यदि सर्पिल \(\sqrt{1}\) से शुरू होकर \(\sqrt{48}\) तक बनाया गया है, तो कुल कितने समकोण त्रिभुज बने?
If the spiral starts from \(\sqrt{1}\) and is constructed up to \(\sqrt{48}\), how many right triangles are formed?
Explanation opens after your attempt
Correct Answer
B. (47)
Concept
\(\sqrt{2}\) is given by the first triangle, so up to \(\sqrt{48}\), the number of triangles is (48-1=47). Keep the initial \(\sqrt{1}\) separate in counting.
Why this answer is correct
The correct answer is B. (47). \(\sqrt{2}\) is given by the first triangle, so up to \(\sqrt{48}\), the number of triangles is (48-1=47). Keep the initial \(\sqrt{1}\) separate in counting.
Exam Tip
\(\sqrt{2}\) पहला त्रिभुज देता है, इसलिए \(\sqrt{48}\) तक त्रिभुजों की संख्या (48-1=47) होगी। गणना में आरंभिक \(\sqrt{1}\) को अलग रखें।
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