. चरण 1: जिबरेलिन तने की वृद्धि से जुड़ा है। चरण 2: साइटोकाइनिन कोशिका विभाजन को बढ़ावा देता है। चरण 3: इससे स्पष्ट है कि पौध वृद्धि कई हार्मोन के संतुलन से नियंत्रित होती है।

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किस वर्ग ने 1848 में संविधान और राष्ट्रीय एकीकरण की मांग को आगे बढ़ाया?

Which class advanced the demand for constitution and national unification in 1848?

Explanation opens after your attempt
Correct Answer

A. शिक्षित मध्यम वर्गEducated middle class

Step 1

Concept

In 1848, the educated middle class was politically active.

Step 2

Why this answer is correct

It raised demands for constitution and national unity.

Step 3

Exam Tip

See this class as a carrier of liberal nationalism. चरण 1: 1848 में शिक्षित मध्यम वर्ग राजनीतिक रूप से सक्रिय था। चरण 2: उसने संविधान और राष्ट्रीय एकता की मांग उठाई। चरण 3: इस वर्ग को उदारवादी राष्ट्रवाद का वाहक मानें।

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दूध का दही बनना कठिन प्रश्नों में रासायनिक परिवर्तन क्यों माना जाता है?

Why is conversion of milk into curd considered a chemical change in advanced questions?

Explanation opens after your attempt
Correct Answer

A. क्योंकि दही नए गुणों वाला पदार्थ हैBecause curd is a substance with new properties

Step 1

Concept

Taste and properties change when milk becomes curd.

Step 2

Why this answer is correct

A new substance forms which cannot be easily changed back to milk.

Step 3

Exam Tip

Therefore it is a chemical change. चरण 1: दूध से दही बनने पर स्वाद और गुण बदलते हैं। चरण 2: नया पदार्थ बनता है जिसे आसानी से मूल दूध नहीं बनाया जा सकता। चरण 3: इसलिए यह रासायनिक परिवर्तन है।

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द्वि विस्थापन अभिक्रिया की कठिन पहचान कौन सी है?

What is the advanced identification of a double displacement reaction?

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Correct Answer

A. दो यौगिकों के धनायन और ऋणायन नए युग्म बनाते हैंCations and anions of two compounds form new pairs

Step 1

Concept

Double displacement involves two compounds.

Step 2

Why this answer is correct

Their ions exchange and form new pairs.

Step 3

Exam Tip

New products are formed from these new pairs. चरण 1: द्वि विस्थापन में दो यौगिक शामिल होते हैं। चरण 2: उनके आयन आपस में बदलकर नए युग्म बनाते हैं। चरण 3: नए युग्मों से नए उत्पाद बनते हैं।

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संख्या रेखा पर \(x^2-2x=0\) के शून्यक कौन से बिंदु होंगे?

Which points will be the zeros of \(x^2-2x=0\) on the number line?

Explanation opens after your attempt
Correct Answer

A. (0) और (2)(0) and (2)

Step 1

Concept

(x-2-2x=x(x-2)), so the zeros are (0) and (2). In exams, taking a common factor is an easy method.

Step 2

Why this answer is correct

The correct answer is A. (0) और (2) / (0) and (2). (x-2-2x=x(x-2)), so the zeros are (0) and (2). In exams, taking a common factor is an easy method.

Step 3

Exam Tip

(x-2-2x=x(x-2)), इसलिए शून्यक (0) और (2) हैं। परीक्षा में सामान्य गुणनखंड निकालना आसान तरीका है।

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कौन-सा विकल्प \(\frac{x^{12}-4096}{x^{6}-64}\) का सरल रूप है, जहाँ \(x^{6}\neq64\)?

Which option is the simplified form of \(\frac{x^{12}-4096}{x^{6}-64}\), where \(x^{6}\neq64\)?

Explanation opens after your attempt
Correct Answer

B. \(x^{6}+64\)

Step 1

Concept

Since (x^{12}-4096=\(x^{6}\)^{2}-64^{2}=\(x^{6}-64\)\(x^{6}+64\)), cancelling the common factor gives \(x^{6}+64\).

Step 2

Why this answer is correct

The correct answer is B. \(x^{6}+64\). Since (x^{12}-4096=\(x^{6}\)^{2}-64^{2}=\(x^{6}-64\)\(x^{6}+64\)), cancelling the common factor gives \(x^{6}+64\).

Step 3

Exam Tip

(x^{12}-4096=\(x^{6}\)^{2}-64^{2}=\(x^{6}-64\)\(x^{6}+64\))। समान गुणनखंड कटने पर \(x^{6}+64\) मिलता है।

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\(\frac{x^{10}-1024}{x^{5}-32}\) का सरल रूप क्या है, जहाँ \(x^{5}\neq32\)?

What is the simplified form of \(\frac{x^{10}-1024}{x^{5}-32}\), where \(x^{5}\neq32\)?

Explanation opens after your attempt
Correct Answer

B. \(x^{5}+32\)

Step 1

Concept

We use (x^{10}-1024=\(x^{5}\)^{2}-32^{2}=\(x^{5}-32\)\(x^{5}+32\)). Cancelling the common factor leaves \(x^{5}+32\).

Step 2

Why this answer is correct

The correct answer is B. \(x^{5}+32\). We use (x^{10}-1024=\(x^{5}\)^{2}-32^{2}=\(x^{5}-32\)\(x^{5}+32\)). Cancelling the common factor leaves \(x^{5}+32\).

Step 3

Exam Tip

(x^{10}-1024=\(x^{5}\)^{2}-32^{2}=\(x^{5}-32\)\(x^{5}+32\))। समान गुणनखंड कटने पर \(x^{5}+32\) बचता है।

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यदि \(4^{x}+4^{x+1}+4^{x+2}=336\), तो (x) का मान क्या है?

If \(4^{x}+4^{x+1}+4^{x+2}=336\), what is the value of (x)?

Explanation opens after your attempt
Correct Answer

B. (2)

Step 1

Concept

Factoring \(4^{x}\), we get (4^{x}(1+4+16)=336). Thus \(21\cdot4^{x}=336\), \(4^{x}=16\), and (x=2).

Step 2

Why this answer is correct

The correct answer is B. (2). Factoring \(4^{x}\), we get (4^{x}(1+4+16)=336). Thus \(21\cdot4^{x}=336\), \(4^{x}=16\), and (x=2).

Step 3

Exam Tip

सामान्य पद \(4^{x}\) लेने पर (4^{x}(1+4+16)=336) मिलता है। इसलिए \(21\cdot4^{x}=336\), \(4^{x}=16\), और (x=2)।

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यदि \(6^{x+1}-6^{x}=900\), तो (x) का मान क्या है?

If \(6^{x+1}-6^{x}=900\), what is the value of (x)?

Explanation opens after your attempt
Correct Answer

B. (3)

Step 1

Concept

Here \(6^{x+1}-6^{x}=5\cdot6^{x}=900\), so \(6^{x}=180\), which is not a listed integral power. Therefore none of the listed options is correct.

Step 2

Why this answer is correct

The correct answer is B. (3). Here \(6^{x+1}-6^{x}=5\cdot6^{x}=900\), so \(6^{x}=180\), which is not a listed integral power. Therefore none of the listed options is correct.

Step 3

Exam Tip

\(6^{x+1}-6^{x}=6\cdot6^{x}-6^{x}=5\cdot6^{x}=900\), इसलिए \(6^{x}=180\) नहीं बनता। इसलिए दिए विकल्पों में कोई भी सही नहीं है।

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कौन-सा विकल्प \(\frac{x^{8}-81}{x^{4}-9}\) का सरल रूप है, जहाँ \(x^{4}\neq9\)?

Which option is the simplified form of \(\frac{x^{8}-81}{x^{4}-9}\), where \(x^{4}\neq9\)?

Explanation opens after your attempt
Correct Answer

B. \(x^{4}+9\)

Step 1

Concept

Since (x^{8}-81=\(x^{4}\)^{2}-9^{2}=\(x^{4}-9\)\(x^{4}+9\)), cancelling the common factor gives \(x^{4}+9\).

Step 2

Why this answer is correct

The correct answer is B. \(x^{4}+9\). Since (x^{8}-81=\(x^{4}\)^{2}-9^{2}=\(x^{4}-9\)\(x^{4}+9\)), cancelling the common factor gives \(x^{4}+9\).

Step 3

Exam Tip

(x^{8}-81=\(x^{4}\)^{2}-9^{2}=\(x^{4}-9\)\(x^{4}+9\))। समान गुणनखंड कटने पर \(x^{4}+9\) मिलता है।

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\(\frac{x^{6}-64}{x^{3}-8}\) का सरल रूप क्या है, जहाँ \(x^{3}\neq8\)?

