फलन (f(x)=x-7) का वास्तविक प्रांत क्या है?
What is the real domain of (f(x)=x-7)?
#real-valued-functions
#domain
#linear-function
50 50-50 2 wrong hide
⏭ Skip Next question
+10 Time+ 10 sec extra
? Hint Small clue
A \([0,\infty\))
B \(\mathbb{R}\)
C \(\mathbb{R}-{7}\)
D (\(-\infty,7]\)
Explanation opens after your attempt
Correct Answer
B. \(\mathbb{R}\)
Step 1
Concept
The linear function (x-7) is defined for every real (x). Hence its domain is \(\mathbb{R}\).
Step 2
Why this answer is correct
The correct answer is B. \(\mathbb{R}\). The linear function (x-7) is defined for every real (x). Hence its domain is \(\mathbb{R}\).
Step 3
Exam Tip
रेखीय फलन (x-7) हर वास्तविक (x) के लिए परिभाषित है। इसलिए इसका प्रांत \(\mathbb{R}\) है।
Login to save your score, XP, coins and progress. Login
फलन (f(x)=7-2x) का परिसर क्या है जब \(x \in \mathbb{R}\)?
What is the range of (f(x)=7-2x) when \(x \in \mathbb{R}\)?
#range
#linear-function
#class11
50 50-50 2 wrong hide
⏭ Skip Next question
+10 Time+ 10 sec extra
? Hint Small clue
A \([7,\infty\))
B (\(-\infty,7]\)
C \(\mathbb{R}\)
D ({7})
Explanation opens after your attempt
Correct Answer
C. \(\mathbb{R}\)
Step 1
Concept
(7-2x) is a non-constant linear function and can take every real value. Therefore its range is \(\mathbb{R}\).
Step 2
Why this answer is correct
The correct answer is C. \(\mathbb{R}\). (7-2x) is a non-constant linear function and can take every real value. Therefore its range is \(\mathbb{R}\).
Step 3
Exam Tip
(7-2x) एक अस्थिर रेखीय फलन है और हर वास्तविक मान ले सकता है। इसलिए इसका परिसर \(\mathbb{R}\) है।
Login to save your score, XP, coins and progress. Login
फलन (f(x)=\sqrt{x-5}) के लिए (x) पर सही शर्त कौन सी है?
Which condition on (x) is correct for (f(x)=\sqrt{x-5})?
#domain
#square-root
#inequality
50 50-50 2 wrong hide
⏭ Skip Next question
+10 Time+ 10 sec extra
? Hint Small clue
A \(x \ge 5\)
B (x>5)
C \(x \le 5\)
D \(x \ne 5\)
Explanation opens after your attempt
Correct Answer
A. \(x \ge 5\)
Step 1
Concept
For the square root to be real, \(x-5 \ge 0\) is required. So the correct condition is \(x \ge 5\).
Step 2
Why this answer is correct
The correct answer is A. \(x \ge 5\). For the square root to be real, \(x-5 \ge 0\) is required. So the correct condition is \(x \ge 5\).
Step 3
Exam Tip
वर्गमूल वास्तविक होने के लिए \(x-5 \ge 0\) चाहिए। इसलिए सही शर्त \(x \ge 5\) है।
Login to save your score, XP, coins and progress. Login
फलन (f(x)=\sqrt{x-5}) का वास्तविक प्रांत क्या है?
What is the real domain of (f(x)=\sqrt{x-5})?
#domain
#square-root
#interval
50 50-50 2 wrong hide
⏭ Skip Next question
+10 Time+ 10 sec extra
? Hint Small clue
A (\(5,\infty\))
B \([5,\infty\))
C (\(-\infty,5]\)
D \(\mathbb{R}\)
Explanation opens after your attempt
Correct Answer
B. \([5,\infty\))
Step 1
Concept
From \(x-5 \ge 0\), we get \(x \ge 5\). The endpoint (5) is included because the square root can be (0).
Step 2
Why this answer is correct
The correct answer is B. \([5,\infty\)). From \(x-5 \ge 0\), we get \(x \ge 5\). The endpoint (5) is included because the square root can be (0).
Step 3
Exam Tip
\(x-5 \ge 0\) से \(x \ge 5\) मिलता है। सिरा (5) शामिल है क्योंकि वर्गमूल (0) हो सकता है।
Login to save your score, XP, coins and progress. Login
फलन (f(x)=\sqrt{8-x}) का वास्तविक प्रांत क्या है?
What is the real domain of (f(x)=\sqrt{8-x})?
#domain
#square-root
#class11
50 50-50 2 wrong hide
⏭ Skip Next question
+10 Time+ 10 sec extra
? Hint Small clue
A \([8,\infty\))
B (\(-\infty,8\))
C (\(-\infty,8]\)
D \(\mathbb{R}-{8}\)
Explanation opens after your attempt
Correct Answer
C. (\(-\infty,8]\)
Step 1
Concept
The expression inside the square root must satisfy \(8-x \ge 0\). This gives \(x \le 8\), so the domain is (\(-\infty,8]\).
Step 2
Why this answer is correct
The correct answer is C. (\(-\infty,8]\). The expression inside the square root must satisfy \(8-x \ge 0\). This gives \(x \le 8\), so the domain is (\(-\infty,8]\).
Step 3
Exam Tip
वर्गमूल के अंदर \(8-x \ge 0\) होना चाहिए। इससे \(x \le 8\) और प्रांत (\(-\infty,8]\) मिलता है।
Login to save your score, XP, coins and progress. Login
फलन (f(x)=\frac{3}{x-6}) में कौन सा मान प्रांत में नहीं है?
Which value is not in the domain of (f(x)=\frac{3}{x-6})?
#domain
#rational-function
#excluded-value
50 50-50 2 wrong hide
⏭ Skip Next question
+10 Time+ 10 sec extra
? Hint Small clue
A (0)
B (3)
C (-6)
D (6)
Explanation opens after your attempt
Step 1
Concept
The denominator is (x-6), and it becomes (0) at (x=6). Therefore (6) is not in the domain.
Step 2
Why this answer is correct
The correct answer is D. (6). The denominator is (x-6), and it becomes (0) at (x=6). Therefore (6) is not in the domain.
Step 3
Exam Tip
हर (x-6) है और (x=6) पर हर (0) बन जाता है। इसलिए (6) प्रांत में नहीं होगा।
Login to save your score, XP, coins and progress. Login
फलन (f(x)=\frac{x+2}{x+5}) का प्रांत क्या है?
What is the domain of (f(x)=\frac{x+2}{x+5})?
