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Real Numbers is a Class 9 Mathematics topic in the Number Systems chapter. Students learn how rational and irrational numbers together form the real number system, represent them on the number line, and distinguish between their decimal expansions. The topic develops understanding of terminating and non-terminating decimals, recurring and non-recurring forms, and the key properties of real numbers under addition, subtraction, multiplication, and division. It also builds a foundation for working confidently with numbers in algebra and geometry.
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Expert · Level 3 · real numbers, surds, square roots, radical simplification, number systemsView options
\(7\sqrt{17}\)
\(11\sqrt{17}\)
\(17\sqrt{7}\)
\(7\sqrt{121}\)
Question 1ExpertLevel 3
What is the simplified form of (\sqrt{432})?
Correct answer: A
Since \(432=144\times 3=12^2\times 3\), \(\sqrt{432}=\sqrt{12^2\times 3}=12\sqrt{3}\). Therefore, option A is correct. For example, \(13\sqrt{3}\) is incorrect because its square is \(507\), not \(432\). Exam tip: To simplify a square root, first identify the greatest perfect-square factor of the number.
\(\sqrt{8}=\sqrt{4\times2}=2\sqrt{2}\) and \(\sqrt{18}=\sqrt{9\times2}=3\sqrt{2}\). Therefore, \(a+b=2\sqrt{2}+3\sqrt{2}=5\sqrt{2}\). \(4\sqrt{2}\) can result from simplifying the second surd incorrectly. Exam tip: First take out perfect-square factors from surds, then add terms with the same radical part.
\(\sqrt{225}=15\) and \(\sqrt{144}=12\). Therefore, \(x=15-12=3\). Option 27 results from incorrectly subtracting 144 from 225; the question requires subtracting the square roots. Exam tip: evaluate each perfect square root separately before performing the subtraction.
\(\sqrt{500}=\sqrt{100\times5}=10\sqrt{5}\) and \(\sqrt{125}=\sqrt{25\times5}=5\sqrt{5}\). Therefore, \(\sqrt{500}-\sqrt{125}=10\sqrt{5}-5\sqrt{5}=5\sqrt{5}\). \(10\sqrt{5}\) is only the value of \(\sqrt{500}\), not the result after subtraction. Exam tip: before subtracting surds, extract perfect-square factors from each radicand.
\(\sqrt{324}=18\) because \(18^2=324\), and \(\sqrt{36}=6\) because \(6^2=36\). Therefore, \(x=18+6=24\), so option C is correct. An answer such as 23 may result from evaluating a square root incorrectly. Exam tip: find each square root of a perfect square separately before adding.
\(675=225\times3=15^2\times3\), so \(\sqrt{675}=\sqrt{15^2\times3}=15\sqrt{3}\). Choosing \(15\sqrt{5}\) would give a radicand of \(225\times5=1125\), not 675. Exam tip: identify the greatest perfect-square factor before simplifying a surd.
If \(a=\sqrt{27}\) and \(b=\sqrt{12}\), what is \(a-b\)?
Correct answer: A
\(\sqrt{27}=\sqrt{9\times3}=3\sqrt{3}\) and \(\sqrt{12}=\sqrt{4\times3}=2\sqrt{3}\). Therefore, \(a-b=3\sqrt{3}-2\sqrt{3}=\sqrt{3}\), so option A is correct. \(2\sqrt{3}\) is only the value of \(b\), not the difference. Exam tip: simplify surds to the same radical form before subtracting them.
The set of real numbers contains every rational number and every irrational number. Thus, \(\mathbb{R}=\mathbb{Q}\cup(\mathbb{R}\setminus\mathbb{Q})\), so option A is correct. Integers and natural numbers are only subsets of rational numbers, so they do not represent all real numbers. Exam tip: for the real-number set, check that both rational and irrational numbers are included.
\(882=441\times2=21^2\times2\). Therefore, \(\sqrt{882}=\sqrt{21^2\times2}=21\sqrt{2}\). Hence, option C is correct. For example, \(20\sqrt{2}\) squares to \(800\), so it cannot equal \(\sqrt{882}\). Exam tip: To simplify a square root, identify the greatest perfect-square factor of the number.