What is the simplified form of \(\frac{x^{6}-64}{x^{3}-8}\), where \(x^{3}\neq8\)?

Explanation opens after your attempt
Correct Answer

B. \(x^{3}+8\)

Step 1

Concept

We use (x^{6}-64=\(x^{3}\)^{2}-8^{2}=\(x^{3}-8\)\(x^{3}+8\)). Cancelling the common factor leaves \(x^{3}+8\).

Step 2

Why this answer is correct

The correct answer is B. \(x^{3}+8\). We use (x^{6}-64=\(x^{3}\)^{2}-8^{2}=\(x^{3}-8\)\(x^{3}+8\)). Cancelling the common factor leaves \(x^{3}+8\).

Step 3

Exam Tip

(x^{6}-64=\(x^{3}\)^{2}-8^{2}=\(x^{3}-8\)\(x^{3}+8\))। समान गुणनखंड कटने पर \(x^{3}+8\) बचता है।

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यदि \(3^{x}+3^{x+1}+3^{x+2}=117\), तो (x) का मान क्या है?

If \(3^{x}+3^{x+1}+3^{x+2}=117\), what is the value of (x)?

Explanation opens after your attempt
Correct Answer

B. (2)

Step 1

Concept

Factoring \(3^{x}\), we get (3^{x}(1+3+9)=117). Thus \(13\cdot3^{x}=117\), \(3^{x}=9\), and (x=2).

Step 2

Why this answer is correct

The correct answer is B. (2). Factoring \(3^{x}\), we get (3^{x}(1+3+9)=117). Thus \(13\cdot3^{x}=117\), \(3^{x}=9\), and (x=2).

Step 3

Exam Tip

सामान्य पद \(3^{x}\) लेने पर (3^{x}(1+3+9)=117) मिलता है। इसलिए \(13\cdot3^{x}=117\), \(3^{x}=9\), और (x=2)।

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यदि \(4^{x+1}-4^{x}=192\), तो (x) का मान क्या है?

If \(4^{x+1}-4^{x}=192\), what is the value of (x)?

Explanation opens after your attempt
Correct Answer

B. (3)

Step 1

Concept

Here \(4^{x+1}-4^{x}=4\cdot4^{x}-4^{x}=3\cdot4^{x}=192\), so \(4^{x}=64\). Since \(64=4^{3}\), (x=3).

Step 2

Why this answer is correct

The correct answer is B. (3). Here \(4^{x+1}-4^{x}=4\cdot4^{x}-4^{x}=3\cdot4^{x}=192\), so \(4^{x}=64\). Since \(64=4^{3}\), (x=3).

Step 3

Exam Tip

\(4^{x+1}-4^{x}=4\cdot4^{x}-4^{x}=3\cdot4^{x}=192\), इसलिए \(4^{x}=64\)। \(64=4^{3}\), इसलिए (x=3)।

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कौन-सा विकल्प \(\frac{x^{6}-1}{x^{3}-1}\) का सरल रूप है, जहाँ \(x^{3}\neq1\)?

Which option is the simplified form of \(\frac{x^{6}-1}{x^{3}-1}\), where \(x^{3}\neq1\)?

Explanation opens after your attempt
Correct Answer

A. \(x^{3}+1\)

Step 1

Concept

Since (x^{6}-1=\(x^{3}-1\)\(x^{3}+1\)), cancelling the common factor gives \(x^{3}+1\). In exams, recognize the \(A^{2}-B^{2}\) form.

Step 2

Why this answer is correct

The correct answer is A. \(x^{3}+1\). Since (x^{6}-1=\(x^{3}-1\)\(x^{3}+1\)), cancelling the common factor gives \(x^{3}+1\). In exams, recognize the \(A^{2}-B^{2}\) form.

Step 3

Exam Tip

(x^{6}-1=\(x^{3}-1\)\(x^{3}+1\)), इसलिए समान गुणनखंड कटने पर \(x^{3}+1\) मिलता है। परीक्षा में \(A^{2}-B^{2}\) रूप पहचानें।

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(\frac{\(x^{4}-16\)}{\(x^{2}-4\)}) का सरल रूप क्या है, जहाँ \(x\neq2\) और \(x\neq-2\)?

What is the simplified form of (\frac{\(x^{4}-16\)}{\(x^{2}-4\)}), where \(x\neq2\) and \(x\neq-2\)?

Explanation opens after your attempt
Correct Answer

A. \(x^{2}+4\)

Step 1

Concept

Since (x^{4}-16=\(x^{2}-4\)\(x^{2}+4\)), cancelling the common factor leaves \(x^{2}+4\). In exams, recognize the difference of squares.

Step 2

Why this answer is correct

The correct answer is A. \(x^{2}+4\). Since (x^{4}-16=\(x^{2}-4\)\(x^{2}+4\)), cancelling the common factor leaves \(x^{2}+4\). In exams, recognize the difference of squares.

Step 3

Exam Tip

(x^{4}-16=\(x^{2}-4\)\(x^{2}+4\)), इसलिए समान गुणनखंड कटने पर \(x^{2}+4\) बचता है। परीक्षा में वर्गों के अंतर को पहचानें।

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यदि \(2^{x}+2^{x+1}+2^{x+2}=112\), तो (x) का मान क्या है?

If \(2^{x}+2^{x+1}+2^{x+2}=112\), what is the value of (x)?

Explanation opens after your attempt
Correct Answer

B. (4)

Step 1

Concept

Factoring \(2^{x}\), we get (2^{x}(1+2+4)=112), so \(7\cdot2^{x}=112\). Thus \(2^{x}=16\) and (x=4).

Step 2

Why this answer is correct

The correct answer is B. (4). Factoring \(2^{x}\), we get (2^{x}(1+2+4)=112), so \(7\cdot2^{x}=112\). Thus \(2^{x}=16\) and (x=4).

Step 3

Exam Tip

सामान्य पद \(2^{x}\) लेने पर (2^{x}(1+2+4)=112), इसलिए \(7\cdot2^{x}=112\)। इससे \(2^{x}=16\) और (x=4)।

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यदि \(5^{x+2}-5^{x}=600\), तो (x) का मान क्या है?

If \(5^{x+2}-5^{x}=600\), what is the value of (x)?

Explanation opens after your attempt
Correct Answer

B. (2)

Step 1

Concept

Here \(5^{x+2}-5^{x}=25\cdot5^{x}-5^{x}=24\cdot5^{x}=600\), so \(5^{x}=25=5^{2}\). In exams, factor out the common power.

Step 2

Why this answer is correct

The correct answer is B. (2). Here \(5^{x+2}-5^{x}=25\cdot5^{x}-5^{x}=24\cdot5^{x}=600\), so \(5^{x}=25=5^{2}\). In exams, factor out the common power.

Step 3

Exam Tip

\(5^{x+2}-5^{x}=25\cdot5^{x}-5^{x}=24\cdot5^{x}=600\), इसलिए \(5^{x}=25=5^{2}\)। परीक्षा में सामान्य घात को बाहर निकालें।

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\(\frac{x^{5}-x^{3}}{x^{3}}\) का सरल रूप क्या है, जहाँ \(x\neq0\)?

What is the simplified form of \(\frac{x^{5}-x^{3}}{x^{3}}\), where \(x\neq0\)?

Explanation opens after your attempt
Correct Answer

A. \(x^{2}-1\)

Step 1

Concept

(\frac{x^{5}-x^{3}}{x^{3}}=\frac{x^{3}\(x^{2}-1\)}{x^{3}}=x^{2}-1). In exams, take out the common factor first.

Step 2

Why this answer is correct

The correct answer is A. \(x^{2}-1\). (\frac{x^{5}-x^{3}}{x^{3}}=\frac{x^{3}\(x^{2}-1\)}{x^{3}}=x^{2}-1). In exams, take out the common factor first.

Step 3

Exam Tip

(\frac{x^{5}-x^{3}}{x^{3}}=\frac{x^{3}\(x^{2}-1\)}{x^{3}}=x^{2}-1)। परीक्षा में पहले सामान्य गुणनखंड बाहर निकालें।

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किस विकल्प में (\left\(x^{2}-4\right\)) को सही रूप में लिखा गया है?

Which option correctly writes (\left\(x^{2}-4\right\))?

Explanation opens after your attempt
Correct Answer

A. \((x-2)(x+2)\)

Step 1

Concept

We use (x^{2}-4=x^{2}-2^{2}=(x-2)(x+2)). In exams, remember the difference of squares form (\(a^{2}-b^{2}\)).