#domain
#rational-expression
#class11
50 50-50 2 wrong hide
⏭ Skip Next question
+10 Time+ 10 sec extra
? Hint Small clue
A \(\mathbb{R}-{-5}\)
B \(\mathbb{R}-{5}\)
C \([ -5,\infty\))
D \(\mathbb{R}\)
Explanation opens after your attempt
Correct Answer
A. \(\mathbb{R}-{-5}\)
Step 1
Concept
The denominator is (x+5), and it becomes (0) at (x=-5). Hence (-5) is excluded from the domain.
Step 2
Why this answer is correct
The correct answer is A. \(\mathbb{R}-{-5}\). The denominator is (x+5), and it becomes (0) at (x=-5). Hence (-5) is excluded from the domain.
Step 3
Exam Tip
हर (x+5) है और (x=-5) पर यह (0) होता है। इसलिए (-5) को प्रांत से हटाते हैं।
Login to save your score, XP, coins and progress. Login
यदि \(A=\{2,4,6\}\) और (f(x)=\frac{x}{2}), तो परिसर क्या है?
If \(A=\{2,4,6\}\) and (f(x)=\frac{x}{2}), what is the range?
#finite-domain
#range
#function-value
50 50-50 2 wrong hide
⏭ Skip Next question
+10 Time+ 10 sec extra
? Hint Small clue
A ({2,4,6})
B ({1,2,3})
C ({4,8,12})
D ({0,1,2})
Explanation opens after your attempt
Correct Answer
B. ({1,2,3})
Step 1
Concept
Substituting (2,4,6) gives (1,2,3). For a finite domain, find the value for each element.
Step 2
Why this answer is correct
The correct answer is B. ({1,2,3}). Substituting (2,4,6) gives (1,2,3). For a finite domain, find the value for each element.
Step 3
Exam Tip
(2,4,6) रखने पर मान (1,2,3) मिलते हैं। सीमित प्रांत में हर तत्व का मान निकालें।
Login to save your score, XP, coins and progress. Login
यदि \(A=\{-3,0,3\}\) और (f(x)=x+4), तो परिसर क्या है?
If \(A=\{-3,0,3\}\) and (f(x)=x+4), what is the range?
#finite-domain
#range
#linear-function
50 50-50 2 wrong hide
⏭ Skip Next question
+10 Time+ 10 sec extra
? Hint Small clue
A ({1,4,7})
B ({-3,0,3})
C ({4,7,10})
D ({-7,-4,-1})
Explanation opens after your attempt
Correct Answer
A. ({1,4,7})
Step 1
Concept
(f(-3)=1), (f(0)=4), and (f(3)=7). Hence the range is ({1,4,7}).
Step 2
Why this answer is correct
The correct answer is A. ({1,4,7}). (f(-3)=1), (f(0)=4), and (f(3)=7). Hence the range is ({1,4,7}).
Step 3
Exam Tip
(f(-3)=1), (f(0)=4), और (f(3)=7) हैं। इसलिए परिसर ({1,4,7}) है।
Login to save your score, XP, coins and progress. Login
फलन (f(x)=x-2 +9) का न्यूनतम मान क्या है?
What is the minimum value of (f(x)=x-2 +9)?
#minimum
#quadratic-function
#range
50 50-50 2 wrong hide
⏭ Skip Next question
+10 Time+ 10 sec extra
? Hint Small clue
A (0)
B (3)
C (9)
D (-9)
Explanation opens after your attempt
Step 1
Concept
Since \(x^2 \ge 0\), \(x^2+9 \ge 9\). The minimum value is (9).
Step 2
Why this answer is correct
The correct answer is C. (9). Since \(x^2 \ge 0\), \(x^2+9 \ge 9\). The minimum value is (9).
Step 3
Exam Tip
क्योंकि \(x^2 \ge 0\), इसलिए \(x^2+9 \ge 9\) है। न्यूनतम मान (9) है।
Login to save your score, XP, coins and progress. Login
फलन (f(x)=x-2 +9) का परिसर क्या है?
What is the range of (f(x)=x-2 +9)?
#range
#quadratic-function
#class11
50 50-50 2 wrong hide
⏭ Skip Next question
+10 Time+ 10 sec extra
? Hint Small clue
A \([0,\infty\))
B \([9,\infty\))
C (\(9,\infty\))
D \(\mathbb{R}\)
Explanation opens after your attempt
Correct Answer
B. \([9,\infty\))
Step 1
Concept
The minimum value of \(x^2\) is (0), so the minimum value of \(x^2+9\) is (9). Thus the range is \([9,\infty\)).
Step 2
Why this answer is correct
The correct answer is B. \([9,\infty\)). The minimum value of \(x^2\) is (0), so the minimum value of \(x^2+9\) is (9). Thus the range is \([9,\infty\)).
Step 3
Exam Tip
\(x^2\) का न्यूनतम मान (0) है, इसलिए \(x^2+9\) का न्यूनतम मान (9) है। अतः परिसर \([9,\infty\)) है।
Login to save your score, XP, coins and progress. Login
फलन (f(x)=5-(x-2)2 ) का अधिकतम मान क्या है?
What is the maximum value of (f(x)=5-(x-2)2 )?
#maximum
#quadratic-function
#range
50 50-50 2 wrong hide
⏭ Skip Next question
+10 Time+ 10 sec extra
? Hint Small clue
A (2)
B (0)
C (7)
D (5)
Explanation opens after your attempt
Step 1
Concept
The minimum value of ((x-2)2 ) is (0). Therefore the maximum value of (5-(x-2)2 ) is (5).
Step 2
Why this answer is correct
The correct answer is D. (5). The minimum value of ((x-2)2 ) is (0). Therefore the maximum value of (5-(x-2)2 ) is (5).
Step 3
Exam Tip
((x-2)2 ) का न्यूनतम मान (0) है। इसलिए (5-(x-2)2 ) का अधिकतम मान (5) है।
Login to save your score, XP, coins and progress. Login
फलन (f(x)=5-(x-2)2 ) का परिसर क्या है?
What is the range of (f(x)=5-(x-2)2 )?
#range
#quadratic-function
#maximum
50 50-50 2 wrong hide
⏭ Skip Next question
+10 Time+ 10 sec extra
? Hint Small clue
A (\(-\infty,5]\)
B \([5,\infty\))
C ([0,5])
D \(\mathbb{R}\)
Explanation opens after your attempt
Correct Answer
A. (\(-\infty,5]\)
Step 1
Concept
Since ((x-2)2 \ge 0), (5-(x-2)2 \le 5). There is no lower bound, so the range is (\(-\infty,5]\).
