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What is the correct solution status for (6x-7y+13=0) and (18x-21y+40=0)?

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Answer and explanation

Correct answer: No solution

Here, \(a_1/a_2=6/18=1/3\) and \(b_1/b_2=(-7)/(-21)=1/3\), whereas \(c_1/c_2=13/40\). Thus, \(a_1/a_2=b_1/b_2\ne c_1/c_2\), which represents an inconsistent pair of equations. The two lines are distinct and parallel, so they have no solution. Exam tip: Compare the ratios of the coefficients of \(x\), \(y\), and the constants in this order to identify the solution status quickly.

Related tags

Pair Of Linear EquationsConditions For SolvabilityNo SolutionParallel LinesCoefficient Ratios

Frequently asked questions

What is the correct answer to this question?

No solution

Why is this the correct answer?

Here, \(a_1/a_2=6/18=1/3\) and \(b_1/b_2=(-7)/(-21)=1/3\), whereas \(c_1/c_2=13/40\). Thus, \(a_1/a_2=b_1/b_2\ne c_1/c_2\), which represents an inconsistent pair of equations. The two lines are distinct and parallel, so they have no solution. Exam tip: Compare the ratios of the coefficients of \(x\), \(y\), and the constants in this order to identify the solution status quickly.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Pair of Linear Equations in Two Variables. Topic: Conditions for solvability.

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