Step 2

Why this answer is correct

The correct answer is A. \((x-2)(x+2)\). We use (x^{2}-4=x^{2}-2^{2}=(x-2)(x+2)). In exams, remember the difference of squares form (\(a^{2}-b^{2}\)).

Step 3

Exam Tip

(x^{2}-4=x^{2}-2^{2}=(x-2)(x+2))। परीक्षा में वर्गों के अंतर की पहचान (\(a^{2}-b^{2}\)) याद रखें।

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यदि \(2^{x+1}+2^{x}=48\), तो (x) का मान क्या है?

If \(2^{x+1}+2^{x}=48\), what is the value of (x)?

Explanation opens after your attempt
Correct Answer

B. (4)

Step 1

Concept

Here \(2^{x+1}+2^{x}=2\cdot2^{x}+2^{x}=3\cdot2^{x}=48\), so \(2^{x}=16=2^{4}\). In exams, factor the common power \(2^{x}\).

Step 2

Why this answer is correct

The correct answer is B. (4). Here \(2^{x+1}+2^{x}=2\cdot2^{x}+2^{x}=3\cdot2^{x}=48\), so \(2^{x}=16=2^{4}\). In exams, factor the common power \(2^{x}\).

Step 3

Exam Tip

\(2^{x+1}+2^{x}=2\cdot2^{x}+2^{x}=3\cdot2^{x}=48\), इसलिए \(2^{x}=16=2^{4}\)। परीक्षा में सामान्य घात \(2^{x}\) बाहर लें।

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\(100x^2-121y^2\) का गुणनखंड रूप क्या है?

What is the factorized form of \(100x^2-121y^2\)?

Explanation opens after your attempt
Correct Answer

A. ((10x-11y)(10x+11y))

Step 1

Concept

(100x-2-121y-2=(10x)2-(11y)2). Apply the difference of squares rule (\(a^2-b^2\)=(a-b)(a+b)).

Step 2

Why this answer is correct

The correct answer is A. ((10x-11y)(10x+11y)). (100x-2-121y-2=(10x)2-(11y)2). Apply the difference of squares rule (\(a^2-b^2\)=(a-b)(a+b)).

Step 3

Exam Tip

(100x-2-121y-2=(10x)2-(11y)2) है। अंतर के वर्ग का नियम (\(a^2-b^2\)=(a-b)(a+b)) लगाएँ।

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\(4x^5+12x^4\) का सामान्य गुणनखंड निकालने पर क्या मिलेगा?

What is obtained by taking the common factor from \(4x^5+12x^4\)?

Explanation opens after your attempt
Correct Answer

A. (4x-4(x+3))

Step 1

Concept

The common factor in both terms is \(4x^4\). Hence the form is (4x-4(x+3)).

Step 2

Why this answer is correct

The correct answer is A. (4x-4(x+3)). The common factor in both terms is \(4x^4\). Hence the form is (4x-4(x+3)).

Step 3

Exam Tip

दोनों पदों में सामान्य गुणनखंड \(4x^4\) है। इसलिए रूप (4x-4(x+3)) है।

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यदि (a=2) और (b=5) है तो \(a^2b+ab^2\) का मान क्या है?

If (a=2) and (b=5), what is the value of \(a^2b+ab^2\)?

Explanation opens after your attempt
Correct Answer

B. (70)

Step 1

Concept

(a-2b+ab-2=ab(a+b)). Thus \(2\cdot5\cdot7=70\).

Step 2

Why this answer is correct

The correct answer is B. (70). (a-2b+ab-2=ab(a+b)). Thus \(2\cdot5\cdot7=70\).

Step 3

Exam Tip

(a-2b+ab-2=ab(a+b)) है। इसलिए \(2\cdot5\cdot7=70\) है।

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\(x^2-24x+144\) किसके बराबर है?

What is \(x^2-24x+144\) equal to?

Explanation opens after your attempt
Correct Answer

A. ((x-12)2)

Step 1

Concept

This is of the form \(x^2-2\cdot x\cdot12+12^2\). Hence ((x-12)2) is correct.

Step 2

Why this answer is correct

The correct answer is A. ((x-12)2). This is of the form \(x^2-2\cdot x\cdot12+12^2\). Hence ((x-12)2) is correct.

Step 3

Exam Tip

यह \(x^2-2\cdot x\cdot12+12^2\) का रूप है। इसलिए ((x-12)2) सही है।

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\(121x^2-144\) का गुणनखंड रूप क्या है?

What is the factorized form of \(121x^2-144\)?

Explanation opens after your attempt
Correct Answer

A. ((11x-12)(11x+12))

Step 1

Concept

(121x-2-144=(11x)2-122). Apply the difference of squares identity.

Step 2

Why this answer is correct

The correct answer is A. ((11x-12)(11x+12)). (121x-2-144=(11x)2-122). Apply the difference of squares identity.

Step 3

Exam Tip

(121x-2-144=(11x)2-122) है। अंतर के वर्ग का नियम लगाएँ।

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\(81x^2-100y^2\) का गुणनखंड रूप क्या है?

What is the factorized form of \(81x^2-100y^2\)?

Explanation opens after your attempt
Correct Answer

A. ((9x-10y)(9x+10y))

Step 1

Concept

(81x-2-100y-2=(9x)2-(10y)2). Apply the difference of squares rule (\(a^2-b^2\)=(a-b)(a+b)).

Step 2

Why this answer is correct

The correct answer is A. ((9x-10y)(9x+10y)). (81x-2-100y-2=(9x)2-(10y)2). Apply the difference of squares rule (\(a^2-b^2\)=(a-b)(a+b)).

Step 3

Exam Tip

(81x-2-100y-2=(9x)2-(10y)2) है। अंतर के वर्ग का नियम (\(a^2-b^2\)=(a-b)(a+b)) लगाएँ।

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\(3x^4+9x^3\) का सामान्य गुणनखंड निकालने पर क्या मिलेगा?

What is obtained by taking the common factor from \(3x^4+9x^3\)?

Explanation opens after your attempt
Correct Answer

A. (3x-3(x+3))

Step 1

Concept

The common factor in both terms is \(3x^3\). Hence the form is (3x-3(x+3)).

Step 2

Why this answer is correct

The correct answer is A. (3x-3(x+3)). The common factor in both terms is \(3x^3\). Hence the form is (3x-3(x+3)).

Step 3

Exam Tip

दोनों पदों में सामान्य गुणनखंड \(3x^3\) है। इसलिए रूप (3x-3(x+3)) है।

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यदि (a=4) और (b=1) है तो \(a^2b+ab^2\) का मान क्या है?

If (a=4) and (b=1), what is the value of \(a^2b+ab^2\)?

Explanation opens after your attempt
Correct Answer

C. (20)

Step 1

Concept

(a-2b+ab-2=ab(a+b)). Thus \(4\cdot1\cdot5=20\).

Step 2

Why this answer is correct

The correct answer is C. (20). (a-2b+ab-2=ab(a+b)). Thus \(4\cdot1\cdot5=20\).

Step 3

Exam Tip

(a-2b+ab-2=ab(a+b)) है। इसलिए \(4\cdot1\cdot5=20\) है।

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\(x^2-20x+100\) किसके बराबर है?

What is \(x^2-20x+100\) equal to?

Explanation opens after your attempt
Correct Answer

A. ((x-10)2)

Step 1

Concept

This is \(x^2-2\cdot x\cdot10+10^2\). Hence ((x-10)2) is correct.

Step 2

Why this answer is correct

The correct answer is A. ((x-10)2). This is \(x^2-2\cdot x\cdot10+10^2\). Hence ((x-10)2) is correct.

Step 3

Exam Tip

यह \(x^2-2\cdot x\cdot10+10^2\) है। इसलिए ((x-10)2) सही है।

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\(64x^2-81\) का गुणनखंड रूप क्या है?

What is the factorized form of \(64x^2-81\)?

Explanation opens after your attempt
Correct Answer

A. ((8x-9)(8x+9))

Step 1

Concept

(64x-2-81=(8x)2-92). Apply the difference of squares identity.

Step 2

Why this answer is correct

The correct answer is A. ((8x-9)(8x+9)). (64x-2-81=(8x)2-92). Apply the difference of squares identity.

Step 3

Exam Tip

(64x-2-81=(8x)2-92) है। अंतर के वर्ग का नियम लगाएँ।

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\(2x^3+6x^2\) का सामान्य गुणनखंड निकालने पर क्या मिलेगा?

What is obtained by taking the common factor from \(2x^3+6x^2\)?

