यदि \(OP^2=63\) और (PQ=1) लंब है, तो \(OQ^2\) का मान क्या होगा?
If \(OP^2=63\) and (PQ=1) is perpendicular, what is the value of \(OQ^2\)?
Explanation opens after your attempt
C. (64)
Concept
By Pythagoras theorem, \(OQ^2=63+1=64\). The question asks for \(OQ^2\), so the answer is (64).
Why this answer is correct
The correct answer is C. (64). By Pythagoras theorem, \(OQ^2=63+1=64\). The question asks for \(OQ^2\), so the answer is (64).
Exam Tip
पाइथागोरस प्रमेय से \(OQ^2=63+1=64\)। प्रश्न \(OQ^2\) पूछता है, इसलिए उत्तर (64) है।
Login to save your score, XP, coins and progress.
