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Class 10 Mathematics Medium Quiz

Level 60 • 50/50 questions • 35 seconds per question.

Level readiness 50/50 Questions
Time Left 29:10 35 sec/question
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Question 1 / 50 0 score
Answered 0/50 Correct 0 Time 29:10

समीकरण (2x+5y=16) और (6x+15y=k) के अनंत हल होने के लिए (k) का मान क्या होगा?

What is the value of (k) for (2x+5y=16) and (6x+15y=k) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

B. (48)

Step 1

Concept

The second equation must be (3) times the first so (k=48). For infinitely many solutions all ratios must be equal.

Step 2

Why this answer is correct

The correct answer is B. (48). The second equation must be (3) times the first so (k=48). For infinitely many solutions all ratios must be equal.

Step 3

Exam Tip

दूसरा समीकरण पहले का (3) गुना होना चाहिए इसलिए (k=48)। अनंत हल के लिए सभी अनुपात बराबर होने चाहिए।

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समीकरण (ax+4y=20) और (9x+12y=61) का कोई हल न होने के लिए (a) का मान क्या होगा?

What is the value of (a) for (ax+4y=20) and (9x+12y=61) to have no solution?

Explanation opens after your attempt
Correct Answer

B. (3)

Step 1

Concept

For no solution (a/9=4/12) and (20/61) must be different. This gives (a=3).

Step 2

Why this answer is correct

The correct answer is B. (3). For no solution (a/9=4/12) and (20/61) must be different. This gives (a=3).

Step 3

Exam Tip

कोई हल नहीं के लिए (a/9=4/12) और (20/61) अलग होना चाहिए। इससे (a=3) मिलता है।

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यदि (5x+2y=13) और (10x+4y=m) असंगत युग्म हैं तो (m) के लिए सही शर्त क्या है?

If (5x+2y=13) and (10x+4y=m) form an inconsistent pair then what is the correct condition for (m)?

Explanation opens after your attempt
Correct Answer

C. \(m \ne 26\)

Step 1

Concept

The first two ratios are equal so the constant ratio must differ for inconsistency. Hence \(m \ne 26\).

Step 2

Why this answer is correct

The correct answer is C. \(m \ne 26\). The first two ratios are equal so the constant ratio must differ for inconsistency. Hence \(m \ne 26\).

Step 3

Exam Tip

पहले दो अनुपात बराबर हैं इसलिए असंगत होने के लिए स्थिर पद का अनुपात अलग होना चाहिए। अतः \(m \ne 26\)।

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समीकरण (8x+3y=21) और (16x+6y=42) के लिए सही निष्कर्ष क्या है?

What is the correct conclusion for (8x+3y=21) and (16x+6y=42)?

Explanation opens after your attempt
Correct Answer

A. अनंत हलInfinitely many solutions

Step 1

Concept

The second equation is (2) times the first so both lines are coincident. Coincident lines have infinitely many solutions.

Step 2

Why this answer is correct

The correct answer is A. अनंत हल / Infinitely many solutions. The second equation is (2) times the first so both lines are coincident. Coincident lines have infinitely many solutions.

Step 3

Exam Tip

दूसरा समीकरण पहले का (2) गुना है इसलिए दोनों रेखाएं संपाती हैं। संपाती रेखाओं के अनंत हल होते हैं।

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समीकरण (9x-4y=17) और (18x-8y=39) के लिए हलों की संख्या क्या होगी?

How many solutions will (9x-4y=17) and (18x-8y=39) have?

Explanation opens after your attempt
Correct Answer

C. कोई हल नहींNo solution

Step 1

Concept

Here (9/18=(-4)/(-8)) but (17/39) is different. Therefore the lines are parallel and distinct.

Step 2

Why this answer is correct

The correct answer is C. कोई हल नहीं / No solution. Here (9/18=(-4)/(-8)) but (17/39) is different. Therefore the lines are parallel and distinct.

Step 3

Exam Tip

यहां (9/18=(-4)/(-8)) लेकिन (17/39) अलग है। इसलिए रेखाएं समानांतर और अलग हैं।

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समीकरण (4x+7y=23) और (9x+15y=48) के लिए सही हल-स्थिति क्या है?

What is the correct solution status for (4x+7y=23) and (9x+15y=48)?

Explanation opens after your attempt
Correct Answer

B. एक अद्वितीय हलOne unique solution

Step 1

Concept

Here \(4/9 \ne 7/15\) so the lines intersect at one point. If the first two ratios differ there is one unique solution.

Step 2

Why this answer is correct

The correct answer is B. एक अद्वितीय हल / One unique solution. Here \(4/9 \ne 7/15\) so the lines intersect at one point. If the first two ratios differ there is one unique solution.