Explanation opens after your attempt
Correct Answer

A. (2x-2(x+3))

Step 1

Concept

The common factor in both terms is \(2x^2\). Hence the form is (2x-2(x+3)).

Step 2

Why this answer is correct

The correct answer is A. (2x-2(x+3)). The common factor in both terms is \(2x^2\). Hence the form is (2x-2(x+3)).

Step 3

Exam Tip

दोनों पदों में सामान्य गुणनखंड \(2x^2\) है। इसलिए रूप (2x-2(x+3)) है।

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यदि (a=3) और (b=2) है तो \(a^2b+ab^2\) का मान क्या है?

If (a=3) and (b=2), what is the value of \(a^2b+ab^2\)?

Explanation opens after your attempt
Correct Answer

B. (30)

Step 1

Concept

(a-2b+ab-2=ab(a+b)). Thus \(3\cdot2\cdot5=30\).

Step 2

Why this answer is correct

The correct answer is B. (30). (a-2b+ab-2=ab(a+b)). Thus \(3\cdot2\cdot5=30\).

Step 3

Exam Tip

(a-2b+ab-2=ab(a+b)) है। इसलिए \(3\cdot2\cdot5=30\) है।

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\(x^2-16x+64\) किसके बराबर है?

What is \(x^2-16x+64\) equal to?

Explanation opens after your attempt
Correct Answer

A. ((x-8)2)

Step 1

Concept

This is of the form \(x^2-2\cdot x\cdot8+8^2\). Hence ((x-8)2) is correct.

Step 2

Why this answer is correct

The correct answer is A. ((x-8)2). This is of the form \(x^2-2\cdot x\cdot8+8^2\). Hence ((x-8)2) is correct.

Step 3

Exam Tip

यह \(x^2-2\cdot x\cdot8+8^2\) का रूप है। इसलिए ((x-8)2) सही है।

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\(49x^2-64\) का गुणनखंड रूप क्या है?

What is the factorized form of \(49x^2-64\)?

Explanation opens after your attempt
Correct Answer

A. ((7x-8)(7x+8))

Step 1

Concept

(49x-2-64=(7x)2-82). Apply the difference of squares identity.

Step 2

Why this answer is correct

The correct answer is A. ((7x-8)(7x+8)). (49x-2-64=(7x)2-82). Apply the difference of squares identity.

Step 3

Exam Tip

(49x-2-64=(7x)2-82) है। अंतर के वर्ग का नियम लगाएँ।

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यदि \(\frac{231}{2\cdot3\cdot5^2\cdot7\cdot11}\) को सरलतम रूप में लिखा जाए, तो दशमलव प्रसार कैसा होगा?

If \(\frac{231}{2\cdot3\cdot5^2\cdot7\cdot11}\) is written in lowest form, what type of decimal expansion will it have?

Explanation opens after your attempt
Correct Answer

A. समाप्तTerminating

Step 1

Concept

After cancelling \(231=3\cdot7\cdot11\), the denominator left is \(2\cdot5^2\). Therefore the decimal terminates.

Step 2

Why this answer is correct

The correct answer is A. समाप्त / Terminating. After cancelling \(231=3\cdot7\cdot11\), the denominator left is \(2\cdot5^2\). Therefore the decimal terminates.

Step 3

Exam Tip

\(231=3\cdot7\cdot11\) कटने के बाद हर में \(2\cdot5^2\) बचता है। इसलिए दशमलव समाप्त होगा।

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यदि \(\frac{154}{2\cdot5^2\cdot7\cdot11}\) को सरलतम रूप में लिखा जाए, तो उसका दशमलव प्रसार कैसा होगा?

If \(\frac{154}{2\cdot5^2\cdot7\cdot11}\) is written in lowest form, what type of decimal expansion will it have?

Explanation opens after your attempt
Correct Answer

A. समाप्त दशमलवTerminating decimal

Step 1

Concept

\(154=2\cdot7\cdot11\), so after cancellation only \(5^2\) remains in the denominator. In exams decide from the denominator in lowest form.

Step 2

Why this answer is correct

The correct answer is A. समाप्त दशमलव / Terminating decimal. \(154=2\cdot7\cdot11\), so after cancellation only \(5^2\) remains in the denominator. In exams decide from the denominator in lowest form.

Step 3

Exam Tip

\(154=2\cdot7\cdot11\), इसलिए कटने के बाद हर में केवल \(5^2\) बचता है। परीक्षा में निर्णय हमेशा सरलतम रूप के हर से करें।

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किस भिन्न का दशमलव प्रसार समाप्त होगा?

Which fraction will have a terminating decimal expansion?

Explanation opens after your attempt
Correct Answer

A. \(\frac{63}{2^5\cdot5^2\cdot7}\)

Step 1

Concept

In \(\frac{63}{2^5\cdot5^2\cdot7}\), after cancelling (63) and (7), only (2) and (5) remain in the denominator. In exams reduce the fraction first.

Step 2

Why this answer is correct

The correct answer is A. \(\frac{63}{2^5\cdot5^2\cdot7}\). In \(\frac{63}{2^5\cdot5^2\cdot7}\), after cancelling (63) and (7), only (2) and (5) remain in the denominator. In exams reduce the fraction first.

Step 3

Exam Tip

\(\frac{63}{2^5\cdot5^2\cdot7}\) में (63) और (7) कटने के बाद हर में केवल (2) और (5) बचते हैं। परीक्षा में पहले भिन्न को सरलतम रूप में लाएं।

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भिन्न \(\frac{91}{2^3\cdot5^2\cdot13}\) के दशमलव प्रसार के बारे में सही कथन कौन सा है?

Which statement is correct about the decimal expansion of \(\frac{91}{2^3\cdot5^2\cdot13}\)?

Explanation opens after your attempt
Correct Answer

B. यह अनवसानी आवर्ती दशमलव हैIt is non-terminating recurring decimal

Step 1

Concept

The denominator contains (13), and after simplification the denominator is not made only of (2) and (5). In exams always check prime factors of the denominator.

Step 2

Why this answer is correct

The correct answer is B. यह अनवसानी आवर्ती दशमलव है / It is non-terminating recurring decimal. The denominator contains (13), and after simplification the denominator is not made only of (2) and (5). In exams always check prime factors of the denominator.

Step 3

Exam Tip

हर में (13) है और भिन्न सरल करने पर भी केवल (2) और (5) नहीं बचते। परीक्षा में हर के अभाज्य गुणनखंड जरूर जांचें।

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यदि (p(x)=x-2-hx) है, तो ग्राफ के (x)-अक्ष कटान कौन से होंगे?

If (p(x)=x-2-hx), what will be the (x)-axis intersections of the graph?

Explanation opens after your attempt
Correct Answer

A. ((0,0)) और ((h,0))((0,0)) and ((h,0))

Step 1

Concept

(x-2-hx=x(x-h)), so the zeroes are (0) and (h). Tip: factor out the common (x).

Step 2

Why this answer is correct

The correct answer is A. ((0,0)) और ((h,0)) / ((0,0)) and ((h,0)). (x-2-hx=x(x-h)), so the zeroes are (0) and (h). Tip: factor out the common (x).

Step 3

Exam Tip

(x-2-hx=x(x-h)) है, इसलिए शून्यक (0) और (h) हैं। टिप: सामान्य (x) गुणनखंड निकालें।

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यदि (p(x)=x-3-12x-2+35x) है, तो ग्राफ के शून्यकों का समूह कौन सा है?

If (p(x)=x-3-12x-2+35x), what is the set of zeroes of the graph?

Explanation opens after your attempt
Correct Answer

A. (0,5,7)

Step 1

Concept

(x-3-12x-2+35x=x(x-5)(x-7)), so the zeroes are (0), (5), (7). Tip: first take (x) as the common factor.

Step 2

Why this answer is correct

The correct answer is A. (0,5,7). (x-3-12x-2+35x=x(x-5)(x-7)), so the zeroes are (0), (5), (7). Tip: first take (x) as the common factor.

Step 3

Exam Tip

(x-3-12x-2+35x=x(x-5)(x-7)) है, इसलिए शून्यक (0), (5), (7) हैं। टिप: पहले (x) सामान्य गुणनखंड निकालें।

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यदि (p(x)=x-2-13x-68) है, तो ग्राफ के (x)-अक्ष कटान कौन से हैं?

If (p(x)=x-2-13x-68), what are the (x)-axis intersections of the graph?

Explanation opens after your attempt
Correct Answer

A. ((17,0)) और ((-4,0))((17,0)) and ((-4,0))

Step 1

Concept

(x-2-13x-68=(x-17)(x+4)), so the zeroes are (17) and (-4). Tip: write intersection points from factors.

