Practice focused topic-wise MCQs with answers and explanations for quick revision and exam preparation.
Difficulty select karke sirf is topic ke focused MCQs practice karein. Score, timer aur explanations student-friendly flow me milenge.
Showing 551-560 of 650 questions.
C. \(\sqrt{36}\)
नए कर्ण का वर्ग (35+1=36) होगा, इसलिए \(OQ=\sqrt{36}\)। कर्ण पूछने पर वर्गमूल रूप लिखें। / The square of the new hypotenuse is (35+1=36), so \(OQ=\sqrt{36}\). When the hypotenuse is asked, write the square root form.
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B. \(\sqrt{41}\)
पिछले चरण में वर्गमूल के अंदर की संख्या (1) कम होती है। इसलिए \(\sqrt{42}\) से पहले \(\sqrt{41}\) होगा। / In the previous step, the number under the root is (1) less. Therefore, \(\sqrt{41}\) comes before \(\sqrt{42}\).
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C. \(\sqrt{19}\)
(r)वें त्रिभुज का कर्ण \(\sqrt{r+1}\) होता है। इसलिए (18)वें त्रिभुज का कर्ण \(\sqrt{19}\) है। / The hypotenuse of the (r)th triangle is \(\sqrt{r+1}\). Therefore, the (18)th triangle has hypotenuse \(\sqrt{19}\).
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B. (47)
\(\sqrt{2}\) पहला त्रिभुज देता है, इसलिए \(\sqrt{48}\) तक त्रिभुजों की संख्या (48-1=47) होगी। गणना में आरंभिक \(\sqrt{1}\) को अलग रखें। / \(\sqrt{2}\) is given by the first triangle, so up to \(\sqrt{48}\), the number of triangles is (48-1=47). Keep the initial \(\sqrt{1}\) separate in counting.
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Which option gives the correct order of three consecutive hypotenuses?
A. \(\sqrt{22},\sqrt{23},\sqrt{24}\)
लगातार कर्णों में वर्गमूल के अंदर की संख्याएं (1) के अंतर से बढ़ती हैं। इसलिए \(\sqrt{22},\sqrt{23},\sqrt{24}\) सही क्रम है। / In consecutive hypotenuses, the numbers under the roots increase by (1). Therefore, \(\sqrt{22},\sqrt{23},\sqrt{24}\) is the correct order.
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If \(OP^2=63\) and (PQ=1) is perpendicular, what is the value of \(OQ^2\)?
C. (64)
पाइथागोरस प्रमेय से \(OQ^2=63+1=64\)। प्रश्न \(OQ^2\) पूछता है, इसलिए उत्तर (64) है। / By Pythagoras theorem, \(OQ^2=63+1=64\). The question asks for \(OQ^2\), so the answer is (64).
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B. \(\sqrt{30}\)
(\(\sqrt{30}\)2+12=31), इसलिए \(\sqrt{30}\) पर लंब बनता है। अगले वर्गमूल के लिए पिछले अंदर मान को पहचानें। / (\(\sqrt{30}\)2+12=31), so the perpendicular is drawn on \(\sqrt{30}\). For the next square root, identify the previous inner value.
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A. लंबाइयों का अंतर (1) नहीं, उनके वर्गों का अंतर (1) हैThe difference of lengths is not (1), the difference of their squares is (1)
(\(\sqrt{11}\)2-\(\sqrt{10}\)2=1), लेकिन \(\sqrt{11}-\sqrt{10}\neq1\)। परीक्षा में लंबाई और वर्ग में अंतर समझें। / (\(\sqrt{11}\)2-\(\sqrt{10}\)2=1), but \(\sqrt{11}-\sqrt{10}\neq1\). In exams, understand the difference between length and square.
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When \(\sqrt{72}\) is obtained in the spiral, what is its simplest form?
A. \(6\sqrt{2}\)
\(\sqrt{72}=\sqrt{36\times2}=6\sqrt{2}\)। पूर्ण वर्ग गुणनखंड निकालना सरल करने का अच्छा तरीका है। / \(\sqrt{72}=\sqrt{36\times2}=6\sqrt{2}\). Taking out the perfect square factor is a good way to simplify.
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If \(OP=\sqrt{50}\), what type of number does (OP) represent?
C. अपरिमेय संख्याIrrational number
\(\sqrt{50}=5\sqrt{2}\) है और \(\sqrt{2}\) अपरिमेय है। इसलिए \(\sqrt{50}\) अपरिमेय संख्या है। / \(\sqrt{50}=5\sqrt{2}\), and \(\sqrt{2}\) is irrational. Therefore, \(\sqrt{50}\) is an irrational number.
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