Step 3

Exam Tip

यहां \(4/9 \ne 7/15\) इसलिए रेखाएं एक बिंदु पर कटती हैं। पहले दो अनुपात अलग हों तो एक अद्वितीय हल होता है।

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यदि \(a_1/a_2=b_1/b_2=c_1/c_2\) हो तो समीकरणों के युग्म की प्रकृति क्या होगी?

If \(a_1/a_2=b_1/b_2=c_1/c_2\) then what will be the nature of the pair of equations?

Explanation opens after your attempt
Correct Answer

C. संगत और आश्रितConsistent and dependent

Step 1

Concept

If all three ratios are equal both equations represent the same line. Such a pair is consistent and dependent.

Step 2

Why this answer is correct

The correct answer is C. संगत और आश्रित / Consistent and dependent. If all three ratios are equal both equations represent the same line. Such a pair is consistent and dependent.

Step 3

Exam Tip

तीनों अनुपात बराबर हों तो दोनों समीकरण एक ही रेखा दर्शाते हैं। ऐसा युग्म संगत और आश्रित होता है।

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यदि \(a_1/a_2=b_1/b_2 \ne c_1/c_2\) हो तो ग्राफ में कौन-सी स्थिति बनेगी?

If \(a_1/a_2=b_1/b_2 \ne c_1/c_2\) then which situation will occur in the graph?

Explanation opens after your attempt
Correct Answer

C. अलग समानांतर रेखाएंDistinct parallel lines

Step 1

Concept

If the first two ratios are equal and the third differs the lines are parallel and distinct. Therefore no common solution is obtained.

Step 2

Why this answer is correct

The correct answer is C. अलग समानांतर रेखाएं / Distinct parallel lines. If the first two ratios are equal and the third differs the lines are parallel and distinct. Therefore no common solution is obtained.

Step 3

Exam Tip

पहले दो अनुपात बराबर और तीसरा अलग हो तो रेखाएं समानांतर और अलग होती हैं। इसलिए कोई सामान्य हल नहीं मिलता।

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समीकरण (px+6y=18) और (10x+15y=45) के अनंत हल होने के लिए (p) का मान क्या होगा?

What is the value of (p) for (px+6y=18) and (10x+15y=45) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

B. (3)

Step 1

Concept

For infinitely many solutions (p/10=6/15=18/45) must hold. Therefore (p=3).

Step 2

Why this answer is correct

The correct answer is B. (3). For infinitely many solutions (p/10=6/15=18/45) must hold. Therefore (p=3).

Step 3

Exam Tip

अनंत हल के लिए (p/10=6/15=18/45) होना चाहिए। इसलिए (p=3)।

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समीकरण (7x+qy=29) और (14x+10y=58) के अनंत हल होने के लिए (q) क्या होगा?

What will (q) be for (7x+qy=29) and (14x+10y=58) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

C. (5)

Step 1

Concept

The second equation is (2) times the first so (q/10=1/2) must hold. Hence (q=5).

Step 2

Why this answer is correct

The correct answer is C. (5). The second equation is (2) times the first so (q/10=1/2) must hold. Hence (q=5).

Step 3

Exam Tip

दूसरा समीकरण पहले का (2) गुना है इसलिए (q/10=1/2) होना चाहिए। अतः (q=5)।

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समीकरण (6x+ky=24) और (3x+5y=17) का अद्वितीय हल होने के लिए कौन-सी शर्त सही है?

Which condition is correct for (6x+ky=24) and (3x+5y=17) to have a unique solution?

Explanation opens after your attempt
Correct Answer

B. \(k \ne 10\)

Step 1

Concept

For a unique solution \(6/3 \ne k/5\) must hold. Therefore \(k \ne 10\) is the correct condition.

Step 2

Why this answer is correct

The correct answer is B. \(k \ne 10\). For a unique solution \(6/3 \ne k/5\) must hold. Therefore \(k \ne 10\) is the correct condition.

Step 3

Exam Tip

अद्वितीय हल के लिए \(6/3 \ne k/5\) होना चाहिए। इसलिए \(k \ne 10\) सही शर्त है।

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समीकरण (5x+ay=35) और (15x+18y=105) के अनंत हल होने के लिए (a) क्या होगा?

What will (a) be for (5x+ay=35) and (15x+18y=105) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

C. (6)

Step 1

Concept

For infinitely many solutions (5/15=a/18=35/105) must hold. This gives (a=6).

Step 2

Why this answer is correct

The correct answer is C. (6). For infinitely many solutions (5/15=a/18=35/105) must hold. This gives (a=6).

Step 3

Exam Tip

अनंत हल के लिए (5/15=a/18=35/105) होना चाहिए। इससे (a=6) मिलता है।

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समीकरण (bx+8y=32) और (12x+24y=71) का कोई हल न होने के लिए (b) क्या होगा?

What will (b) be for (bx+8y=32) and (12x+24y=71) to have no solution?