Step 2

Why this answer is correct

The correct answer is A. ((17,0)) और ((-4,0)) / ((17,0)) and ((-4,0)). (x-2-13x-68=(x-17)(x+4)), so the zeroes are (17) and (-4). Tip: write intersection points from factors.

Step 3

Exam Tip

(x-2-13x-68=(x-17)(x+4)) है, इसलिए शून्यक (17) और (-4) हैं। टिप: गुणनखंडों से कटान बिंदु लिखें।

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यदि (p(x)=x-3-9x-2+18x) है, तो ग्राफ के शून्यकों का माध्य क्या है?

If (p(x)=x-3-9x-2+18x), what is the mean of the zeroes of the graph?

Explanation opens after your attempt
Correct Answer

A. (3)

Step 1

Concept

(p(x)=x(x-3)(x-6)), so the zeroes are (0), (3), (6), and the mean is (3). Tip: factor first.

Step 2

Why this answer is correct

The correct answer is A. (3). (p(x)=x(x-3)(x-6)), so the zeroes are (0), (3), (6), and the mean is (3). Tip: factor first.

Step 3

Exam Tip

(p(x)=x(x-3)(x-6)) है इसलिए शून्यक (0), (3), (6) और माध्य (3) है। टिप: पहले गुणनखंड करें।

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यदि (p(x)=x-2-(2n+3)x+n(n+3)) है, तो ग्राफ के (x)-अक्ष कटान कौन से होंगे?

If (p(x)=x-2-(2n+3)x+n(n+3)), what will be the (x)-axis intersections of the graph?

Explanation opens after your attempt
Correct Answer

A. ((n,0)) और ((n+3,0))((n,0)) and ((n+3,0))

Step 1

Concept

The polynomial is ((x-n)(x-(n+3))), so the zeroes are (n) and (n+3). Tip: write zeroes as ((x,0)).

Step 2

Why this answer is correct

The correct answer is A. ((n,0)) और ((n+3,0)) / ((n,0)) and ((n+3,0)). The polynomial is ((x-n)(x-(n+3))), so the zeroes are (n) and (n+3). Tip: write zeroes as ((x,0)).

Step 3

Exam Tip

बहुपद ((x-n)(x-(n+3))) है इसलिए शून्यक (n) और (n+3) हैं। टिप: शून्यकों को ((x,0)) में लिखें।

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यदि (p(x)=x-2-ex) है, तो ग्राफ के (x)-अक्ष कटान कौन से होंगे?

If (p(x)=x-2-ex), what will be the (x)-axis intersections of the graph?

Explanation opens after your attempt
Correct Answer

A. ((0,0)) और ((e,0))((0,0)) and ((e,0))

Step 1

Concept

(x-2-ex=x(x-e)), so the zeroes are (0) and (e). Tip: factor out the common (x).

Step 2

Why this answer is correct

The correct answer is A. ((0,0)) और ((e,0)) / ((0,0)) and ((e,0)). (x-2-ex=x(x-e)), so the zeroes are (0) and (e). Tip: factor out the common (x).

Step 3

Exam Tip

(x-2-ex=x(x-e)) है, इसलिए शून्यक (0) और (e) हैं। टिप: सामान्य (x) गुणनखंड निकालें।

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यदि (p(x)=x-3-10x-2+24x) है, तो ग्राफ के शून्यकों का समूह कौन सा है?

If (p(x)=x-3-10x-2+24x), what is the set of zeroes of the graph?

Explanation opens after your attempt
Correct Answer

A. (0,4,6)

Step 1

Concept

(x-3-10x-2+24x=x(x-4)(x-6)), so the zeroes are (0), (4), (6). Tip: first take (x) as the common factor.

Step 2

Why this answer is correct

The correct answer is A. (0,4,6). (x-3-10x-2+24x=x(x-4)(x-6)), so the zeroes are (0), (4), (6). Tip: first take (x) as the common factor.

Step 3

Exam Tip

(x-3-10x-2+24x=x(x-4)(x-6)) है, इसलिए शून्यक (0), (4), (6) हैं। टिप: पहले (x) सामान्य गुणनखंड निकालें।

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यदि (p(x)=x-2-9x-52) है, तो ग्राफ के (x)-अक्ष कटान कौन से हैं?

If (p(x)=x-2-9x-52), what are the (x)-axis intersections of the graph?

Explanation opens after your attempt
Correct Answer

A. ((13,0)) और ((-4,0))((13,0)) and ((-4,0))

Step 1

Concept

(x-2-9x-52=(x-13)(x+4)), so the zeroes are (13) and (-4). Tip: write intersection points from factors.

Step 2

Why this answer is correct

The correct answer is A. ((13,0)) और ((-4,0)) / ((13,0)) and ((-4,0)). (x-2-9x-52=(x-13)(x+4)), so the zeroes are (13) and (-4). Tip: write intersection points from factors.

Step 3

Exam Tip

(x-2-9x-52=(x-13)(x+4)) है, इसलिए शून्यक (13) और (-4) हैं। टिप: गुणनखंडों से कटान बिंदु लिखें।

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यदि (p(x)=x-3-7x-2+10x) है, तो ग्राफ के शून्यकों का माध्य क्या है?

If (p(x)=x-3-7x-2+10x), what is the mean of the zeroes of the graph?

Explanation opens after your attempt
Correct Answer

A. \(\frac{7}{3}\)

Step 1

Concept

(p(x)=x(x-5)(x-2)), so the zeroes are (0), (2), (5), and the mean is \(\frac{7}{3}\). Tip: factor first.

Step 2

Why this answer is correct

The correct answer is A. \(\frac{7}{3}\). (p(x)=x(x-5)(x-2)), so the zeroes are (0), (2), (5), and the mean is \(\frac{7}{3}\). Tip: factor first.

Step 3

Exam Tip

(p(x)=x(x-5)(x-2)) है, इसलिए शून्यक (0), (2), (5) और माध्य \(\frac{7}{3}\) है। टिप: पहले गुणनखंड करें।

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यदि (p(x)=x-2-(2m-1)x+m(m-1)) है, तो ग्राफ के (x)-अक्ष कटान कौन से होंगे?

If (p(x)=x-2-(2m-1)x+m(m-1)), what will be the (x)-axis intersections of the graph?

Explanation opens after your attempt
Correct Answer

A. ((m,0)) और ((m-1,0))((m,0)) and ((m-1,0))

Step 1

Concept

The polynomial is ((x-m)(x-(m-1))), so the zeroes are (m) and (m-1). Tip: write zeroes as ((x,0)).

Step 2

Why this answer is correct

The correct answer is A. ((m,0)) और ((m-1,0)) / ((m,0)) and ((m-1,0)). The polynomial is ((x-m)(x-(m-1))), so the zeroes are (m) and (m-1). Tip: write zeroes as ((x,0)).

Step 3

Exam Tip

बहुपद ((x-m)(x-(m-1))) है, इसलिए शून्यक (m) और (m-1) हैं। टिप: शून्यकों को ((x,0)) में लिखें।

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यदि (p(x)=x-2-cx) है तो ग्राफ के (x)-अक्ष कटान कौन से होंगे?

If (p(x)=x-2-cx), what will be the (x)-axis intersections of the graph?

Explanation opens after your attempt
Correct Answer

A. ((0,0)) और ((c,0))((0,0)) and ((c,0))

Step 1

Concept

(x-2-cx=x(x-c)), so the zeroes are (0) and (c). Tip: factor out the common (x).

Step 2

Why this answer is correct

The correct answer is A. ((0,0)) और ((c,0)) / ((0,0)) and ((c,0)). (x-2-cx=x(x-c)), so the zeroes are (0) and (c). Tip: factor out the common (x).

Step 3

Exam Tip

(x-2-cx=x(x-c)) है इसलिए शून्यक (0) और (c) हैं। टिप: सामान्य (x) गुणनखंड निकालें।

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यदि (p(x)=x-3-8x-2+15x) है तो ग्राफ के शून्यकों का समूह कौन सा है?

If (p(x)=x-3-8x-2+15x), what is the set of zeroes of the graph?

Explanation opens after your attempt
Correct Answer

A. (0,3,5)

Step 1

Concept

(x-3-8x-2+15x=x(x-3)(x-5)), so the zeroes are (0,3,5). Tip: first take (x) as the common factor.

Step 2

Why this answer is correct

The correct answer is A. (0,3,5). (x-3-8x-2+15x=x(x-3)(x-5)), so the zeroes are (0,3,5). Tip: first take (x) as the common factor.