Step 2
Why this answer is correct
The correct answer is A. (\(-\infty,5]\). Since ((x-2)2 \ge 0), (5-(x-2)2 \le 5). There is no lower bound, so the range is (\(-\infty,5]\).
Step 3
Exam Tip
((x-2)2 \ge 0), इसलिए (5-(x-2)2 \le 5) है। नीचे कोई सीमा नहीं है, इसलिए परिसर (\(-\infty,5]\) है।
Login to save your score, XP, coins and progress. Login
फलन (f(x)=|x-4|+1) का न्यूनतम मान क्या है?
What is the minimum value of (f(x)=|x-4|+1)?
#modulus-function
#minimum
#class11
50 50-50 2 wrong hide
⏭ Skip Next question
+10 Time+ 10 sec extra
? Hint Small clue
A (0)
B (1)
C (4)
D (5)
Explanation opens after your attempt
Step 1
Concept
The minimum value of (|x-4|) is (0). Hence the minimum value of (|x-4|+1) is (1).
Step 2
Why this answer is correct
The correct answer is B. (1). The minimum value of (|x-4|) is (0). Hence the minimum value of (|x-4|+1) is (1).
Step 3
Exam Tip
(|x-4|) का न्यूनतम मान (0) होता है। इसलिए (|x-4|+1) का न्यूनतम मान (1) है।
Login to save your score, XP, coins and progress. Login
फलन (f(x)=|x-4|+1) का परिसर क्या है?
What is the range of (f(x)=|x-4|+1)?
#range
#modulus-function
#class11
50 50-50 2 wrong hide
⏭ Skip Next question
+10 Time+ 10 sec extra
? Hint Small clue
A \(\mathbb{R}\)
B \([0,\infty\))
C \([1,\infty\))
D (\(-\infty,1]\)
Explanation opens after your attempt
Correct Answer
C. \([1,\infty\))
Step 1
Concept
\(|x-4|\ge 0\), so \(|x-4|+1\ge 1\). Therefore the range is \([1,\infty\)).
Step 2
Why this answer is correct
The correct answer is C. \([1,\infty\)). \(|x-4|\ge 0\), so \(|x-4|+1\ge 1\). Therefore the range is \([1,\infty\)).
Step 3
Exam Tip
\(|x-4|\ge 0\), इसलिए \(|x-4|+1\ge 1\) है। अतः परिसर \([1,\infty\)) है।
Login to save your score, XP, coins and progress. Login
फलन (f(x)=6-|x+2|) का अधिकतम मान क्या है?
What is the maximum value of (f(x)=6-|x+2|)?
#maximum
#modulus-function
#range
50 50-50 2 wrong hide
⏭ Skip Next question
+10 Time+ 10 sec extra
? Hint Small clue
A (6)
B (2)
C (8)
D (0)
Explanation opens after your attempt
Step 1
Concept
The minimum value of (|x+2|) is (0). Therefore the maximum value of (6-|x+2|) is (6).
Step 2
Why this answer is correct
The correct answer is A. (6). The minimum value of (|x+2|) is (0). Therefore the maximum value of (6-|x+2|) is (6).
Step 3
Exam Tip
(|x+2|) का न्यूनतम मान (0) है। इसलिए (6-|x+2|) का अधिकतम मान (6) है।
Login to save your score, XP, coins and progress. Login
फलन (f(x)=6-|x+2|) का परिसर क्या है?
What is the range of (f(x)=6-|x+2|)?
#range
#modulus-function
#class11
50 50-50 2 wrong hide
⏭ Skip Next question
+10 Time+ 10 sec extra
? Hint Small clue
A \([6,\infty\))
B (\(-\infty,6]\)
C ([0,6])
D \(\mathbb{R}\)
Explanation opens after your attempt
Correct Answer
B. (\(-\infty,6]\)
Step 1
Concept
As (|x+2|) becomes larger, (6-|x+2|) becomes smaller. The maximum is (6), and there is no lower bound.
Step 2
Why this answer is correct
The correct answer is B. (\(-\infty,6]\). As (|x+2|) becomes larger, (6-|x+2|) becomes smaller. The maximum is (6), and there is no lower bound.
Step 3
Exam Tip
(|x+2|) बड़ा होने पर (6-|x+2|) छोटा होता जाता है। अधिकतम (6) है और नीचे कोई सीमा नहीं है।
Login to save your score, XP, coins and progress. Login
यदि (f(x)=\frac{x-3}{4}), तो (f(11)) क्या है?
If (f(x)=\frac{x-3}{4}), what is (f(11))?
#function-value
#linear-function
#class11
50 50-50 2 wrong hide
⏭ Skip Next question
+10 Time+ 10 sec extra
? Hint Small clue
A (4)
B (3)
C (2)
D (1)
Explanation opens after your attempt
Step 1
Concept
(f(11)=\frac{11-3}{4}=2). Substitute first and then simplify.
Step 2
Why this answer is correct
The correct answer is C. (2). (f(11)=\frac{11-3}{4}=2). Substitute first and then simplify.
Step 3
Exam Tip
(f(11)=\frac{11-3}{4}=2) है। प्रतिस्थापन के बाद सरल करें।
Login to save your score, XP, coins and progress. Login
यदि (f(x)=x-2 -2x), तो (f(4)) का मान क्या है?
If (f(x)=x-2 -2x), what is the value of (f(4))?
#function-value
#quadratic-function
#class11
50 50-50 2 wrong hide
⏭ Skip Next question
+10 Time+ 10 sec extra
? Hint Small clue
A (8)
B (12)
C (16)
D (4)
Explanation opens after your attempt
Step 1
Concept
(f(4)=42 -2(4)=16-8=8). Do the square and multiplication in the correct order.
Step 2
Why this answer is correct
The correct answer is A. (8). (f(4)=42 -2(4)=16-8=8). Do the square and multiplication in the correct order.
Step 3
Exam Tip
(f(4)=42 -2(4)=16-8=8) है। वर्ग और गुणा दोनों को सही क्रम में करें।
Login to save your score, XP, coins and progress. Login
यदि (f(x)=\sqrt{x+1}), तो (f(8)) क्या है?
If (f(x)=\sqrt{x+1}), what is (f(8))?
#function-value
#square-root
#class11
50 50-50 2 wrong hide
⏭ Skip Next question
+10 Time+ 10 sec extra
? Hint Small clue
A (2)
B (3)
C (4)
D (9)
Explanation opens after your attempt
Step 1
Concept
(f(8)=\sqrt{8+1}=\sqrt{9}=3). Add inside the radical before taking the square root.