Explanation opens after your attempt
Correct Answer

B. (4)

Step 1

Concept

For no solution (b/12=8/24) and (32/71) must be different. Hence (b=4).

Step 2

Why this answer is correct

The correct answer is B. (4). For no solution (b/12=8/24) and (32/71) must be different. Hence (b=4).

Step 3

Exam Tip

कोई हल नहीं के लिए (b/12=8/24) और (32/71) अलग होना चाहिए। इसलिए (b=4)।

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समीकरण (14x+21y=49) और (2x+3y=8) के ग्राफ के बारे में सही कथन कौन-सा है?

Which statement is correct about the graph of (14x+21y=49) and (2x+3y=8)?

Explanation opens after your attempt
Correct Answer

C. रेखाएं अलग समानांतर हैंLines are distinct parallel

Step 1

Concept

Here (14/2=21/3) but (49/8) is different. Therefore the graph will show distinct parallel lines.

Step 2

Why this answer is correct

The correct answer is C. रेखाएं अलग समानांतर हैं / Lines are distinct parallel. Here (14/2=21/3) but (49/8) is different. Therefore the graph will show distinct parallel lines.

Step 3

Exam Tip

यहां (14/2=21/3) लेकिन (49/8) अलग है। इसलिए ग्राफ में अलग समानांतर रेखाएं बनेंगी।

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समीकरण (15x+10y=40) और (3x+2y=8) के ग्राफ में क्या दिखेगा?

What will be shown in the graph of (15x+10y=40) and (3x+2y=8)?

Explanation opens after your attempt
Correct Answer

A. एक ही रेखाSame line

Step 1

Concept

The first equation is (5) times the second. Therefore both equations show the same line.

Step 2

Why this answer is correct

The correct answer is A. एक ही रेखा / Same line. The first equation is (5) times the second. Therefore both equations show the same line.

Step 3

Exam Tip

पहला समीकरण दूसरे का (5) गुना है। इसलिए दोनों समीकरण एक ही रेखा दिखाते हैं।

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समीकरण (2x+11y=27) और (5x+19y=46) के ग्राफ का सही वर्णन क्या है?

What is the correct description of the graph of (2x+11y=27) and (5x+19y=46)?

Explanation opens after your attempt
Correct Answer

C. एक बिंदु पर कटती रेखाएंLines intersecting at one point

Step 1

Concept

Here \(2/5 \ne 11/19\) so the lines will intersect at one point. This gives one unique solution.

Step 2

Why this answer is correct

The correct answer is C. एक बिंदु पर कटती रेखाएं / Lines intersecting at one point. Here \(2/5 \ne 11/19\) so the lines will intersect at one point. This gives one unique solution.

Step 3

Exam Tip

यहां \(2/5 \ne 11/19\) इसलिए रेखाएं एक बिंदु पर कटेंगी। इससे एक अद्वितीय हल मिलेगा।

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समीकरण (4x+9y-31=0) और (12x+27y-93=0) के लिए सही अनुपात संबंध कौन-सा है?

Which ratio relation is correct for (4x+9y-31=0) and (12x+27y-93=0)?

Explanation opens after your attempt
Correct Answer

C. (412=9 / 27=(-31) / (-93))

Step 1

Concept

Here all three ratios are equal. Therefore both lines are coincident and have infinitely many solutions.

Step 2

Why this answer is correct

The correct answer is C. (4 / 12=9 / 27=(-31) / (-93)). Here all three ratios are equal. Therefore both lines are coincident and have infinitely many solutions.

Step 3

Exam Tip

यहां तीनों अनुपात बराबर हैं। इसलिए दोनों रेखाएं संपाती हैं और अनंत हल हैं।

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समीकरण (8x-3y+22=0) और (16x-6y+47=0) के लिए सही अनुपात संबंध क्या है?

What is the correct ratio relation for (8x-3y+22=0) and (16x-6y+47=0)?

Explanation opens after your attempt
Correct Answer

A. (816=(-3) / (-6) \ne 22 / 47)

Step 1

Concept

The first two ratios are equal and the third is different. Therefore there will be no solution.

Step 2

Why this answer is correct

The correct answer is A. (8 / 16=(-3) / (-6) \ne 22 / 47). The first two ratios are equal and the third is different. Therefore there will be no solution.

Step 3

Exam Tip

पहले दो अनुपात बराबर हैं और तीसरा अलग है। इसलिए कोई हल नहीं होगा।

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समीकरण (9x+5y-28=0) और (18x+11y-56=0) के लिए सही निष्कर्ष क्या है?

What is the correct conclusion for (9x+5y-28=0) and (18x+11y-56=0)?

Explanation opens after your attempt
Correct Answer

C. एक अद्वितीय हलOne unique solution

Step 1

Concept

Here \(9/18 \ne 5/11\) so the lines intersect at one point. In this case one unique solution is obtained.