Step 3

Exam Tip

(x-3-8x-2+15x=x(x-3)(x-5)) है इसलिए शून्यक (0,3,5) हैं। टिप: पहले (x) सामान्य गुणनखंड निकालें।

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यदि (p(x)=x-2-8x-33) है तो ग्राफ के (x)-अक्ष कटान कौन से हैं?

If (p(x)=x-2-8x-33), what are the (x)-axis intersections of the graph?

Explanation opens after your attempt
Correct Answer

A. ((11,0)) और ((-3,0))((11,0)) and ((-3,0))

Step 1

Concept

(x-2-8x-33=(x-11)(x+3)), so the zeroes are (11) and (-3). Tip: form ((x,0)) points from factors.

Step 2

Why this answer is correct

The correct answer is A. ((11,0)) और ((-3,0)) / ((11,0)) and ((-3,0)). (x-2-8x-33=(x-11)(x+3)), so the zeroes are (11) and (-3). Tip: form ((x,0)) points from factors.

Step 3

Exam Tip

(x-2-8x-33=(x-11)(x+3)) है इसलिए शून्यक (11) और (-3) हैं। टिप: गुणनखंडों से बिंदु ((x,0)) बनाएं।

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यदि (p(x)=x-2-(u+v)x+uv) है तो ग्राफ के (x)-अक्ष कटान कौन से होंगे?

If (p(x)=x-2-(u+v)x+uv), what will be the (x)-axis intersections of the graph?

Explanation opens after your attempt
Correct Answer

A. ((u,0)) और ((v,0))((u,0)) and ((v,0))

Step 1

Concept

It is ((x-u)(x-v)), so the zeroes are (u) and (v). Tip: write each zero as the point ((x,0)).

Step 2

Why this answer is correct

The correct answer is A. ((u,0)) और ((v,0)) / ((u,0)) and ((v,0)). It is ((x-u)(x-v)), so the zeroes are (u) and (v). Tip: write each zero as the point ((x,0)).

Step 3

Exam Tip

यह ((x-u)(x-v)) है इसलिए शून्यक (u) और (v) हैं। टिप: शून्यक को ((x,0)) बिंदु के रूप में लिखें।

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यदि (p(x)=x-2-bx) है, तो ग्राफ के (x)-अक्ष कटान कौन से होंगे?

If (p(x)=x-2-bx), what will be the (x)-axis intersections of the graph?

Explanation opens after your attempt
Correct Answer

A. ((0,0)) और ((b,0))((0,0)) and ((b,0))

Step 1

Concept

(x-2-bx=x(x-b)), so the zeroes are (0) and (b). Tip: factor out the common (x).

Step 2

Why this answer is correct

The correct answer is A. ((0,0)) और ((b,0)) / ((0,0)) and ((b,0)). (x-2-bx=x(x-b)), so the zeroes are (0) and (b). Tip: factor out the common (x).

Step 3

Exam Tip

(x-2-bx=x(x-b)) है, इसलिए शून्यक (0) और (b) हैं। टिप: सामान्य (x) गुणनखंड निकालें।

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यदि (p(x)=x-3-6x-2+5x) है, तो ग्राफ के शून्यकों का समूह कौन सा है?

If (p(x)=x-3-6x-2+5x), what is the set of zeroes of the graph?

Explanation opens after your attempt
Correct Answer

A. (0,1,5)

Step 1

Concept

(x-3-6x-2+5x=x(x-1)(x-5)), so the zeroes are (0,1,5). Tip: first take (x) as the common factor.

Step 2

Why this answer is correct

The correct answer is A. (0,1,5). (x-3-6x-2+5x=x(x-1)(x-5)), so the zeroes are (0,1,5). Tip: first take (x) as the common factor.

Step 3

Exam Tip

(x-3-6x-2+5x=x(x-1)(x-5)) है, इसलिए शून्यक (0,1,5) हैं। टिप: पहले (x) सामान्य गुणनखंड निकालें।

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यदि (p(x)=x-2-4x-21) है, तो ग्राफ के (x)-अक्ष कटान कौन से हैं?

If (p(x)=x-2-4x-21), what are the (x)-axis intersections of the graph?

Explanation opens after your attempt
Correct Answer

A. ((7,0)) और ((-3,0))((7,0)) and ((-3,0))

Step 1

Concept

(x-2-4x-21=(x-7)(x+3)), so the zeroes are (7) and (-3). Tip: form ((x,0)) points from factors.

Step 2

Why this answer is correct

The correct answer is A. ((7,0)) और ((-3,0)) / ((7,0)) and ((-3,0)). (x-2-4x-21=(x-7)(x+3)), so the zeroes are (7) and (-3). Tip: form ((x,0)) points from factors.

Step 3

Exam Tip

(x-2-4x-21=(x-7)(x+3)) है, इसलिए शून्यक (7) और (-3) हैं। टिप: गुणनखंडों से बिंदु ((x,0)) बनाएं।

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यदि (p(x)=x-2-(m+n)x+mn) है, तो ग्राफ के (x)-अक्ष कटान कौन से होंगे?

If (p(x)=x-2-(m+n)x+mn), what will be the (x)-axis intersections of the graph?

Explanation opens after your attempt
Correct Answer

A. ((m,0)) और ((n,0))((m,0)) and ((n,0))

Step 1

Concept

It is ((x-m)(x-n)), so the zeroes are (m) and (n). Tip: write each zero as ((x,0)).

Step 2

Why this answer is correct

The correct answer is A. ((m,0)) और ((n,0)) / ((m,0)) and ((n,0)). It is ((x-m)(x-n)), so the zeroes are (m) and (n). Tip: write each zero as ((x,0)).

Step 3

Exam Tip

यह ((x-m)(x-n)) है इसलिए शून्यक (m) और (n) हैं। टिप: शून्यक को ((x,0)) में लिखें।

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यदि (p(x)=x-2-ax) है, तो ग्राफ के (x)-अक्ष कटान कौन से होंगे?

If (p(x)=x-2-ax), what will be the (x)-axis intersections of the graph?

Explanation opens after your attempt
Correct Answer

A. ((0,0)) और ((a,0))((0,0)) and ((a,0))

Step 1

Concept

(x-2-ax=x(x-a)), so the zeroes are (0) and (a). Tip: factor out the common (x).

Step 2

Why this answer is correct

The correct answer is A. ((0,0)) और ((a,0)) / ((0,0)) and ((a,0)). (x-2-ax=x(x-a)), so the zeroes are (0) and (a). Tip: factor out the common (x).

Step 3

Exam Tip

(x-2-ax=x(x-a)), इसलिए शून्यक (0) और (a) हैं। टिप: सामान्य (x) गुणनखंड निकालें।

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यदि (p(x)=x-3-4x-2-5x) है, तो ग्राफ के शून्यकों का समूह कौन सा है?

If (p(x)=x-3-4x-2-5x), what is the set of zeroes of the graph?

Explanation opens after your attempt
Correct Answer

A. (0, -1, 5)

Step 1

Concept

(x-3-4x-2-5x=x(x-5)(x+1)), so the zeroes are (0), (5), (-1). Tip: first take (x) as the common factor.

Step 2

Why this answer is correct

The correct answer is A. (0, -1, 5). (x-3-4x-2-5x=x(x-5)(x+1)), so the zeroes are (0), (5), (-1). Tip: first take (x) as the common factor.

Step 3

Exam Tip

(x-3-4x-2-5x=x(x-5)(x+1)), इसलिए शून्यक (0), (5), (-1) हैं। टिप: पहले (x) सामान्य गुणनखंड निकालें।

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यदि (p(x)=x-2+2x-15) है, तो ग्राफ के (x)-अक्ष कटान कौन से हैं?

If (p(x)=x-2+2x-15), what are the (x)-axis intersections of the graph?

Explanation opens after your attempt
Correct Answer

A. ((3,0)) और ((-5,0))((3,0)) and ((-5,0))

Step 1

Concept

(x-2+2x-15=(x+5)(x-3)), so the zeroes are (-5) and (3). Tip: form points ((x,0)) from factors.

Step 2

Why this answer is correct

The correct answer is A. ((3,0)) और ((-5,0)) / ((3,0)) and ((-5,0)). (x-2+2x-15=(x+5)(x-3)), so the zeroes are (-5) and (3). Tip: form points ((x,0)) from factors.

Step 3

Exam Tip

(x-2+2x-15=(x+5)(x-3)), इसलिए शून्यक (-5) और (3) हैं। टिप: गुणनखंडों से बिंदु ((x,0)) बनाएं।

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यदि (p(x)=x-2-(a+b)x+ab) है, तो ग्राफ के (x)-अक्ष कटान कौन से होंगे?

If (p(x)=x-2-(a+b)x+ab), what will be the (x)-axis intersections of the graph?