Step 2
Why this answer is correct
The correct answer is B. (3). (f(8)=\sqrt{8+1}=\sqrt{9}=3). Add inside the radical before taking the square root.
Step 3
Exam Tip
(f(8)=\sqrt{8+1}=\sqrt{9}=3) है। वर्गमूल निकालते समय अंदर का मान पहले जोड़ें।
Login to save your score, XP, coins and progress. Login
फलन (f(x)=\sqrt{x+10}) का वास्तविक प्रांत क्या है?
What is the real domain of (f(x)=\sqrt{x+10})?
#domain
#square-root
#interval
50 50-50 2 wrong hide
⏭ Skip Next question
+10 Time+ 10 sec extra
? Hint Small clue
A \([-10,\infty\))
B (\(-\infty,-10]\)
C (\(-10,\infty\))
D \(\mathbb{R}\)
Explanation opens after your attempt
Correct Answer
A. \([-10,\infty\))
Step 1
Concept
The expression inside the square root must satisfy \(x+10 \ge 0\). This gives \(x \ge -10\).
Step 2
Why this answer is correct
The correct answer is A. \([-10,\infty\)). The expression inside the square root must satisfy \(x+10 \ge 0\). This gives \(x \ge -10\).
Step 3
Exam Tip
वर्गमूल के अंदर \(x+10 \ge 0\) चाहिए। इससे \(x \ge -10\) मिलता है।
Login to save your score, XP, coins and progress. Login
फलन (f(x)=\sqrt{12-3x}) का वास्तविक प्रांत क्या है?
What is the real domain of (f(x)=\sqrt{12-3x})?
#domain
#square-root
#linear-inequality
50 50-50 2 wrong hide
⏭ Skip Next question
+10 Time+ 10 sec extra
? Hint Small clue
A \([4,\infty\))
B (\(-\infty,4]\)
C (\(-\infty,4\))
D \(\mathbb{R}-{4}\)
Explanation opens after your attempt
Correct Answer
B. (\(-\infty,4]\)
Step 1
Concept
From \(12-3x \ge 0\), we get \(x \le 4\). Therefore the domain is (\(-\infty,4]\).
Step 2
Why this answer is correct
The correct answer is B. (\(-\infty,4]\). From \(12-3x \ge 0\), we get \(x \le 4\). Therefore the domain is (\(-\infty,4]\).
Step 3
Exam Tip
\(12-3x \ge 0\) से \(x \le 4\) मिलता है। इसलिए प्रांत (\(-\infty,4]\) है।
Login to save your score, XP, coins and progress. Login
फलन (f(x)=\frac{5}{x-2 -9}) के प्रांत से कौन से मान हटेंगे?
Which values are excluded from the domain of (f(x)=\frac{5}{x-2 -9})?
#domain
#rational-function
#excluded-values
50 50-50 2 wrong hide
⏭ Skip Next question
+10 Time+ 10 sec extra
? Hint Small clue
A ({-9,9})
B ({0})
C ({-3,3})
D \(\mathbb{R}\)
Explanation opens after your attempt
Correct Answer
C. ({-3,3})
Step 1
Concept
The denominator is \(x^2-9\), and \(x^2-9=0\) gives \(x=\pm3\). So (-3) and (3) are excluded.
Step 2
Why this answer is correct
The correct answer is C. ({-3,3}). The denominator is \(x^2-9\), and \(x^2-9=0\) gives \(x=\pm3\). So (-3) and (3) are excluded.
Step 3
Exam Tip
हर \(x^2-9\) है और \(x^2-9=0\) से \(x=\pm3\) मिलता है। इसलिए (-3) और (3) हटेंगे।
Login to save your score, XP, coins and progress. Login
फलन (f(x)=\frac{5}{x-2 -9}) का प्रांत क्या है?
What is the domain of (f(x)=\frac{5}{x-2 -9})?
#domain
#rational-function
#class11
50 50-50 2 wrong hide
⏭ Skip Next question
+10 Time+ 10 sec extra
? Hint Small clue
A \(\mathbb{R}-{-3,3}\)
B \(\mathbb{R}-{0}\)
C ([-3,3])
D \(\mathbb{R}\)
Explanation opens after your attempt
Correct Answer
A. \(\mathbb{R}-{-3,3}\)
Step 1
Concept
The denominator must not be (0), and \(x^2-9=0\) gives (x=-3,3). Hence the domain is \(\mathbb{R}-{-3,3}\).
Step 2
Why this answer is correct
The correct answer is A. \(\mathbb{R}-{-3,3}\). The denominator must not be (0), and \(x^2-9=0\) gives (x=-3,3). Hence the domain is \(\mathbb{R}-{-3,3}\).
Step 3
Exam Tip
हर (0) नहीं होना चाहिए और \(x^2-9=0\) पर (x=-3,3) मिलते हैं। इसलिए प्रांत \(\mathbb{R}-{-3,3}\) है।
Login to save your score, XP, coins and progress. Login
फलन (f(x)=\frac{1}{x-2 +6}) का प्रांत क्या है?
What is the domain of (f(x)=\frac{1}{x-2 +6})?
#domain
#rational-function
#class11
50 50-50 2 wrong hide
⏭ Skip Next question
+10 Time+ 10 sec extra
? Hint Small clue
A \(\mathbb{R}-{6}\)
B \(\mathbb{R}-{-6}\)
C \([0,\infty\))
D \(\mathbb{R}\)
Explanation opens after your attempt
Correct Answer
D. \(\mathbb{R}\)
Step 1
Concept
\(x^2+6\) is positive for every real (x). Therefore the denominator never becomes (0).
Step 2
Why this answer is correct
The correct answer is D. \(\mathbb{R}\). \(x^2+6\) is positive for every real (x). Therefore the denominator never becomes (0).
Step 3
Exam Tip
\(x^2+6\) हर वास्तविक (x) के लिए धनात्मक है। इसलिए हर कभी (0) नहीं बनता।
Login to save your score, XP, coins and progress. Login
फलन (f(x)=\frac{1}{x-2 +6}) के लिए सबसे बड़ा मान कब मिलेगा?
For (f(x)=\frac{1}{x-2 +6}), when is the greatest value obtained?