Step 2

Why this answer is correct

The correct answer is C. एक अद्वितीय हल / One unique solution. Here \(9/18 \ne 5/11\) so the lines intersect at one point. In this case one unique solution is obtained.

Step 3

Exam Tip

यहां \(9/18 \ne 5/11\) इसलिए रेखाएं एक बिंदु पर कटती हैं। ऐसी स्थिति में एक अद्वितीय हल मिलता है।

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यदि (ax+9y=27) और (14x+21y=64) का कोई हल नहीं है तो (a) क्या होगा?

If (ax+9y=27) and (14x+21y=64) have no solution then what will (a) be?

Explanation opens after your attempt
Correct Answer

C. (6)

Step 1

Concept

For no solution (a/14=9/21) and (27/64) must be different. Therefore (a=6).

Step 2

Why this answer is correct

The correct answer is C. (6). For no solution (a/14=9/21) and (27/64) must be different. Therefore (a=6).

Step 3

Exam Tip

कोई हल नहीं के लिए (a/14=9/21) और (27/64) अलग होना चाहिए। इसलिए (a=6)।

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समीकरण (3x+by=24) और (12x+20y=96) के अनंत हल होने के लिए (b) का मान क्या है?

What is the value of (b) for (3x+by=24) and (12x+20y=96) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

C. (5)

Step 1

Concept

For infinitely many solutions (3/12=b/20=24/96) must hold. Therefore (b=5).

Step 2

Why this answer is correct

The correct answer is C. (5). For infinitely many solutions (3/12=b/20=24/96) must hold. Therefore (b=5).

Step 3

Exam Tip

अनंत हल के लिए (3/12=b/20=24/96) होना चाहिए। इसलिए (b=5)।

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समीकरण (11x+py=33) और (4x+2y=15) का अद्वितीय हल होने के लिए कौन-सी शर्त सही है?

Which condition is correct for (11x+py=33) and (4x+2y=15) to have a unique solution?

Explanation opens after your attempt
Correct Answer

B. (p \ne 112)

Step 1

Concept

For a unique solution \(11/4 \ne p/2\) must hold. Therefore \(p \ne 11/2\) is the correct condition.

Step 2

Why this answer is correct

The correct answer is B. \(p \ne 11 / 2\). For a unique solution \(11/4 \ne p/2\) must hold. Therefore \(p \ne 11/2\) is the correct condition.

Step 3

Exam Tip

अद्वितीय हल के लिए \(11/4 \ne p/2\) होना चाहिए। इसलिए \(p \ne 11/2\) सही शर्त है।

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यदि (7x+4y=37) और (21x+12y=n) के अनंत हल हैं तो (n) कितना होगा?

If (7x+4y=37) and (21x+12y=n) have infinitely many solutions then what is (n)?

Explanation opens after your attempt
Correct Answer

C. (111)

Step 1

Concept

The second equation must be (3) times the first. Therefore (n=111).

Step 2

Why this answer is correct

The correct answer is C. (111). The second equation must be (3) times the first. Therefore (n=111).

Step 3

Exam Tip

दूसरा समीकरण पहले का (3) गुना होना चाहिए। इसलिए (n=111) होगा।

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यदि (10x-5y=30) और (2x-y=t) असंगत हैं तो (t) के लिए सही शर्त क्या है?

If (10x-5y=30) and (2x-y=t) are inconsistent then what is the correct condition for (t)?

Explanation opens after your attempt
Correct Answer

B. \(t \ne 6\)

Step 1

Concept

The first two ratios are equal so (30/t) must be different for inconsistency. Hence \(t \ne 6\).

Step 2

Why this answer is correct

The correct answer is B. \(t \ne 6\). The first two ratios are equal so (30/t) must be different for inconsistency. Hence \(t \ne 6\).

Step 3

Exam Tip

पहले दो अनुपात बराबर हैं इसलिए असंगत होने के लिए (30/t) अलग होना चाहिए। अतः \(t \ne 6\)।

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समीकरण (6x+7y=41) और (18x+21y=123) को देखकर सबसे उचित निष्कर्ष क्या है?

What is the most suitable conclusion by observing (6x+7y=41) and (18x+21y=123)?

Explanation opens after your attempt
Correct Answer

C. अनंत हल हैंThere are infinitely many solutions

Step 1

Concept

The second equation is (3) times the first. Therefore both lines are coincident.

Step 2

Why this answer is correct

The correct answer is C. अनंत हल हैं / There are infinitely many solutions. The second equation is (3) times the first. Therefore both lines are coincident.

Step 3

Exam Tip

दूसरा समीकरण पहले का (3) गुना है। इसलिए दोनों रेखाएं संपाती हैं।

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समीकरण (12x+16y=36) और (3x+4y=11) को देखकर कौन-सा निष्कर्ष सही है?