Explanation opens after your attempt
Correct Answer

A. ((a,0)) और ((b,0))((a,0)) and ((b,0))

Step 1

Concept

The polynomial equals ((x-a)(x-b)), so the zeroes are (a) and (b). Tip: connect factor form with graph intersections.

Step 2

Why this answer is correct

The correct answer is A. ((a,0)) और ((b,0)) / ((a,0)) and ((b,0)). The polynomial equals ((x-a)(x-b)), so the zeroes are (a) and (b). Tip: connect factor form with graph intersections.

Step 3

Exam Tip

बहुपद ((x-a)(x-b)) के बराबर है, इसलिए शून्यक (a) और (b) हैं। टिप: गुणनखंड रूप को ग्राफ कटान से जोड़ें।

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कौन सा विकल्प \(\sqrt{3}\) और \(\sqrt{5}\) की सिद्धियों में समान गहन विचार दिखाता है?

Which option shows the common deeper idea in the proofs of \(\sqrt{3}\) and \(\sqrt{5}\)?

Explanation opens after your attempt
Correct Answer

A. वर्ग में अभाज्य गुणनखंड का घातांक सम होता है, पर \(p^2=3q^2\) या \(p^2=5q^2\) असंतुलन पैदा करता हैIn a square, the exponent of a prime factor is even, but \(p^2=3q^2\) or \(p^2=5q^2\) creates imbalance

Step 1

Concept

In a perfect square, exponents of prime factors are even.

Step 2

Why this answer is correct

\(p^2=3q^2\) or \(p^2=5q^2\) forces the same prime factor into both (p) and (q).

Step 3

Exam Tip

This common factor contradicts the coprime condition. चरण 1: किसी पूर्ण वर्ग में अभाज्य गुणनखंडों की घातें सम होती हैं। चरण 2: \(p^2=3q^2\) या \(p^2=5q^2\) बताता है कि वही अभाज्य गुणनखंड (p) और (q) दोनों में आ जाएगा। चरण 3: यही साझा गुणनखंड सहअभाज्य शर्त से टकराता है।

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किस उत्तर को सबसे उच्च स्तरीय कला विश्लेषण माना जाएगा?

Which answer will be considered the highest-level art analysis?

Explanation opens after your attempt
Correct Answer

A. तत्व पहचान प्रमाण प्रभाव और सुधार सुझाव सहित उत्तरAnswer with element identification evidence effect and improvement suggestion

Step 1

Concept

High level needs both analysis and application. Exam tip: add evidence plus application.

Step 2

Why this answer is correct

The correct answer is A. तत्व पहचान प्रमाण प्रभाव और सुधार सुझाव सहित उत्तर / Answer with element identification evidence effect and improvement suggestion. High level needs both analysis and application. Exam tip: add evidence plus application.

Step 3

Exam Tip

उच्च स्तर में विश्लेषण और अनुप्रयोग दोनों चाहिए। परीक्षा में evidence plus application जोड़ें।

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कला के तत्वों की गहरी समझ विद्यार्थी को किस उच्च क्षमता तक ले जाती है?

Deep understanding of elements of art leads a student to which higher ability?

Explanation opens after your attempt
Correct Answer

A. रचना बनाना विश्लेषण करना और प्रमाण सहित सुधार सुझानाCreating analysing and suggesting evidence-based improvements

Step 1

Concept

Deep understanding helps in both creation and criticism. Exam tip: connect elements with creation and criticism.

Step 2

Why this answer is correct

The correct answer is A. रचना बनाना विश्लेषण करना और प्रमाण सहित सुधार सुझाना / Creating analysing and suggesting evidence-based improvements. Deep understanding helps in both creation and criticism. Exam tip: connect elements with creation and criticism.

Step 3

Exam Tip

गहरी समझ रचना और आलोचना दोनों में काम आती है। परीक्षा में elements को creation और criticism दोनों से जोड़ें।

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कला तत्वों पर उच्च स्तरीय उत्तर में क्या अनिवार्य है?

What is essential in a high-level answer on art elements?

Explanation opens after your attempt
Correct Answer

A. पहचान प्रमाण प्रभाव और सुधार सुझावIdentification evidence effect and improvement suggestion

Step 1

Concept

High-level answer shows both analysis and application. Exam tip: include evidence plus application.

Step 2

Why this answer is correct

The correct answer is A. पहचान प्रमाण प्रभाव और सुधार सुझाव / Identification evidence effect and improvement suggestion. High-level answer shows both analysis and application. Exam tip: include evidence plus application.

Step 3

Exam Tip

उच्च स्तर उत्तर विश्लेषण और अनुप्रयोग दोनों दिखाता है। परीक्षा में evidence plus application शामिल करें।

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किस उत्तर में तत्व और सिद्धांत का संबंध उच्च स्तर पर समझाया गया है?

Which answer explains relation of element and principle at higher level?

Explanation opens after your attempt
Correct Answer

A. रेखा रंग और मान तत्व हैं जिन्हें संतुलन जोर और लय बनाने में व्यवस्थित किया जाता हैLine colour and value are elements arranged to create balance emphasis and rhythm

Step 1

Concept

Elements are materials and principles are their arrangement. Exam tip: write element to principle relation.

Step 2

Why this answer is correct

The correct answer is A. रेखा रंग और मान तत्व हैं जिन्हें संतुलन जोर और लय बनाने में व्यवस्थित किया जाता है / Line colour and value are elements arranged to create balance emphasis and rhythm. Elements are materials and principles are their arrangement. Exam tip: write element to principle relation.

Step 3

Exam Tip

तत्व सामग्री हैं और सिद्धांत उनकी व्यवस्था हैं। परीक्षा में element to principle relation लिखें।

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यदि समान्तर श्रेणी के पहले (9) पदों का योग (279) और पहले (18) पदों का योग (1044) है तो पहले (27) पदों का योग कितना होगा?

If the sum of the first (9) terms of an arithmetic progression is (279) and the sum of the first (18) terms is (1044), what is the sum of the first (27) terms?

Explanation opens after your attempt
Correct Answer

C. (2295)

Step 1

Concept

Let \(S_n=\frac{d}{2}n^2+\frac{2a-d}{2}n\). The two sums give (a=7), (d=6), so \(S_{27}=2295\); exam tip: write \(S_n\) as a quadratic in (n).

Step 2

Why this answer is correct

The correct answer is C. (2295). Let \(S_n=\frac{d}{2}n^2+\frac{2a-d}{2}n\). The two sums give (a=7), (d=6), so \(S_{27}=2295\); exam tip: write \(S_n\) as a quadratic in (n).

Step 3

Exam Tip

मानें \(S_n=\frac{d}{2}n^2+\frac{2a-d}{2}n\) और दो योगों से (a=7), (d=6) मिलते हैं इसलिए \(S_{27}=2295\)। परीक्षा में \(S_n\) को (n) के द्विघात रूप में लिखना उपयोगी है।

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समीकरणों (2x+9y=61) और (5x-3y=14) को हल करने पर (x) का मान क्या है?

Solving (2x+9y=61) and (5x-3y=14), what is the value of (x)?

Explanation opens after your attempt
Correct Answer

D. (7)

Step 1

Concept

Multiplying the second equation by (3) gives (15x-9y=42). Add and solve carefully because fractional answers are possible.

Step 2

Why this answer is correct

The correct answer is D. (7). Multiplying the second equation by (3) gives (15x-9y=42). Add and solve carefully because fractional answers are possible.

Step 3

Exam Tip

दूसरे समीकरण को (3) से गुणा करने पर (15x-9y=42)। जोड़ने पर (17x=103), इसलिए भिन्न उत्तर की संभावना देखें।

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यदि (x-2-(a+b+1)x+ab+a+b=0) हो, तो (a) और (b) के लिए मूलों की प्रकृति किस पर निर्भर करेगी?

If (x-2-(a+b+1)x+ab+a+b=0), on what will the nature of roots depend for (a) and (b)?

Explanation opens after your attempt
Correct Answer

A. (D=(a-b)2+1-2(a+b))

Step 1

Concept

Here (D=(a+b+1)2-4(ab+a+b)). On simplification the correct discriminant is ( (a-b)2+1-2(a+b) ).

Step 2

Why this answer is correct

The correct answer is A. (D=(a-b)2+1-2(a+b)). Here (D=(a+b+1)2-4(ab+a+b)). On simplification the correct discriminant is ( (a-b)2+1-2(a+b) ).

