Which conclusion is correct by observing (12x+16y=36) and (3x+4y=11)?
Answer and explanation
Correct answer: The first two ratios are equal, but the ratio of the constants is different
For the two equations in standard form, \(a_1/a_2=12/3=4\) and \(b_1/b_2=16/4=4\), whereas \(c_1/c_2=36/11\), which is not 4. Thus, \(a_1/a_2=b_1/b_2\ne c_1/c_2\), so the lines are distinct and parallel and the pair has no solution. Exam tip: when the first two coefficient ratios are equal but the constant ratio is different, the pair has no solution.
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What is the correct answer to this question?
The first two ratios are equal, but the ratio of the constants is different
Why is this the correct answer?
For the two equations in standard form, \(a_1/a_2=12/3=4\) and \(b_1/b_2=16/4=4\), whereas \(c_1/c_2=36/11\), which is not 4. Thus, \(a_1/a_2=b_1/b_2\ne c_1/c_2\), so the lines are distinct and parallel and the pair has no solution. Exam tip: when the first two coefficient ratios are equal but the constant ratio is different, the pair has no solution.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Pair of Linear Equations in Two Variables. Topic: Conditions for solvability.
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