Which conclusion is correct by observing (12x+16y=36) and (3x+4y=11)?

Explanation opens after your attempt
Correct Answer

B. पहले दो अनुपात बराबर हैं लेकिन स्थिर पद का अनुपात अलग हैFirst two ratios are equal but the constant ratio is different

Step 1

Concept

Here (12/3=16/4) but (36/11) is different. Therefore there will be no solution.

Step 2

Why this answer is correct

The correct answer is B. पहले दो अनुपात बराबर हैं लेकिन स्थिर पद का अनुपात अलग है / First two ratios are equal but the constant ratio is different. Here (12/3=16/4) but (36/11) is different. Therefore there will be no solution.

Step 3

Exam Tip

यहां (12/3=16/4) लेकिन (36/11) अलग है। इसलिए कोई हल नहीं होगा।

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समीकरण (11x+6y=35) और (5x+3y=17) में (a) और (b) के अनुपातों की तुलना से क्या पता चलता है?

What is found by comparing the ratios of (a) and (b) in (11x+6y=35) and (5x+3y=17)?

Explanation opens after your attempt
Correct Answer

C. (115 \ne 6 / 3) इसलिए एक अद्वितीय हल / 3) so one unique solution

Step 1

Concept

Here the first two ratios are different. Therefore the lines intersect at one point and give one solution.

Step 2

Why this answer is correct

The correct answer is C. \(11 / 5 \ne 6 / 3\) इसलिए एक अद्वितीय हल / 3) so one unique solution. Here the first two ratios are different. Therefore the lines intersect at one point and give one solution.

Step 3

Exam Tip

यहां पहले दो अनुपात अलग हैं। इसलिए रेखाएं एक बिंदु पर कटती हैं और एक हल देती हैं।

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समीकरण (16x+24y=88) और (2x+3y=11) का युग्म किस प्रकार का है?

What type of pair is (16x+24y=88) and (2x+3y=11)?

Explanation opens after your attempt
Correct Answer

A. संगत और आश्रितConsistent and dependent

Step 1

Concept

The first equation is (8) times the second. Therefore both are the same line and the pair is dependent.

Step 2

Why this answer is correct

The correct answer is A. संगत और आश्रित / Consistent and dependent. The first equation is (8) times the second. Therefore both are the same line and the pair is dependent.

Step 3

Exam Tip

पहला समीकरण दूसरे का (8) गुना है। इसलिए दोनों एक ही रेखा हैं और युग्म आश्रित है।

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समीकरण (18x+27y=63) और (2x+3y=8) का युग्म किस प्रकार का है?

What type of pair is (18x+27y=63) and (2x+3y=8)?

Explanation opens after your attempt
Correct Answer

C. असंगतInconsistent

Step 1

Concept

Here (18/2=27/3) but (63/8) is different. Therefore this is an inconsistent pair.

Step 2

Why this answer is correct

The correct answer is C. असंगत / Inconsistent. Here (18/2=27/3) but (63/8) is different. Therefore this is an inconsistent pair.

Step 3

Exam Tip

यहां (18/2=27/3) लेकिन (63/8) अलग है। इसलिए यह असंगत युग्म है।

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समीकरण (13x+4y=39) और (6x+2y=17) का युग्म किस प्रकार का है?

What type of pair is (13x+4y=39) and (6x+2y=17)?

Explanation opens after your attempt
Correct Answer

C. संगत और स्वतंत्रConsistent and independent

Step 1

Concept

Here \(13/6 \ne 4/2\) so the lines intersect. Hence the pair is consistent and independent.

Step 2

Why this answer is correct

The correct answer is C. संगत और स्वतंत्र / Consistent and independent. Here \(13/6 \ne 4/2\) so the lines intersect. Hence the pair is consistent and independent.

Step 3

Exam Tip

यहां \(13/6 \ne 4/2\) इसलिए रेखाएं कटती हैं। अतः युग्म संगत और स्वतंत्र है।

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एक दुकान में दो वस्तुओं के लिए (3x+4y=150) और (9x+12y=450) समीकरण बनते हैं। हलों की संख्या क्या होगी?

In a shop the equations for two items are (3x+4y=150) and (9x+12y=450). How many solutions will there be?

Explanation opens after your attempt
Correct Answer

C. अनंत हलInfinitely many solutions

Step 1

Concept

The second equation is (3) times the first. Therefore both conditions give the same information and have infinitely many solutions.

Step 2

Why this answer is correct

The correct answer is C. अनंत हल / Infinitely many solutions. The second equation is (3) times the first. Therefore both conditions give the same information and have infinitely many solutions.