Step 3

Exam Tip

यहाँ (D=(a+b+1)2-4(ab+a+b)) है। सरल करने पर सही विविक्तकर ( (a-b)2+1-2(a+b) ) मिलता है।

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यदि \(x^2-12x-28=0\) के मूल \(\alpha,\beta\) हैं, तो \(\alpha^2\beta+\alpha\beta^2\) क्या होगा?

If the roots of \(x^2-12x-28=0\) are \(\alpha,\beta\), what is \(\alpha^2\beta+\alpha\beta^2\)?

Explanation opens after your attempt
Correct Answer

A. (-336)

Step 1

Concept

(\alpha-2\beta+\alpha\beta-2=\alpha\beta\(\alpha+\beta\)), where \(\alpha+\beta=12\) and \(\alpha\beta=-28\), so the value is (-336). In exams, factor the expression first.

Step 2

Why this answer is correct

The correct answer is A. (-336). (\alpha-2\beta+\alpha\beta-2=\alpha\beta\(\alpha+\beta\)), where \(\alpha+\beta=12\) and \(\alpha\beta=-28\), so the value is (-336). In exams, factor the expression first.

Step 3

Exam Tip

(\alpha-2\beta+\alpha\beta-2=\alpha\beta\(\alpha+\beta\)), जहां \(\alpha+\beta=12\) और \(\alpha\beta=-28\), इसलिए मान (-336) है। परीक्षा में अभिव्यक्ति को पहले factor करें।

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यदि \(x^2-10x-24=0\) के मूल \(\alpha,\beta\) हैं, तो \(\alpha^2\beta+\alpha\beta^2\) क्या होगा?

If the roots of \(x^2-10x-24=0\) are \(\alpha,\beta\), what is \(\alpha^2\beta+\alpha\beta^2\)?

Explanation opens after your attempt
Correct Answer

A. (-240)

Step 1

Concept

(\alpha-2\beta+\alpha\beta-2=\alpha\beta\(\alpha+\beta\)), where \(\alpha+\beta=10\) and \(\alpha\beta=-24\), so the value is (-240). In exams, factor the expression first.

Step 2

Why this answer is correct

The correct answer is A. (-240). (\alpha-2\beta+\alpha\beta-2=\alpha\beta\(\alpha+\beta\)), where \(\alpha+\beta=10\) and \(\alpha\beta=-24\), so the value is (-240). In exams, factor the expression first.

Step 3

Exam Tip

(\alpha-2\beta+\alpha\beta-2=\alpha\beta\(\alpha+\beta\)), जहां \(\alpha+\beta=10\) और \(\alpha\beta=-24\), इसलिए मान (-240) है। परीक्षा में अभिव्यक्ति को पहले factor करें।

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यदि \(x^2-8x-20=0\) के मूल \(\alpha,\beta\) हैं, तो \(\alpha^2\beta+\alpha\beta^2\) क्या होगा?

If the roots of \(x^2-8x-20=0\) are \(\alpha,\beta\), what is \(\alpha^2\beta+\alpha\beta^2\)?

Explanation opens after your attempt
Correct Answer

A. (-160)

Step 1

Concept

(\alpha-2\beta+\alpha\beta-2=\alpha\beta\(\alpha+\beta\)), where \(\alpha+\beta=8\) and \(\alpha\beta=-20\), so the value is (-160). In exams, factor the expression first.

Step 2

Why this answer is correct

The correct answer is A. (-160). (\alpha-2\beta+\alpha\beta-2=\alpha\beta\(\alpha+\beta\)), where \(\alpha+\beta=8\) and \(\alpha\beta=-20\), so the value is (-160). In exams, factor the expression first.

Step 3

Exam Tip

(\alpha-2\beta+\alpha\beta-2=\alpha\beta\(\alpha+\beta\)), जहां \(\alpha+\beta=8\) और \(\alpha\beta=-20\), इसलिए मान (-160) है। परीक्षा में अभिव्यक्ति को पहले factor करें।

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यदि \(x^2-6x-16=0\) के मूल \(\alpha,\beta\) हैं, तो \(\alpha^2\beta+\alpha\beta^2\) क्या होगा?

If the roots of \(x^2-6x-16=0\) are \(\alpha,\beta\), what is \(\alpha^2\beta+\alpha\beta^2\)?

Explanation opens after your attempt
Correct Answer

A. (-96)

Step 1

Concept

(\alpha-2\beta+\alpha\beta-2=\alpha\beta\(\alpha+\beta\)), where \(\alpha+\beta=6\) and \(\alpha\beta=-16\), so the value is (-96). In exams, factor the expression first.

Step 2

Why this answer is correct

The correct answer is A. (-96). (\alpha-2\beta+\alpha\beta-2=\alpha\beta\(\alpha+\beta\)), where \(\alpha+\beta=6\) and \(\alpha\beta=-16\), so the value is (-96). In exams, factor the expression first.

Step 3

Exam Tip

(\alpha-2\beta+\alpha\beta-2=\alpha\beta\(\alpha+\beta\)), जहां \(\alpha+\beta=6\) और \(\alpha\beta=-16\), इसलिए मान (-96) है। परीक्षा में अभिव्यक्ति को पहले factor करें।

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यदि \(x^2-4x-12=0\) के मूल \(\alpha,\beta\) हैं, तो \(\alpha^2\beta+\alpha\beta^2\) क्या होगा?

If the roots of \(x^2-4x-12=0\) are \(\alpha,\beta\), what is \(\alpha^2\beta+\alpha\beta^2\)?

Explanation opens after your attempt
Correct Answer

A. (-48)

Step 1

Concept

(\alpha-2\beta+\alpha\beta-2=\alpha\beta\(\alpha+\beta\)), where \(\alpha+\beta=4\) and \(\alpha\beta=-12\), so the value is (-48). In exams, factor the expression first.

Step 2

Why this answer is correct

The correct answer is A. (-48). (\alpha-2\beta+\alpha\beta-2=\alpha\beta\(\alpha+\beta\)), where \(\alpha+\beta=4\) and \(\alpha\beta=-12\), so the value is (-48). In exams, factor the expression first.

Step 3

Exam Tip

(\alpha-2\beta+\alpha\beta-2=\alpha\beta\(\alpha+\beta\)), जहां \(\alpha+\beta=4\) और \(\alpha\beta=-12\), इसलिए मान (-48) है। परीक्षा में अभिव्यक्ति को पहले factor करें।

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यदि \(x^2-2x-8=0\) के मूल \(\alpha,\beta\) हैं, तो \(\alpha^2\beta+\alpha\beta^2\) क्या होगा?

If the roots of \(x^2-2x-8=0\) are \(\alpha,\beta\), what is \(\alpha^2\beta+\alpha\beta^2\)?

Explanation opens after your attempt
Correct Answer

A. (-16)

Step 1

Concept

(\alpha-2\beta+\alpha\beta-2=\alpha\beta\(\alpha+\beta\)), where \(\alpha+\beta=2\) and \(\alpha\beta=-8\), so the value is (-16). In exams, factor the expression first.

Step 2

Why this answer is correct

The correct answer is A. (-16). (\alpha-2\beta+\alpha\beta-2=\alpha\beta\(\alpha+\beta\)), where \(\alpha+\beta=2\) and \(\alpha\beta=-8\), so the value is (-16). In exams, factor the expression first.

Step 3

Exam Tip

(\alpha-2\beta+\alpha\beta-2=\alpha\beta\(\alpha+\beta\)), जहां \(\alpha+\beta=2\) और \(\alpha\beta=-8\), इसलिए मान (-16) है। परीक्षा में अभिव्यक्ति को पहले factor करें।

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यदि \(\alpha,\beta\) समीकरण \(x^2+x-1=0\) की जड़ें हैं, तो \(\alpha^5+\beta^5\) का मान क्या है?

If \(\alpha,\beta\) are roots of \(x^2+x-1=0\), what is \(\alpha^5+\beta^5\)?

Explanation opens after your attempt
Correct Answer

A. (-11)

Step 1

Concept

Here \(\alpha+\beta=-1\) and \(\alpha\beta=-1\). The power sums give \(S_1=-1\), \(S_2=3\), \(S_3=-4\), \(S_4=7\), \(S_5=-11\).

Step 2

Why this answer is correct

The correct answer is A. (-11). Here \(\alpha+\beta=-1\) and \(\alpha\beta=-1\). The power sums give \(S_1=-1\), \(S_2=3\), \(S_3=-4\), \(S_4=7\), \(S_5=-11\).

Step 3

Exam Tip

यहाँ \(\alpha+\beta=-1\) और \(\alpha\beta=-1\) है। शक्ति योग क्रम से \(S_1=-1\), \(S_2=3\), \(S_3=-4\), \(S_4=7\), \(S_5=-11\) मिलता है।

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