#range
#rational-function
#maximum
50 50-50 2 wrong hide
⏭ Skip Next question
+10 Time+ 10 sec extra
? Hint Small clue
A जब (x=0) / When (x=0)
B जब (x=1) / When (x=1)
C जब (x=6) / When (x=6)
D कभी नहीं / Never
Explanation opens after your attempt
Correct Answer
A. जब (x=0) / When (x=0)
Step 1
Concept
The denominator \(x^2+6\) is smallest at (6) when (x=0). Therefore the fraction is greatest then.
Step 2
Why this answer is correct
The correct answer is A. जब (x=0) / When (x=0). The denominator \(x^2+6\) is smallest at (6) when (x=0). Therefore the fraction is greatest then.
Step 3
Exam Tip
हर \(x^2+6\) सबसे छोटा (6) तब होता है जब (x=0)। इसलिए भिन्न का मान सबसे बड़ा तब मिलता है।
Login to save your score, XP, coins and progress. Login
फलन (f(x)=\frac{1}{x-2 +6}) का परिसर क्या है?
What is the range of (f(x)=\frac{1}{x-2 +6})?
#range
#rational-function
#class11
50 50-50 2 wrong hide
⏭ Skip Next question
+10 Time+ 10 sec extra
? Hint Small clue
A (\(0,\frac{1}{6}]\)
B \([0,\frac{1}{6}]\)
C \([\frac{1}{6},\infty\))
D \(\mathbb{R}\)
Explanation opens after your attempt
Correct Answer
A. (\(0,\frac{1}{6}]\)
Step 1
Concept
The minimum denominator is (6), so the maximum value is \(\frac{1}{6}\). The value (0) is never reached but can be approached.
Step 2
Why this answer is correct
The correct answer is A. (\(0,\frac{1}{6}]\). The minimum denominator is (6), so the maximum value is \(\frac{1}{6}\). The value (0) is never reached but can be approached.
Step 3
Exam Tip
हर का न्यूनतम मान (6) है, इसलिए अधिकतम मान \(\frac{1}{6}\) है। (0) कभी नहीं मिलता पर मान (0) के पास जा सकता है।
Login to save your score, XP, coins and progress. Login
फलन (f(x)=\sqrt{16-x-2 }) के लिए सही प्रांत कौन सा है?
Which is the correct domain for (f(x)=\sqrt{16-x-2 })?
#domain
#square-root
#interval
50 50-50 2 wrong hide
⏭ Skip Next question
+10 Time+ 10 sec extra
? Hint Small clue
A ((-4,4))
B ([-4,4])
C (\(-\infty,-4]\cup[4,\infty\))
D \(\mathbb{R}\)
Explanation opens after your attempt
Correct Answer
B. ([-4,4])
Step 1
Concept
For the square root, \(16-x^2 \ge 0\) is needed. This gives \(-4 \le x \le 4\).
Step 2
Why this answer is correct
The correct answer is B. ([-4,4]). For the square root, \(16-x^2 \ge 0\) is needed. This gives \(-4 \le x \le 4\).
Step 3
Exam Tip
वर्गमूल के लिए \(16-x^2 \ge 0\) चाहिए। इससे \(-4 \le x \le 4\) मिलता है।
Login to save your score, XP, coins and progress. Login
फलन (f(x)=\sqrt{16-x-2 }) का सबसे बड़ा मान क्या है?
What is the greatest value of (f(x)=\sqrt{16-x-2 })?
#range
#square-root
#maximum
50 50-50 2 wrong hide
⏭ Skip Next question
+10 Time+ 10 sec extra
? Hint Small clue
A (0)
B (2)
C (4)
D (16)
Explanation opens after your attempt
Step 1
Concept
\(16-x^2\) is greatest at (16) when (x=0). Therefore the greatest square-root value is (4).
Step 2
Why this answer is correct
The correct answer is C. (4). \(16-x^2\) is greatest at (16) when (x=0). Therefore the greatest square-root value is (4).
Step 3
Exam Tip
\(16-x^2\) सबसे बड़ा (16) तब होता है जब (x=0)। इसलिए वर्गमूल का सबसे बड़ा मान (4) है।
Login to save your score, XP, coins and progress. Login
फलन (f(x)=\sqrt{16-x-2 }) का परिसर क्या है?
What is the range of (f(x)=\sqrt{16-x-2 })?
#range
#square-root
#interval
50 50-50 2 wrong hide
⏭ Skip Next question
+10 Time+ 10 sec extra
? Hint Small clue
A ([0,4])
B ([-4,4])
C ((0,4))
D \([4,\infty\))
Explanation opens after your attempt
Correct Answer
A. ([0,4])
Step 1
Concept
A square-root value is not negative, and the maximum is (4). Hence the range is ([0,4]).
Step 2
Why this answer is correct
The correct answer is A. ([0,4]). A square-root value is not negative, and the maximum is (4). Hence the range is ([0,4]).
Step 3
Exam Tip
वर्गमूल का मान ऋणात्मक नहीं होता और अधिकतम (4) है। इसलिए परिसर ([0,4]) है।
Login to save your score, XP, coins and progress. Login
फलन (f(x)=(x+5)2 ) का परिसर क्या है?
What is the range of (f(x)=(x+5)2 )?
#range
#quadratic-function
#class11
50 50-50 2 wrong hide
⏭ Skip Next question
+10 Time+ 10 sec extra
? Hint Small clue
A (\(-\infty,0]\)
B \(\mathbb{R}\)
C \([5,\infty\))
D \([0,\infty\))
Explanation opens after your attempt
Correct Answer
D. \([0,\infty\))
Step 1
Concept
((x+5)2 ) is always (0) or positive. At (x=-5), the minimum value is (0).
Step 2
Why this answer is correct
The correct answer is D. \([0,\infty\)). ((x+5)2 ) is always (0) or positive. At (x=-5), the minimum value is (0).
Step 3
Exam Tip
((x+5)2 ) हमेशा (0) या धनात्मक होता है। (x=-5) पर न्यूनतम मान (0) मिलता है।
Login to save your score, XP, coins and progress. Login
फलन (f(x)=(x-3)2 +2) का परिसर क्या है?
What is the range of (f(x)=(x-3)2 +2)?
#range
#quadratic-function
#minimum
50 50-50 2 wrong hide
⏭ Skip Next question
+10 Time+ 10 sec extra
? Hint Small clue
A \([2,\infty\))
B \([3,\infty\))
C \([0,\infty\))
D \(\mathbb{R}\)
Explanation opens after your attempt
Correct Answer
A. \([2,\infty\))
Step 1
Concept
The minimum value of ((x-3)2 ) is (0). Therefore the minimum value of the whole function is (2).
Step 2
Why this answer is correct
The correct answer is A. \([2,\infty\)). The minimum value of ((x-3)2 ) is (0). Therefore the minimum value of the whole function is (2).