Step 3

Exam Tip

दूसरा समीकरण पहले का (3) गुना है। इसलिए दोनों शर्तें एक ही जानकारी देती हैं और अनंत हल होते हैं।

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दो टिकटों के दामों के लिए (5x+4y=180) और (10x+8y=370) समीकरण बने। यह प्रणाली कैसी है?

For prices of two tickets the equations (5x+4y=180) and (10x+8y=370) are formed. What type of system is this?

Explanation opens after your attempt
Correct Answer

C. असंगतInconsistent

Step 1

Concept

The first two ratios are equal but (180/370) is different. Therefore the system is inconsistent.

Step 2

Why this answer is correct

The correct answer is C. असंगत / Inconsistent. The first two ratios are equal but (180/370) is different. Therefore the system is inconsistent.

Step 3

Exam Tip

पहले दो अनुपात बराबर हैं लेकिन (180/370) अलग है। इसलिए प्रणाली असंगत है।

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दो संख्याओं के लिए (4x+y=19) और (x-3y=2) समीकरण बनते हैं तो हल-स्थिति क्या होगी?

For two numbers the equations (4x+y=19) and (x-3y=2) are formed. What will be the solution status?

Explanation opens after your attempt
Correct Answer

A. एक अद्वितीय हलOne unique solution

Step 1

Concept

Here (4/1 \ne 1/(-3)) so the lines intersect. Such a pair has one unique solution.

Step 2

Why this answer is correct

The correct answer is A. एक अद्वितीय हल / One unique solution. Here (4/1 \ne 1/(-3)) so the lines intersect. Such a pair has one unique solution.

Step 3

Exam Tip

यहां (4/1 \ne 1/(-3)) इसलिए रेखाएं कटती हैं। ऐसे युग्म का एक अद्वितीय हल होता है।

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समीकरण (5x+6y=32) और (15x+18y=96) में तीनों अनुपातों का संबंध क्या है?

What is the relation among all three ratios in (5x+6y=32) and (15x+18y=96)?

Explanation opens after your attempt
Correct Answer

A. तीनों बराबर हैंAll three are equal

Step 1

Concept

Here (5/15=6/18=32/96). Therefore both equations form the same line.

Step 2

Why this answer is correct

The correct answer is A. तीनों बराबर हैं / All three are equal. Here (5/15=6/18=32/96). Therefore both equations form the same line.

Step 3

Exam Tip

यहां (5/15=6/18=32/96)। इसलिए दोनों समीकरण एक ही रेखा बनाते हैं।

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समीकरण (10x+15y=50) और (2x+3y=13) के लिए कौन-सा संबंध सही है?

Which relation is correct for (10x+15y=50) and (2x+3y=13)?

Explanation opens after your attempt
Correct Answer

C. (102=15 / 3 \ne 50 / 13)

Step 1

Concept

The first two ratios are equal but the constant ratio is different. Therefore there is no solution.

Step 2

Why this answer is correct

The correct answer is C. \(10 / 2=15 / 3 \ne 50 / 13\). The first two ratios are equal but the constant ratio is different. Therefore there is no solution.

Step 3

Exam Tip

पहले दो अनुपात बराबर हैं लेकिन स्थिर पद का अनुपात अलग है। इसलिए कोई हल नहीं है।

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समीकरण (7x+8y=26) और (14x+15y=51) के लिए कौन-सा कथन सही है?

Which statement is correct for (7x+8y=26) and (14x+15y=51)?

Explanation opens after your attempt
Correct Answer

B. (714 \ne 8 / 15) इसलिए एक अद्वितीय हल / 15) so one unique solution

Step 1

Concept

Here \(7/14 \ne 8/15\) so the lines intersect. Therefore there is one unique solution.

Step 2

Why this answer is correct

The correct answer is B. \(7 / 14 \ne 8 / 15\) इसलिए एक अद्वितीय हल / 15) so one unique solution. Here \(7/14 \ne 8/15\) so the lines intersect. Therefore there is one unique solution.

Step 3

Exam Tip

यहां \(7/14 \ne 8/15\) इसलिए रेखाएं कटती हैं। इस कारण एक अद्वितीय हल है।

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समीकरण (4x+5y=29) और (8x+10y=s) के संगत और आश्रित होने के लिए (s) क्या होगा?

What should (s) be for (4x+5y=29) and (8x+10y=s) to be consistent and dependent?

Explanation opens after your attempt
Correct Answer

C. (58)

Step 1

Concept

To be consistent and dependent the second equation must be (2) times the first. Hence (s=58).

Step 2

Why this answer is correct

The correct answer is C. (58). To be consistent and dependent the second equation must be (2) times the first. Hence (s=58).

Step 3

Exam Tip

संगत और आश्रित होने के लिए दूसरा समीकरण पहले का (2) गुना होना चाहिए। अतः (s=58)।

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समीकरण (6x+7y=31) और (12x+14y=r) के असंगत होने के लिए कौन-सी शर्त सही है?

