Practice focused topic-wise MCQs with answers and explanations for quick revision and exam preparation.
Difficulty select karke sirf is topic ke focused MCQs practice karein. Score, timer aur explanations student-friendly flow me milenge.
Showing 241-250 of 600 questions.
What is the value of (\left\(3^2\right\)0+4^{-1})?
B. \(\frac{5}{4}\)
(\left\(3^2\right\)0=1) और \(4^{-1}=\frac{1}{4}\) है। इसलिए योग \(\frac{5}{4}\) है। / (\left\(3^2\right\)0=1) and \(4^{-1}=\frac{1}{4}\). Therefore the sum is \(\frac{5}{4}\).
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What is the value of \(9^{-1}+3^{-2}\)?
B. \(\frac{2}{9}\)
\(9^{-1}=\frac{1}{9}\) और \(3^{-2}=\frac{1}{9}\) है। इसलिए योग \(\frac{2}{9}\) है। / \(9^{-1}=\frac{1}{9}\) and \(3^{-2}=\frac{1}{9}\). So the sum is \(\frac{2}{9}\).
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What is the value of \(3^5\cdot9^{-1}\)?
B. (27)
(9^{-1}=\(3^2\)^{-1}=3^{-2}) है। इसलिए \(3^5\cdot3^{-2}=3^3=27\) है। / (9^{-1}=\(3^2\)^{-1}=3^{-2}). Hence \(3^5\cdot3^{-2}=3^3=27\).
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What is the expansion of ((3x-4)2)?
A. \(9x^2-24x+16\)
((a-b)2=a-2-2ab+b-2) लगाएँ। यहाँ (a=3x) और (b=4) हैं। / Use ((a-b)2=a-2-2ab+b-2). Here (a=3x) and (b=4).
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What is the expansion of ((4x+3)2)?
A. \(16x^2+24x+9\)
((a+b)2) में (a=4x) और (b=3) लें। मध्य पद \(2\cdot4x\cdot3=24x\) है। / Take (a=4x) and (b=3) in ((a+b)2). The middle term is \(2\cdot4x\cdot3=24x\).
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What is the simplified form of ((6x+5)(6x-5))?
A. \(36x^2-25\)
((a+b)(a-b)=a-2-b-2) है। यहाँ (a=6x) और (b=5) हैं। / ((a+b)(a-b)=a-2-b-2). Here (a=6x) and (b=5).
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If \(2^{x+1}=64\), what is the value of (x)?
B. (5)
क्योंकि \(64=2^6\), इसलिए (x+1=6) है। इससे (x=5) मिलता है। / Since \(64=2^6\), (x+1=6). This gives (x=5).
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If \(5^{x-2}=125\), what is the value of (x)?
C. (5)
\(125=5^3\), इसलिए (x-2=3) है। इससे (x=5) मिलता है। / \(125=5^3\), so (x-2=3). This gives (x=5).
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What is the simplified form of (\frac{\(2^3\)2\cdot4^{-1}}{8})?
A. (2)
(\(2^3\)2=26), \(4^{-1}=2^{-2}\) और \(8=2^3\) है। कुल घात (6-2-3=1) है इसलिए उत्तर (2) है। / (\(2^3\)2=26), \(4^{-1}=2^{-2}\), and \(8=2^3\). The total exponent is (6-2-3=1), so the answer is (2).
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What is the factorized form of \(81x^2-100y^2\)?
A. ((9x-10y)(9x+10y))
(81x-2-100y-2=(9x)2-(10y)2) है। अंतर के वर्ग का नियम (\(a^2-b^2\)=(a-b)(a+b)) लगाएँ। / (81x-2-100y-2=(9x)2-(10y)2). Apply the difference of squares rule (\(a^2-b^2\)=(a-b)(a+b)).
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