Step 3
Exam Tip
((x-3)2 ) का न्यूनतम मान (0) है। इसलिए पूरे फलन का न्यूनतम मान (2) है।
Login to save your score, XP, coins and progress. Login
फलन (f(x)=2-(x+1)2 ) का परिसर क्या है?
What is the range of (f(x)=2-(x+1)2 )?
#range
#quadratic-function
#maximum
50 50-50 2 wrong hide
⏭ Skip Next question
+10 Time+ 10 sec extra
? Hint Small clue
A \([2,\infty\))
B (\(-\infty,2]\)
C ([0,2])
D \(\mathbb{R}\)
Explanation opens after your attempt
Correct Answer
B. (\(-\infty,2]\)
Step 1
Concept
Since ((x+1)2 \ge 0), (2-(x+1)2 \le 2). Thus the range is (\(-\infty,2]\).
Step 2
Why this answer is correct
The correct answer is B. (\(-\infty,2]\). Since ((x+1)2 \ge 0), (2-(x+1)2 \le 2). Thus the range is (\(-\infty,2]\).
Step 3
Exam Tip
क्योंकि ((x+1)2 \ge 0), इसलिए (2-(x+1)2 \le 2) है। अतः परिसर (\(-\infty,2]\) है।
Login to save your score, XP, coins and progress. Login
वास्तविक मान वाले फलन \(f:A\to\mathbb{R}\) में कौन सा कथन सही है?
Which statement is correct for a real valued function \(f:A\to\mathbb{R}\)?
#real-valued-functions
#definition
#codomain
50 50-50 2 wrong hide
⏭ Skip Next question
+10 Time+ 10 sec extra
? Hint Small clue
A इसके निर्गत मान \(\mathbb{R}\) में होते हैं / Its output values lie in \(\mathbb{R}\)
B इसका प्रांत हमेशा \(\mathbb{R}\) होता है / Its domain is always \(\mathbb{R}\)
C इसका परिसर हमेशा (A) होता है / Its range is always (A)
D यह हमेशा स्थिर होता है / It is always constant
Explanation opens after your attempt
Correct Answer
A. इसके निर्गत मान \(\mathbb{R}\) में होते हैं / Its output values lie in \(\mathbb{R}\)
Step 1
Concept
In a real valued function, the values are real numbers. The domain (A) can be any suitable set.
Step 2
Why this answer is correct
The correct answer is A. इसके निर्गत मान \(\mathbb{R}\) में होते हैं / Its output values lie in \(\mathbb{R}\). In a real valued function, the values are real numbers. The domain (A) can be any suitable set.
Step 3
Exam Tip
वास्तविक मान वाले फलन में मान वास्तविक संख्याओं में होते हैं। प्रांत (A) कोई उपयुक्त समुच्चय हो सकता है।
Login to save your score, XP, coins and progress. Login
किसी फलन का परिसर किसे कहते हैं?
What is called the range of a function?
#range
#definition
#class11
50 50-50 2 wrong hide
⏭ Skip Next question
+10 Time+ 10 sec extra
? Hint Small clue
A सभी संभावित इनपुट / All possible inputs
B सभी प्राप्त वास्तविक मान / All actually obtained real values
C सहप्रांत का नाम / The name of codomain
D केवल पहला इनपुट / Only the first input
Explanation opens after your attempt
Correct Answer
B. सभी प्राप्त वास्तविक मान / All actually obtained real values
Step 1
Concept
The range is the set of values actually produced by the function. It should be understood separately from the codomain.
Step 2
Why this answer is correct
The correct answer is B. सभी प्राप्त वास्तविक मान / All actually obtained real values. The range is the set of values actually produced by the function. It should be understood separately from the codomain.
Step 3
Exam Tip
परिसर उन मानों का समुच्चय है जो फलन वास्तव में देता है। इसे सहप्रांत से अलग समझना चाहिए।
Login to save your score, XP, coins and progress. Login
किसी फलन का प्रांत किसे कहते हैं?
What is called the domain of a function?
#domain
#definition
#class11
50 50-50 2 wrong hide
⏭ Skip Next question
+10 Time+ 10 sec extra
? Hint Small clue
A सभी अनुमत इनपुट / All allowed inputs
B सभी प्राप्त आउटपुट / All obtained outputs
C केवल अधिकतम मान / Only maximum value
D केवल न्यूनतम मान / Only minimum value
Explanation opens after your attempt
Correct Answer
A. सभी अनुमत इनपुट / All allowed inputs
Step 1
Concept
The domain is the set of values that can be used as (x) in the function. While finding it, check denominator and square-root conditions.
Step 2
Why this answer is correct
The correct answer is A. सभी अनुमत इनपुट / All allowed inputs. The domain is the set of values that can be used as (x) in the function. While finding it, check denominator and square-root conditions.
Step 3
Exam Tip
प्रांत वे मान हैं जिन्हें (x) के रूप में फलन में रखा जा सकता है। प्रांत निकालते समय हर और वर्गमूल की शर्त देखें।
Login to save your score, XP, coins and progress. Login
फलन (f(x)=\frac{1}{\sqrt{x+2}}) का प्रांत क्या है?
What is the domain of (f(x)=\frac{1}{\sqrt{x+2}})?
#domain
#square-root
#rational-function
50 50-50 2 wrong hide
⏭ Skip Next question
+10 Time+ 10 sec extra
? Hint Small clue
A \([-2,\infty\))
B (\(-2,\infty\))
C (\(-\infty,-2]\)
D \(\mathbb{R}\)
Explanation opens after your attempt
Correct Answer
B. (\(-2,\infty\))
Step 1
Concept
The denominator contains \(\sqrt{x+2}\), so (x+2>0) is required. Hence (x>-2).
Step 2
Why this answer is correct
The correct answer is B. (\(-2,\infty\)). The denominator contains \(\sqrt{x+2}\), so (x+2>0) is required. Hence (x>-2).
Step 3
Exam Tip
हर में \(\sqrt{x+2}\) है, इसलिए (x+2>0) चाहिए। अतः (x>-2) है।
Login to save your score, XP, coins and progress. Login
फलन (f(x)=\frac{1}{\sqrt{7-x}}) का प्रांत क्या है?
What is the domain of (f(x)=\frac{1}{\sqrt{7-x}})?