Which condition is correct for (6x+7y=31) and (12x+14y=r) to be inconsistent?

Explanation opens after your attempt
Correct Answer

B. \(r \ne 62\)

Step 1

Concept

The first two ratios are equal so the constant ratio must be different for inconsistency. Hence \(r \ne 62\).

Step 2

Why this answer is correct

The correct answer is B. \(r \ne 62\). The first two ratios are equal so the constant ratio must be different for inconsistency. Hence \(r \ne 62\).

Step 3

Exam Tip

पहले दो अनुपात बराबर हैं इसलिए असंगत होने के लिए स्थिर पद का अनुपात अलग होना चाहिए। अतः \(r \ne 62\)।

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समीकरण (5x+3y=14) और (10x+ay=33) का कोई हल न होने के लिए (a) क्या होगा?

What will (a) be for (5x+3y=14) and (10x+ay=33) to have no solution?

Explanation opens after your attempt
Correct Answer

C. (6)

Step 1

Concept

For no solution (5/10=3/a) and (14/33) must be different. This gives (a=6).

Step 2

Why this answer is correct

The correct answer is C. (6). For no solution (5/10=3/a) and (14/33) must be different. This gives (a=6).

Step 3

Exam Tip

कोई हल नहीं के लिए (5/10=3/a) और (14/33) अलग होना चाहिए। इससे (a=6) मिलता है।

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समीकरण (8x+ky=72) और (2x+7y=18) के अनंत हल होने के लिए (k) क्या होगा?

What will (k) be for (8x+ky=72) and (2x+7y=18) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

C. (28)

Step 1

Concept

The first equation must be (4) times the second. Therefore (k=28).

Step 2

Why this answer is correct

The correct answer is C. (28). The first equation must be (4) times the second. Therefore (k=28).

Step 3

Exam Tip

पहला समीकरण दूसरे का (4) गुना होना चाहिए। इसलिए (k=28) है।

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यदि (lx+11y=44) और (10x+22y=91) का कोई हल नहीं है तो (l) का मान क्या होगा?

If (lx+11y=44) and (10x+22y=91) have no solution then what will be the value of (l)?

Explanation opens after your attempt
Correct Answer

C. (5)

Step 1

Concept

For no solution (l/10=11/22) and (44/91) must be different. Hence (l=5).

Step 2

Why this answer is correct

The correct answer is C. (5). For no solution (l/10=11/22) and (44/91) must be different. Hence (l=5).

Step 3

Exam Tip

कोई हल नहीं के लिए (l/10=11/22) और (44/91) अलग होना चाहिए। इसलिए (l=5)।

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समीकरण (12x+5y=41) और (24x+10y=82) को देखकर कौन-सा कथन सही है?

Which statement is correct by observing (12x+5y=41) and (24x+10y=82)?

Explanation opens after your attempt
Correct Answer

B. रेखाएं एक ही हैंLines are the same

Step 1

Concept

The second equation is (2) times the first. Therefore both lines are the same.

Step 2

Why this answer is correct

The correct answer is B. रेखाएं एक ही हैं / Lines are the same. The second equation is (2) times the first. Therefore both lines are the same.

Step 3

Exam Tip

दूसरा समीकरण पहले का (2) गुना है। इसलिए दोनों रेखाएं एक ही हैं।

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समीकरण (14x-10y=36) और (7x-5y=19) को देखकर सही निष्कर्ष क्या है?

What is the correct conclusion by observing (14x-10y=36) and (7x-5y=19)?

Explanation opens after your attempt
Correct Answer

A. कोई हल नहींNo solution

Step 1

Concept

Here (14/7=(-10)/(-5)) but (36/19) is different. Therefore the lines are parallel and distinct.

Step 2

Why this answer is correct

The correct answer is A. कोई हल नहीं / No solution. Here (14/7=(-10)/(-5)) but (36/19) is different. Therefore the lines are parallel and distinct.

Step 3

Exam Tip

यहां (14/7=(-10)/(-5)) लेकिन (36/19) अलग है। इसलिए रेखाएं समानांतर और अलग हैं।

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समीकरण (17x+6y=52) और (8x+3y=25) के लिए सही हल-स्थिति क्या है?

What is the correct solution status for (17x+6y=52) and (8x+3y=25)?

Explanation opens after your attempt
Correct Answer

C. एक अद्वितीय हलOne unique solution

Step 1

Concept

Here \(17/8 \ne 6/3\) so the lines will intersect. Hence there is one unique solution.

Step 2

Why this answer is correct

The correct answer is C. एक अद्वितीय हल / One unique solution. Here \(17/8 \ne 6/3\) so the lines will intersect. Hence there is one unique solution.

