Practice focused topic-wise MCQs with answers and explanations for quick revision and exam preparation.
Difficulty select karke sirf is topic ke focused MCQs practice karein. Score, timer aur explanations student-friendly flow me milenge.
Showing 211-220 of 600 questions.
What is the rationalised form of \( \frac{6}{\sqrt{7}} \)?
A. \( \frac{6\sqrt{7}}{7} \)
अंश और हर को \( \sqrt{7} \) से गुणा करें। इससे हर (7) हो जाता है। / Multiply numerator and denominator by \( \sqrt{7} \). This makes the denominator (7).
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What is the rationalised form of \( \frac{5}{3\sqrt{2}} \)?
A. \( \frac{5\sqrt{2}}{6} \)
अंश और हर को \( \sqrt{2} \) से गुणा करने पर \( \frac{5\sqrt{2}}{6} \) मिलता है। हर से करणी हटनी चाहिए। / Multiplying numerator and denominator by \( \sqrt{2} \) gives \( \frac{5\sqrt{2}}{6} \). The radical should be removed from the denominator.
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What is the rationalised form of \( \frac{1}{\sqrt{10}+\sqrt{9}} \)?
A. \( \sqrt{10}-3 \)
हर \( \sqrt{10}+3 \) है और संयुग्मी \( \sqrt{10}-3 \) होगा। हर (10-9=1) बनता है। / The denominator is \( \sqrt{10}+3 \) and its conjugate is \( \sqrt{10}-3 \). The denominator becomes (10-9=1).
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What is the rationalised form of \( \frac{1}{\sqrt{11}-\sqrt{2}} \)?
A. \( \frac{\sqrt{11}+\sqrt{2}}{9} \)
संयुग्मी \( \sqrt{11}+\sqrt{2} \) से गुणा करें। हर (11-2=9) मिलेगा। / Multiply by the conjugate \( \sqrt{11}+\sqrt{2} \). The denominator becomes (11-2=9).
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What is the simplified form of \( \sqrt{98}+\sqrt{162}-\sqrt{50} \)?
A. \(11\sqrt{2}\)
\( \sqrt{98}=7\sqrt{2} \), \( \sqrt{162}=9\sqrt{2} \), और \( \sqrt{50}=5\sqrt{2} \)। इसलिए परिणाम \(11\sqrt{2}\) है। / \( \sqrt{98}=7\sqrt{2} \), \( \sqrt{162}=9\sqrt{2} \), and \( \sqrt{50}=5\sqrt{2} \). So the result is \(11\sqrt{2}\).
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What is the simplified form of \(2\sqrt{44}+3\sqrt{99}\)?
B. \(13\sqrt{11}\)
\(2\sqrt{44}=4\sqrt{11}\) और \(3\sqrt{99}=9\sqrt{11}\) है। योग \(13\sqrt{11}\) होगा। / \(2\sqrt{44}=4\sqrt{11}\) and \(3\sqrt{99}=9\sqrt{11}\). The sum is \(13\sqrt{11}\).
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What is the simplified form of \( \sqrt{112}+2\sqrt{175} \)?
B. \(14\sqrt{7}\)
\( \sqrt{112}=4\sqrt{7} \) और \(2\sqrt{175}=10\sqrt{7}\) है। योग \(14\sqrt{7}\) है। / \( \sqrt{112}=4\sqrt{7} \) and \(2\sqrt{175}=10\sqrt{7}\). The sum is \(14\sqrt{7}\).
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What is the simplified form of \(5\sqrt{48}-3\sqrt{75}\)?
A. \(5\sqrt{3}\)
\(5\sqrt{48}=20\sqrt{3}\) और \(3\sqrt{75}=15\sqrt{3}\) है। अंतर \(5\sqrt{3}\) मिलता है। / \(5\sqrt{48}=20\sqrt{3}\) and \(3\sqrt{75}=15\sqrt{3}\). The difference is \(5\sqrt{3}\).
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What is the value of \( \sqrt{32}\times\sqrt{50} \)?
A. (40)
\( \sqrt{32}\times\sqrt{50}=\sqrt{1600}=40 \)। करणी गुणन में अंदर की संख्याएँ गुणा करें। / \( \sqrt{32}\times\sqrt{50}=\sqrt{1600}=40 \). In radical multiplication, multiply the radicands.
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What is the value of \( \sqrt{180}\div\sqrt{20} \)?
B. (3)
\( \frac{\sqrt{180}}{\sqrt{20}}=\sqrt{9}=3 \)। वर्गमूल के भाग में अंदर की संख्याओं का भाग लें। / \( \frac{\sqrt{180}}{\sqrt{20}}=\sqrt{9}=3 \). In division of square roots, divide the radicands.
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