#domain
#square-root
#rational-function
50 50-50 2 wrong hide
⏭ Skip Next question
+10 Time+ 10 sec extra
? Hint Small clue
A (\(-\infty,7\))
B (\(-\infty,7]\)
C \([7,\infty\))
D \(\mathbb{R}-{7}\)
Explanation opens after your attempt
Correct Answer
A. (\(-\infty,7\))
Step 1
Concept
The square root is in the denominator, so (7-x>0) is needed. This gives (x<7).
Step 2
Why this answer is correct
The correct answer is A. (\(-\infty,7\)). The square root is in the denominator, so (7-x>0) is needed. This gives (x<7).
Step 3
Exam Tip
हर में वर्गमूल है, इसलिए (7-x>0) चाहिए। इससे (x<7) मिलता है।
Login to save your score, XP, coins and progress. Login
फलन (f(x)=\frac{x}{x-2 +1}) का प्रांत क्या है?
What is the domain of (f(x)=\frac{x}{x-2 +1})?
#domain
#rational-function
#class11
50 50-50 2 wrong hide
⏭ Skip Next question
+10 Time+ 10 sec extra
? Hint Small clue
A \(\mathbb{R}\)
B \(\mathbb{R}-{0}\)
C \([0,\infty\))
D ((-1,1))
Explanation opens after your attempt
Correct Answer
A. \(\mathbb{R}\)
Step 1
Concept
The denominator \(x^2+1\) is never (0). Therefore the function is defined for every real (x).
Step 2
Why this answer is correct
The correct answer is A. \(\mathbb{R}\). The denominator \(x^2+1\) is never (0). Therefore the function is defined for every real (x).
Step 3
Exam Tip
हर \(x^2+1\) कभी (0) नहीं होता। इसलिए फलन हर वास्तविक (x) पर परिभाषित है।
Login to save your score, XP, coins and progress. Login
यदि \(A=\{0,1,2,3\}\) और (f(x)=2x+1), तो परिसर क्या है?
If \(A=\{0,1,2,3\}\) and (f(x)=2x+1), what is the range?
#finite-domain
#range
#linear-function
50 50-50 2 wrong hide
⏭ Skip Next question
+10 Time+ 10 sec extra
? Hint Small clue
A ({1,3,5,7})
B ({0,1,2,3})
C ({2,4,6,8})
D ({1,2,3,4})
Explanation opens after your attempt
Correct Answer
A. ({1,3,5,7})
Step 1
Concept
Substituting (0,1,2,3) gives (1,3,5,7). In the range, write only the obtained values.
Step 2
Why this answer is correct
The correct answer is A. ({1,3,5,7}). Substituting (0,1,2,3) gives (1,3,5,7). In the range, write only the obtained values.
Step 3
Exam Tip
(0,1,2,3) रखने पर मान (1,3,5,7) मिलते हैं। परिसर में केवल प्राप्त मान लिखते हैं।
Login to save your score, XP, coins and progress. Login
यदि \(A=\{-2,-1,0,1\}\) और (f(x)=x-2 +1), तो परिसर क्या है?
If \(A=\{-2,-1,0,1\}\) and (f(x)=x-2 +1), what is the range?
#finite-domain
#range
#quadratic-function
50 50-50 2 wrong hide
⏭ Skip Next question
+10 Time+ 10 sec extra
? Hint Small clue
A ({1,2,5})
B ({2,5})
C ({-2,-1,0,1})
D ({0,1,2})
Explanation opens after your attempt
Correct Answer
A. ({1,2,5})
Step 1
Concept
The values obtained are (5,2,1,2). The distinct values are ({1,2,5}).
Step 2
Why this answer is correct
The correct answer is A. ({1,2,5}). The values obtained are (5,2,1,2). The distinct values are ({1,2,5}).
Step 3
Exam Tip
मान क्रमशः (5,2,1,2) मिलते हैं। अलग-अलग मान ({1,2,5}) हैं।
Login to save your score, XP, coins and progress. Login
यदि (f(x)=|x-6|), तो (f(2)) क्या है?
If (f(x)=|x-6|), what is (f(2))?
#function-value
#modulus-function
#class11
50 50-50 2 wrong hide
⏭ Skip Next question
+10 Time+ 10 sec extra
? Hint Small clue
A (8)
B (4)
C (-4)
D (6)
Explanation opens after your attempt
Step 1
Concept
(f(2)=|2-6|=|-4|=4). The final modulus value is always non-negative.
Step 2
Why this answer is correct
The correct answer is B. (4). (f(2)=|2-6|=|-4|=4). The final modulus value is always non-negative.
Step 3
Exam Tip
(f(2)=|2-6|=|-4|=4) है। मॉड्यूलस का अंतिम मान हमेशा गैर-ऋणात्मक होता है।
Login to save your score, XP, coins and progress. Login
यदि (f(x)=3x-2 ) और \(x \in \mathbb{R}\), तो परिसर क्या है?
If (f(x)=3x-2 ) and \(x \in \mathbb{R}\), what is the range?
#range
#quadratic-function
#class11
50 50-50 2 wrong hide
⏭ Skip Next question
+10 Time+ 10 sec extra
? Hint Small clue
A (\(0,\infty\))
B \([0,\infty\))
C \(\mathbb{R}\)
D (\(-\infty,0]\)
Explanation opens after your attempt
Correct Answer
B. \([0,\infty\))
Step 1
Concept
Since \(x^2\ge 0\), \(3x^2\ge 0\). At (x=0), the value (0) is obtained.
Step 2
Why this answer is correct
The correct answer is B. \([0,\infty\)). Since \(x^2\ge 0\), \(3x^2\ge 0\). At (x=0), the value (0) is obtained.
Step 3
Exam Tip
\(x^2\ge 0\), इसलिए \(3x^2\ge 0\) है। (x=0) पर मान (0) मिलता है।
Login to save your score, XP, coins and progress. Login
फलन (f(x)=-x-2 ) का परिसर क्या है जब \(x \in \mathbb{R}\)?
What is the range of (f(x)=-x-2 ) when \(x \in \mathbb{R}\)?
#range
#quadratic-function
#class11
50 50-50 2 wrong hide
⏭ Skip Next question
+10 Time+ 10 sec extra
? Hint Small clue
A \([0,\infty\))
B \(\mathbb{R}\)
C (\(-\infty,0]\)
D (\(0,\infty\))
Explanation opens after your attempt
Correct Answer
C. (\(-\infty,0]\)
Step 1
Concept
Since \(x^2\ge 0\), \(-x^2\le 0\). The maximum (0) occurs at (x=0).
Step 2
Why this answer is correct
The correct answer is C. (\(-\infty,0]\). Since \(x^2\ge 0\), \(-x^2\le 0\). The maximum (0) occurs at (x=0).