\(\sqrt{400}=20\) and \(\sqrt{225}=15\). Therefore, \(x=20-15=5\). Hence, 5 is the correct option. Getting 4 would indicate an error in evaluating the square roots or subtracting them. Exam tip: evaluate the square roots of perfect squares separately before subtracting.
Since \(8^2=64\) and \(9^2=81\), \(\sqrt{80}\) lies between 8 and 9 and is very close to 9. In fact, \(\sqrt{80}\approx 8.94\), so 9 is the closest number. Option 8 is not the closest because 80 is much nearer to 81 than to 64. Exam tip: Compare nearby perfect squares to estimate a square root quickly.
Since \(588=196\times 3=14^2\times 3\), \(\sqrt{588}=\sqrt{14^2\times 3}=14\sqrt{3}\). \(13\sqrt{3}\) is not correct because \(13^2\times3=507\), not 588. Exam tip: To simplify a square root, first identify the greatest perfect-square factor of the number.
\(\sqrt{50}=\sqrt{25\times2}=5\sqrt{2}\) and \(\sqrt{8}=\sqrt{4\times2}=2\sqrt{2}\). Therefore, \(a-b=5\sqrt{2}-2\sqrt{2}=3\sqrt{2}\). \(5\sqrt{2}\) is only the value of \(a\), not the difference. Exam tip: Simplify surds to the same radical form before subtracting them.
\(968=484\times2=22^2\times2\). Therefore, \(\sqrt{968}=\sqrt{22^2\times2}=22\sqrt{2}\). Although \(21\sqrt{2}\) may seem close, \(21^2\times2=882\), not 968. Exam tip: to simplify a square root, identify the greatest perfect-square factor of the number.
Since \(529=23^2\), we get \(\sqrt{529}=23\). Therefore, \(x=\frac{23}{\sqrt{23}}=\frac{\sqrt{23}\times\sqrt{23}}{\sqrt{23}}=\sqrt{23}\). Option 23 is incorrect because division by \(\sqrt{23}\) still remains. Exam tip: Use \(a=\sqrt{a}\times\sqrt{a}\) to simplify fractions involving square roots.
Since \(726=121\times6=11^2\times6\), \(\sqrt{726}=\sqrt{11^2\times6}=11\sqrt{6}\). The option \(11\sqrt{7}\) is incorrect because its radicand would be \(121\times7=847\). Exam tip: to simplify a square root, first identify the greatest perfect-square factor of the number.
If (x=\sqrt{288}), what is the simplified form of (x)?
Correct answer: B
Since \(288=144\times 2=12^2\times 2\), \(\sqrt{288}=\sqrt{12^2\times 2}=12\sqrt{2}\). Option A, \(6\sqrt{8}\), has the same value but is not in simplest form because \(\sqrt{8}\) can be simplified further. Exam tip: to simplify a surd, identify the greatest perfect-square factor of the number.
Since \(6^2=36\) and \(7^2=49\), \(\sqrt{41}\) lies between 6 and 7. Also, \(6.5^2=42.25\) and \(41<42.25\), so \(\sqrt{41}<6.5\). Therefore, \(\sqrt{41}\) is closer to 6 than to 7; its value is about 6.40. Exam tip: Compare the squares of consecutive integers to quickly identify the nearest integer to a square root.
If (a=\sqrt{32}) and (b=\sqrt{18}), what is (a+b)?
Correct answer: C
\(\sqrt{32}=\sqrt{16\times2}=4\sqrt{2}\) and \(\sqrt{18}=\sqrt{9\times2}=3\sqrt{2}\). Therefore, \(a+b=4\sqrt{2}+3\sqrt{2}=7\sqrt{2}\). \(6\sqrt{2}\) would result only if the coefficients added to 6; here they are 4 and 3. Exam tip: simplify surds into like radical terms before adding them.
\(847=49\times17=7^2\times17\). Therefore, \(\sqrt{847}=\sqrt{7^2\times17}=7\sqrt{17}\). Since \(17\) is not a perfect square, the expression cannot be simplified further. Also, \(7\sqrt{121}=77\), so it is not equal to \(\sqrt{847}\). Exam tip: To simplify a square root, identify the greatest perfect-square factor of the number.
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