Step 3

Exam Tip

यहां \(17/8 \ne 6/3\) इसलिए रेखाएं कटेंगी। अतः एक अद्वितीय हल है।

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समीकरण (3x+4y=22) और (9x+12y=t) के असंगत होने के लिए (t) के लिए सही शर्त क्या है?

What is the correct condition on (t) for (3x+4y=22) and (9x+12y=t) to be inconsistent?

Explanation opens after your attempt
Correct Answer

B. \(t \ne 66\)

Step 1

Concept

The first two ratios are equal so the constant ratio must be different for inconsistency. Hence \(t \ne 66\) is correct.

Step 2

Why this answer is correct

The correct answer is B. \(t \ne 66\). The first two ratios are equal so the constant ratio must be different for inconsistency. Hence \(t \ne 66\) is correct.

Step 3

Exam Tip

पहले दो अनुपात बराबर हैं इसलिए असंगत होने के लिए स्थिर पद का अनुपात अलग होना चाहिए। अतः \(t \ne 66\) सही है।

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समीकरण (4x+ay=36) और (12x+21y=108) के अनंत हल होने के लिए (a) का मान क्या होगा?

What will be the value of (a) for (4x+ay=36) and (12x+21y=108) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

C. (7)

Step 1

Concept

For infinitely many solutions (4/12=a/21=36/108) must hold. Therefore (a=7).

Step 2

Why this answer is correct

The correct answer is C. (7). For infinitely many solutions (4/12=a/21=36/108) must hold. Therefore (a=7).

Step 3

Exam Tip

अनंत हल के लिए (4/12=a/21=36/108) होना चाहिए। इसलिए (a=7) मिलता है।

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समीकरण (5x+2y=18) और (15x+ky=54) का अद्वितीय हल होने के लिए कौन-सी शर्त सही है?

Which condition is correct for (5x+2y=18) and (15x+ky=54) to have a unique solution?

Explanation opens after your attempt
Correct Answer

B. \(k \ne 6\)

Step 1

Concept

For a unique solution \(5/15 \ne 2/k\) must hold. Therefore \(k \ne 6\) is the correct condition.

Step 2

Why this answer is correct

The correct answer is B. \(k \ne 6\). For a unique solution \(5/15 \ne 2/k\) must hold. Therefore \(k \ne 6\) is the correct condition.

Step 3

Exam Tip

अद्वितीय हल के लिए \(5/15 \ne 2/k\) होना चाहिए। इसलिए \(k \ne 6\) सही शर्त है।

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समीकरण (6x-7y+13=0) और (18x-21y+40=0) के लिए सही हल-स्थिति क्या है?

What is the correct solution status for (6x-7y+13=0) and (18x-21y+40=0)?

Explanation opens after your attempt
Correct Answer

C. कोई हल नहींNo solution

Step 1

Concept

Here (6/18=(-7)/(-21)) but (13/40) is different. Therefore the lines are parallel and distinct.

Step 2

Why this answer is correct

The correct answer is C. कोई हल नहीं / No solution. Here (6/18=(-7)/(-21)) but (13/40) is different. Therefore the lines are parallel and distinct.

Step 3

Exam Tip

यहां (6/18=(-7)/(-21)) लेकिन (13/40) अलग है। इसलिए रेखाएं समानांतर और अलग हैं।

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दो वस्तुओं की कीमतों के लिए (2x+7y=160) और (5x+16y=370) समीकरण बने। हल-स्थिति क्या होगी?

For prices of two items the equations (2x+7y=160) and (5x+16y=370) are formed. What will be the solution status?

Explanation opens after your attempt
Correct Answer

A. एक अद्वितीय हलOne unique solution

Step 1

Concept

Here \(2/5 \ne 7/16\) so the lines intersect at one point. Such a pair has one unique solution.

Step 2

Why this answer is correct

The correct answer is A. एक अद्वितीय हल / One unique solution. Here \(2/5 \ne 7/16\) so the lines intersect at one point. Such a pair has one unique solution.

Step 3

Exam Tip

यहां \(2/5 \ne 7/16\) इसलिए रेखाएं एक बिंदु पर कटती हैं। ऐसे युग्म का एक अद्वितीय हल होता है।

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समीकरण (7x+9y=43) और (14x+18y=86) के ग्राफ के बारे में सही कथन कौन-सा है?

Which statement is correct about the graph of (7x+9y=43) and (14x+18y=86)?

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Correct Answer

B. एक ही रेखाSame line

Step 1

Concept

The second equation is (2) times the first. Therefore both equations show the same line in the graph.

Step 2

Why this answer is correct

The correct answer is B. एक ही रेखा / Same line. The second equation is (2) times the first. Therefore both equations show the same line in the graph.

Step 3

Exam Tip

दूसरा समीकरण पहले का (2) गुना है। इसलिए ग्राफ में दोनों समीकरण एक ही रेखा दिखाते हैं।

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