Step 3
Exam Tip
क्योंकि \(x^2\ge 0\), इसलिए \(-x^2\le 0\) है। अधिकतम (0) (x=0) पर मिलता है।
Login to save your score, XP, coins and progress. Login
फलन (f(x)=4x-2 -1) का परिसर क्या है?
What is the range of (f(x)=4x-2 -1)?
#range
#quadratic-function
#minimum
50 50-50 2 wrong hide
⏭ Skip Next question
+10 Time+ 10 sec extra
? Hint Small clue
A \([-1,\infty\))
B \([0,\infty\))
C (\(-\infty,-1]\)
D \(\mathbb{R}\)
Explanation opens after your attempt
Correct Answer
A. \([-1,\infty\))
Step 1
Concept
The minimum value of \(4x^2\) is (0). Hence the minimum value of \(4x^2-1\) is (-1).
Step 2
Why this answer is correct
The correct answer is A. \([-1,\infty\)). The minimum value of \(4x^2\) is (0). Hence the minimum value of \(4x^2-1\) is (-1).
Step 3
Exam Tip
\(4x^2\) का न्यूनतम मान (0) है। इसलिए \(4x^2-1\) का न्यूनतम मान (-1) है।
Login to save your score, XP, coins and progress. Login
फलन (f(x)=\sqrt{3x+12}) का प्रांत क्या है?
What is the domain of (f(x)=\sqrt{3x+12})?
#domain
#square-root
#linear-inequality
50 50-50 2 wrong hide
⏭ Skip Next question
+10 Time+ 10 sec extra
? Hint Small clue
A \([-4,\infty\))
B (\(-\infty,-4]\)
C (\(-4,\infty\))
D \(\mathbb{R}\)
Explanation opens after your attempt
Correct Answer
A. \([-4,\infty\))
Step 1
Concept
For the square root, \(3x+12 \ge 0\) is required. This gives \(x \ge -4\).
Step 2
Why this answer is correct
The correct answer is A. \([-4,\infty\)). For the square root, \(3x+12 \ge 0\) is required. This gives \(x \ge -4\).
Step 3
Exam Tip
वर्गमूल के लिए \(3x+12 \ge 0\) चाहिए। इससे \(x \ge -4\) मिलता है।
Login to save your score, XP, coins and progress. Login
फलन (f(x)=\frac{2x+1}{3}) का परिसर क्या है जब \(x \in \mathbb{R}\)?
What is the range of (f(x)=\frac{2x+1}{3}) when \(x \in \mathbb{R}\)?
#range
#linear-function
#class11
50 50-50 2 wrong hide
⏭ Skip Next question
+10 Time+ 10 sec extra
? Hint Small clue
A \([0,\infty\))
B \(\mathbb{R}\)
C ({1})
D (\(-\infty,0]\)
Explanation opens after your attempt
Correct Answer
B. \(\mathbb{R}\)
Step 1
Concept
\(\frac{2x+1}{3}\) is a non-constant linear function. When (x) is real, its range is \(\mathbb{R}\).
Step 2
Why this answer is correct
The correct answer is B. \(\mathbb{R}\). \(\frac{2x+1}{3}\) is a non-constant linear function. When (x) is real, its range is \(\mathbb{R}\).
Step 3
Exam Tip
\(\frac{2x+1}{3}\) अस्थिर रेखीय फलन है। (x) वास्तविक होने पर इसका परिसर \(\mathbb{R}\) है।
Login to save your score, XP, coins and progress. Login
फलन (f(x)=-4) का परिसर क्या है?
What is the range of (f(x)=-4)?
#constant-function
#range
#class11
50 50-50 2 wrong hide
⏭ Skip Next question
+10 Time+ 10 sec extra
? Hint Small clue
A \(\mathbb{R}\)
B \([-4,\infty\))
C ({-4})
D (\(-\infty,-4]\)
Explanation opens after your attempt
Step 1
Concept
This is a constant function and gives only (-4) for every input. Hence the range is ({-4}).
Step 2
Why this answer is correct
The correct answer is C. ({-4}). This is a constant function and gives only (-4) for every input. Hence the range is ({-4}).
Step 3
Exam Tip
यह स्थिर फलन है और हर इनपुट पर केवल (-4) देता है। इसलिए परिसर ({-4}) है।
Login to save your score, XP, coins and progress. Login
यदि (f(x)=\sqrt{x}) और प्रांत ([0,9]) है, तो परिसर क्या है?
If (f(x)=\sqrt{x}) and the domain is ([0,9]), what is the range?
#range
#restricted-domain
#square-root
50 50-50 2 wrong hide
⏭ Skip Next question
+10 Time+ 10 sec extra
? Hint Small clue
A ([0,3])
B ([0,9])
C ([3,9])
D ((0,3))
Explanation opens after your attempt
Correct Answer
A. ([0,3])
Step 1
Concept
\(\sqrt{x}\) takes values from (0) to (3) on ([0,9]). Therefore the range is ([0,3]).
Step 2
Why this answer is correct
The correct answer is A. ([0,3]). \(\sqrt{x}\) takes values from (0) to (3) on ([0,9]). Therefore the range is ([0,3]).
Step 3
Exam Tip
\(\sqrt{x}\) ([0,9]) पर (0) से (3) तक मान लेता है। इसलिए परिसर ([0,3]) है।
Login to save your score, XP, coins and progress. Login
यदि (f(x)=x-2 ) और प्रांत ([-2,3]) है, तो परिसर क्या है?
If (f(x)=x-2 ) and the domain is ([-2,3]), what is the range?
#range
#restricted-domain
#quadratic-function
50 50-50 2 wrong hide
⏭ Skip Next question
+10 Time+ 10 sec extra
? Hint Small clue
A ([4,9])
B ([0,9])
C ([-2,3])
D ([0,4])
Explanation opens after your attempt
Correct Answer
B. ([0,9])
Step 1
Concept
The interval ([-2,3]) includes (0), so the minimum value is (0). The largest square is \(3^2=9\), so the range is ([0,9]).
Step 2
Why this answer is correct
The correct answer is B. ([0,9]). The interval ([-2,3]) includes (0), so the minimum value is (0). The largest square is \(3^2=9\), so the range is ([0,9]).
Step 3
Exam Tip
अंतराल ([-2,3]) में (0) शामिल है, इसलिए न्यूनतम मान (0) है। सबसे बड़ा वर्ग \(3^2=9\) है, इसलिए परिसर ([0,9]) है।
Login to save your score, XP, coins and progress. Login
